I am working on a html with selenium. After clicking the last link, pop up comes which says as save a file.
using selenium I am recording all the events and then generating the selenium RC script.
I want to know that how to get the pop up file from code using python?
In the case of saving a file, you can get around the popup box by configuring the options of your browser profile. See this answer for an explanation using Firefox. General idea is that you need to tell Firefox itself to not prompt when saving files of certain types. Note that this will result in the file being saved somewhere, but you can also control where it goes in case you want to delete the file (or handle it separately in Python).
Webdriver cannot communicate with the browser modal popup.
But this can be done, check out the below link for your answer
http://blog.codecentric.de/en/2010/07/file-downloads-with-selenium-mission-impossible/
Related
Lets say I open up an URL in chrome or in any browser.
Now I want to save the console logs or messages in a file so that I can perform certain validations.
Can we do this using python?
Please let me know how to do this?
Note: The solution should work if I run browser in headless mode.
I did not get any solution till yet.
I am new to python selenium and I need more explanation on the effect of the below code on selenium Firefox profile.
profile.set_preference('browser.helperApps.neverAsk.saveToDisk', ('application/vnd.ms-excel'))
Firefox browser is by default asking if to save or to open the file when user tries to download a file.
To prevent Firefox opening that dialog we can predefine not to ask this for predefined types of files.
Each file type should be mentioned explicitly with such setting in order to not ask when downloading of such a kind of file initiated.
Basically when setting up your Firefox profile you add a call to set the property browser.helperApps.neverAsk.saveToDisk like this.
You won't face download pop up.
so basically it means that download any file and save it to the desired location using Selenium Webdriver.
After some research on my problem, it seems I should use either requests or urllib or both.
So basically, I am trying to learn the code I need to download a csv file from this url:
https://globalaccess.sustainalytics.com/#/tools/0
The way I manually download my files is as follows: first, I need to log in using username and password. Next I have to go to a tab called "Screening" that takes to me another page that has several buttons called "Generate". I click a specific generate button (it's always the same one) among the option to get the excel file. After that I have the option to save the file or open from a little window within the website.
My question is what code can I use on Python to download and save the file in a particular folder?
Use Selenium
https://selenium-python.readthedocs.io/
You'll need to download a 'chromedriver' to the same directory as your python script, then use the intro tutorial on the selenium docs site to drive the browser to type/click where you want.
If you use chrome you can right click on any given link/input box click inspect, then in the window that comes up right click the bit of highlighted code and 'copy xpath'. Use the find element by xpath function in Selenium to send keys or clicks to that element.
The problem: I want to write a Python script that takes a screenshot of a website I have opened in a browser each time it loads.
The thing is that I have a website where there are like 300 exam questions which I can get through, try each one of them and I will have the correction when I submit my answer. I will not have access to this questionnaire after a certain date, but I want to keep the questions (which I could write down, but laziness is strong in me, and want to learn Python).
The "attempt": I thought of doing a simple Python script with imgkit to take the screenshots. I'm opened to other suggestions, as imgkit was the first thing I saw while looking for this, and the code looks plain and simple to me:
import imgkit
imgkit.from_url('http://webpage.com', 'out.jpg')
But I have to provide the url for each webpage, and that will be more tedious than taking a screenshot with OS features, thus I want to automatize it.
The questions:
There is a way to make Python monitor a browser tab and take a screenshot each time it reloads (that will be when a new question appears)?
Or maybe get the tab's URL to pass it to imgkit and take the screenshot.
Another thing that I saw is that imgkit can generate a "screenshot" from a HTML file. Can Python download the HTML code from a tab I have open in my browser?
Selenium is your friend here. It is a framework designed for testing but it will make what you want really easy.
Selenium allows you to spin-up a web browser and control it. So you can instruct it to go to the web address you want and then do things. Normally you would instruct it to click here, write in a form, etc.
In your case you only want it to open a certain address, take a screenshot, go the the next address and repeat.
Here you have a tutorial on how to do exactly what you want.
The specific code is:
from selenium import webdriver
#1. Get the driver to manage the web-browser you choose
driver = webdriver.Chrome()
#2. Go the the webadress you want
driver.get('https://python.org')
#3. Take a screenshot
driver.save_screenshot("screenshot.png")
driver.close()
PS: In order for the tutorial to run you will need to have installed the web driver for Selenium to be able to spin-up and run Chrome. Here are the instructions for that.
I'm using python and selenium chrome driver to click on an upload file button which opens an open file window as shown:
My code uploads the files without interacting with the window. What I'm trying to do is close this window but am not sure how to go about doing this.
I've read various other posts with the similar problem but none I could find really gave me what I was looking for. I understand selenium can't access the window, and I've read I need a different module to interact with it. What would be the best way to do this?
In the end I was able to upload the item directly into the page by finding the upload button and sending it the file path.
driver.find_element_by_xpath("//*[#id='upl-fileInp']").send_keys("C:/Users/user/folder/file.jpg")
Workaround
You need put inside element of upload the root file. Don't open the upload by button, just insert /root/of/file/file.pdf inside input upload value using Javascript. Remember, that's my workaround... haha