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Send Reply to email thread

I'm trying to reply to an email based on the following criteria:
Scan the inbox for unseen mails with specific Subject content, if there is mails that satisfy those criteria then: send back an reply message to the sender saying "something", if those criteria are not met then: send back an reply message to the sender saying "something".
This is what i came up with so far:
import imaplib
import email
import smtplib
username = 'sample#gmail.com'
password = 'xxxx'
imap_server = imaplib.IMAP4_SSL('smtp.gmail.com')
imap_server.login(username, password)
imap_server.select('INBOX')
result, data = imap_server.search(None, '(UNSEEN)')
email_ids = data[0].split()
for email_id in email_ids:
result, data = imap_server.fetch(email_id, "(RFC822)")
raw_email = data[0][1]
email_message = email.message_from_bytes(raw_email)
subject = email_message["Subject"]
if subject == "SOME SPECIFIC CONTENT":
reply = email.message.EmailMessage()
reply["To"] = email_message["From"]
reply["Subject"] = "Re: " + email_message["Subject"]
reply["In_Reply-To"] = email_message["From"]
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login(username, password)
server.sendmail(username, reply["In_Reply-To"], 'Subject: Criteria met\n\nThank you.')
server.quit()
else:
reply = email.message.EmailMessage()
reply['To'] = email_message['From']
reply['Subject'] = "RE:" + email_message['Subject']
reply["In_Reply-To"] = email_message["From"]
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login(username, password)
server.sendmail(username, reply["In_Reply-To"], 'Subject: Criteria not met\n\Thank you.')
print('Sending email')
server.quit()
imap_server.close()
It sends the email but without the desired thread, just sends a new email and not actually replying back to the sender.
Any suggestion on how to modify the code so it actually send an reply with the desired thread?
Thank you in advance.

Like the comment mentions, you should use the Message-Id of the original message, not the sender address.
Also, you should obey Reply-To: and add References:.
reply = email.message.EmailMessage()
reply["To"] = email_message["Reply-To"] or email_message["From"]
reply["Subject"] = "Re: " + email_message["Subject"]
reply["In_Reply-To"] = email_message["Message-Id"]
reply["References"] = (email_message["References"] or "") + " " + email_message["Message-Id"]
Properly speaking, the References: header should be trimmed from the middle if it's too long.
Some vendors have their own nonstandard threading extensions; in particular, Microsoft's Thread-Id: etc headers are probably best ignored.

Python Email Notification Not Sending

This code is supposed to send an email to a specified address and when I hard code the "TEXT" & "SUBJECT" it seems to send fine but when I create it as a function and call it it never sends the email and never prints the "Notification Sent" message. What am I missing?
Tried hard coding the TEXT and SUBJECT and it sends fine! NOTE: YOU MUST ENABLE LESS SECURE APPS WHEN USING GMAIL!
import smtplib
class email_thing:
def email_notification(self,SUBJECT,TEXT):
TO = 'email#example.com'
self.SUBJECT = SUBJECT
self.TEXT = TEXT
gmail_sender = 'email#example.com'
gmail_passwd = 'examplepassword'
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login(gmail_sender, gmail_passwd)
return self.SUBJECT
return self.TEXT
BODY = '\r\n'.join(['To: %s' % TO,
'From: %s' % gmail_sender,
'Subject: %s' % SUBJECT,
'',TEXT])
try:
server.sendmail(gmail_sender, [TO], BODY)
print ('Notification Sent!')
except:
print ('error sending mail')
server.quit()
test_send = email_thing()
test_send.email_notification(SUBJECT ='Test Email',TEXT = 'This is a test from python!')

Remove
return self.SUBJECT
return self.TEXT
return exits method at once so code after return is never executed.

In python's smtplib why isn't the subject or From field set?

can anyone see why the following code sends emails successfully but it shows up as being from the email address of the sender instead of the name of the sender in the recipients inbox, and the subject shows up as "No Subject" in their inbox. Thanks in advance.
def send_email(destination, subject, message):
from_who = "My Name"
to_send = """\From: %s\nTo: %s\nSubject: %s\n\n%s""" % (from_who, destination, subject, message)
try:
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(my_email_addr, my_pwrd)
server.sendmail(from_who, destination, message)
server.close()
except:
print "failed"

If you want to use SMTP in python, you need to send the data as a dictionary.
from email.parser import Parser
# This will parse out your to-, from-, and subject fields automatically
headers = Parser().parsestr(to_send)
# This will take care of the to- and from-fields for you
server.send_message(headers)
test.py
from email.parser import Parser
from_whom = "hello#example.com"
destination = "world#example.com"
subject = "Foobar!"
message = "Bar bar binks"
to_send = """From: %s\nTo: %s\nSubject: %s\n\n%s""" % (from_whom, destination, subject, message)
print(to_send)
headers = Parser().parsestr(to_send)
print(headers["To"]) # world#example.com
print(headers["From"]) # hello#example.com
print(headers["Subject"]) # Foobar!
EDIT
Alternatively, you could do this:
to_send = string.join((
"From: %s" % from_whom,
"To: %s" % destination,
"Subject: %s" % subject,
"",
message
), "\r\n")
# ...
server.sendmail(from_whom, [destination], to_send)
# ...
I think the other way is cleaner, but this is up to you.

