Subclass not inheriting parent class - python

I'm having trouble with my code. I'm trying to create a subclass which inherits the parent class's attributes and methods but it doesn't work. Here's what I have so far:
class Employee(object):
def __init__(self, emp, name, seat):
self.emp = emp
self.name = name
self.seat = seat
Something is wrong with the block of code below - the subclass.
Do I have to create the __init__ again? And how do I create a new attribute for the subclass. From reading questions, it sounds like __init__ in the subclass will override the parent class - is that true if I call it to define another attribute?
class Manager(Employee):
def __init__(self, reports):
self.reports = reports
reports = []
reports.append(self.name) #getting an error that name isn't an attribute. Why?
def totalreports(self):
return reports
I want the names from the Employee class to be in the reports list.
For example, if I have:
emp_1 = Employee('345', 'Big Bird', '22 A')
emp_2 = Employee('234', 'Bert Ernie', '21 B')
mgr_3 = Manager('212', 'Count Dracula', '10 C')
print mgr_3.totalreports()
I want reports = ['Big Bird', 'Bert Ernie'] but it doesn't work

You never called the parent class's __init__ function, which is where those attributes are defined:
class Manager(Employee):
def __init__(self, reports):
super(Manager, self).__init__()
self.reports = reports
To do this, you'd have to modify the Employee class's __init__ function and give the parameters default values:
class Employee(object):
def __init__(self, emp=None, name=None, seat=None):
self.emp = emp
self.name = name
self.seat = seat
Also, this code will not work at all:
def totalreports(self):
return reports
reports's scope is only within the __init__ function, so it will be undefined. You'd have to use self.reports instead of reports.
As for your final question, your structure won't really allow you to do this nicely. I would create a third class to handle employees and managers:
class Business(object):
def __init__(self, name):
self.name = name
self.employees = []
self.managers = []
def employee_names(self);
return [employee.name for employee in self.employees]
You'd have to add employees to the business by appending them to the appropriate list objects.

You need to run the superclass's init() in the appropriate place, plus capture the (unknown to the subclass) arguments and pass them up:
class Manager(Employee):
def __init__(self, reports, *args, **kwargs):
self.reports = reports
reports = []
super(Manager, self).__init__(*args, **kwargs)
reports.append(self.name) #getting an error that name isn't an attribute. Why?

Related

What is an alternative to using `__getattr__()` method for wrapper classes?

