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How do I reset pygame.time.Clock()?

I made a sudoku game for my introduction to computer programming class and I want to expand it over Winter break by adding some new features. The first of which I want to be a clock. I found some code on here that helped me implement a clock system on my screen, but now I want the clock to reset when the restart button is pressed and the user goes back to the home screen.
Any help would be greatly appreciated! I am not married to my current code I am more than willing to change it, I am just very new to programming and don't even know where to start with something like this.
Attached is the current code I have to make my clock run and display it to my screen:
I tried to "time = 0", and "time = pygame.clock.Time()" hoping that it would initialize the time again and the count would start from 0 but it did not work. I looked for other answers, but I am new to programming and they didn't make much sense to me.
I was expecting the time to be reset to 0.000 and to start counting up again, but it just continued counting from where it left off
Below is the code I currently have that makes my clock and displays it to my game screen:
clock = pygame.time.Clock() # initialize clock
font = pygame.freetype.SysFont(None, 34) # font for clock
font.origin = True # makes the font not shake around for whatever
while True:
if not game_over:
screen.fill(pygame.Color(button_words_color), (0, 0, screen_dimension, 50))
ticks = pygame.time.get_ticks()
millis = ticks % 1000
seconds = int(ticks / 1000 % 60)
minutes = int(ticks / 60000 % 24)
out = '{minutes:02d}:{seconds:02d}:{millis}'.format(minutes=minutes, millis=millis, seconds=seconds)
font.render_to(screen, (5, 35), out, pygame.Color(button_color)) # (5, 35) is where it's displayed)
pygame.display.flip()
clock.tick(60)

pygame.time.get_ticks() returns the milliseconds since pygame.init() and cannot be reseted. However you can remember and change the start time:
start_ticks = pygame.time.get_ticks()
while True:
current_ticks = pygame.time.get_ticks()
# [...]
if not game_over:
ticks = current_ticks - start_ticks
# [...]
else:
start_ticks = current_ticks
# [...]

How to implement a Pygame timed game loop?

I am looking to write a better game loop in Python using pygame.time.Clock(), and I understand the concept of keeping time and de-coupling rendering from the main game loop in order to better utilise the ticks. I also understand about passing time lag into the rendering so that it renders the correct amount of movement, but the only examples I've found are written in C# and although I first thought it fairly simple to convert to Python, it's not behaving.
I've figured out that Pygame's Clock() already works out the milliseconds between the last 2 calls to .tick, and I've tried to adapt the sample code I found, but I really need to see a working example written in Python. Here's what I've come up with so far:
FPS = 60
MS_PER_UPDATE = 1000 / FPS
lag = 0.0
clock = pygame.time.Clock()
running = True
# Do an initial tick so the loop has 2 previous ticks.
clock.tick(FPS)
while running:
clock.tick(FPS)
lag += clock.get_time()
user_input()
while lag >= MS_PER_UPDATE:
update()
lag -= MS_PER_UPDATE
render(lag / MS_PER_UPDATE)
I'm not sure if this is all worth it in Pygame, or if it's already taken care of in some of it's time functions already? My game runs slower on the laptop (expected) but I thought doing this might even out the FPS a bit between my main PC and laptop by de-coupling the rendering. Does anyone have experience doing these advanced game loops in Pygame? I just want it to be as good as it can be...

Just take the time it took to render the last frame (called delta time) and pass it to your game objects so they can decide what to do (e.g. move more or less).
Here's a super simple example:
import pygame
class Actor(pygame.sprite.Sprite):
def __init__(self, *args):
super().__init__(*args)
self.image = pygame.Surface((32, 32))
self.rect = pygame.display.get_surface().get_rect()
self.image.fill(pygame.Color('dodgerblue'))
def update(self, events, dt):
self.rect.move_ip((1 * dt / 5, 2 * dt / 5))
if self.rect.x > 500: self.rect.x = 0
if self.rect.y > 500: self.rect.y = 0
def main():
pygame.init()
screen = pygame.display.set_mode((500, 500))
sprites = pygame.sprite.Group()
Actor(sprites)
clock = pygame.time.Clock()
dt = 0
while True:
events = pygame.event.get()
for e in events:
if e.type == pygame.QUIT:
return
sprites.update(events, dt)
screen.fill((30, 30, 30))
sprites.draw(screen)
pygame.display.update()
dt = clock.tick(60)
if __name__ == '__main__':
main()
If your game slows down below 60 (or whatever) FPS, dt gets bigger, and Actor moves more to make up for the lost time.

