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Loading A PyQt5 UI Via A Class

I'm currently trying to update my PySide code using PyQt5. And I have a class called "loader.py" that used to use "QUiLoader" from "PySide.QtUiTools", but as far as I know in PyQt5 this module has been changed by "uic".
So the problem here is that I changed my "QUiLoader" import from "uic" but I always get this error:
ui_loader.py", line 4, in <module> class UiLoader(uic): TypeError: module() takes at most 2 arguments (3 given)
Original Code in Pyside
Here is where I got the code for my PySide app
Code in PyQt5
ui_loader.py
from PyQt5 import uic
from PyQt5.QtCore import QMetaObject
class UiLoader(uic):
def __init__(self, base_instance):
uic.__init__(self, base_instance)
self.base_instance = base_instance
def createWidget(self, class_name, parent=None, name=''):
if parent is None and self.base_instance:
return self.base_instance
else:
# create a new widget for child widgets
widget = uic.createWidget(self, class_name, parent, name)
if self.base_instance:
setattr(self.base_instance, name, widget)
return widget
def load_ui(ui_file, base_instance=None):
loader = UiLoader(base_instance)
widget = loader.load(ui_file)
QMetaObject.connectSlotsByName(widget)
return widget
main.py
from PyQt5.QtWidgets import QMainWindow, QApplication
from ui_loader import load_ui
import sys
class MainWindow(QMainWindow):
def __init__(self, parent=None):
QMainWindow.__init__(self, parent)
load_ui('my_interface.ui', self)
def main():
app = QApplication(sys.argv)
window = MainWindow()
window.show()
app.exec_()
if __name__ == '__main__':
main()
I have also tried to used submethod of the class and refactoring all the code but it was useless.

You can actually load the ui using uic and then just inherit that ui into a class then self.setupUI()
ui_MainWindow, QtBaseClass = uic.loadUiType("main_window.ui")
class MainWindow(QMainWindow, ui_MainWindow):
def __init__(self):
QMainWindow.__init__(self)
self.setupUi(self)
Another way as musicamante is suggesting would be like this:
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
uic.loadUi("main_window.ui", self)

How to show the stackwidget?

I'm trying to use the stackWidget to show different widgets .
However when I pressed the item on the listWdget , stackWidget below will not be displayed.
Here is my code,and I don't know where is wrong.
#!/usr/bin/python
# music_1.py
import sys
from PyQt4 import QtGui, QtCore
from music_ui import Ui_Form
class music(QtGui.QDialog):
def __init__(self, parent=None):
QtGui.QDialog.__init__(self, parent)
self.ui = Ui_Form()
self.ui.setupUi(self)
self.ui.listWidget.insertItem(0,("Warm"))
self.ui.listWidget.insertItem(1,("Funny"))
self.ui.listWidget.insertItem(2,("Terror"))
self.ui.stackedWidget=QtGui.QStackedWidget()
warm=Warm()
funny=Funny()
terror=Terror()
self.ui.stackedWidget.addWidget(warm)
self.ui.stackedWidget.addWidget(funny)
self.ui.stackedWidget.addWidget(terror)
self.connect(self.ui.listWidget,QtCore.SIGNAL("currentRowChanged(int)"),self.ui.stackedWidget,QtCore.SLOT("setCurrentIndex(int)"))
class Warm(QtGui.QWidget):
def __init__(self,parent=None):
super(Warm,self).__init__(parent)
w1=QtGui.QPushButton("w1")
w2=QtGui.QPushButton("w2")
buttonLayout=QtGui.QHBoxLayout()
buttonLayout.addStretch(1)
buttonLayout.addWidget(w1)
buttonLayout.addWidget(w2)
class Funny(QtGui.QWidget):
def __init__(self,parent=None):
super(Funny,self).__init__(parent)
f1=QtGui.QPushButton("f1")
f2=QtGui.QPushButton("f2")
f3=QtGui.QPushButton("f3")
buttonLayout=QtGui.QHBoxLayout()
buttonLayout.addStretch(1)
buttonLayout.addWidget(f1)
buttonLayout.addWidget(f2)
buttonLayout.addWidget(f3)
class Terror(QtGui.QWidget):
def __init__(self,parent=None):
super(Terror,self).__init__(parent)
t1=QtGui.QPushButton("t1")
t2=QtGui.QPushButton("t2")
buttonLayout=QtGui.QHBoxLayout()
buttonLayout.addStretch(1)
buttonLayout.addWidget(t1)
buttonLayout.addWidget(t2)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = music()
myapp.show()
sys.exit(app.exec_())

I never worked with UI Files but this is my guess:
self.ui.stackedWidget=QtGui.QStackedWidget()
here you create a QStackedWidget which gets assigned to the class. The problem is that it is not added to the UI that is getting displayed but just to the instance of the Ui_Form. What you have to do is either:
Add the QStackedWidget in the UI Designer and erase the line above
or
Add the QStackedWidget to one of your layouts
which can be done like this:
self.ui.mySuperCoolLayout.addWidget(self.ui.stackedWidget)