Suppose that I have two classes:
a class named Swimmer
a class named Person
For my particular application, we can NOT have Swimmer inherit from Person, although we want something like inheritance.
Instead of class inheritance each Swimmer will have an instance of the Person class as a member variable.
class Person:
pass
class Swimmer:
def __init__(self, person):
self._person = person
def __getattr__(self, attrname:str):
try:
attr = getattr(self._person)
return attr
except AttributeError:
raise AttributeError
Perhaps the Person class has the following class methods:
kneel()
crawl()
walk()
lean_over()
lay_down()
The Swimmer class has all of the same methods as the Person class, plus some additional methods:
run()
swim()
dive()
throw_ball()
When it comes to kneeling, crawling, walking, and laying down, a Swimmer is meant to be a transparent wrapper around the Person class.
I want to write something like this:
swimmer_instance = SwimmerClass(person_instance)
I wrote a __getattr__() method.
However, I ran into many headaches with __getattr__().
Consider writing the code self.oops. There is no attribute of the _Swimmer class named oops. We should not look for oops inside of self._person.
Aanytime that I mistyped the name of an attribute of Swimmer, my computer searched for that attribute in the instance of the Person class. Normally, fixing such spelling mistakes is easy. But, with a __getattr__() method, tracking down the problem becomes difficult.
How can I avoid this problem?
Perhaps one option is create a sub-class of the Swimmer class. In the sub-class have have a method, the name of which is a misspelling of __getattr__. However, I am not sure about this idea; please advise me.
class _Swimmer:
def __init__(self, person):
self._person = person
def run(self):
return "I ran"
def swim(self):
return "I swam"
def dive(self):
# SHOULD NOT LOOK FOR `oops` inside of self._person!
self.oops
return "I dove"
def _getattrimp(self, attrname:str):
# MISSPELLING OF `__getattr__`
try:
attr = getattr(self._person)
return attr
except AttributeError:
raise AttributeError
class Swimmer(_Swimmer):
def __getattr__(self, attrname:str):
attr = self._getattrimp(attrname)
return attr
Really, it is important to me that we not look inside of self._person for anything except the following:
Kneel()
Crawl()
Walk()
Lean()
LayDown()
The solution must be more general than just something what works for the Swimmer class and Person class.
How do we write a function which accepts any class as input and pops out a class which has methods of the same name as the input class?
We can get a list of Person attributes by writing person_attributes = dir(Person).
Is it appropriate to dynamically create a sub-class of Swimmer which takes Person as input?
class Person:
def kneel(self, *args, **kwargs):
return "I KNEELED"
def crawl(self, *args, **kwargs):
return "I crawled"
def walk(self, *args, **kwargs):
return "I WALKED"
def lean_over(self, *args, **kwargs):
return "I leaned over"
################################################################
import functools
class TransparentMethod:
def __init__(self, mthd):
self._mthd = mthd
#classmethod
def make_transparent_method(cls, old_method):
new_method = cls(old_method)
new_method = functools.wraps(old_method)
return new_method
def __call__(self, *args, **kwargs):
ret_val = self._mthd(*args, **kwargs)
return ret_val
###############################################################
attributes = dict.fromkeys(dir(Person))
for attr_name in attributes.keys():
old_attr = getattr(Person, attr_name)
new_attr = TransparentMethod.make_transparent_method(old_attr)
name = "_Swimmer"
bases = (object, )
_Swimmer = type(name, bases, attributes)
  
class Swimmer(_Swimmer):
pass
If I understand your question correctly, you want a function that will combine two classes into one.
The way I did this was to create a blank container class with the 3 parameter type() constructor, then loop over every class passed to the function, using setattr to set new attributes of the container class. I had to blacklist the __class__ and __dict__ attributes because Python doesn't allow one to change these. Note that this function will overwrite previously added methods, such as the __init__() method, so pass the class with the constructor last.
I implemented this in the combineClasses function below. I also provided an example. In the example, I created the a basic Person class and a _Swimmer class. I called combineClasses on these two and stored the resulting class as Swimmer, so it can nicely be called as a wrapper class.
def combineClasses(name, *args):
container = type(name, (object,), {})
reserved = ['__class__', '__dict__']
for arg in args:
for method in dir(arg):
if method not in reserved:
setattr(container, method, getattr(arg, method))
return container
class Person:
def __init__(self, name):
self.name = name
def sayHi(self):
print(f'Hi, I am {self.name}')
class _Swimmer:
def swim(self):
print('I am swimming')
class _Cashier:
def work(self):
print(f'I am working! My name is {self.name}')
Swimmer = combineClasses('Swimmer', _Swimmer, Person)
bob = Swimmer('Bob')
bob.swim() # => "I am swimming"
bob.sayHi() # => "Hi, I am Bob"
print(bob.name) # => "Bob"
print(type(bob)) # => "<class '__main__.Swimmer'>"

