How to delete Tkinter widgets from a window? - python

I have a list of tkinter widgets that I want to change dynamically.
How to delete the widgets from the window?

You can call pack_forget to remove a widget (if you use pack to add it to the window).
Example:
from tkinter import *
root = Tk()
b = Button(root, text="Delete me", command=lambda: b.pack_forget())
b.pack()
root.mainloop()
If you use pack_forget, you can later show the widget again calling pack again. If you want to permanently delete it, call destroy on the widget (then you won't be able to re-add it).
If you use the grid method, you can use grid_forget or grid_remove to hide the widget.

One way you can do it, is to get the slaves list from the frame that needs to be cleared and destroy or "hide" them according to your needs. To get a clear frame you can do it like this:
from tkinter import *
root = Tk()
def clear():
list = root.grid_slaves()
for l in list:
l.destroy()
Label(root,text='Hello World!').grid(row=0)
Button(root,text='Clear',command=clear).grid(row=1)
root.mainloop()
You should call grid_slaves(), pack_slaves() or slaves() depending on the method you used to add the widget to the frame.

You simply use the destroy() method to delete the specified widgets like this:
lbl = tk.Label(....)
btn = tk.Button(....., command=lambda: lbl.destroy())
Using this you can completely destroy the specific widgets.

You say that you have a list of widgets to change dynamically. Do you want to reuse and reconfigure existing widgets, or create all new widgets and delete the old ones? It affects the answer.
If you want to reuse the existing widgets, just reconfigure them. Or, if you just want to hide some of them temporarily, use the corresponding "forget" method to hide them. If you mapped them with pack() calls, you would hide with pack_forget() (or just forget()) calls. Accordingly, grid_forget() to hide gridded widgets, and place_forget() for placed widgets.
If you do not intend to reuse the widgets, you can destroy them with a straight destroy() call, like widget.destroy(), to free up resources.

clear_btm=Button(master,text="Clear") #this button will delete the widgets
clear_btm["command"] = lambda one = button1, two = text1, three = entry1: clear(one,two,three) #pass the widgets
clear_btm.pack()
def clear(*widgets):
for widget in widgets:
widget.destroy() #finally we are deleting the widgets.

Today I learn some simple and good click event handling using tkinter gui library in python3, which I would like to share inside this thread.
from tkinter import *
cnt = 0
def MsgClick(event):
children = root.winfo_children()
for child in children:
# print("type of widget is : " + str(type(child)))
if str(type(child)) == "<class 'tkinter.Message'>":
# print("Here Message widget will destroy")
child.destroy()
return
def MsgMotion(event):
print("Mouse position: (%s %s)" % (event.x, event.y))
return
def ButtonClick(event):
global cnt, msg
cnt += 1
msg = Message(root, text="you just clicked the button..." + str(cnt) + "...time...")
msg.config(bg='lightgreen', font=('times', 24, 'italic'))
msg.bind("<Button-1>", MsgClick)
msg.bind("<Motion>", MsgMotion)
msg.pack()
#print(type(msg)) tkinter.Message
def ButtonDoubleClick(event):
import sys; sys.exit()
root = Tk()
root.title("My First GUI App in Python")
root.minsize(width=300, height=300)
root.maxsize(width=400, height=350)
button = Button(
root, text="Click Me!", width=40, height=3
)
button.pack()
button.bind("<Button-1>", ButtonClick)
button.bind("<Double-1>", ButtonDoubleClick)
root.mainloop()
Hope it will help someone...

You can use forget method on the widget
from tkinter import *
root = Tk()
b = Button(root, text="Delete me", command=b.forget)
b.pack()
b['command'] = b.forget
root.mainloop()

I found that when the widget is part of a function and the grid_remove is part of another function it does not remove the label. In this example...
def somefunction(self):
Label(self, text=" ").grid(row = 0, column = 0)
self.text_ent = Entry(self)
self.text_ent.grid(row = 1, column = 0)
def someotherfunction(self):
somefunction.text_ent.grid_remove()
...there is no valid way of removing the Label.
The only solution I could find is to give the label a name and make it global:
def somefunction(self):
global label
label = Label(self, text=" ")
label.grid(row = 0, column = 0)
self.text_ent = Entry(self)
self.text_ent.grid(row = 1, column = 0)
def someotherfunction(self):
global label
somefunction.text_ent.grid_remove()
label.grid_remove()
When I ran into this problem there was a class involved, one function being in the class and one not, so I'm not sure the global label lines are really needed in the above.

