Hey I am trying to publish a score to Facebook through python's urllib2 library.
import urllib2,urllib
url = "https://graph.facebook.com/USER_ID/scores"
data = {}
data['score']=SCORE
data['access_token']='APP_ACCESS_TOKEN'
data_encode = urllib.urlencode(data)
request = urllib2.Request(url, data_encode)
response = urllib2.urlopen(request)
responseAsString = response.read()
I am getting this error:
response = urllib2.urlopen(request)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 124, in urlopen
return _opener.open(url, data, timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 389, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 502, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 427, in error
return self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 361, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 510, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 400: Bad Request
Not sure if this is relating to Facebook's Open Graph or improper urllib2 API use.
I ran your code and got the same error (there is no more error in the body, would have posted that in a comment but can't yet I guess) so I googled "publish facebook scores."
I believe you'll need to grant your app permission to publish scores first, unless you've done that already. See http://developers.facebook.com/blog/post/539/.
You may have to provide user:agent as some browser. I remember getting similar error while running crawler in some website, as it detected that no browser is calling for it.
Related
I'm trying to make some search on Amazon Product Ads and using the botlenose to help me do this. But, I'm just receive the HTTP Error 400.
Some other important infos:
I'm from Brazil, and my TAG from Amazon too. Is it a problem?
I did check my KEY, Secret and TAG and it's OK. I did look some other questions on StackOverflow, but nothing work for me.
import bottlenose
AWS_ACCESS_KEY_ID="XXXXXXXXXXXXXXX"
AWS_SECRET_ACCESS_KEY="xxxxxxxxxxxxxxxxxxxxxxx"
AWS_ASSOCIATE_TAG="yyyyyyyyyyy"
amazon = bottlenose.Amazon(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY, AWS_ASSOCIATE_TAG, Region='BR')
response = amazon.ItemLookup(ItemId="B007OZNUCE")
enter code here# Of course, I changed the keys for security reasons.
Traceback (most recent call last):
File "", line 6, in
File "/Users/am/Documents/PycharmProjects/08/lib/python3.7/site-packages/bottlenose/api.py", line 274, in call
{'api_url': api_url, 'cache_url': cache_url})
File "/Users/am/Documents/PycharmProjects/08lib/python3.7/site-packages/bottlenose/api.py", line 235, in _call_api
return urllib2.urlopen(api_request, timeout=self.Timeout)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 531, in open
response = meth(req, response)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 641, in http_response
'http', request, response, code, msg, hdrs)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 569, in error
return self._call_chain(*args)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 503, in _call_chain
result = func(*args)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/urllib/request.py", line 649, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request
After that, I tried to generate the signed url by:
http://associates-amazon.s3.amazonaws.com/signed-requests/helper/index.html
and tried do put the both urls (by bottlenose and by Amazon link), and both return the same error> Later I tried by Browser the same URLs and I received the error:
<ItemLookupErrorResponse xmlns="http://ecs.amazonaws.com/doc/2013-08-01/">
<Error>
<Code>AWS.InvalidAccount</Code>
<Message>
Your AccessKey Id is not registered for Product Advertising API. Please use the AccessKey Id obtained after registering at https://affiliate-program.amazon.com/assoc_credentials/home.
</Message>
</Error>
<RequestID>4d761947-8b00-44d4-a9c0-0a9079e8d603</RequestID>
</ItemLookupErrorResponse>
Now, I'm contacting the Amazon Support to fix it.
Thanks for all!
I'm trying to use the yts api, and I wrote the following code.
import urllib2
import json
url = 'https://yts.ag/api/v2/list_movies.json?quality=3D'
json_obj = urllib2.urlopen(url)
data = json.load(json_obj)
print data
But I ran into the following error:
File "<stdin>", line 1, in <module>
File "C:\Python27\lib\urllib2.py", line 154, in urlopen
return opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 435, in open
response = meth(req, response)
File "C:\Python27\lib\urllib2.py", line 548, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python27\lib\urllib2.py", line 473, in error
return self._call_chain(*args)
File "C:\Python27\lib\urllib2.py", line 407, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 556, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
Help me how to fix this
I'm not completely sure what's going on with your urllib2 request, as it works fine with the other urls I tested, with and without JSON responses.
I suspect it's an encoding thing for the quality=3D query, but my brief attempt at handling that also failed.
Simply putting the request in a browser works, as does the following 'requests' code.
In a nutshell, I'm not truly answering your question regarding fixing the urllib2 usage, but definitely fixing the problem of getting the data.
I'd suggest working with the 'requests' module in this case. Try
import requests
import json
url = 'https://yts.ag/api/v2/list_movies.json?quality=3D'
response = requests.get( url = url )
data = response.json()
print data
Note that the requests response.json() handles the json.load() for you.
It will save you many a headache over urllib2.
The 'requests' documentation:
http://docs.python-requests.org/en/latest/
I am really an ETL guy trying to learn Python, please help
import urllib2
urls =urllib2.urlopen("url1","url2")
i=0
while i< len(urls):
htmlfile = urllib2.urlopen(urls[i])
htmltext = htmlfile.read()
print htmltext
i+=1
I am getting errors as
Traceback (most recent call last):
File ".\test.py", line 2, in
urls =urllib2.urlopen("url1","url2")
File "c:\python27\Lib\urllib2.py", line 154, in urlopen
return opener.open(url, data, timeout)
File "c:\python27\Lib\urllib2.py", line 437, in open
response = meth(req, response)
File "c:\python27\Lib\urllib2.py", line 550, in http_response
'http', request, response, code, msg, hdrs)
File "c:\python27\Lib\urllib2.py", line 475, in error
return self._call_chain(*args)
File "c:\python27\Lib\urllib2.py", line 409, in _call_chain
result = func(*args)
File "c:\python27\Lib\urllib2.py", line 558, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 405: Method Not Allowed
Your error is coming from line 2:
urls =urllib2.urlopen("url1","url2")
Whatever url you're trying to access is returning a http error code
HTTP Error 405: Method Not Allowed
Looking at the urllib2 docs, you should only be using 1 url as an argument
https://docs.python.org/2/library/urllib2.html
Open the URL url, which can be either a string or a Request object.
data may be a string specifying additional data to send to the server, or None if no such data is needed. Currently HTTP requests are the only ones that use data; the HTTP request will be a POST instead of a GET when the data parameter is provided.
