I tried to open a pdf file and save it as xml1.0 using pywinauto. i have started writting the below code but i am not able to find the controls for menu and saving it as xml. i am new to pywinauto. can you help me in this. and also please suggest where can i get the tutorial for python pywinauto.
from pywinauto import application
In_File = "sample.pdf"
Ap = "C:\Program Files\Adobe\Acrobat 7.0\Acrobat\Acrobat.exe"
app = application.Application()
app.start_(Ap)
app.
Thanks
Here is an example for Adobe Reader X
import pywinauto
pwa_app = pywinauto.application.Application()
w_handle = pywinauto.findwindows.find_windows(title=u'Adobe Reader', class_name='AcrobatSDIWindow')[0]
window = pwa_app.window_(handle=w_handle)
window.MenuItem(u'&File->#0').Click()
By the way am the author of GUI tool for pywinauto - SWAPY. It can generate some code.
I hope it would help your automation.
Related
I m making an Excel automation via pywinauto library. But there is a hard challange for me due to using Excel Oracle add-ins called Smartview.
I need to click 'Private Connections' button, however i can't find any little info in app.Excel.print_control_identifiers() Private Connections
So i tried to use inspector.exe for find ui element regarding private connections button, however i couldn't find any little solvetion inside of inspector.exe's result inspector's result
Then i used another program called UISpy, however i can only find private connection's pane inside of the program. UISpy's result
i tried to find an answer but i couldn't find out anything. So, can you help me to click here?
By the way here is my code :
import pywinauto
from pywinauto import application
from pywinauto.keyboard import send_keys
from pywinauto.controls.common_controls import TreeViewWrapper
program_path = r"C:\Program Files\Microsoft Office\root\Office16\EXCEL.EXE"
file_path = r"C:\Users\AytugMeteBeder\Desktop\deneme.xlsx"
app = application.Application(backend="uia").start(r'{} "{}"'.format(program_path, file_path))
# sapp = application.Application(backend="uia").connect(title = 'deneme.xlsx - Excel')
time.sleep(7)
myExcel = app.denemeExcel.child_window(title="Smart View", control_type="TabItem").wrapper_object()
myExcel.click_input()
Panel = app.denemeExcel.child_window(title="Panel", control_type="Button").wrapper_object()
Panel.click_input()
time.sleep(1)
app.denemeExcel.print_control_identifiers()
using python Im trying to open my HTML file.
parallel Im loading data to my HTML but it is not reflecting in GTK webkit.
but GTK web view is not loading the runtime data but.
we have option to load data
map_webview.is_controlled_by_automation()
but is is not refreshing the page. any alternate option to refresh the webkit with new data.
below is my Code
self.map_window = self.builder.get_object("map_window")
self.map_webview = self.builder.get_object("webkit")
# self.map_window.fullscreen()
#self.map_webview = WebKit2.WebView()
self.data_file = "file://" + os.getcwd() + "/TrainMap/steptracker.html"
self.map_webview.load_uri(self.data_file)
# self.map_window.add(self.map_webview)
self.map_window.show_all()
self.map_webview.is_controlled_by_automation()
issue is resolved
used another approach(Pycario) to develop the web-view
I have a very small application written in PyCharm using python3:
import folium
map = folium.Map(location=[58.1, 23.3], zoom_start=10)
map.save('map2.html')
This will create a map2.html which I can access in my browser by using pycharm and the url looks like: http://localhost:63342/iss-country/map2.html?_ijt=dcsefdg8om4ddfovlt5ooq6ro5
How can I automatically open this in my browser? So when I run the application it does not only generate the html page but also visits it immediatley. I found the webbrowser module which can be useful but how do I know the correct localhost url?
I don't see the issue with using the webbrowser module. Just make the file name and path a variable and call the webbrowser open method.
output_file = "map2.html"
map = folium.Map(location=[58.1, 23.3], zoom_start=10)
map.save(output_file)
webbrowser.open(output_file, new=2) # open in new tab
I have a python script that tries to upload a file from my PC to a web application.
I press via WebDriver the specific upload button in the browser and then a Win7 explorer window opens for me to navigate and select the desired file to upload.
How could I manipulate this window with pywinauto?
optional: could this be done in linux as well (with an appropriate library I suppose) ?
This is my sample code:
wd.find_element_by_css_selector("img.editLecturesButtons.fromVideo").click()
#switch to the lightbox
wd.switch_to_frame(int("1"))
#hit upload
wd.find_element_by_xpath("//*[#id='fileUpload']").click()
#TODO
import os,pywinauto.application
file = os.path.normpath("C:\Users\me\Desktop\image.jpg")
....
I agree with Mark, you should try the Webdriver methods. Regard to pywinauto, code may looks like:
import pywinauto
pwa_app = pywinauto.application.Application()
w_handle = pywinauto.findwindows.find_windows(title=u'Open', class_name='#32770')[0]
window = pwa_app.window_(handle=w_handle)
ctrl = window['Name']
ctrl.SetText(file)
ctrl = window['OK']
ctrl.Click()
This sollution only for Windows, since pywinauto uses win32 api.
I wanted to automate Adobe Reader menus,
from pywinauto import application
app = application.Application()
app.start_(r"C:\Program Files (x86)\Adobe\Reader 9.0\Reader\AcroRd32.exe")
so after how to get complete windows title "Adobe Reader" & navigate to File menus
Check the documentation: http://pywinauto.googlecode.com/hg/pywinauto/docs/index.html
You can use MenuItems() to retrieve the menu items of a Dialog