Related

How to identify labels on a Python Tkinter Tab in the event handler

I am placing labels on a Tab in Tkinter with a for loop. How can I identify in the event handler which label was clicked (or its loop index)? I guess it is functionally similar to a ListBox but without the formatting restrictions. I might want to put the labels in a circle or place them diagonally. I tried finding the coordinates of the label but these are available only if the tab is the first one visible or the tab is redrawn when made active. Also the x, y passed in the event handler is the x, y within the label which does not help to identify the label.
I could copy the label code about 10 times and and have about 10 event handlers. This would work but this is no longer 1970!
Perhaps I could bind a handler to the tab canvas and identify the label from its coordinates. The label would need to be on the first tab or the tab drawn when active.
Perhaps I could create a different event handler for each label by holding the event handlers in an array. I would need an event handler for each label. The code would need to change if the number of labels changed.
I am currently trying a label with ''. Would using buttons with command be easier?
What simple part of Python am I missing? I cannot be the first person to need this! Any help or advice would be appreciated.
You can save a reference to the label text for each label widget in a dict.
import tkinter as tk
from tkinter import ttk
root = tk.Tk()
root.geometry('+800+50')
notebook = ttk.Notebook(root, width=300, height=200, padding=[10,10,10,10])
notebook.pack()
tab_one = tk.Frame(notebook, bg='wheat')
notebook.add(tab_one, text='Cheese', padding=[10,10,10,10])
tab_two = tk.Frame(notebook, bg='mint cream')
notebook.add(tab_two, text='Misc.', padding=[10,10,10,10])
def clicked(event):
print('Clicked:', name_dict[event.widget])
# Populating Cheese tab with clickable Labels
name_list = ['Cheddar', 'Ilchester', 'Limburger']
name_dict = {}
for index, name in enumerate(name_list):
a = tk.Label(tab_one, width=10, text=name, bg='peru')
a.grid(row=index, column=0, padx=5, pady=5)
name_dict[a] = name # Save references in a dict
a.bind('<Button-1>', clicked)
tk.Label(tab_two, text='Just some text...', bg='powder blue').pack(anchor='nw')
root.mainloop()
Is this what you had in mind?
When you bind events, the function receives an object that includes a reference to the widget that received the event. In the following example, notice how it uses event.widget to refer to the widget that was clicked on.
import tkinter as tk
def update_label(event):
event.widget.configure(text="You clicked me")
root = tk.Tk()
for i in range(10):
l = tk.Label(root, text="Click me", width=20)
l.pack()
l.bind("<1>", update_label)
root.mainloop()

Python Tkinter- Remember State of Created New Window (Checkboxes)