The 2nd argument you're putting in may be turning the request into a POST, which would explain the Method Not Allowed code.
I'm having trouble using Google URL Shortener API in AppEngine production environment.
In the Developers console, I have the URL Shortener API turned on, and oAuth 2 is also turned on. On top of that I have the simple API Access Browser key obtained from the API Access screen.
Here is the problem. When I run the following code, I get "HTTPError: HTTP Error 403: Forbidden" in the Developers Console log. Interestingly, the same code properly returns the short url in the development environment.
def goo_shorten_url(url):
post_url = 'https://www.googleapis.com/urlshortener/v1/url?fields=id'
logging.info('post_url: {}'.format(post_url))
postdata = {'longUrl':url}
headers = {'Content-Type':'application/json'}
req = urllib2.Request(
post_url,
json.dumps(postdata),
headers
)
ret = urllib2.urlopen(req).read()
print ret
return json.loads(ret)['id']
If I include the API key in the post url as follows,
post_url = 'https://www.googleapis.com/urlshortener/v1/url?fields=id&key=MYAPIKEY'
Prod and Dev both return HTTP Error 403.
I suspect one of these three is true, but would like to hear your thoughts.
An API key is required, but I'm not using the right API key.
An API key is not required (which explains why it work with no key in Dev), but my API key is wrong resulting both Prod and Dev fail.
Google doesn't allow applications to programmatically submit a POST request to its Url shortener API.(this doesn't explain why it would work in Dev at all)
Thanks for reading.
Prod
File "/base/data/home/apps/s~myapp/1.377367579804576653/util/test_module.py", line 50, in get
strin = goo_shorten_url(longurl)
File "/base/data/home/apps/s~myapp/1.377367579804576653/util/JOTools.py", line 41, in goo_shorten_url
ret = urllib2.urlopen(req).read()
File "/base/data/home/runtimes/python27/python27_dist/lib/python2.7/urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "/base/data/home/runtimes/python27/python27_dist/lib/python2.7/urllib2.py", line 410, in open
response = meth(req, response)
File "/base/data/home/runtimes/python27/python27_dist/lib/python2.7/urllib2.py", line 523, in http_response
'http', request, response, code, msg, hdrs)
File "/base/data/home/runtimes/python27/python27_dist/lib/python2.7/urllib2.py", line 448, in error
return self._call_chain(*args)
File "/base/data/home/runtimes/python27/python27_dist/lib/python2.7/urllib2.py", line 382, in _call_chain
result = func(*args)
File "/base/data/home/runtimes/python27/python27_dist/lib/python2.7/urllib2.py", line 531, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden
Dev with API Key
File "C:_dev\eclipse-work\gae\MyProj\util\test_module.py", line 50, in get
strin = goo_shorten_url(longurl)
File "C:_dev\eclipse-work\gae\MyProj\util\JOTools.py", line 41, in goo_shorten_url
ret = urllib2.urlopen(req).read()
File "C:\PYTHON27\lib\urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "C:\PYTHON27\lib\urllib2.py", line 410, in open
response = meth(req, response)
File "C:\PYTHON27\lib\urllib2.py", line 523, in http_response
'http', request, response, code, msg, hdrs)
File "C:\PYTHON27\lib\urllib2.py", line 448, in error
return self._call_chain(*args)
File "C:\PYTHON27\lib\urllib2.py", line 382, in _call_chain
result = func(*args)
File "C:\PYTHON27\lib\urllib2.py", line 531, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden
Google has a nice API for this. You can test your requests here. Hope this helps.
Hello fellow Programmers,
today I wanted to get some JSON Data from this website using Python 3.3: http://ladv.de/api/-apikey-redacted-/ausDetail?id=884&wettbewerbe=true&all=true
The official API tells me that calling this URL returns some JSON Data. But if I use the following code to get it (which I found on stackoverflow, too), it throws an error:
import urllib.request
import json
request = 'http://ladv.de/api/mmetzger/ausDetail?id=884&wettbewerbe=true&all=true'
response = urllib.request.urlopen(request)
obj = json.load(response)
str_response = response.readall().decode('utf-8')
obj = json.loads(str_response)
print(obj)
prints out
Traceback (most recent call last):
File "D:/ladvclient/testscrape.py", line 5, in <module>
response = urllib.request.urlopen(request)
File "C:\Python33\lib\urllib\request.py", line 156, in urlopen
return opener.open(url, data, timeout)
File "C:\Python33\lib\urllib\request.py", line 475, in open
response = meth(req, response)
File "C:\Python33\lib\urllib\request.py", line 587, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python33\lib\urllib\request.py", line 513, in error
return self._call_chain(*args)
File "C:\Python33\lib\urllib\request.py", line 447, in _call_chain
result = func(*args)
File "C:\Python33\lib\urllib\request.py", line 595, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 404: Not Found
Where is the bug, and what is the correct code?
Thanks in advance,
forumfresser
The site you're trying to fetch is not available, as seen here:
http://ladv.de/api/-apikey-redacted-/ausDetail?id=884&wettbewerbe=true&all=true
You could also just read the error message by yourself:
urllib.error.HTTPError: HTTP Error 404: Not Found