Convert an EXE and its dependencies into one stand-alone EXE - python

I'm using cx_Freeze to compile Python programs into executables and it works just fine, but the problem is that it doesn't compile the program into one EXE, it converts them into a .exe file AND a whole bunch of .dll files including python32.dll that are necessary for the program to run.
Does anyone know how I can package all of these files into one .exe file? I would rather it be a plain EXE file and not just a file that copies the DLLs into a temporary directory in order to launch the program.
EDIT: This is in reference to Python 3

You have at least two options: PyInstaller or py2exe.
With py2exe, there's an option called bundle_files, that you can set:
3 (default): Don't bundle.
2: Bundle everything but the Python interpreter.
1: Bundle everything, including the Python interpreter.
Here is a sample setup.py:
from distutils.core import setup
import py2exe, sys, os
sys.argv.append('py2exe')
setup(
options = {'py2exe': {'bundle_files': 1}},
windows = [{'script': "single.py"}],
zipfile = None,
)
This approach does not require extracting files to a temporary location.

Pyinstaller is usually the easier option when compiling a python script into one file.
pyinstaller.py program.py --onefile
See the documentation here: http://www.pyinstaller.org/export/v2.0/project/doc/Manual.html?format=raw

Have you tried innosetup? It can create installer files from the output of cxfreeze. There might be an option somewhere to bundle everything into one file.

Related

Python EXE file creation

I have this code which i need to create it as a python exe file, where in user has to click the workflow done.
My Sample Project
import os
import pandas as pd
import sys
import csv
path = os.getcwd()
v1 = pd.read_csv(r"path\V1.tsv", delimiter = '\t')
v1.to_csv(r"path\v2.csv", index=False)
I used Pyinstaller to create a .exe file but it didnt help me achieve what I want. Can some one suggest me?
Depending on what disappointed you about PyInstaller, (speed? size? too many files in directory?), you may either want to try:
PyInstaller's --onefile flag, which will compile everything into one .exe file but will take forever to run
cx_Freeze. This can generate .exe files like PyInstaller, though performance won't be much better. What I find most useful is to compile the files into an installer by calling py setup.py bdist_msi (Windows) or py setup.py bdist_dmg (Linux). People can use the installer to add the .exe to their machines. Installer-created .exe files will run very quickly.
Have your tried using the --onefile flag to specify that you only want 1 exe file to be created for that script.
For example use the cmd: pyinstaller --onefile file_name.py
If this does not help can you specify the issue that is occurring.

Compile Python to a standalone exe?

I need to make a python script into a standalone .exe file. I have tried to use py2exe using this compile code:
from distutils.core import setup
import py2exe
setup(console=['script.py'])
But all it does is spit out a folder with the exe file, as well as a bunch of other stuff. Problem is, I cannot run the exe file without it being in the same exact folder as the other files.
Is there a way to make a standalone .exe file that does not require any other files to run?
Use pyinstaller instead.
https://github.com/pyinstaller/pyinstaller/wiki
When you use it, make sure you use the --onefile option, this will pack all the libraries into a single .exe file. You may need to use one of the developing versions, as it is an old project.
-Robbie
Yes, I would suggest the following for you:
from distutils.core import setup
import py2exe
import sys
__author__ = 'you'
sys.argv.append('py2exe')
setup(
options={'py2exe': {
'bundle_files': 1,
'unbuffered': True,
'compressed': True}},
console=['script.py'],
zipfile=None,
)
This will create a single exe file, from the script that you can run from anywhere on your machine.

can you manualy make standalone python executeable? [duplicate]