I have a button called view and when it is clicked on it will create a new window with a list in a listbox and a list of checkboxes that correspond to the listbox. When switching through the items in the listbox you will see that the listbox items are independent of each other and will have their own check box values. As of right now it will remember the checkbox values for each listbox item except when you close the created window. When you close the second window that was created all of that information disappears when you try and open the window back up again. I need a way to create a second window, do everything it does now with the listbox and checkboxes, but when closed it can be opened again and pick up where you left off.
For example, if I highlight the first item in the listbox and check the first checkbox, I should be able to close that window and open it again and when the first item in the listbox is highlighted, I see that there is a check in the first checkbox.
import tkinter
from tkinter import *
def myfunction(event):
canvas1.configure(scrollregion=canvas1.bbox("all"))
def onselect(evt):
# Note here that Tkinter passes an event object to onselect()
w = evt.widget
x = 0
index = int(w.curselection()[0])
value = w.get(index)
print('You selected item %d: "%s"' % (index, value))
for y in enable:
for item in list_for_listbox:
checkbuttons[item][y][1].grid_forget()
checkbuttons[value][y][1].grid(row=x, column=0)
# Label(frame2, text="some text").grid(row=x, column=1)
x += 1
def printcommand():
for item in list_for_listbox:
for y in enable:
print(item + " [" + y + "] " + str(checkbuttons[item][y][0].get()))
def create_new_window():
global new_window
new_window = tkinter.Toplevel()
new_window.geometry("750x500")
new_window_commands()
master = tkinter.Tk()
master.title("Checkboxes test")
master.geometry("750x500")
button1 = Button(master, command =create_new_window,text="View")
button1.place(x=50,y=250)
def new_window_commands():
# enable = ['button 1', 'button 2', 'button 3', 'button 4', 'button 5', 'button 6', 'button 7']
global list_for_listbox
global enable
global checkbuttons
global canvas1
enable = []
for x_number_of_items in range(1, 15):
enable.append("button " + str(x_number_of_items))
list_for_listbox = ["one", "two", "three", "four"]
listbox = Listbox(new_window)
listbox.place(x=5, y=5, width=100, height=10 + 16*len(list_for_listbox))
listbox.update()
frame1 = Frame(new_window, borderwidth=1, relief=GROOVE, highlightthickness=1, highlightbackground="black",
highlightcolor="black")
frame1.place(x=listbox.winfo_width() + 10, y=5, width=300, height=listbox.winfo_height())
canvas1 = Canvas(frame1)
frame2 = Frame(canvas1, height=500)
scrollbar1 = Scrollbar(frame1, orient="vertical", command=canvas1.yview)
canvas1.configure(yscrollcomman=scrollbar1.set)
scrollbar1.pack(side="right", fill="y")
canvas1.pack(side="left")
canvas1.create_window((0, 0), window=frame2, anchor='nw')
frame2.bind("<Configure>", myfunction)
printbutton = Button(new_window, text="Print", command=printcommand)
printbutton.place(x=100, y=250)
checkbuttons = {}
for item in list_for_listbox:
listbox.insert(END, item)
checkbuttons[item] = (dict())
for y in enable:
temp_var = BooleanVar()
checkbuttons[item][y] = [temp_var, Checkbutton(frame2, text=y, variable=temp_var)]
listbox.bind('<<ListboxSelect>>', onselect)
print(enable)
mainloop()
printcommand()
With your current structure, the simplest fix would be:
Only create the new_window once.
withdraw() new_window instead of letting it close each time.
Open the same instance of new_window again when called upon.
You'll need to implement the following:
# Default your new_window to None
new_window = None
def create_new_window():
global new_window
# If new_window doesn't exist, create a new one
if not new_window:
new_window = tkinter.Toplevel()
new_window.geometry("750x500")
# add a new protocol to redirect on closing the window.
new_window.protocol("WM_DELETE_WINDOW", hide_window)
new_window_commands()
else:
# if new_window already exist, just unhide it
new_window.deiconify()
# add a new function for when window is closing
def hide_window():
global new_window
new_window.withdraw()
You might also want to add the same protocol method under master so that when it closes, destroy both master and new_window object:
master.protocol('WM_DELETE_WINDOW', destroy_all)
def destroy_all():
global master
global new_window
master.destroy()
new_window.destroy()
If possible, for your next tkinter code I would suggest considering an object oriented approach though. I will see if I can provide a short sample here later.
As a side note, while I understand a lot of documentations in tkinter uses the from tkinter import * approach, I would discourage this practice and advise to import tkinter as tk instead (or as you already did, import tkinter, which accomplishes the same thing). See relevant answer here
Here's a quick sample of OOP approach in a similar vein:
import tkinter as tk
# Here the main window can be called upon as its own instance with its own instance attributes.
class Window(tk.Tk):
def __init__(self):
super().__init__()
self.main_button = tk.Button(self, text="Creat a sub window", command=self.open_sub_window)
self.main_button.pack()
# define the things you wish to retain under the main window as an instance attribute
self.sub_check_var = tk.BooleanVar()
self.sub_entry_var = tk.StringVar()
# when creating a new window, just reference back to the main attributes you've already created.
def open_sub_window(self):
self.sub_window = tk.Toplevel()
tk.Checkbutton(self.sub_window, text="I'm a checkbox!", variable=self.sub_check_var).pack()
lbl_frm = tk.LabelFrame(self.sub_window, text="I am an entry!")
lbl_frm.pack()
tk.Entry(lbl_frm, text=self.sub_entry_var).pack()
gui = Window()
gui.mainloop()
Note this is but one way to do it. You just need to feel around to get comfortable with your implementation, there's no right/wrong way to do things.

