How do you access query parameters or the query string in Flask routes? It's not obvious from the Flask documentation.
The example route /data below illustrates the context that I would like to access that data. If someone requests something like example.com/data?abc=123, I would like access to the string ?abc=123 or to be able to retrieve the value of parameters like abc.
#app.route("/data")
def data():
# query_string = ???
return render_template("data.html")
from flask import request
#app.route('/data')
def data():
# here we want to get the value of user (i.e. ?user=some-value)
user = request.args.get('user')
The full URL is available as request.url, and the query string is available as request.query_string.decode().
Here's an example:
from flask import request
#app.route('/adhoc_test/')
def adhoc_test():
return request.query_string
To access an individual known param passed in the query string, you can use request.args.get('param'). This is the "right" way to do it, as far as I know.
ETA: Before you go further, you should ask yourself why you want the query string. I've never had to pull in the raw string - Flask has mechanisms for accessing it in an abstracted way. You should use those unless you have a compelling reason not to.
I came here looking for the query string, not how to get values from the query string.
request.query_string returns the URL parameters as raw byte string (Ref 1).
Example of using request.query_string:
from flask import Flask, request
app = Flask(__name__)
#app.route('/data', methods=['GET'])
def get_query_string():
return request.query_string
if __name__ == '__main__':
app.run(debug=True)
Output:
References:
Official API documentation on query_string
We can do this by using request.query_string.
Example:
Lets consider view.py
from my_script import get_url_params
#app.route('/web_url/', methods=('get', 'post'))
def get_url_params_index():
return Response(get_url_params())
You also make it more modular by using Flask Blueprints - https://flask.palletsprojects.com/en/1.1.x/blueprints/
Lets consider first name is being passed as a part of query string
/web_url/?first_name=john
## here is my_script.py
## import required flask packages
from flask import request
def get_url_params():
## you might further need to format the URL params through escape.
firstName = request.args.get('first_name')
return firstName
As you see this is just a small example - you can fetch multiple values + formate those and use it or pass it onto the template file.
Werkzeug/Flask as already parsed everything for you. No need to do the same work again with urlparse:
from flask import request
#app.route('/')
#app.route('/data')
def data():
query_string = request.query_string ## There is it
return render_template("data.html")
The full documentation for the request and response objects is in Werkzeug: http://werkzeug.pocoo.org/docs/wrappers/
Try like this for query string:
from flask import Flask, request
app = Flask(__name__)
#app.route('/parameters', methods=['GET'])
def query_strings():
args1 = request.args['args1']
args2 = request.args['args2']
args3 = request.args['args3']
return '''<h1>The Query String are...{}:{}:{}</h1>''' .format(args1,args2,args3)
if __name__ == '__main__':
app.run(debug=True)
Output:
Every form of the query string retrievable from flask request object as described in O'Reilly Flask Web Devleopment:
From O'Reilly Flask Web Development, and as stated by Manan Gouhari earlier, first you need to import request:
from flask import request
request is an object exposed by Flask as a context variable named (you guessed it) request. As its name suggests, it contains all the information that the client included in the HTTP request. This object has many attributes and methods that you can retrieve and call, respectively.
You have quite a few request attributes which contain the query string from which to choose. Here I will list every attribute that contains in any way the query string, as well as a description from the O'Reilly book of that attribute.
First there is args which is "a dictionary with all the arguments passed in the query string of the URL." So if you want the query string parsed into a dictionary, you'd do something like this:
from flask import request
#app.route('/'):
queryStringDict = request.args
(As others have pointed out, you can also use .get('<arg_name>') to get a specific value from the dictionary)
Then, there is the form attribute, which does not contain the query string, but which is included in part of another attribute that does include the query string which I will list momentarily. First, though, form is "A dictionary with all the form fields submitted with the request." I say that to say this: there is another dictionary attribute available in the flask request object called values. values is "A dictionary that combines the values in form and args." Retrieving that would look something like this:
from flask import request
#app.route('/'):
formFieldsAndQueryStringDict = request.values
(Again, use .get('<arg_name>') to get a specific item out of the dictionary)
Another option is query_string which is "The query string portion of the URL, as a raw binary value." Example of that:
from flask import request
#app.route('/'):
queryStringRaw = request.query_string
Then as an added bonus there is full_path which is "The path and query string portions of the URL." Por ejemplo:
from flask import request
#app.route('/'):
pathWithQueryString = request.full_path
And finally, url, "The complete URL requested by the client" (which includes the query string):
from flask import request
#app.route('/'):
pathWithQueryString = request.url
Happy hacking :)
I prefer
user = request.args['user'] if 'user' in request.args else 'guest'
over
user = request.args.get('user')
this way, you can check the url actually contains the query string first
The implementation below worked for me.
