argparse: setting optional argument with value of mandatory argument - python

With Python's argparse, I would like to add an optional argument that, if not given, gets the value of another (mandatory) argument.
parser.add_argument('filename',
metavar = 'FILE',
type = str,
help = 'input file'
)
parser.add_argument('--extra-file', '-f',
metavar = 'ANOTHER_FILE',
type = str,
default = ,
help = 'complementary file (default: FILE)'
)
I could of course manually check for None after the arguments are parsed, but isn't there a more pythonic way of doing this?

As far as I know, there is no way to do this that is more clean than:
ns = parser.parse_args()
ns.extra_file = ns.extra_file if ns.extra_file else ns.filename
(just like you propose in your question).
You could probably do some custom action gymnastics similar to this, but I really don't think that would be worthwhile (or "pythonic").

This has slightly different semantics than your original set of options, but may work for you:
parse.add_argument('filename', action='append', dest='filenames')
parse.add_argument('--extra-file', '-f', action='append', dest='filenames')
args = parse.parse_args()
This would replace args.filename with a list args.filenames of at least one file, with -f appending its argument to that list. Since it's possible to specify -f on the command line before the positional argument, you couldn't on any particular order of the input files in args.filenames.
Another option would be to dispense with the -f option and make filename a multi-valued positional argument:
parse.add_argument('filenames', nargs='+')
Again, args.filenames would be a list of at least one filename. This would also interfere if you have other positional arguments for your script.

Related

Python argparse with optional positional and default None

Working with Python and argparse, trying to accomplish the following:
$> my_app
Namespace(positional=None)
$> my_app file.txt somedir
Namespace(positional=['file.txt', 'somedir'])
i.e., a positional argument of type list, whose default is None. I would expect the following code to accomplish this:
p = argparse.ArgumentParser()
p.add_argument("positional", nargs='*', default=None)
print(p.parse_args())
But I get:
$> my_app
Namespace(positional=[])
$> my_app file.txt somedir
Namespace(positional=['file.txt', 'somedir'])
The rest of my code uses None as defaults for lists. If None is provided, the code select a sensible default. Thus passing [] is not an option.
The behavior of argparse does rather feel like a bug, but maybe I'm missing something. Any thoughts?
Answer (thx hpaulj) seems to be "as intended" to which I would add "completely unintuitively".
You can achieve the desired behavior like this
import argparse
p = argparse.ArgumentParser()
p.add_argument("positional", nargs='*', default=argparse.SUPPRESS)
print(p.parse_args(namespace=argparse.Namespace(positional=None)))
This prevents the arguments from appearing at all in the namespace which on turn causes the default namespace to take over.
Your case is handled in
def _get_values(self, action, arg_strings):
...
# when nargs='*' on a positional, if there were no command-line
# args, use the default if it is anything other than None
elif (not arg_strings and action.nargs == ZERO_OR_MORE and
not action.option_strings):
if action.default is not None:
value = action.default
self._check_value(action, value)
else:
# since arg_strings is always [] at this point
# there is no need to use self._check_value(action, value)
value = arg_strings
Normally the default is placed in the Namespace at the start of parsing. During parsing that default is overwritten with value(s) provided by the user. optionals are 'seen' when the right flag is used. positionals are 'seen' when the right number of strings are present. Since '*' and '?' accept 0 strings, they will always be 'seen'. Thus their defaults require special handling, if at all.

How ca I get Python ArgParse to stop overwritting positional arguments in child parser

