Hey I'm using streamripper for win32.
I've setup a sample python script to display dummy metadata.
Streamripper just plain doesn't pick it up. I've put it in the same format as the example:
http://streamripper.sourceforge.net/history.php
It just doesn't work for me.
Anyone know how to fix?
import time
while 1:
print 'TITLE=thisname\nARTIST=thisartist\n.\n'
time.sleep(10)
I put the script in the root directory of streamripper.
Tried linking by using:
script.py
c:/program files/streamripper/script.py
c:\\program files\\streamripper\\script.py
example:
CMD-->
cd c:/program files/streamripper
streamripper http://stream-114.shoutcast.com:80/smoothjazz_skyfm_mp3_96kbps -E script.py
nothing works...
the correct usage is:
streamrippper URL -E python "path to script"
must add python to environment variables of windows
perl conveniently already does on win32 install, but python doesn't
streamripper URL -E perl "path to script"
Also in python, you must flush the output immediately
This works:
import time
import sys
while 1:
print 'TITLE=thetitle\nARTIST=theartistname\n.'
sys.stdout.flush()
time.sleep(10)
Related
I'm currently working on Pycharm with remote python Interpreter(miniconda3/bin/python).
So when I type echo $PATH in remote server, it prints
/home/woosung/bin:/home/woosung/.local/bin:/home/woosung/miniconda3/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/snap/bin
I created project in Pycharm and set remote python Interpreter as miniconda3 python, it works well when I just run some *.py files.
But when I typed some os.system() lines, weird things happened.
For instance, in test.py from Pycharm project
import os
os.system('echo $PATH')
os.system('python --version')
Output is
ssh://woosung#xxx.xxx.xxx.xxx:xx/home/woosung/miniconda3/bin/python -u /tmp/pycharm_project_203/test.py
/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games
Python 2.7.12
Process finished with exit code 0
I tried same command in remote server,
woosung#test-pc:~$ echo $PATH
/home/woosung/bin:/home/woosung/.local/bin:/home/woosung/miniconda3/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/snap/bin
woosung#test-pc:~$ python --version
Python 3.6.6 :: Anaconda, Inc.
PATH and the version of python are totally different! How can I fix this?
I've already tried add os.system('export PATH="$PATH:$HOME/miniconda3/bin"') to test.py. But it still gives same $PATH.(/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games)
EDIT
Thanks to the comment of #Dietrich Epp, I successfully add interpreter path to the shell $PATH.
(os.environ["PATH"] += ":/home/woosung/miniconda3/bin")
But I stuck the more basic problem. When I add the path and execute command the some *.py file including import library which is only in miniconda3, the shell gives ImportError.
For instance, in test.py
import matplotlib
os.environ["PATH"] += ":/home/woosung/miniconda3/bin"
os.system("python import_test.py")
and import_test.py
import matplotlib
And when I run test.py,
Traceback (most recent call last):
File "import_test.py", line 1, in <module>
import matplotlib
ImportError: No module named matplotlib
Looks like the shell doesn't understand how to utilize modified $PATH.
I find the solution.
It is not direct but quite simple.
I changed os.system("python import_test.py") to os.system(sys.executable + ' import_test.py').
This makes the shell uses the Pycharm remote interpreter(miniconda3), not original.
#!/usr/bin/python
import requests, zipfile, StringIO, sys
extractDir = "myfolder"
zip_file_url = "download url"
response = requests.get(zip_file_url)
zipDocument = zipfile.ZipFile(StringIO.StringIO(response.content))
zipinfos = zipDocument.infolist()
for zipinfo in zipinfos:
extrat = zipDocument.extract(zipinfo,path=extractDir)
System configuration
Ubuntu OS 16.04
Python 2.7.12
$ python extract.py
when I run the code on Terminal with above command, it works properly and create the folder and extract the file into it.
Similarly, when I create a cron job using sodu rights the code executes but don't create any folder or extracts the files.
crontab command:-
40 10 * * * /usr/bin/sudo /usr/bin/python /home/ubuntu/demo/directory.py > /home/ubuntu/demo/logmyshit.log 2>&1
also tried
40 10 * * * /usr/bin/python /home/ubuntu/demo/directory.py > /home/ubuntu/demo/logmyshit.log 2>&1
Notes :
I check the syslog, it says the cron is running successfully
The above code gives no errors
also made the python program executable by chmod +x filename.py
Please help where am I going wrong.
Oups, there is nothing really wrong in running a Python script in crontab, but many bad things can happen because the environment is not the one you are used to.
When you type in an interactive shell python directory.py, the PATH and all required PYTHON environment variable have been set as part of login and interactive shell initialization, and the current directory is your home directory by default or anywhere you currently are.
When the same command is run from crontab, the current directory is not specified (but may not be what you expect), PATH is only /bin:/usr/bin and python environment variables are not set. That means that you will have to tweak environment variables in crontab file until you get a correct Python environment, and set the current directory.
I had a very similar problem and it turned out cron didn’t like importing matplotlib, I ended up having to specify Agg backend. I figured it out by putting log statements after each line to see how far the program got before it crapped out. Of course, my log was empty which tipped me off that it crashed on imports.
TLDR: log each line inside the script
I need some advice with a Python script. I'm still new and learned it by myself. I found the script on Google. After I retype it, it doesn't print the result in the console. How can the result of the script be shown in the console? Details as below:
C:\Python27>test1.py af8978b1797b72acfff9595a5a2a373ec3d9106d
C:\Python27>
After I press enter, nothing happens. Should the result be shown or not?