Tkinter Entry widget requires two events to update

I've been trying to develop a small gui to calculate some totals with weighting etc. While trying to get a total to update real-time with a changing entry, I noticed it took two events to update; This is a simplified version of my code that shows the problem:
from Tkinter import *
root=Tk()
frame=Frame(root)
frame.pack()
entry=Entry(frame)
entry.pack()
label=Label(frame,text="entry:")
label.pack()
def updatelabel(event):
label=Label(frame,text="entry:"+entry.get())
label.pack()
print "called"
entry.bind("<Key>", updatelabel)
root.mainloop()
When you input into the field the function calls, but does not update to what was typed until the next character is typed. How would I go about getting the label to update to what is in the field at the time?
You don't really need to explicitly process events and use callback functions to accomplish what you want. In other words it's possible to get Tkinter to do it for you automatically using a StringVar().
from Tkinter import *
root=Tk()
frame=Frame(root)
frame.pack()
entry_var = StringVar()
entry_var.set('')
entry = Entry(frame, textvariable=entry_var)
entry.pack()
label = Label(frame, text='entry: ')
label.pack(side=LEFT)
contents = Label(frame, textvariable=entry_var)
contents.pack(side=LEFT)
entry.focus_set() # force initial keyboard focus to be on entry widget
root.mainloop()
Instead of using entry.bind("<Key>", update label), I used the root window instead: root.bind("<Key>", update label). This did the trick, however it is important to realize that the function updatelabel() will be called every time a key is pressed in your tkinter window. This could cause some problems if you have more than one entry box updating labels.
Here is the code I wrote with a few modifications:
from Tkinter import *
root=Tk()
frame=Frame(root)
frame.pack()
update_label = StringVar() # Made a StringVar so you don't get new labels every time a key is pressed.
update_label.set("entry:")
entry=Entry(frame)
entry.pack()
label=Label(frame,textvariable=update_label) # Used textvariable= instead of text=
label.pack()
def updatelabel(event):
update_label.set("entry:" + entry.get()) # Setting the variable used in textvariable=
print "called"
root.bind("<Key>", updatelabel) # Changed entry.bind to root.bind
root.mainloop()
No it doesn't require two entries to be called, it is called on the first entry. The key bindings are on the Entry widgets to avoid the problems that a binding to the root will create if you have more than one entry widget.
import tkinter as tk
class SmallApp(tk.Frame):
def __init__(self, master = None):
tk.Frame.__init__(self, master)
self.master = master
self.pack()
self.entry = tk.Entry(self)
self.entry.pack()
self.var = "entry:"
self.label = tk.Label(text = self.var)
self.label.pack()
self.entry.bind("<Key>", self.updatelabel)
def updatelabel(self, event):
self.var += event.char
self.label.configure(text=self.var)
root = tk.Tk()
app = SmallApp(root)
app.mainloop()

Tkinter - How would I go about resetting list of objects?

Yesterday I asked this question Creating elements by loop Tkinter to find out how to dynamically create some bullet points. Now I'm looking to add a clear button so when pressed, will reset the entire form. I have tried setting the list back to [] but it didn't work.
edit - So basically when I press reset I'd like it to look exactly like it did when the form was loaded.
The buttons are removed with the destroy method:
for button in self.button:
button.destroy()
import Tkinter as tk
class ButtonBlock(object):
def __init__(self, master):
self.master = master
self.button = []
self.button_val = tk.IntVar()
entry = tk.Entry()
entry.grid(row=0, column=0)
entry.bind('<Return>', self.onEnter)
entry.focus()
clear_button = tk.Button(master, text='Clear', command=self.onClear)
clear_button.grid(row=0, column=1)
def onClear(self):
for button in self.button:
button.destroy()
def onEnter(self, event):
entry = event.widget
num = int(entry.get())
self.onClear()
for i in range(1, num+1):
self.button.append(tk.Radiobutton(
self.master, text=str(i), variable=self.button_val, value=i,
command=self.onSelect))
self.button[-1].grid(sticky='WENS', row=i, column=0, padx=1, pady=1)
def onSelect(self):
print(self.button_val.get())
if __name__ == '__main__':
root = tk.Tk()
ButtonBlock(root)
root.mainloop()
Setting the list back (i.e. using self.button = []) just clears the data stored in the button variable. That action alone is not connected to the user interface (UI). You have to explicitly remove the widget objects which were created (by the onEnter method).
So the clearing feature you are looking for should be feasible by extending the answer from your previous question. Add an onClear method to the ButtonBlock class so that when your "Clear" control (i.e. using a button widget) is selected its callback function calls ButtonBlock.onClear(), similar to how your Entry widget invokes the onEnter method.
EDIT: See unutbu's answer to this question. When selected, the clear_button control calls ButtonBlock.onClear(). The for loop in onClear gets a reference to each button ojbect from the button list and calls the object's destroy method, which removes it from the UI.

