Best practice with pyGTK and Builder XML files - python

I usually design GUI with Glade, thus producing a series of Builder XML files (one such file for each application window).
Now my idea is to define a class, e.g. MainWindow, that inherits from gtk.Window and that implements all the signal handlers for the application main window. The problem is that when I retrieve the main window from the containing XML file, it is returned as a gtk.Window instance.
The solution I have adopted so far is the following:
I have defined a class "Window" in the following way
class Window():
def __init__(self, win_name):
builder = gtk.Builder()
self.builder = builder
builder.add_from_file("%s.glade" % win_name)
self.window = builder.get_object(win_name)
builder.connect_signals(self)
def run(self):
return self.window.run()
def show_all(self):
return self.window.show_all()
def destroy(self):
return self.window.destroy()
def child(self, name):
return self.builder.get_object(name)
In the actual application code I have then defined a new class, say MainWindow, that inherits frow Window, and that looks like
class Main(Window):
def __init__(self):
Window.__init__(self, "main")
### Signal handlers #####################################################
def on_mnu_file_quit_activated(self, widget, data = None):
...
The string "main" refers to the main window, called "main", which resides into the XML Builder file "main.glade" (this is a sort of convention I decided to adopt).
So the question is: how can I inherit from gtk.Window directly, by defining, say, the class Foo(gtk.Window), and recast the return value of builder.get_object(win_name) to Foo?

Related

When changing screens with QStackedWidget, how to call a function in the changed screen?

I'm trying to call the init function of the screen I'm changing my screen index to
For an example, i have this code:
from PyQt5 import QtWidgets as qtw
from PyQt5 import QtGui as qtg
from sys import argv as sysArgv
from sys import exit as sysExit
arialLarge = qtg.QFont("Arial", 18)
class MainWindow(qtw.QWidget):
def __init__(self):
super().__init__()
# Current screen label;
mainWindowLabel = qtw.QLabel("This is the main window", self)
mainWindowLabel.setFont(arialLarge)
mainWindowLabel.move(20, 40)
# Button for going to the HelloWindow screen;
gotoHelloWindowButton = qtw.QPushButton("Go to hello window", self, clicked=lambda: appStack.setCurrentIndex(appStack.currentIndex()+1))
gotoHelloWindowButton.move(100, 100)
class HelloWindow(qtw.QWidget):
def __init__(self):
super().__init__()
# EG: print hello world when I visit this page
print("hello world")
# Current screen label;
helloWindowLabel = qtw.QLabel("This is the hello window", self)
helloWindowLabel.setFont(arialLarge)
helloWindowLabel.move(20, 40)
# Button for going to the MainWindow screen;
gotoMainWindowButton = qtw.QPushButton("Go to main window", self, clicked=lambda: appStack.setCurrentIndex(appStack.currentIndex()-1))
gotoMainWindowButton.move(100, 100)
if __name__ == "__main__":
app = qtw.QApplication(sysArgv)
appStack = qtw.QStackedWidget()
appStack.addWidget(MainWindow())
appStack.setFixedSize(300, 300)
appStack.show()
appStack.addWidget(HelloWindow())
sysExit(app.exec())
If im visiting the HelloWindow from the MainWindow, how can i run the init function of the HelloWindow screen so I can run whatever code I want in there?
I need to be able to do this as on the app im working on as on the mainpage i have dynamically created buttons that all have functions parameters with different indexes to my server, and i need to be able to fetch the data from server based off the clicked button's data index so on the other page I can view the desired data.
The __init__ of a python class is what is called when an instance is created (using SomeClass()), so you should not try (or even think) to call it again, as it could create serious problems and bugs that are hard to track.
I strongly suggest you to read the documentation about classes in Python, as you cannot ignore that aspect in object oriented programming.
If you need to call something everytime the index is changed, then you should better subclass QStackedWidget and control everything from there.
A good solution is to create a standardized function that will be called everytime the page is presented, and ensure that the stack widget correctly calls it.
class FirstPage(QtWidgets.QWidget):
def __init__(self):
super().__init__(self)
# ...
self.nextButton = QtWidgets.QPushButton('Next')
self.doSomething()
def doSomething(self):
...
class SecondPage(QtWidgets.QWidget):
def __init__(self):
super().__init__(self)
# ...
self.prevButton = QtWidgets.QPushButton('Previous')
self.doSomething()
def doSomething(self):
...
class Stack(QtWidgets.QStackedWidget):
def __init__(self):
super().__init__(self)
self.first = FirstPage()
self.first.nextButton.clicked.connect(self.goNext)
self.addWidget(self.first)
self.second = SecondPage()
self.second.prevButton.clicked.connect(self.goPrev)
self.currentChanged.connect(self.initCurrent)
def goNext(self):
self.setCurrentIndex(1)
def goPrev(self):
self.setCurrentIndex(0)
def initCurrent()
if self.currentWidget():
self.currentWidget().doSomething()
if __name__ == "__main__":
app = qtw.QApplication(sysArgv)
appStack = Stack()
appStack.setFixedSize(300, 300)
appStack.show()
sysExit(app.exec())
Note that adding a QMainWindow to a parent is not a good idea, as Qt main windows are intended to be used as top level windows; also note that using fixed geometries (positions and sizes) is often considered bad practice, and you should use layout managers instead.