Working with PyQt and Qt designer ui files

I'm new to PyQt and I'm trying to work with ui files directly from within my PyQt script. I have two ui files, mainwindow.ui and landing.ui. Clicking on a button 'pushButton' on the main window should open the landing window. However, clicking on the button does not work as I expected. Here is the code(I'm just trying to work stuff out so the code is pretty rough):
from PyQt4 import QtCore, uic
from PyQt4 import QtGui
import os
CURR = os.path.abspath(os.path.dirname('__file__'))
form_class = uic.loadUiType(os.path.join(CURR, "mainwindow.ui"))[0]
landing_class = uic.loadUiType(os.path.join(CURR, "landing.ui"))[0]
def loadUiWidget(uifilename, parent=None):
uifile = QtCore.QFile(uifilename)
uifile.open(QtCore.QFile.ReadOnly)
ui = uic.loadUi(uifilename)
uifile.close()
return ui
#QtCore.pyqtSlot()
def clicked_slot():
"""this is called when login button is clicked"""
LandingPage = loadUiWidget(os.path.join(CURR, "landing.ui"))
center(LandingPage)
icon(LandingPage)
LandingPage.show()
class MyWindow(QtGui.QMainWindow, form_class):
def __init__(self, parent=None):
QtGui.QMainWindow.__init__(self, parent)
self.setupUi(self)
self.pushButton.clicked.connect(clicked_slot)
class LandingPage(QtGui.QMainWindow, landing_class):
def __init__(self, parent=None):
QtGui.QMainWindow.__init__(self, parent)
self.setupUi(self)
def center(self):
""" Function to center the application
"""
qRect = self.frameGeometry()
centerPoint = QtGui.QDesktopWidget().availableGeometry().center()
qRect.moveCenter(centerPoint)
self.move(qRect.topLeft())
def icon(self):
""" Function to set window icon
"""
appIcon = QtGui.QIcon("icon.png")
self.setWindowIcon(appIcon)
if __name__ == "__main__":
import sys
app = QtGui.QApplication(sys.argv)
pixmap = QtGui.QPixmap(os.path.join(CURR, "splash.png"))
splash = QtGui.QSplashScreen(pixmap)
splash.show()
app.processEvents()
MainWindow = MyWindow(None)
center(MainWindow)
icon(MainWindow)
MainWindow.show()
splash.finish(MainWindow)
sys.exit(app.exec_())
What mistake I'm I making??

There are two main problems with your script: firstly, you are not constructing the path to the ui files correctly; and secondly, you are not keeping a reference to the landing-page window (and so it will get garbage-collected immediately after it is shown).
Here is how the part of the script that loads the ui files should be structured:
import os
from PyQt4 import QtCore, QtGui, uic
# get the directory of this script
path = os.path.dirname(os.path.abspath(__file__))
MainWindowUI, MainWindowBase = uic.loadUiType(
os.path.join(path, 'mainwindow.ui'))
LandingPageUI, LandingPageBase = uic.loadUiType(
os.path.join(path, 'landing.ui'))
class MainWindow(MainWindowBase, MainWindowUI):
def __init__(self, parent=None):
MainWindowBase.__init__(self, parent)
self.setupUi(self)
self.pushButton.clicked.connect(self.handleButton)
def handleButton(self):
# keep a reference to the landing page
self.landing = LandingPage()
self.landing.show()
class LandingPage(LandingPageBase, LandingPageUI):
def __init__(self, parent=None):
LandingPageBase.__init__(self, parent)
self.setupUi(self)

Load other windows when button clicked. PyQt

I am trying to call another window from a button click in python 2.7 using PyQt4. The code below opens the AddBooking dialog but immediately closes it. Im new to Gui programming, can somebody please tell me what is wrong with my code?
from PyQt4 import QtGui
from HomeScreen import Ui_HomeScreen
from AddBooking import Ui_AddBooking
import sys
class HomeScreen(QtGui.QWidget, Ui_HomeScreen):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setupUi(self)
self.show()
self.Add_Booking_Button.clicked.connect(self.handleButton)
def handleButton(self):
AddBooking2()
class AddBooking2(QtGui.QWidget, Ui_AddBooking):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setupUi(self)
self.show()
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
window = HomeScreen()
window.show()
sys.exit(app.exec_())