In Tkinter is there any way to make a widget invisible?

Something like this, would make the widget appear normally:
Label(self, text = 'hello', visible ='yes')
While something like this, would make the widget not appear at all:
Label(self, text = 'hello', visible ='no')
You may be interested by the pack_forget and grid_forget methods of a widget. In the following example, the button disappear when clicked
from Tkinter import *
def hide_me(event):
event.widget.pack_forget()
root = Tk()
btn=Button(root, text="Click")
btn.bind('<Button-1>', hide_me)
btn.pack()
btn2=Button(root, text="Click too")
btn2.bind('<Button-1>', hide_me)
btn2.pack()
root.mainloop()
One option, as explained in another answer, is to use pack_forget or grid_forget. Another option is to use lift and lower. This changes the stacking order of widgets. The net effect is that you can hide widgets behind sibling widgets (or descendants of siblings). When you want them to be visible you lift them, and when you want them to be invisible you lower them.
The advantage (or disadvantage...) is that they still take up space in their master. If you "forget" a widget, the other widgets might readjust their size or orientation, but if you raise or lower them they will not.
Here is a simple example:
import Tkinter as tk
class SampleApp(tk.Tk):
def __init__(self, *args, **kwargs):
tk.Tk.__init__(self, *args, **kwargs)
self.frame = tk.Frame(self)
self.frame.pack(side="top", fill="both", expand=True)
self.label = tk.Label(self, text="Hello, world")
button1 = tk.Button(self, text="Click to hide label",
command=self.hide_label)
button2 = tk.Button(self, text="Click to show label",
command=self.show_label)
self.label.pack(in_=self.frame)
button1.pack(in_=self.frame)
button2.pack(in_=self.frame)
def show_label(self, event=None):
self.label.lift(self.frame)
def hide_label(self, event=None):
self.label.lower(self.frame)
if __name__ == "__main__":
app = SampleApp()
app.mainloop()
I know this is a couple of years late, but this is the 3rd Google response now for "Tkinter hide Label" as of 10/27/13... So if anyone like myself a few weeks ago is building a simple GUI and just wants some text to appear without swapping it out for another widget via "lower" or "lift" methods, I'd like to offer a workaround I use (Python2.7,Windows):
from Tkinter import *
class Top(Toplevel):
def __init__(self, parent, title = "How to Cheat and Hide Text"):
Toplevel.__init__(self,parent)
parent.geometry("250x250+100+150")
if title:
self.title(title)
parent.withdraw()
self.parent = parent
self.result = None
dialog = Frame(self)
self.initial_focus = self.dialog(dialog)
dialog.pack()
def dialog(self,parent):
self.parent = parent
self.L1 = Label(parent,text = "Hello, World!",state = DISABLED, disabledforeground = parent.cget('bg'))
self.L1.pack()
self.B1 = Button(parent, text = "Are You Alive???", command = self.hello)
self.B1.pack()
def hello(self):
self.L1['state']="normal"
if __name__ == '__main__':
root=Tk()
ds = Top(root)
root.mainloop()
The idea here is that you can set the color of the DISABLED text to the background ('bg') of the parent using ".cget('bg')" http://effbot.org/tkinterbook/widget.htm rendering it "invisible". The button callback resets the Label to the default foreground color and the text is once again visible.
Downsides here are that you still have to allocate the space for the text even though you can't read it, and at least on my computer, the text doesn't perfectly blend to the background. Maybe with some tweaking the color thing could be better and for compact GUIs, blank space allocation shouldn't be too much of a hassle for a short blurb.
See Default window colour Tkinter and hex colour codes for the info about how I found out about the color stuff.
I'm also extremely late to the party, but I'll leave my version of the answer here for others who may have gotten here, like I did, searching for how to hide something that was placed on the screen with the .place() function, and not .pack() neither .grid().
In short, you can hide a widget by setting the width and height to zero, like this:
widget.place(anchor="nw", x=0, y=0, width=0, height=0)