Changed to options listed in PyQt4 combo_boxes defined in a different class not reflected

I am working on a small GUI project using PyQt4. I have defined one class (inside a separate file) defining the basic functionality of combo_boxes that I have to use and another class to use the functionality for all the combo_boxes.
The code looks something like
class core:
def __init__(self, default_value, window_name):
self.combo_box = QtGui.QComboBox(window_name)
self.combo_box.addItem(default_value)
self.combo_box.addItem("some other value")
self.combo_box.addItem("a third value")
self.combo_box.activated[str].connect(self.set_text)
self.text = default_value
def set_text(self, text):
print text
The main class is something like:
from file import *
class Window(QtGui.QMainWindow):
def __init__(self):
super(Window, self).__init__()
self.setGeometry(200, 100, 820, 700)
combo_box_one = core("first", self)
combo_box_two = core("second", self)
#some other methods follow defining the geometry for each combo_box and other functions
def main():
app = QtGui.QApplication(sys.argv)
gui = Window()
sys.exit(app.exec_())
main()
The GUI is working as expected. All the combo_boxes appear as per the defined geometry. However, when on selecting different options, nothing seems to happen. Ideally, I would expect the text on the option to be printed. In fact, when I return the combo_box object to the main class and set it connections there, the change in options is reflected. But when the same thing is done in the coreclass, the changes are not reflected as printed text. Is it a scope related thing? Please help me understand what's happening.
Slots can only be implemented in classes that inherit from QObject, a simple solution is that the core class inherits from QComboBox, since QComboBox inherits from QObject.
class core(QtGui.QComboBox):
def __init__(self, default_value, window_name):
QtGui.QComboBox.__init__(self, window_name)
self.addItem(default_value)
self.addItem("some other value")
self.addItem("a third value")
self.activated[str].connect(self.set_text)
def set_text(self, text):
print(text)

How to call a QWidget from another QWidget in PyQt

I am developping an application with PyQt based on a QWidget. I put my whole app inside a class (named "Example"). Inside this app, I have a button which calls to another QWidget window (named "Report Widget") I designed on QtDesigner and opens it.
The problem is that I don't know how to do this. Here is the method I use (which comes from something I found on internet).
On my main class "Example", a method defines the Button calling for the "Report Widget" :
ReportBtn = QtGui.QPushButton("Generate report")
ReportBtn.clicked.connect(self.ShowReportWidget)
The second line calls the ShowReportWidget method of the Example (main) class :
def ShowReportWidget(self):
self.f = QtGui.QWidget()
self.ReportWidget = ReportWidget(self.f)
self.ReportWidget.show()
This method calls the class ReportWidget, which is a class from the Example (main) class :
class ReportWidget(QtGui.QWidget):
def __init__(self, parent = None):
QtGui.QWidget.__init__(self)
self.ui = rw.Ui_ReportWidget()
self.ui.setupUi(parent)
and finally, this class refers to an outer class (Ui_ReportWidget), contained in another separate Python file (the one generated from the QtDesigner .ui file), which I import as rw in the beginning of my script.
The problem is that with this method, when I click on the Report Widget button, a new window pops but is empty. The content of the Ui_ReportWidget class is not loaded.
I hope my question is clear enough.
Thanks
SetupUi takes an Qwidget as input , while the init() function should take the calling QObject as the parent.
def ShowReportWidget(self):
self.f = QtGui.QWidget()
self.ReportWidget = ReportWidget(self)
self.ReportWidget.setupUi(self.f)
self.f.exec_()
class ReportWidget(QtGui.QWidget):
def __init__(self, parent = None):
QtGui.QWidget.__init__(self,parent)
def setupUi(self,Widget):
self.ui = rw.Ui_ReportWidget()
self.ui.setupUi(Widget)

How to connect to parent SIGNAL in PyQt?

