We Keep Coding

unable to decode this string using python

I have this text.ucs file which I am trying to decode using python.
file = open('text.ucs', 'r')
content = file.read()
print content
My result is
\xf\xe\x002\22
I tried doing decoding with utf-16, utf-8
content.decode('utf-16')
and getting error
Traceback (most recent call last): File "", line 1, in
File "C:\Python27\lib\encodings\utf_16.py", line 16, in
decode
return codecs.utf_16_decode(input, errors, True) UnicodeDecodeError: 'utf16' codec can't decode bytes in position
32-33: illegal encoding
Please let me know if I am missing anything or my approach is wrong
Edit: Screenshot has been asked

The string is encoded as UTF16-BE (Big Endian), this works:
content.decode("utf-16-be")

oooh, as i understand you using python 2.x.x but encoding parameter was added only in python 3.x.x as I know, i am doesn't master of python 2.x.x but you can search in google about io.open for example try:
file = io.open('text.usc', 'r',encoding='utf-8')
content = file.read()
print content
but chek do you need import io module or not

You can specify which encoding to use with the encoding argument:
with open('text.ucs', 'r', encoding='utf-16') as f:
text = f.read()

your string need to Be Uncoded With The Coding utf-8 you can do What I Did Now for decode your string
f = open('text.usc', 'r',encoding='utf-8')
print f

Python 3: JSON File Load with Non-ASCII Characters

just trying to load this JSON file(with non-ascii characters) as a python dictionary with Unicode encoding but still getting this error:
return codecs.ascii_decode(input, self.errors)[0]
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 90: ordinal not in range(128)
JSON file content = "tooltip":{
"dxPivotGrid-sortRowBySummary": "Sort\"{0}\"byThisRow",}
import sys
import json
data = []
with open('/Users/myvb/Desktop/Automation/pt-PT.json') as f:
for line in f:
data.append(json.loads(line.encode('utf-8','replace')))

You have several problems as near as I can tell. First, is the file encoding. When you open a file without specifying an encoding, the file is opened with whatever sys.getfilesystemencoding() is. Since that may vary (especially on Windows machines) its a good idea to explicitly use encoding="utf-8" for most json files. Because of your error message, I suspect that the file was opened with an ascii encoding.
Next, the file is decoded from utf-8 into python strings as it is read by the file system object. The utf-8 line has already been decoded to a string and is already ready for json to read. When you do line.encode('utf-8','replace'), you encode the line back into a bytes object which the json loads (that is, "load string") can't handle.
Finally, "tooltip":{ "navbar":"Operações de grupo"} isn't valid json, but it does look like one line of a pretty-printed json file containing a single json object. My guess is that you should read the entire file as 1 json object.
Putting it all together you get:
import json
with open('/Users/myvb/Desktop/Automation/pt-PT.json', encoding="utf-8") as f:
data = json.load(f)
From its name, its possible that this file is encoded as a Windows Portugese code page. If so, the "cp860" encoding may work better.

I had the same problem, what worked for me was creating a regular expression, and parsing every line from the json file:
REGEXP = '[^A-Za-z0-9\'\:\.\;\-\?\!]+'
new_file_line = re.sub(REGEXP, ' ', old_file_line).strip()

Having a file with content similar to yours I can read the file in one simple shot:
>>> import json
>>> fname = "data.json"
>>> with open(fname) as f:
... data = json.load(f)
...
>>> data
{'tooltip': {'navbar': 'Operações de grupo'}}

You don't need to read each line. You have two options:
import sys
import json
data = []
with open('/Users/myvb/Desktop/Automation/pt-PT.json') as f:
data.append(json.load(f))
Or, you can load all lines and pass them to the json module:
import sys
import json
data = []
with open('/Users/myvb/Desktop/Automation/pt-PT.json') as f:
data.append(json.loads(''.join(f.readlines())))
Obviously, the first suggestion is the best.