To give a bit of context so you can see what my requirement was and how I got here.
In my program, I have a window that needs to display several things that I've organized into 2 frames, something like this:
[WINDOW - app]
[FRAME 1 - hMainWndFrame]
[Buttons and other controls (widgets)]
[FRAME 2 - hJTensWndFrame]
[other Buttons and controls (widgets)]
Only one frame needs to be visible at a time, so on application initialisation, i have something like this:
hMainWndFrame = Frame(app, bg="#aababd")
hMainWndFrame.place(anchor="nw", x=0, y=0, width=480, height=320)
...
hJTensWndFrame = Frame(app, bg="#aababd")
I'm using .place() instead of .pack() or .grid() because i specifically want to set precise coordinates on the window for each widget. So, when i want to hide the main frame and display the other one (along with all the other controls), all i have to do is call the .place() function again, on each frame, but specifying zero for width and height for the one i want to hide and the necessary width and height for the one i want to show, such as:
hMainWndFrame.place(anchor="nw", x=0, y=0, width=0, height=0)
hJTensWndFrame.place(anchor="nw", x=0, y=0, width=480, height=320)
Now it's true, I only tested this on Frames, not on other widgets, but I guess it should work on everything.
For hiding a widget you can use function pack_forget() and to again show it you can use pack() function and implement them both in separate functions.
from Tkinter import *
root = Tk()
label=Label(root,text="I was Hidden")
def labelactive():
label.pack()
def labeldeactive():
label.pack_forget()
Button(root,text="Show",command=labelactive).pack()
Button(root,text="Hide",command=labeldeactive).pack()
root.mainloop()
I was not using grid or pack.
I used just place for my widgets as their size and positioning was fixed.
I wanted to implement hide/show functionality on frame.
Here is demo
from tkinter import *
window=Tk()
window.geometry("1366x768+1+1")
def toggle_graph_visibility():
graph_state_chosen=show_graph_checkbox_value.get()
if graph_state_chosen==0:
frame.place_forget()
else:
frame.place(x=1025,y=165)
score_pixel = PhotoImage(width=300, height=430)
show_graph_checkbox_value = IntVar(value=1)
frame=Frame(window,width=300,height=430)
graph_canvas = Canvas(frame, width = 300, height = 430,scrollregion=(0,0,300,300))
my_canvas=graph_canvas.create_image(20, 20, anchor=NW, image=score_pixel)
vbar=Scrollbar(frame,orient=VERTICAL)
vbar.config(command=graph_canvas.yview)
vbar.pack(side=RIGHT,fill=Y)
graph_canvas.config(yscrollcommand=vbar.set)
graph_canvas.pack(side=LEFT,expand=True,fill=BOTH)
frame.place(x=1025,y=165)
Checkbutton(window, text="show graph",variable=show_graph_checkbox_value,command=toggle_graph_visibility).place(x=900,y=165)
window.mainloop()
Note that in above example when 'show graph' is ticked then there is vertical scrollbar.
Graph disappears when checkbox is unselected.
I was fitting some bar graph in that area which I have not shown to keep example simple.
Most important thing to learn from above is the use of frame.place_forget() to hide and frame.place(x=x_pos,y=y_pos) to show back the content.
For someone who hate OOP like me (This is based on Bryan Oakley's answer)
import tkinter as tk
def show_label():
label1.lift()
def hide_label():
label1.lower()
root = tk.Tk()
frame1 = tk.Frame(root)
frame1.pack()
label1 = tk.Label(root, text="Hello, world")
label1.pack(in_=frame1)
button1 = tk.Button(root, text="Click to hide label",command=hide_label)
button2 = tk.Button(root, text="Click to show label", command=show_label)
button1.pack(in_=frame1)
button2.pack(in_=frame1)
root.mainloop()
import tkinter as tk
...
x = tk.Label(text='Hello', visible=True)
def visiblelabel(lb, visible):
lb.config(visible=visible)
visiblelabel(x, False) # Hide
visiblelabel(x, True) # Show
P.S. config can change any attribute:
x.config(text='Hello') # Text: Hello
x.config(text='Bye', font=('Arial', 20, 'bold')) # Text: Bye, Font: Arial Bold 20
x.config(bg='red', fg='white') # Background: red, Foreground: white
It's a bypass of StringVar, IntVar etc.

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