Don't use multi-inheritance and neither call show function inside class initializer. The problem is that the object you are creating with AddBooking2() is a temporal and it's destroyed automatically when the function ends. So you need use some variable to reference that object something like:
addbooking = AddBooking2()
addbooking.show()
Also, since you are working with QtDesigner and pyuic4 tools you can make connections a little bit easier. Said that, your code can be modified:
from PyQt4 import QtGui
from PyQt4.QtCore import pyqtSlot
from HomeScreen import Ui_HomeScreen
from AddBooking import Ui_AddBooking
import sys
class HomeScreen(QtGui.QWidget):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_HomeScreen()
self.ui.setupUi(self)
#pyqtSlot("")
def on_Add_Booking_Button_clicked(self): # The connection is carried by the Ui_* classes generated by pyuic4
addbooking = AddBooking2()
addbooking.show()
class AddBooking2(QtGui.QWidget):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_AddBooking()
self.ui.setupUi(self)
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
window = HomeScreen()
window.show()
sys.exit(app.exec_())

The dialog closes immediately because you are not keeping a reference to it, and so it will get garbage-collected as soon as it goes out of scope.
The simplest way to fix it would be to do something like this:
def handleButton(self):
self.dialog = AddBooking2()
self.dialog.show()
and you can also remove the self.show() lines from AddBooking2.__init__ and HomeScreen.__init__, which are redundant. Other than that, your code looks fine.

Open a GUI file from another file PyQT

I've created many GUI interfaces in PyQT using QT Designer, but now I'm trying to open an interface from another one, and I don't know how to do it..
Start.py is the file which run the GUI Interface Authentification_1 and Acceuil_start.py is the file which run the GUI interface Acceuil_2.py, now I want from Start.py to lunch Acceuil_start.py.
Do you have any idea about that ? Thank you.
Here's my code :
Start.py :
import sys
from PyQt4 import QtCore, QtGui
from Authentification_1 import Ui_Fenetre_auth
from Acceuil_2 import Ui_MainWindow #??? Acceuil_2.py is the file which I want to open
class StartQT4(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_Fenetre_auth()
self.ui.setupUi(self)
def authentifier(val): #Slot method
self.Acceuil = Acceuil() #???
self.Acceuil.show() #???
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = StartQT4()
myapp.show()
sys.exit(app.exec_())
Acceuil_start.py
import sys
from PyQt4 import QtCore, QtGui
from Authentification_1 import Ui_Fenetre_auth
from Acceuil_2 import Ui_MainWindow
class StartQT4(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = StartQT4()
myapp.show()
sys.exit(app.exec_())

First, you should to name your GUI classes so they have a different name, and not the generic one, so you could distinct them.
Why you would need to do that? Well - simply, because it makes sense - if every class is representing different type of dialog, so it is the different type - and it should be named differently. Some of the names are/may be: QMessageBox, AboutBox, AddUserDialog, and so on.
In Acceuil_start.py (you should rename class in other module, too).
import sys
from PyQt4 import QtCore, QtGui
from Authentification_1 import Ui_Fenetre_auth
from Acceuil_2 import Ui_MainWindow
class Acceuil(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = Acceuil()
myapp.show()
sys.exit(app.exec_())
in the parent class, when you want to create the window, you are close (but it should work in any case):
def authentifier(val): #Slot method
self.Acceuil = Acceuil(self) # You should always pass the parent to the child control
self.Acceuil.show() #???
About parent issue: If your widget/window is creating another widget, setting creator object to be parent is always a good idea (apart from some singular cases), and you should read this to see why is that so:
QObjects organize themselves in object trees. When you create a QObject with another object as parent, it's added to the parent's children() list, and is deleted when the parent is. It turns out that this approach fits the needs of GUI objects very well. For example, a QShortcut (keyboard shortcut) is a child of the relevant window, so when the user closes that window, the shorcut is deleted too.
Edit - Minimal Working Sample
To see what I am trying to tell you, I've built a simple example. You have two classes - MainWindow and
ChildWindow. Every class can work without other class by creating separate QApplication objects. But, if you import ChildWindow in MainWindow, you will create ChildWindow in slot connected to singleshot timer which will trigger in 5 seconds.
MainWindow.py:
import sys
from PyQt4 import QtCore, QtGui
from ChildWindow import ChildWindow
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
QtCore.QTimer.singleShot(5000, self.showChildWindow)
def showChildWindow(self):
self.child_win = ChildWindow(self)
self.child_win.show()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MainWindow()
myapp.show()
sys.exit(app.exec_())
ChildWindow.py:
import sys
from PyQt4 import QtCore, QtGui
class ChildWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setWindowTitle("Child Window!")
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = ChildWindow()
myapp.show()
sys.exit(app.exec_())

To reference the other dialog from Start.py, you must prefix it by the module name, which in this case is Acceuil_start. As such, it is OK if there are duplicated function names in each module. So, you would have:
def authentifier(val): #Slot method
dlg = Acceuil_start.StartQT4()
dlg.exec_()
However, if you want these to run from the same process, keep in mind that you can't have two app objects. You would probably want to structure Acceuil_start.py to act like a dialog, rather than a main window. If these are two distinct main windows, you might find it easier to just invoke another Python interpreter with the Acceuil_start.py as a parameter.