Can't click on image again, what's wrong with my pygame code?

Okay, I'am trying to create a Tom and Jerry game with the pygame library.
The game focuses on catching mice by clicking on them as they appear in their holes. The problem
is that sometimes a cat appears instead of a mouse and should the player erroneously click on the
cat (s)he looses all earned points, but the game continues.
The mouse is an image of a mouse and the cat is an image of an cat.
If you click on the mouse, you get mouse, otherwise the cat gets the points.
The code is a mess, that's because I don't know what I'am doing and just set an another event loop because then it works, because it runs after I create the mouse. It works to click on the mouse but then you click somewhere else and after that it's like you did not clicked on the mouse.
The mouse is created in a loop and is supposed to wait for 5 seconds and if you click on the mouse within these seconds then an appropriate message prints out in the console ,,Jerry clicked!" else "1 click". If you don't click on the mouse within 5 seconds a image covers the mouse so she disappears.
Now, what I'am trying to do right now is to print the message 1 click when the player does not click on anything but print 1 click jerry clicked when the player clicks on the mouse. I have a image of the mousehole and then I put the mouse on the mousehole, that is, on an another image.
This code works with one image at least:
pygame.init()
width=350;
height=400
screen = pygame.display.set_mode( (width, height ) )
pygame.display.set_caption('clicked on image')
redSquare = pygame.image.load("images/red-square.png").convert()
x = 20; # x coordnate of image
y = 30; # y coordinate of image
screen.blit(redSquare , ( x,y)) # paint to screen
pygame.display.flip() # paint screen one time
running = True
while (running):
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.MOUSEBUTTONDOWN:
# Set the x, y postions of the mouse click
x, y = event.pos
if redSquare.get_rect().collidepoint(x, y):
print('clicked on image')
#loop over, quite pygame
pygame.quit()
My problem is that, when I click on the mouse and then I don't click on the mouse I can't click on the mouse again at another position.
So what's wrong? What I'am doing wrong here?
Here is my code:
import pygame
from pygame import *
from random import *
init()
run = True
screen = (800,800)
screen = display.set_mode(screen)
xpos = 0
ypos = 0
mouseorcatxpos = 5
mouseorcatypos = 0
mousehole = image.load("mousehole.png").convert()
cat = image.load("tom.png")
jerry = image.load("jerry.png")
def makeholes():
global ypos
global xpos
for holey in range(1,9):
for holex in range(1,9):
screen.blit(mousehole,(xpos,ypos))
display.flip()
xpos += 100
ypos += 100
xpos = 0
def mouseorcat():
global xpos
mouseorcatxpos = 5
ypos = 0
for mousecaty in range(1,9):
pygame.event.pump()
for mousecatx in range(1,9):
randommouse = randint(1, 3)
randomcat = randint(1, 10)
if(randommouse == 2):
screen.blit(jerry, (mouseorcatxpos, ypos))
display.flip()
for event in pygame.event.get():
if (event.type == MOUSEBUTTONDOWN):
if jerry.get_rect().collidepoint(xpos, ypos) == False:
print("l clicked!")
x, y = event.pos
if jerry.get_rect().collidepoint(xpos, y):
print("JERRY CLICKED!!")
x, y = event.pos
print(x, y)
time.wait(5000)
#screen.blit(mousehole, (mouseorcatxpos - 5, ypos))
display.flip()
elif(randomcat == 2):
screen.blit(cat, (mouseorcatxpos, ypos))
display.flip()
time.wait(1500)
screen.blit(mousehole, (mouseorcatxpos-5, ypos))
display.flip()
mouseorcatxpos += 100
mouseorcatxpos = 0
ypos += 100
makeholes()
while run == True:
for event in pygame.event.get():
mouseorcat()
if event.type == QUIT:
run = False