Here's the code that I retyped:
#!/usr/bin/python
#coding: ascii
import requests
import sys
import re
url = 'http://hashtoolkit.com/reverse-hash?hash='
try:
hash = sys.argv[1]
except:
print ("usage: python "+sys.argv[0]+" hash")
sys.exit()
http = request.get(url+hash)
content = http.content
cracked = re.findall("<span title=\*decrypted (md5|sha1|sha384|sha512) hash\*>(.*)</span>", content) # expression regular
print ("\n\tAlgoritmo: "+cracked[0][0])
print ("\tPassword Cracked: "+cracked[0][1])
The first line in your script is called a Shebang line.
A Shebang line tells the script to run the Python interpreter from that location.
The shebang line you provided is a Linux system path, but it looks from the path you are executing Python from, that you are running on Windows.
You can do one of two things here to fix that:
Remove the Shebange Line.
Remove the first line from your script.
Execute the script using python test1.py COMMAND_LINE_ARGUMENTS
Modify Your Shebang line.
Change the first line of your script from !/usr/bin/python to
#!python (This is assuming that python is in your systems PATH variable.)`
Execute the script using test1.py COMMAND_LINE_ARGUMENTS
Also, you are trying to import the requests module that is not installed in the standard library.
If you haven't installed this yet, you can do so by going to your Python install directory and go to the scripts folder.
Hold shift and right click and go Open command window here
Type pip install requests and hit enter.
After that you should be good to go, execute the script by navigating to it and type test.py COMMAND_LINE_ARGUMENT
If a Python script doesn't have the shebang line:
python test.py COMMAND_LINE_ARGUMENT
you need to run your script using python. try:
C:\Python27>python test1.py af8978b1797b72acfff9595a5a2a373ec3d9106d
Windows 10 Home Version 1607. Python 3.5.2
I'm new to python, I've tried to run python script using a batch file. I've added my folder contain batch files to the PATH Environment Variables. Have tried to run my python script by typing in 'HelloWorld' on Win+R
However a error message pops saying 'This app can't run on your pc' and the cmd keeps on returning the current message
Access Denied. Press any key to continue.....
Python Script. Saved as HelloWorld.py
#! python3
import sys
print('Hello World')
print(sys.argv)
Batch File. Saved as HelloWorld.bat
#py C:\Users\Anthony\MyPythonScripts\HelloWorld.py %*
#pause
You are mistakenly using py instead of python to execute your script.
This causes the messages you are getting.
If you use python 3.5.2 or python 2.7 in a project or in a script to run it you should use the command
d:\Users\nameofuser>python nameofmyscript.
For exemple i have a script in python2:
import os
print "Hello wolrd! I'm a rabbit!"
i will run it with python rabbit.py
answer: Hello wolrd! I'm a rabbit!
if i have my script in python 3
import os
print("Hello wolrd! I'm a rabbit!")
this time i can use python3 rabbit.py or python rabbit.py
The only thing you can't do is to use python3 for a python 2.7 script you will have a SyntaxError
How can I run a python script with my own command line name like myscript without having to do python myscript.py in the terminal?
Add a shebang line to the top of the script:
#!/usr/bin/env python
Mark the script as executable:
chmod +x myscript.py
Add the dir containing it to your PATH variable. (If you want it to stick, you'll have to do this in .bashrc or .bash_profile in your home dir.)
export PATH=/path/to/script:$PATH
The best way, which is cross-platform, is to create setup.py, define an entry point in it and install with pip.
Say you have the following contents of myscript.py:
def run():
print('Hello world')
Then you add setup.py with the following:
from setuptools import setup
setup(
name='myscript',
version='0.0.1',
entry_points={
'console_scripts': [
'myscript=myscript:run'
]
}
)
Entry point format is terminal_command_name=python_script_name:main_method_name
Finally install with the following command.
pip install -e /path/to/script/folder
-e stands for editable, meaning you'll be able to work on the script and invoke the latest version without need to reinstall
After that you can run myscript from any directory.
I usually do in the script:
#!/usr/bin/python
... code ...
And in terminal:
$: chmod 755 yourfile.py
$: ./yourfile.py
Another related solution which some people may be interested in. One can also directly embed the contents of myscript.py into your .bashrc file on Linux (should also work for MacOS I think)
For example, I have the following function defined in my .bashrc for dumping Python pickles to the terminal, note that the ${1} is the first argument following the function name:
depickle() {
python << EOPYTHON
import pickle
f = open('${1}', 'rb')
while True:
try:
print(pickle.load(f))
except EOFError:
break
EOPYTHON
}
With this in place (and after reloading .bashrc), I can now run depickle a.pickle from any terminal or directory on my computer.
The simplest way that comes to my mind is to use "pyinstaller".
create an environment that contains all the lib you have used in your code.
activate the environment and in the command window write pip install pyinstaller
Use the command window to open the main directory that codes maincode.py is located.
remember to keep the environment active and write pyinstaller maincode.py
Check the folder named "build" and you will find the executable file.
I hope that this solution helps you.
GL
I've struggled for a few days with the problem of not finding the command py -3 or any other related to pylauncher command if script was running by service created using Nssm tool.
But same commands worked when run directly from cmd.
What was the solution? Just to re-run Python installer and at the very end click the option to disable path length limit.
I'll just leave it here, so that anyone can use this answer and find it helpful.