I am attempting to get my script working, but argparse keeps overwriting my positional arguments from the parent parser. How can I get argparse to honor the parent's value for these? It does keep values from optional args.
Here is a very simplified version of what I need. If you run this, you will see that the args are overwritten.
testargs.py
#! /usr/bin/env python3
import argparse
import sys
def main():
preparser = argparse.ArgumentParser(add_help=False)
preparser.add_argument('first',
nargs='?')
preparser.add_argument('outfile',
nargs='?',
type=argparse.FileType('w', encoding='utf-8'),
default=sys.stdout,
help='Output file')
preparser.add_argument(
'--do-something','-d',
action='store_true')
# Parse args with preparser, and find config file
args, remaining_argv = preparser.parse_known_args()
print(args)
parser = argparse.ArgumentParser(
parents=[preparser],
description=__doc__)
parser.add_argument(
'--clear-screen', '-c',
action='store_true')
args = parser.parse_args(args=remaining_argv,namespace=args )
print(args)
if __name__ == '__main__':
main()
And call it with testargs.py something /tmp/test.txt -d -c
You will see it keeps the -d but drops both the positional args and reverts them to defaults.
EDIT: see additional comments in the accepted answer for some caveats.
When you specify parents=[preparser] it means that parser is an extension of preparser, and will parse all arguments relevent to preparser which it is never given.
Lets say the preparser only has one positional argument first and the parser only has one positional argument second, when you make parser a child of preparser it expects both arguments:
import argparse
parser1 = argparse.ArgumentParser(add_help=False)
parser1.add_argument("first")
parser2 = argparse.ArgumentParser(parents=[parser1])
parser2.add_argument("second")
args2 = parser2.parse_args(["arg1","arg2"])
assert args2.first == "arg1" and args2.second == "arg2"
However passing only the remaining arguments that are left over from parser1 would just be ['second'] which is not the correct arguments to parser2:
parser1 = argparse.ArgumentParser(add_help=False)
parser1.add_argument("first")
args1, remaining_args = parser1.parse_known_args(["arg1","arg2"])
parser2 = argparse.ArgumentParser(parents=[parser1])
parser2.add_argument("second")
>>> args1
Namespace(first='arg1')
>>> remaining_args
['arg2']
>>> parser2.parse_args(remaining_args)
usage: test.py [-h] first second
test.py: error: the following arguments are required: second
To only process the arguments that were not handled by the first pass, do not specify it as the parent to the second parser:
parser1 = argparse.ArgumentParser(add_help=False)
parser1.add_argument("first")
args1, remaining_args = parser1.parse_known_args(["arg1","arg2"])
parser2 = argparse.ArgumentParser() #parents=[parser1]) #NO PARENT!
parser2.add_argument("second")
args2 = parser2.parse_args(remaining_args,args1)
assert args2.first == "arg1" and args2.second == "arg2"
The 2 positionals are nargs='?'. A positional like that is always 'seen', since an empty list matches that nargs.
First time through 'text.txt' matches with first and is put in the Namespace. Second time through there isn't any string to match, so the default is used - same as if you had not given that string the first time.
If I change first to have the default nargs, I get
error: the following arguments are required: first
from the 2nd parser. Even though there's a value in the Namespace it still tries to get a value from the argv. (it's like a default, but not quite).
Defaults for positionals with nargs='?' (or *) are tricky. They are optional, but not in quite the same way as optionals. The positional Actions are still called, but with a empty list of values.
I don't think the parents feature does anything for you. preparser already handles that set of arguments; there's no need to handle them again in parser, especially since all the relevant argument strings have been stripped out.
Another option is to leave the parents in, but use the default sys.argv[1:] in the 2nd parser. (but beware of side effects like opening files)
args = parser.parse_args(namespace=args )
A third option is to parse the arguments independently and merge them with a dictionary update.
adict = vars(preparse_args)
adict.update(vars(parser_args))
# taking some care in who overrides who
For more details look in argparse.py file at ArgumentParser._get_values, specifically the not arg_strings cases.
A note about the FileType. That type works nicely for small scripts where you will use the files right away and exit. It isn't so good on large programs where you might want to close the file after use (close stdout???), or use files in a with context.
edit - note on parents
add_argument creates an Action object, and adds it to the parser's list of actions. parse_args basically matches input strings with these actions.
parents just copies those Action objects (by reference) from parent to child. To the child parser it is just as though the actions were created with add_argument directly.
parents is most useful when you are importing a parser and don't have direct access to its definition. If you are defining both parent and child, then parents just saves you some typing/cut-n-paste.
This and other SO questions (mostly triggered the by-reference copy) show that the developers did not intend you to use both the parent and child to do parsing. It can be done, but there are glitches that the they did not consider.
===================
I can imagine defining a custom Action class that would 'behave' in a situation like this. It might, for example, check the namespace for some not default value before adding its own (possibly default) value.
Consider, for example if I changed the action of first to 'append':
preparser.add_argument('first', action='append', nargs='?')
The result is:
1840:~/mypy$ python3 stack37147683.py /tmp/test.txt -d -c
Namespace(do_something=True, first=['/tmp/test.txt'], outfile=<_io.TextIOWrapper name='<stdout>' mode='w' encoding='UTF-8'>)
Namespace(clear_screen=True, do_something=True, first=['/tmp/test.txt', None], outfile=<_io.TextIOWrapper name='<stdout>' mode='w' encoding='UTF-8'>)
From the first parser, first=['/tmp/test.txt']; from the second, first=['/tmp/test.txt', None].
Because of the append, the item from the first is preserved, and a new default has been added by the second parser.