Change a inherited class to another inherited class keeping the attributes

I need to change a inherited class to another inherited class where only one of the attributes has changed
i need to "Promote" a Cashier to a Manager, the only thing that is suppose to change is the salary
both Cashier and Manager are inherited classes of Employee (where I'm not sure if I'm using the "hasattr" function the right way)
class Employee:
def __init__(self,name):
self.name=name
if(hasattr(self,'shifts')==False):
self.shifts=[]
class Manager(Employee):
def __init__(self,name,salary):
Employee.__init__(self,name)
self.salary=salary
class Cashier(Employee):
def __init__(self,name,salarey_per_hours):
Employee.__init__(self,name)
self.salery_per_hours=salarey_per_hours
def promote(self,salary):
return Manager(self.name,salary)
P.s It's my first time uploading a question
What you could do is create the addition method of your class and add self to the manager class you are returning like so:
class Employee(object):
def __init__(self, name):
self.name=name
if not hasattr(self, 'shifts'):
self.shifts = []
def __add__(self, other):
if isinstance(other, Employee):
for key, value in other.__dict__.items():
if key == 'salary':
continue
self.__setattr__(key, value)
return self
class Manager(Employee):
def __init__(self, name, salary):
super().__init__(name)
self.salary = salary
class Cashier(Employee):
def __init__(self,name,salary):
super().__init__(name)
self.salary = salary
def promote(self, salary):
manager = Manager(self.name, salary)
manager += self
return manager
cashier = Cashier('hank', 22)
cashier.shifts = [1, 2, 3, 4]
print(cashier.shifts)
promoted_cashier = cashier.promote(30)
print(promoted_cashier.shifts)
Here you make sure that everything except the "salary" is transferred to the promoted class. And since both the Manager and the Cashier are an Employee this should work nicely. I changed your code a bit to what I'm used to since there was some unusual coding with you Calling Employee in the init which I assumed you did not explicitly needed. Sorry if that was not the case.
You can change the object's class by obj.__class__ to the another class by
doing obj.__class__ = SomeClass
Beware that is can lead to strange behaviours if it is handled incorrectly.
by modifying your code
class Employee:
def __init__(self,name):
self.name=name
if(hasattr(self,'shifts')==False):
self.shifts=[]
class Manager(Employee):
def __init__(self,name,salary):
Employee.__init__(self,name)
self.salary=salary
class Cashier(Employee):
def __init__(self,name,salarey_per_hours):
Employee.__init__(self,name)
self.salery_per_hours=salarey_per_hours
def promote(self,salary):
self.__class__ = Manager
# return Manager(self.name,salary)
You can also take a look at this post changing the class of a python object (casting)

How to call attribute from parent class?

I am currently learning how to program in Python I am stuck calling an attribute from a Parent class. In the example below, how can I call the attribute "name" on "daisy" to print the name. I always get an error "'Mammal' object has no attribute 'name'.
class Vertebrate:
spinal_cord = True
def __init__(self, name):
self.name = name
class Mammal(Vertebrate):
def __init__(self, name, animal_type):
self.animal_type = animal_type
self.temperature_regulation = True
daisy = Mammal('Daisy', 'dog')
print(daisy.name)
here I want to print the name which has been defined in the Vertebrate class, but I always get an error
"'Mammal' object has no attribute 'name'"
You need to call super in the __init__ of Mammal, like this:
class Mammal(Vertebrate):
def __init__(self, name, animal_type):
super().__init__(name)
self.animal_type = animal_type
self.temperature_regulation = True
When __init__ of Mammal is called, it doesn't automatically call the __init__ of it's parent class, that's what super does here.
When you assign an init function to the child class, it overrides the default init function of parent class being called. In such a case you need to explicitly call the parent class using the super function. You also need to assign the class Vertebrate to be a child of the class Object to be able to access all of the object's modules within it.
class Vertebrate(object):
def __init__(self, name):
self.name = name
spinal_cord = True
class Mammal(Vertebrate):
def __init__(self, name, animal_type):
super(Mammal, self).__init__(name)
self.animal_type = animal_type
self.temperature_regulation = True
animal = Mammal("Daisy", "dog")
print animal.name