This question already has answers here:
Create a single executable from a Python project [closed]
(3 answers)
Closed 3 years ago.
I wrote a script that will help a Windows user in her daily life. I want to simply send her the .exe and not ask her to install python, dlls or have to deal with any additional files.
I've read plenty of the stackoverflow entries regarding compiling Python scripts into executable files. I am a bit confused as there are many options but some seem dated (no updates since 2008) and none were simple enough for me not to be asking this right now after a few hours spent on this.
I'm hoping there's a better, up-to-date way to do this.
I looked into:
pylunch
py2exe
cx_Freeze
py2app (only for Mac)
pyinstaller
bbfreeze
but either I couldn't get them to work or couldn't understand how to get the result I need. The closest I got was with py2exe but it still gave me the MSVCR71.dll
I would appreciate a step-by-step answer as I was also unable to follow some of the tweaking answers here that require some prior understanding of how to use py2exe or some of the other tools.
I'm using Python 2.5 as one of the modules is only available for that version.
PyInstaller will create a single-file executable if you use the --onefile option (though what it actually does is extracts then runs itself).
There's a simple PyInstaller tutorial here. If you have any questions about using it, please post them...
Using py2exe, include this in your setup.py:
from distutils.core import setup
import py2exe, sys, os
sys.argv.append('py2exe')
setup(
options = {'py2exe': {'bundle_files': 1}},
windows = [{'script': "YourScript.py"}],
zipfile = None,
)
then you can run it through command prompt / Idle, both works for me. Hope it helps
i would recommend going to http://sourceforge.net/projects/py2exe/files/latest/download?source=files to download py2exe. Then make a python file named setup.py.
Inside it, type
from distutils.core import setup
import py2exe
setup(console=['nameoffile.py'])
Save in your user folder
Also save the file you want converted in that same folder
Run window's command prompt
type in setup.py install py2exe
It should print many lines of code...
Next, open the dist folder.
Run the exe file.
If there are needed files for the program to work, move them to the folder
Copy/Send the dist folder to person.
Optional: Change the name of the dist folder
Hope it works!:)
I would join #Nicholas in recommending PyInstaller (with the --onefile flag), but be warned: do not use the "latest release", PyInstaller 1.3 -- it's years old. Use the "pre-release" 1.4, download it here -- or even better the code from the svn repo -- install SVN and run svn co http://svn.pyinstaller.org/trunk pyinstaller.
As #Nicholas implies, dynamic libraries cannot be run from the same file as the rest of the executable -- but fortunately they can be packed together with all the rest in a "self-unpacking" executable that will unpack itself into some temporary directory as needed; PyInstaller does a good job at this (and at many other things -- py2exe is more popular, but pyinstaller in my opinion is preferable in all other respects).
1) Get py2exe from here, according to your Python version.
2) Make a file called "setup.py" in the same folder as the script you want to convert, having the following code:
from distutils.core import setup
import py2exe
setup(console=['myscript.py']) #change 'myscript' to your script
3) Go to command prompt, navigate to that folder, and type:
python setup.py py2exe
4) It will generate a "dist" folder in the same folder as the script. This folder contains the .exe file.
you may want to see if your app can run under IronPython. If so, you can compile it to an exe
http://www.codeplex.com/IronPython
You can create executable from python script using NSIS (Nullsoft scriptable install system). Follow the below steps to convert your python files to executable.
Download and install NSIS in your system.
Compress the folder in the .zip file that you want to export into the executable.
Start NSIS and select Installer based on ZIP file. Find and provide a path to your compressed file.
Provide your Installer Name and Default Folder path and click on Generate to generate your exe file.
Once its done you can click on Test to test executable or Close to complete the process.
The executable generated can be installed on the system and can be distributed to use this application without even worrying about installing the required python and its packages.
For a video tutorial follow: How to Convert any Python File to .EXE
You could create an installer for you EXE file by:
1. Press WinKey + R
2. Type "iexpress" (without quotes) into the run window
3. Complete the wizard for creating the installation program.
4. Distribute the completed EXE.

Using py2exe, how to create an executable usng python and tkinter?

I'm trying to turn a program that I've written in Python 2.7 (using tkinter for the GUI) into a standalone executable using py2exe. I've written the following script in a file called setup.py:
from distutils.core import setup
import py2exe
setup(data_files=['C:\Python27\tcl\tcl8.5\init.tcl'] , windows = ["Brand_Counter.py"])
When I run this, the command prompt opens for a second, then nothing happens. As far as I can tell, according to the documentation my code should create a subdirectory "dist" which will contain my executable, but this isn't happening. Does anybody see anything wrong with my code?
To do a build of a py2exe project, you should issue this command from the directory that contains your setup.py file:
python setup.py py2exe
Works well for me.
EDIT ---
In addition you're using the data_files parameter which takes a list of tuples. Your parameter should look something like this:
data_files=[('tclfiles', ['C:\Python27\tcl\tcl8.5\init.tcl'])]
Adjusted for wherever you want to place your init.tcl file. For more examples see this link: py2exe data_files

.PY into .EXE Python 2.6

I'm trying to convert my .PY script into a .EXE file, in the process I have tried PY2EXE with the following command line..
python C:\Users\Noob\Desktop\setup.py py2exe -p ftplib
-> -p ftplib is for my module import.
When I use this code, I'm left with an .EXE and a bunch of files, if I take the .EXE out then it will come up with an error. It is required to have "_socket.pyd" and "python26.dll" or it will crash (the program). How do I compile this (not having to use PY2EXE or having to use it) without these extra files?
Thanks a lot!
You should not be taking the exe out of your folder and executing. Just execute it from the dist directory where got created, it has the python26.dll which the executable needs. If you want to ship it, zip the dist directory and ship it. Otherwise you have to create an installer using specific installer software like NSIS.
I hope you took a look at the Python2.6 specific section, which has details on how to write data_files to include msvcr90.dll
Also, I am finding this -p ftplib cmd option pretty new. Usually all things to do are within setup.py. Can you point out where this kind of option specification is mentioned.
It is possible to make single file executables with py2exe, the setup.pyfile would look something like this:
from distutils.core import setup
import py2exe
setup(
console=['yourscript.py'], # list of scripts to convert into console exes
zipfile=None, # library files in exe instead of zipfile (defaults to "library.zip")
options = {
'py2exe': {
'bundle_files': 1, # bundle dlls and python interpreter in the exe
}
}
)
See py2exe's list of options for more info. Also have a look at the "What are all those files?" question from the FAQ.
You might also want to have a look at PyInstaller (which seems to be doing a better job of creating single file exe's with Microsoft MSVCR*.DLL files included if you need those) Be sure to use the 1.5 series for python 2.6 on Windows.

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