arparse python argument from directory

I have a file structure like this:
project/
main_prog.py
tools/
script.py
md_script/
__init__.py
md_script.py
I search in tools for local python modules. In this example it's md_script. And i want to use it as positional argument like install in my code, but when i use it, I'v got an error:
./jsh.py md_script
usage: jsh.py [-h] {install,call,list,log,restore} ... [md_script]
jsh.py: error: invalid choice: 'md_script' (choose from 'install', 'call', 'list', 'log', 'restore')
python3.4 on ubuntu14.10
Here is my code:
parser = argparse.ArgumentParser(prog='jsh.py',
description='Some help.', epilog='Example of usage: some help')
subparsers = parser.add_subparsers()
parser_install = subparsers.add_parser('install', help = 'Install new project.')
parser_install.add_argument('install', nargs='?', help = 'Name of project to be installed')
if os.path.isdir(full/path/to/tools/):
name_arg = next(os.walk(full/path/to/tools))[1]
tools_arg = parser.add_argument_group('Tools', 'Modules from tools')
for element in name_arg:
tools_arg.add_argument(element, nargs='?', help='md_script description')
args = parser.parse_args()
try:
if not len(sys.argv) > 1:
parser.print_help()
elif 'install' in args:
do_some_stuff
elif element in args:
do_some_md_script_stuff
else:
parser.print_help()
The usage line shows what's wrong:
usage: jsh.py [-h] {install,call,list,log,restore} ... [md_script]
You need to use something like
jsh.py install md_script
You specified subparsers, so you have to give it a subparser name.
From the usage it also looks like you created other subparsers, call, list, etc that you don't show in the code.
You also define positional arguments after creating subparser. That's where the [md_script] comes from. Be careful about making a lot of nargs='?' positionals (including the argument for the install subparser). This could make things confusing for your users. In fact it seems to confusing you. Remember that subparser is in effect a positional argument (one that requires 1 string).
I'd suggest experimenting with a simplier parser before creating one this complicated.
So from your comments and examples I see that you goal is let the user name a module, so your script can invoke it in some way or other. For that populating the subparsers with these names makes sense.
I wonder why you also create an optional positional argument with the same name:
module_pars = subparsers.add_parser(element, help = 'Modules from tools')
module_pars.add_argument(element, nargs='?', help=element+' description')
Is that because you are using the presence of the attribute as evidence that this subparser was invoked?
elif element in args:
do_some_md_script_stuff
The argparse documentation has a couple of other ideas.
One particularly effective way of handling sub-commands is to combine the use of the add_subparsers() method with calls to set_defaults() so that each subparser knows which Python function it should execute.
and
However, if it is necessary to check the name of the subparser that was invoked, the dest keyword argument to the add_subparsers() call will work:
These avoid the messiness of a '?' positional argument, freeing you to use subparser arguments for real information.
subparsers = parser.add_subparsers(dest='module')
....
for element in name_arg:
# module_pars = 'parser_'+element # this does nothing
module_pars = subparsers.add_parser(element, help = 'Modules from tools')
module_pars.set_defaults(func = do_some_md_script_stuff)
# or module_pars.set_default(element='I am here')
module_pars.add_argument('real_argument')
Now you can check:
if args.module='md_script':
do_some_md_script_stuff(args)
or
if hasattr(args, 'func'):
func(args)
With the alternative set_defaults, your original test should still work:
if element in args:
do_some_md_script_stuff
I did it like this. It's exactly what I want to.
if os.path.isdir(TOOLS_PATH):
name_arg = next(os.walk(TOOLS_PATH))[1]
for element in name_arg:
module_pars = 'parser_'+element
module_pars = subparsers.add_parser(element, help = 'Modules from tools')
module_pars.add_argument(element, nargs='?', help=element+' description')
I didn't test it, because i dont have a test module, but ./jsh.py md_script goes into elif element in args: print('md_script') and print string. So it looks like it works.
Thanks for all replies.
Edit: I tested it. In add_argument i must change nargs='?' for nargs='*' to catch more than one argument.
And to catch arguments from command line I used this:
elif args:
for element in name_arg:
if element in args:
element_arg = sys.argv[2:]
done_cmd,msg = opt_exec_module(element,*element_arg)
my_logger(done_cmd,msg)
Not very elegant but it works.