Resolving Diamond Inheritance within Python Classes

Consider the following python code:
class Parent(object):
def __init__(self, name, serial_number):
self.name = name
self.serial_number = serial_number
class ChildA(Parent):
def __init__(self, name, serial_number):
self.name = name
self.serial_number = serial_number
super(ChildA, self).__init__(name = self.name, serial_number = self.serial_number)
def speak(self):
print("I am from Child A")
class ChildB(Parent):
def __init__(self, name, serial_number):
self.name = name
self.serial_number = serial_number
super(ChildB, self).__init__(name = self.name, serial_number = self.serial_number)
def speak(self):
print("I am from Child B")
class GrandChild(ChildA, ChildB):
def __init__(self, a_name, b_name, a_serial_number, b_serial_number):
self.a_name = a_name
self.b_name = b_name
self.a_serial_number = a_serial_number
self.b_serial_number = b_serial_number
super(GrandChild, self).__init_( something )
When running the super function in GrandChild, what is the proper way to format the __init__ arguments so that ChildA and ChildB both get the correct arguments?
Also how do you access the two different versions of the speak method (ChildA's version and ChildB's version) from within the GrandChild class?
so, when you call super from the grandchild, ChildA's __init__ method will be called because super follows the __mro__ property (parents left to right then grandparents left-to-right, then great grandparents, ...)
Since ChildA's init also calls super, then all the super calls will be chained, calling child b's __init__ and eventually the parent init.
For that to work, your interface generally needs to be consistent. That is positional arguments need to mean the same things, and be in the order.
In situations where that's not the case, keyword arguments may work better.
class Parent:
def __init__(self, name, serial, **kwargs):
self.name = name
self.serial = serial
class ChildA(Parent):
def __init__(self, a_name, a_serial, **kwargs):
self.a_name = a_name
self.a_serial = a_serial
super().__init__(**kwargs)
class ChildB(Parent):
def __init__(self, b_name, b_serial, **kwargs):
self.b_name = b_name
self.b_serial = b_serial
super().__init__(**kwargs)
class GrandChild(ChildA, ChildB):
def __init__(self):
super().__init__(name = "blah", a_name = "a blah", b_name = "b blah", a_serial = 99, b_serial = 99, serial = 30)
Also note that in your code name and serial are reused as instance properties between all the classes and that's probably not what you want.
In python, you can explicitly call a particular method on (one of) your parent class(es):
ChildA.__init__(self, a_name, a_serial)
ChildB.__init__(self, b_name, b_serial)
Note that you need to put the self in explicitly when calling this way.
You can also – as you did – use the super() way, which will call the "first" parent. The exact order is dynamic, but by default it will do left-to-right, depth-first, pre-order scans of your inheritance hierarchy. Hence, your super() call will only call __init__ on ChildA.

Initialise child class with instance of parent class

Suppose I have a class:
class Person(object):
def __init__(self, name, hobbies):
self.name = name
self.hobbies = hobbies
... (and so on)
Now I want to initialise a child class, Employee, which extends person. I would like to initialise that class with an instance of the Person class. So I would like to do:
class Employee(Person):
def __init__(self, person, salary):
# Initialise the superclass from the given instance somehow
# I know I could do:
super(Employee, self).__init__(person.name, person.hobbies)
# But could I somehow do something like:
super(Employee, self).__init__(person)
# (In this case the difference is small, but it could
# be important in other cases)
# Add fields specific to an "Employee"
self.salary = salary
So that I can then call:
p1 = Person('Bob', ['Bowling', 'Skiing'])
employed_p1 = Employee(p1, 1000)
Is there any way I can do this, or do I explicitly have to call the parent class's constructor again?
Thanks a lot!
I thnk you want something like this:
class Person(object):
def __init__(self, name, hobbies):
self.name = name
self.hobbies = hobbies
def display(self):
print(self.name+' '+self.hobbies[0])
class Employee(Person):
def __init__(self, a, b =None,salary=None):
if b is None:
self.person = a
else:
self.person = Person(a,b)
self.name = self.person.name
self.hobbies = self.person.hobbies
self.salary = salary
bob = Employee('bob',['Bowling', 'Skiing'])
bob.display()
sue1 = Person('sue',['photography','music'])
sue2 = Employee(sue1,salary=123)
sue2.display()
I've added in the 'display' function just to make it easier to follow. Hope this helps.

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