Python Include contents of If/else in output not just print

I am not that experienced with python, but do some python coding for small jobs. Currently I have a job that opens a log file and pulls any records that are considered errors. This list of errors is then added as part of an email notification. What I would like to do is either include the list or a notification that the list was empty. I have been able to do this in the console, but don't know how to get this added as a parameter in the email.
if errorlist:
print "\n".join(errorlist)
else:
print "No Errors Found"
# Send Email
SMTP_SERVER = {SMTP SERVER}
SMTP_PORT = {SMTP PORT}
sender = {Sender}
password = {Password}
recipient = {Recipient}
subject = "This is the subject line"
errorlist = "<br>" "\n".join(errorlist)
body = "" + errorlist + ""
headers = ["From: " + sender,
"Subject: " + subject,
"To: " + ", " .join(recipient),
"MIME-Version: 1.0",
"Content-Type: text/html"]
headers = "\r\n".join(headers)
session = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)
session.ehlo()
session.starttls()
session.ehlo
session.login(sender, password)
session.sendmail(sender, recipient, headers + "\r\n\r\n" + body)
session.quit()

The email is sent in this line:
session.sendmail(sender, recipient, headers + "\r\n\r\n" + body)
The body variable contains the body of your email. In order to add something into the body of the email, it should be added to the string contained by the body variable. Adapting the code you already have added (which successfully prints your desired result), you could replace this line:
body = "" + errorlist + ""
with this:
if errorlist:
body = "\n".join(errorlist)
else:
body = "No Errors Found"

if errorlist:
error_string = "\n".join(errorlist) # assign it to variable
print (error_string) # still print it
else:
error_string = "" # assign blank to error_string
print ("No Errors Found") # still print "no errors found"
.
.
.
body = ""+error_string+"" # 'body = error_string' is the same though
.
.
.
session.sendmail(sender, recipient, headers + "\r\n\r\n" + body) # this line you could replace "body" with "error_string" because they are pretty much goign to be equivilant because of the previous comment
You want to assign your error string into a variable, and then use the variable later when constructing the body. Also there is more room for simplification

SMTP sent mail to many recipients but doesn't received it

I've written a Python script to automatically send some information to my friends. I used SMTPlib, it works well if I only sent to me or one additional email.
When I try to send to 17 emails, (including my sender email), then it shows in sent mail on web-based Gmail. I saw that the mail was sent but I didn't receive it. Only the first recipient received the email.
If I reply to all from that mail, then everyone got only that reply.
I can't figure out why they didn't receive it when I sent it from script, I ask my friend check spam, but she didn't find anything.
This is my code:
#!/usr/bin/env python
import smtplib
import csv
from datetime import datetime, timedelta
SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587
sender = 'MYBOT#gmail.com'
password = None
with open('pass', 'rt') as f:
password = f.read().strip('\n')
def send_mail(recipient, subject, body):
"""
Send happy bithday mail
"""
headers = ["From: " + sender,
"Subject: " + subject,
"To: " + recipient,
"MIME-Version: 1.0",
"Content-Type: text/html"]
headers = "\r\n".join(headers)
smtp = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)
smtp.ehlo()
smtp.starttls()
smtp.ehlo
smtp.login(sender, password)
body = "" + body +""
smtp.sendmail(sender, recipient, headers + "\r\n\r\n" + body)
print "Sent to ",
print recipient
smtp.quit()
def send_happybirthday(recipient):
body = """Happy birthday to you!
\n<br/>From C2k8pro with love
"""
subject ='[BirthReminder] Happy birthday to you! from C2k8pro'
send_mail(recipient, subject, body)
def send_notification(all_mails, names):
body = """Tomorrow is birthday of %s""" % names
send_mail(all_mails, body, body)
def test_send_mail():
notify_body = """Tomorrow is birthday of """
recipients = ['MYBOT#gmail.com']
today = datetime.now()
format = "%d-%m-%Y"
print today
today_in_str = datetime.strftime(today, format)
def read_csv():
FILENAME = 'mails.csv'
reader = csv.reader(open(FILENAME, 'rt'), delimiter=',')
today = datetime.now()
one_day = timedelta(days=1)
tomorrow = today + one_day
all_mails = []
str_format = "%d/%m"
str_today = today.strftime(str_format)
str_tomorrow = tomorrow.strftime(str_format)
print 'Today is ', str_today
tomorrow_birth = []
for row in reader:
name = row[1].strip()
dob = row[2]
dmy = dob.split("/")
mail = row[3]
all_mails.append(mail)
#TODO fix dob with only 1 digit
birth_date = dmy[0] + "/" + dmy[1]
if str_today == birth_date:
print 'Happy birthday %s' % name
try:
send_happybirthday(mail)
except Exception, e:
print e
elif str_tomorrow == birth_date:
tomorrow_birth.append(name)
print "Tomorrow is %s's birthday" % name
# Remove empty string
all_mails = filter(None, all_mails)
print 'All mails: ', len(all_mails)
str_all_mails = ', '.join(all_mails)
if tomorrow_birth:
all_tomorrow = ', '.join(tomorrow_birth)
send_notification(str_all_mails, all_tomorrow)
def main():
read_csv()
if __name__ == "__main__":
main()
Can anyone explain this. Thanks!

I found solution from here
Send Email to multiple recipients from .txt file with Python smtplib
I passed a string contain all recipients separated by comma to msg['To'] and sendmail().
It's true for msg['To'] but with sendmail, I have to use a list.