from flask import request
def getVerificationStatus():
try:
requestId=int(request.args.get('requestId'))
print(requestId)
status= verificationStepRepository.getVerificationStatus(requestId)
return tb.responsify(200, "success", status)
except Exception as e:
return errorHandler.dispatchInternalServerError(str(e))
Often we just want to map the whole query string into an appropriate python data structure and take it from there. The appropriate structure is a multi-dictionary because keywords can repeat, for example we need to handle A=123&A=456&B=789. A multi-dictionary is a list of 2-tuples where each 2-tuple contains the key as its first item and the list of values as its second, so the above goes to [('A',['123','456']),('B',['789'])]. All of this is achieved by
qstr = request.args.lists() # A generator for the multi-dict
qstr = list(qstr) # To get the actual multi-dict
If all you want is a dictionary where the first occurrence of a duplicate keyword is used you can just go
qstr = request.args.to_dict()
This can be done using request.args.get().
For example if your query string has a field date, it can be accessed using
date = request.args.get('date')
Don't forget to add "request" to list of imports from flask,
i.e.
from flask import request
If the request if GET and we passed some query parameters then,
fro`enter code here`m flask import request
#app.route('/')
#app.route('/data')
def data():
if request.method == 'GET':
# Get the parameters by key
arg1 = request.args.get('arg1')
arg2 = request.args.get('arg2')
# Generate the query string
query_string="?arg1={0}&arg2={1}".format(arg1, arg2)
return render_template("data.html", query_string=query_string)
This Code worked for me:
from flask import Flask, request
app = Flask(__name__)
#app.route('/')
def search():
query = request.args
for key,value in query.items():
print(key,value)
return "Hello World"
if __name__ == '__main__':
app.run(debug=True)
Related
I want to pass a variable called manual to Flask a route, which will then do something based on the value in the POST form data. But the forms data is interpreted as string in flask even though I send it in a form as a dictionary.
here's the code
#app.route("/result", methods= [ 'POST', 'GET'])
def result():
manual = request.form.get("manual")
if manual is None:
return "manual is required"
here's how I am sending the data
r = requests.get('http://127.0.0.1:5000/result'
,data={manual':False})
I understand that I can do something like;
if manual == 'True'
but I don't want to be comparing strings, I want to do it in the standard way whichever it is.
Thanks
First of all, do a POST request, not a GET:
r = requests.post('http://127.0.0.1:5000/result', json={'manual': False})
Then (untested):
#app.route("/result", methods=['POST'])
def result():
json_data = flask.request.json
manual = json_data.get("manual")
if manual is None:
return "manual is required"
Have a look at the doc for details: More complicated POST requests.
Note that there are differences between using the data parameter and the json parameter. An important thing to note is the presence of the Content-Type header:
Using the json parameter in the request will change the Content-Type
in the header to application/json.
In my flask server, a user passes a parameter to the server via a POST request, which symbolizes an entity in the server (a file, or a database entry).
If the id passed with the parameter, does not exist in the server, the server responds with:
return make_response(json.dumps({'error_message': 'item does not exist'}), 400)
How can i pass parameters in json.dumps()?
What i want to do is display: error_message: item XXXXXX does not exist
Where XXXXXX is the id that is passed as parameter to the server in the POST request.
For passing the parameter, one way you could do it is creating a formatted string, such as:
from flask import jsonify
value = # something
return make_response(jsonify("error message": "item {} does not exist".format(value)), 400)
Or you could do something like the following:
value = # something
data = {"error message": "item {} does not exist".format(value)}
return make_response(jsonify(data), 400)
And to note: use jsonify instead.
This function wraps dumps() to add a few enhancements that make life easier. It turns the JSON output into a Response object with the application/json mimetype.
So I'm using flask to create endpoints as receivers and data processors. I have two threads of http POST requests, the first one is sent to the first route, similarly for the second one. The thing is I want the 2nd processor to be triggered only when the 1st one is, so I created a session key, to validate for the execution of the 2nd processor.