I have a MainWindow that looks like this:
def __init__(self, parent = None):
QMainWindow.__init__(self, parent)
self.setupUi(self)
self.showMaximized()
menu=mainMenu.MainMenu()
classification=classificationMain.ClassificationMain()
self.stackedWidget.addWidget(menu)
self.stackedWidget.addWidget(classification)
self.stackedWidget.setCurrentWidget(menu)
self.stackedWidget.showFullScreen()
#connections
menu.pushButton.clicked.connect(self.showClassification)
classification.backButton.clicked.connect(self.showMainWindow)
def showClassification(self ):
self.stackedWidget.setCurrentIndex(3)
def showMainWindow(self):
self.stackedWidget.setCurrentIndex(2)
The MainWindows waits for signal from the rest of the dialogs. Now, the Classification dialog has another StackedWidget in it, since it works as a main window for an important part of the application. It looks like:
class ClassificationMain(QDialog, Ui_Dialog):
def __init__(self, parent = None):
QDialog.__init__(self, parent)
self.setupUi(self)
choose=choosePatient.ChoosePatient()
self.stackedWidget.addWidget(choose)
self.stackedWidget.setCurrentWidget(choose)
Now, I want to reload the data inside ChoosePatient every time the button "Show Classification" from MainMenu is clicked, but now the data is loaded only once in the line classification=classificationMain.ClassificationMain() of MainWindow.
I was thinking I had to connect a slot inside ChoosePatient with the click of "Show Classification" button inside MainMenu, but I would need an instance of MainMenu, which is not possible.
How can a method of ChoosePatient can be execute every time the button in the "parent" window is clicked? (also, please tell me if this is not the right way to work with pyqt windows)
You need to save references to your composed widgets, and also to expose some public methods to the parents:
class ClassificationMain(QDialog, Ui_Dialog):
def __init__(self, parent = None):
QDialog.__init__(self, parent)
self.setupUi(self)
self.chooseWidget=choosePatient.ChoosePatient()
self.stackedWidget.addWidget(self.chooseWidget)
self.stackedWidget.setCurrentWidget(self.chooseWidget)
def reloadPatients(self):
# whatever your operation should be on the ChoosePatient
self.chooseWidget.reload()
# MAIN WINDOW
def __init__(self, parent = None):
...
self.classification=classificationMain.ClassificationMain()
self.stackedWidget.addWidget(self.classification)
...
#connections
menu.pushButton.clicked.connect(self.showClassification)
def showClassification(self ):
self.stackedWidget.setCurrentIndex(3)
self.classification.reloadPatients()
You could also just skip the reloadPatients method and connect to the ChoosePatient directly if you want:
def showClassification(self ):
self.stackedWidget.setCurrentIndex(3)
self.classification.chooseWidget.reload()
My personal opinion is to make your custom classes wrap up the internal functionality nicely so that you only need to interface with it over the custom class, and not dig into its internals. That way you can change how it works inside without breaking the main window.

PyQt4 custom widget (uic loaded) added to layout is invisible

I've created a custom widget in pyqt4 that I've worked on and tested and now am ready to load it into my main window. Since it doesn't show up in designer, I need to manually add it to my main window manually.
My widget uses uic to load the ui file instead of converting it to a py file (it's been quicker less hassle so far) so it looks something like this:
class widgetWindow(QtGui.QWidget):
def __init__(self, parent = None):
super(widgetWindow, self).__init__(parent)
self.ui = uic.loadUi("widget.ui")
#everything else
now in my main class (example for brevity) I create the layout, add the widget to the layout and then add it to the main widget
class main(QtGui.QMainWindow):
def __init__(self, parent = None):
super(main, self).__init__(parent)
self.ui = uic.loadUi("testWindow.ui")
mainlayout = QtGui.QVBoxLayout()
window = widgetWindow(self)
mainlayout.addWidget(window)
centerWidget = QtGui.QWidget()
centerWidget.setLayout(mainlayout)
self.ui.setCentralWidget(centerWidget)
There are no errors thrown, and it will make space for the widget, but it simply won't show anything.
adding in the line window.ui.show() will just pop open a new window overtop the space that it should be occupying on the main window. What am I missing?
Doing some more research into the uic loader, there are two ways to load a ui file. The way I'm using it in the question is one way, the other way is with the uic.loadUiType(). This creates both the base class and the form class to be inherited by the class object instead of just the QtGui.QWidget class object.
widgetForm, baseClass= uic.loadUiType("addTilesWidget.ui")
class windowTest(baseClass, widgetForm):
def __init__(self, parent = None):
super(windowTest, self).__init__(parent)
self.setupUi(self)
This way, the widget can be loaded into another form as expected. As for exactly why, I haven't found that answer yet.
Some more info on the different setup types: http://bitesofcode.blogspot.com/2011/10/comparison-of-loading-techniques.html
Try to add the parent argument into the loadUi statements:
self.ui = uic.loadUi("widget.ui",parent)
self.ui = uic.loadUi("testWindow.ui",self)
And try the following line at the end of your main class.
self.setCentralWidget(centerWidget)
You need to specify that 'centerWidget' is the central widget of the main window.
i.e your code for class main should be have a line like:
self.setCentralWidget(centerWidget)
class main(QMainWindow):
def __init__(self, parent = None):
super(main, self).__init__(parent)
....
self.setCentralWidget(centerWidget)

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