lxml.etree.XML ValueError for Unicode string

I'm transforming an xml document with xslt. While doing it with python3 I had this following error. But I don't have any errors with python2
-> % python3 cstm/artefact.py
Traceback (most recent call last):
File "cstm/artefact.py", line 98, in <module>
simplify_this_dataset('fisheries-service-des-peches.xml')
File "cstm/artefact.py", line 85, in simplify_this_dataset
xslt_root = etree.XML(xslt_content)
File "lxml.etree.pyx", line 3012, in lxml.etree.XML (src/lxml/lxml.etree.c:67861)
File "parser.pxi", line 1780, in lxml.etree._parseMemoryDocument (src/lxml/lxml.etree.c:102420)
ValueError: Unicode strings with encoding declaration are not supported. Please use bytes input or XML fragments without declaration.
#!/usr/bin/env python3
# vim:fileencoding=UTF-8:ts=4:sw=4:sta:et:sts=4:ai
# -*- coding: utf-8 -*-
from lxml import etree
def simplify_this_dataset(dataset):
"""Create A simplify version of an xml file
it will remove all the attributes and assign them as Elements instead
"""
module_path = os.path.dirname(os.path.abspath(__file__))
data = open(module_path+'/data/ex-fire.xslt')
xslt_content = data.read()
xslt_root = etree.XML(xslt_content)
dom = etree.parse(module_path+'/../CanSTM_dataset/'+dataset)
transform = etree.XSLT(xslt_root)
result = transform(dom)
f = open(module_path+ '/../CanSTM_dataset/otra.xml', 'w')
f.write(str(result))
f.close()

data = open(module_path+'/data/ex-fire.xslt')
xslt_content = data.read()
This implicitly decodes the bytes in the file to Unicode text, using the default encoding. (This might give wrong results, if the XML file isn't in that encoding.)
xslt_root = etree.XML(xslt_content)
XML has its own handling and signalling for encodings, the <?xml encoding="..."?> prolog. If you pass a Unicode string starting with <?xml encoding="..."?> to a parser, the parser would like to reintrepret the rest of the byte string using that encoding... but can't, because you've already decoded the byte input to a Unicode string.
Instead, you should either pass the undecoded byte string to the parser:
data = open(module_path+'/data/ex-fire.xslt', 'rb')
xslt_content = data.read()
xslt_root = etree.XML(xslt_content)
or, better, just have the parser read straight from the file:
xslt_root = etree.parse(module_path+'/data/ex-fire.xslt')

You can also decode the UTF-8 string and encode it with ascii before passing it to etree.XML
xslt_content = data.read()
xslt_content = xslt_content.decode('utf-8').encode('ascii')
xslt_root = etree.XML(xslt_content)

I made it work by simply reencoding with the default options
xslt_content = data.read().encode()