But no matter what I did, session key is always wiped when I sent POST to the second processor. Here's my code, which has been simplified. Pardon my amateur ablity to express the problem, I'm extremely new to coding.
from flask import Flask, request, redirect, url_for, session
app = Flask(__name__)
app.secret_key = "abc"
#app.route('/first_processor', methods=['POST'])
def first_processor():
data = {
'message': 'json received',
'json': request.json
}
cond = data['json']
if cond['event'] == "message:received":
session["key"] = cond['key']
return redirect(url_for("second_processor"))
else:
return data
#app.route('/second_processor', methods=['POST'])
def second_processor():
if "key" in session:
print('OK')
else:
print("FAIL")
return data
if __name__ == "__main__":
app.run(debug=True)
Apparently I saw two minor problems. The first one is that
#app.route('/second_processor', methods=['POST']) `
only allows POST method, and
redirect(url_for("second_processor"))
is a GET request. And you cannot force a POST request. Even though, according to the documentation, there is a _method parameter in the url_for function.
Related question: Issue a POST request with url_for in Flask
The second problem is that you created the data variable inside the first_processor function, but you don't pass it to the second_processor.
if 'key' in session:
print('OK')
else:
print("FAIL")
--> return data
you could either:
pass the data inside the session,
make data global ( not sure if it is a good practice though)
store data in a file or db and read it inside second_processor.
I need to setup a /metrics endpoint so that Prometheus can consume statistics about an endpoint. How do I go about doing this?
I have this in my Flask app:
#app.route('/metrics')
def metrics():
def generateMetrics():
metrics = ""
... some string builder logic
return metrics
response = make_response(generateMetrics(), 200)
response.mimetype = "text/plain"
return response
Is this the best way? What is the difference between returning a String (just returning metrics here) and returning plain text? Why do I need the mimetype?
Is this the best way?
There are several ways to set the MIME type, better explained and discussed in this StackOverflow question. Your way works fine and gets the job done.
What is the difference between returning a String and returning plain text?
If you return a string Flask will automatically handle some of the Response logic for you. This means using some default values. If you set up two different endpoints you'll see that the difference turns out to be that your code returns the following header:
Content-Type:"text/plain; charset=utf-8"
While just returning a string (and default MIME type) would return the following header:
Content-Type:"text/html; charset=utf-8"
Why do I need the mimetype?
You might say that it is technically more correct, given that your response is simply plain text, and not HTML. However, a more forcing reason for needing it would be that a third party system you are using (Prometheus) relies on or cares about the contents of the "Content-Type" header. If they do, then you must set it for them to accept it.
Example code
For the Content-Type header demonstration I used the following example Python code:
from flask import Flask, make_response
app = Flask(__name__)
def generateMetrics():
return "hello world"
#app.route('/metrics')
def metrics():
response = make_response(generateMetrics(), 200)
response.mimetype = "text/plain"
return response
#app.route('/metrics2')
def metrics2():
return generateMetrics()
I then viewed the returned body and headers using Postman.
In Flask I have url rules with variables. For example:
my_blueprint.add_url_rule('/<user_token>/bills/',view_func=BillsView.as_view('bills'))
This is going to pass the user_token variable to the BillsView's get and post methods.
I am trying to intercept that user_token variable in the before_request of my blueprint.
Here is my blueprint before_request:
def before_req():
...
...
my_blueprint.before_request(before_req)
The closest I have come is to use request.url_rule. But that does not give me the content of the variable. Just the rule that matches.
Register a URL processor using #app.url_value_preprocessor, which takes the endpoint and values matched from the URL. The values dict can be modified, such as popping a value that won't be used as a view function argument, and instead storing it in the g namespace.
from flask import g
#app.url_value_preprocessor
def store_user_token(endpoint, values):
g.user_token = values.pop('user_token', None)
The docs include a detailed example of using this for extracting an internationalization language code from the URL.
Apart from the URL preprocessors as described above, another approach to get args passed to the URL explicitly will be to use this.
#app.before_request
def get_request_args():
"Provides all request args"
request_args = {**request.view_args, **request.args} if request.view_args else {**request.args}
print('All Request args ',request_args)
More info in the documentation of request.args and request.view_args