Override the positional and optional arguments with another argument in command line (argparse python module)

I am using argparser to parse the command line arguments.
Now, I have something like
./script.py 1112323 0 --salary 100000 -- age 34
Here first two are positional arguments and rest are optional.
Now, I want to have a feature such that when the user gives a filename as input in command line, then it should override these above arguments and take the arguments from header of the file. I meam when user gives sth like
id|sequence|age|name|........... (header of the file with first two cols as positional arguments and rest positional)
On giving this in command line:
./script.py -f filename
it should not complain of above positional arguments.
Is this feasible over my current implementation?
You will most likely need to implement this check yourself. Make both arguments (positional and -f) optional (required=False and nargs="*") and then implement your custom check and use the error method of ArgumentParser. To make it easier for user mention the correct usage in help string.
Something like this:
parser = ArgumentParser()
parser.add_argument("positional", nargs="*", help="If you don't provide positional arguments you need use -f")
parser.add_argument("-f", "--file", required=False, help="...")
args = parser.parse_args()
if not args.file and not args.positional:
parser.error('You must use either -f or positional argument')

argparse key=value parameters

This first link has the same question in the first section, but it is unanswered
(python argparse: parameter=value). And this second question is similar, but I can't seem to get it working for my particular case
( Using argparse to parse arguments of form "arg= val").
So my situation is this -- I am re-writing a Python wrapper which is used by many other scripts (I would prefer not to modify these other scripts). Currently, the Python wrapper is called with command line arguments of the form --key=value for a number of different arguments, but was parsed manually. I would like to parse them with argparse.
N.B. The argument names are unwieldy, so I am renaming using the dest option in add_argument.
parser = argparse.ArgumentParser(description='Wrappin Ronnie Reagan')
parser.add_argument("--veryLongArgName1", nargs=1, dest="arg1", required=True)
parser.add_argument("--veryLongArgName2", nargs=1, dest="arg2")
parser.add_argument("--veryLongArgName3", nargs=1, dest="arg3")
userOpts = vars(parser.parse_args())
Which, while apparently parsing the passed command lines correctly, displays this as the help:
usage: testing_argsparse.py [-h] --veryLongArgName1 ARG1
[--veryLongArgName2 ARG2]
[--veryLongArgName3 ARG3]
testing_argsparse.py: error: argument --veryLongArgName1 is required
But what I want is that all parameters are specified with the --key=value format, not --key value. i.e.
usage: testing_argsparse.py [-h] --veryLongArgName1=ARG1
[--veryLongArgName2=ARG2]
[--veryLongArgName3=ARG3]
testing_argsparse.py: error: argument --veryLongArgName1 is required
testing_argsparse.py --veryLongArgName1=foo
works. argparse module accepts both --veryLongArgName1=foo and --veryLongArgName1 foo formats.
What exact command line arguments are you trying to pass to argparse that's causing it to not work?
A little late but for anyone with a similar request as the OP you could use a custom HelpFormatter.
class ArgFormatter(argparse.HelpFormatter):
def _format_args(self, *args):
result = super(ArgFormatter, self)._format_args(*args)
return result and '%%%' + result
def _format_actions_usage(self, *args):
result = super(ArgFormatter, self)._format_actions_usage(*args)
return result and result.replace(' %%%', '=')
This can then be passed to ArgumentParser to give the wanted behavior.
parser = argparse.ArgumentParser(
description='Wrappin Ronnie Reagan',
formatter_class=ArgFormatter)
This intercepts the args (ARG1, ARG2, ...) and adds a custom prefix which is later replaced (along with the unwanted space) for an = symbol. The and in the return statements makes sure to only modify the result if it's non-empty.

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