Need help to figure out a solution to this UnicodeDecodeError

When I use this code (adapted from Stephen Holiday code - thanks, Stephen for your code!):
#!/usr/bin/env python
# -*- coding: utf-8 -*-
# -*- coding: utf-8 -*-
"""
USSSALoader.py
"""
import os
import re
#import urllib2
from zipfile import ZipFile
import csv
import pickle
def getNameList():
namesDict=extractNamesDict()
maleNames=list()
femaleNames=list()
for name in namesDict:
counts=namesDict[name]
tuple=(name,counts[0],counts[1])
if counts[0]>counts[1]:
maleNames.append(tuple)
elif counts[1]>counts[0]:
femaleNames.append(tuple)
names=(maleNames,femaleNames)
return names
def extractNamesDict():
zf=ZipFile('names.zip', 'r')
filenames=zf.namelist()
names=dict()
genderMap={'M':0,'F':1}
for filename in filenames:
file=zf.open(filename,'r')
rows=csv.reader(file, delimiter=',')
for row in rows:
name=row[0].upper()
# name=row[0].upper().encode('utf-8')
gender=genderMap[row[1]]
count=int(row[2])
if not names.has_key(name):
names[name]=[0,0]
names[name][gender]=names[name][gender]+count
file.close()
print '\tImported %s'%filename
return names
if __name__ == "__main__":
getNameList()
I got this error:
iterator = raw_query.Run(**kwargs)
File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore.py", line 1622, in Run
itr = Iterator(self.GetBatcher(config=config))
File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore.py", line 1601, in GetBatcher
return self.GetQuery().run(_GetConnection(), query_options)
File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore.py", line 1490, in GetQuery
filter_predicate=self.GetFilterPredicate(),
File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore.py", line 1534, in GetFilterPredicate
property_filters.append(datastore_query.make_filter(name, op, values))
File "C:\Program Files (x86)\Google\google_appengine\google\appengine\datastore\datastore_query.py", line 107, in make_filter
properties = datastore_types.ToPropertyPb(name, values)
File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore_types.py", line 1745, in ToPropertyPb
pbvalue = pack_prop(name, v, pb.mutable_value())
File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore_types.py", line 1556, in PackString
pbvalue.set_stringvalue(unicode(value).encode('utf-8'))
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe1 in position 1: ordinal not in range(128)
This happens when I have names with non-ASCII caracters (like "Chávez" or "Barañao"). I tried to fix this problem doing this:
for row in rows:
# name=row[0].upper()
name=row[0].upper().encode('utf-8')
gender=genderMap[row[1]]
count=int(row[2])
But, then, I got this other error:
File "C:\Users\CG\Desktop\Google Drive\Sci&Tech\projects\naivebayes\USSSALoader.py", line 17, in getNameList
namesDict=extractNamesDict()
File "C:\Users\CG\Desktop\Google Drive\Sci&Tech\projects\naivebayes\USSSALoader.py", line 43, in extractNamesDict
name=row[0].upper().encode('utf-8')
UnicodeDecodeError: 'ascii' codec can't decode byte 0xed in position 3: ordinal not in range(128)
I also tried this:
def extractNamesDict():
zf=ZipFile('names.zip', 'r', encode='utf-8')
filenames=zf.namelist()
But ZipFile doesn't have such argument.
So, how to fix that avoiding this UnicodeDecodeError for non-ASCII names?
I'm using this code with GAE.

It looks like your first traceback is AppEngine-related. Are you building a loader that will populate the datastore? If so, seeing the code that comprises the models and does the put'ing would be helpful. I will probably be corrected by someone, but in order for that piece to work I believe you actually need to decode instead of encode (i.e. when you read the sheet prior to the put, convert the string to unicode by using decode('utf-8') or decode('latin1'), depending on your situation).
As far as your local code, I won't pretend to know the deep internals of Unicode handling, but I've generally used decode() and encode() to handle these types of situations. I believe the correct encoding to use depends on the underlying text (meaning you'd need to know if it were encoded utf-8 or latin-1, etc.). Here is a quick test with your example:
>>> s = 'Chávez'
>>> type(s)
<type 'str'>
>>> u = s.decode('latin1')
>>> type(u)
<type 'unicode'>
>>> e = u.encode('latin1')
>>> print e
Chávez
In this case, I needed to use latin1 to decode the encoded string (I was using the terminal), but in your situation using utf-8 may very well work.

Unless I'm missing something, this line in the library:
pbvalue.set_stringvalue(unicode(value).encode('utf-8'))
should be:
pbvalue.set_stringvalue(value.decode(filename_encoding).encode('utf-8'))
And the value filename_encoding passed in from your code if not stored in the zip archive somehow (and at least in the early versions of the format, I doubt it's stored). It's yet another occurrence of the classic error of assuming that bytes and "characters" are the same thing.
If you're feeling froggy, dive into the code and fix it, and maybe even contribute a patch. Otherwise, you'll have to write heroic code that checks for U+0080 and above in filenames and performs special handling.

In python 2.7 ( and linux Mint 17.1) , you must use:
hashtags=['transito','tránsito','ñandú','pingüino','fhürer']
for h in hashtags:
u=h.decode('utf-8')
print(u.encode('utf-8'))
transito
tránsito
ñandú
pingüino
fhürer

Why does printing to a utf-8 file fail?