I rewrote your game to show you how I would do it.
To keep track of the time and to limit the framerate I used a pygame.time.Clock and a timer variable. The clock returns the time in milliseconds since clock.tick was called the last time, which is used to increase the timer variable. The cat just replaces the mouse after two seconds and the mouse is set to a new position. I use pygame.Rects to store the positions, but you could also use lists or tuples.
import sys
import random
import pygame
pygame.init()
size = (800, 800)
screen = pygame.display.set_mode(size)
# Images replaced by pygame.Surface. Do that too
# in the future before you post your code.
mousehole = pygame.Surface((40, 40)).convert()
mousehole.fill(pygame.Color(30, 30, 30))
cat = pygame.Surface((40, 40)).convert()
cat.fill(pygame.Color(110, 110, 130))
jerry = pygame.Surface((40, 40)).convert()
jerry.fill(pygame.Color(190, 130, 0))
# Create the background image and blit the holes.
background = pygame.Surface(size).convert()
for holey in range(8):
for holex in range(8):
background.blit(mousehole, (holex*100, holey*100))
def new_position():
"""Return a random position between 0-700 in steps of 100."""
return (random.randrange(0, 701, 100), random.randrange(0, 701, 100))
def main():
fps = 30
clock = pygame.time.Clock()
jerry_rect = jerry.get_rect() # Stores jerry's position and size.
jerry_rect.topleft = new_position() # New random position.
# The cat is outside of the screen first.
cat_rect = cat.get_rect(topleft=(-100, -100))
points = 0
timer = 0
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.MOUSEBUTTONDOWN:
if jerry_rect.collidepoint(event.pos):
points += 1
print('Jerry caught! Points:', points)
timer = 0
jerry_rect.topleft = new_position()
else:
print('Missed. Points:', points)
# Run logic.
timer += clock.tick(fps) / 1000 # timer + seconds since last tick.
if timer > 2: # Cat catches mouse after 2 seconds.
cat_rect.topleft = jerry_rect.topleft
jerry_rect.topleft = new_position()
timer = 0
points = 0
print('Tom caught Jerry.')
# Draw.
# Clear the screen by blitting the bg.
screen.blit(background, (0, 0))
screen.blit(jerry, jerry_rect)
screen.blit(cat, cat_rect)
pygame.display.flip()
if __name__ == '__main__':
main()
pygame.quit()
sys.exit()
Side notes:
Don't use star imports (from module import *), because that can make code harder to read. If you want you can use from pygame.locals import *, if it's the only star import.
Don't use global variables, because they can make code harder to read, understand and maintain. Pass variables to functions as arguments and then return the result.
Update: Some notes about your program:
The first big problem is that your game has two event loops and the important one is deeply nested inside of two other for loops and a if. The event loop should be directly under the main while loop (one indentation level (when you have more experience you can put it into a function or class method)).
The two for loops seem to have the purpose to let the code run until randommouse or randomcat are 2. To run code until a condition is met is the purpose of a while loop. But in this case you should better just pick a random number and write the if/elif conditions so that they always apply. For example, you want a 2/3 chance for mouse and 1/3 for a cat,
random_number = random.randint(1, 3)
if random_number < 3:
print("2/3 probability. It's a mouse")
else:
print("1/3 probability. It's a cat")
Or use random.choice with a list:
>>> random.choice(['mouse', 'mouse', 'cat'])
'mouse'
time.wait(5000) shouldn't be used because the game just hangs in this time. You can't even close the window. Limit the framerate and get the time since the last tick with a pygame.time.Clock.
pygame.event.pump() is not needed.
If you call get_rect() without an argument, the rect is positioned at (0, 0).
if jerry.get_rect().collidepoint(xpos, y):
That's the reason why clicking on jerry only works in the top row, and because you use the global xpos here. Since xpos is 0, the whole top row counts as Jerry.
You can pass coordinates to get_rect like so (you can also use center or other args instead of topleft):
jerry_rect = jerry.get_rect(topleft=(50, 100))
I'm sorry but I don't think I can simply fix your code. I've tried it several times, but I always end up re-writing it completely.
I begin by extracting the event loop out of the two nested for loops, then remove these loops, create rects for the mouse and cat, fix the collision detection, add a timer and so on. Take a close look at my example and try to rewrite your game in a similar way, and keep asking questions if you don't understand something.

Python time counter in Pygame-mouse events

I want to calculate the time of user's mouse events in Pygame, if user doesn't move his mouse about 15 seconds, then I want to display a text to the screen. I tried time module for that, but it's not working.
import pygame,time
pygame.init()
#codes
...
...
font = pygame.font.SysFont(None,25)
text = font.render("Move your mouse!", True, red)
FPS = 30
while True:
#codes
...
...
start = time.time()
cur = pygame.mouse.get_pos() #catching mouse event
end = time.time()
diff = end-start
if 15 < diff:
gameDisplay.blit(text,(10,500))
pygame.display.update()
clock.tick(FPS)
pygame.quit()
quit()
Well output is not what I want, I don't know how to calculate it if user doesn't move his mouse.
If I want to write a text when user's mouse in a special area, it's working like;
if 100 < cur[0] < 200 and 100 < cur[1] < 200:
gameDisplay.blit(text,(10,500))
But how can I calculate? I even couldn't find how to tell Python, user's mouse is on the same coordinates or not.Then I can say, if mouse coordinates changes, start the timer, and if it's bigger than 15, print the text.
Edit: You can assume it in normal Python without Pygame module, assume you have a function that catching the mouse events, then how to tell Python if coordinates of mouse doesn't change, start the timer, if the time is bigger than 15 seconds,print a text, then refresh the timer.

To display a text on the screen if there is no mouse movement within the pygame window for 3 seconds:
#!/usr/bin/python
import sys
import pygame
WHITE, RED = (255,255,255), (255,0,0)
pygame.init()
screen = pygame.display.set_mode((300,200))
pygame.display.set_caption('Warn on no movement')
font = pygame.font.SysFont(None, 25)
text = font.render("Move your mouse!", True, RED, WHITE)
clock = pygame.time.Clock()
timer = pygame.time.get_ticks
timeout = 3000 # milliseconds
deadline = timer() + timeout
while True:
now = timer()
if pygame.mouse.get_rel() != (0, 0): # mouse moved within the pygame screen
deadline = now + timeout # reset the deadline
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
screen.fill(WHITE)
if now > deadline: # no movement for too long
screen.blit(text, (10, 50))
pygame.display.flip()
clock.tick(60) # set fps

You should add:
start = time.time()
cur = None
before while loop.
You should also change start = time.time() in while loop to:
if cur != pygame.mouse.get_pos():
start = time.time()
Also you could use pygame.time (it's similar to time but measure time in milliseconds)

In your code, the while True: code block is continuously running. The cur = pygame.mouse.get_pos() function is non blocking. This means it does not wait for mouse input - it will return straight away. So you need to initialize the start and cur variables before your while True: code block and then check the mouse position constantly in your loop.
If cur has changed since the last time the loop ran, then reset the start variable to the current time, and if the difference between the current time and start becomes larger than your 15 seconds, you can display the text.

You can also do that even without getting time, since you can calculate the pause as an integer counter through your FPS. Consider following example. Note that if the cursor is out of the window, the values of its positon will not change even if you move the cursor.
import pygame
pygame.init()
clock = pygame.time.Clock( )
DISP = pygame.display.set_mode((600, 400))
FPS = 25
Timeout = 15
Ticks = FPS*Timeout # your pause but as an integer value
count = 0 # counter
MC = pygame.mouse.get_pos()
MC_old = MC
MainLoop = True
while MainLoop :
clock.tick(FPS)
pygame.event.pump()
Keys = pygame.key.get_pressed()
if Keys[pygame.K_ESCAPE]:
MainLoop = False
MC = pygame.mouse.get_pos() # get mouse position
if (MC[0]-MC_old[0] == 0) and (MC[1]-MC_old[1] == 0) :
count = count + 1
else : count = 0
if count > Ticks :
print "What are you waiting for"
count = 0
MC_old = MC # save mouse position
pygame.display.flip( )
pygame.quit( )

How do I make a timer in pygame without delaying the program

I am making a pygame game and need the variable "img" to cycle through multiple slides to make a walking animation, but all the timers i can find made with python/pygame delay the program which i don't want.

You can measure time with Python's time module. You could do something like the following:
import time
t = time.clock()
deltaT = 1 #time between updates, in seconds
while True: #inside the game loop...
if (time.clock() - t) > deltaT:
#change your image
t = time.clock()
Although if you're animating sprites, you might have better luck looking for animation modules for pygame.

You can do something like the following:
import time, pygame
from pygame.locals import *
images = ['img1.jpg', 'img2.jpg', 'img3.jpg', 'img4.jpg']
pygame.init()
screen = pygame.display.set_mode((1024, 1280))
i = 0
x = time.time()
while True:
screen.blit(images[i]) #Create the image, this syntax is wrong
screen.fill((255, 255, 255))
if i != 3:
i+=1
elif i == 4:
i = 0