So I ran into a problem this afternoon, I was able to solve it, but I don't quite understand why it worked.
this is related to a problem I had the other week: python check if utf-8 string is uppercase
basically, the following will not work:
#!/usr/bin/python
import codecs
from lxml import etree
outFile = codecs.open('test.xml', 'w', 'utf-8') #cannot use codecs.open()
root = etree.Element('root')
sect = etree.SubElement(root,'sect')
words = ( u'\u041c\u041e\u0421\u041a\u0412\u0410', # capital of Russia, all uppercase
u'R\xc9SUM\xc9', # RESUME with accents
u'R\xe9sum\xe9', # Resume with accents
u'R\xe9SUM\xe9', ) # ReSUMe with accents
for word in words:
print word
if word.encode('utf8').decode('utf8').isupper(): #.isupper won't function on utf8
title = etree.SubElement(sect,'title')
title.text = word
else:
item = etree.SubElement(sect,'item')
item.text = word
print>>outFile,etree.tostring(root,pretty_print=True,xml_declaration=True,encoding='utf-8')
it fails with the following:
Traceback (most recent call last):
File "./temp.py", line 25, in
print >>outFile,etree.tostring(root,pretty_print=True,xml_declaration=True,encoding='utf-8')
File "/usr/lib/python2.7/codecs.py",
line 691, in write
return self.writer.write(data) File "/usr/lib/python2.7/codecs.py",
line 351, in write
data, consumed = self.encode(object, self.errors)
UnicodeDecodeError: 'ascii' codec
can't decode byte 0xd0 in position 66:
ordinal not in range(128)
but if I open the new file without codecs.open('test.xml', 'w', 'utf-8') and instead use
outFile = open('test.xml', 'w') it works perfectly.
So whats happening??
since encoding='utf-8' is specified in etree.tostring() is it encoding the file again?
if I leave codecs.open() and remove encoding='utf-8' the file then becomes an ascii file. Why? becuase etree.tostring() has a default encoding of ascii I persume?
but etree.tostring() is simply being written to stdout, and is then redirect to a file that was created as a utf-8 file??
is print>> not workings as I expect? outFile.write(etree.tostring()) behaves the same way.
Basically, why wouldn't this work? what is going on here. It might be trivial, but I am obviously a bit confused and have a desire to figure out why my solution works,

You've opened the file with UTF-8 encoding, which means that it expects Unicode strings.
tostring is encoding to UTF-8 (in the form of bytestrings, str), which you're writing to the file.
Because the file is expecting Unicode, it's decoding the bytestrings to Unicode using the default ASCII encoding so that it can then encode the Unicode to UTF-8.
Unfortunately, the bytestrings aren't ASCII.
EDIT: The best advice to avoid this kind of problem is to use Unicode internally, decoding on input and encoding on output.

Using print>>outFile is a little strange. I don't have lxml installed, but the built-in xml.etree library is similar (but doesn't support pretty_print). Wrap the root Element in an ElementTree and use the write method.
Also, if you using a # coding line to declare the encoding of the source file, you can use readable Unicode strings instead of escape codes:
#!/usr/bin/python
# coding: utf8
import codecs
from xml.etree import ElementTree as etree
root = etree.Element(u'root')
sect = etree.SubElement(root,u'sect')
words = [u'МОСКВА',u'RÉSUMÉ',u'Résumé',u'RéSUMé']
for word in words:
print word
if word.isupper():
title = etree.SubElement(sect,u'title')
title.text = word
else:
item = etree.SubElement(sect,u'item')
item.text = word
tree = etree.ElementTree(root)
tree.write('text.xml',xml_declaration=True,encoding='utf-8')

In addition to MRABs answer some lines of code:
import codecs
from lxml import etree
root = etree.Element('root')
sect = etree.SubElement(root,'sect')
# do some other xml building here
with codecs.open('test.xml', 'w', encoding='utf-8') as f:
f.write(etree.tostring(root, encoding=unicode))