Value Error: invalid literalfor int() with base 10: ' ' - python

Ok guys, I am using python to try to complete a task. In short, I need to read in a number from a text file that can be thousands of digits long. I'm getting this error as I try to take the digits from the string and cast them to integers so I can do some math with them.
of = open("input.txt","r")
counter = 0
big=0
of.seek(0,0)
while True:
temp = of.read(5)
if temp=="":
break
else:
a=int(temp[0])
b=int(temp[1])
c=int(temp[2])
d=int(temp[3])
e=int(temp[4])
if a*b*c*d*e>big:
big = a*b*c*d*e
counter+=1
of.seek(counter,0)
print big
of.close()
I'm really stuck on this one so any help much appreciated.
Thanks in advance.
EDIT==============================================================
After tinkering around a bit I finally got the code to run correctly. Here's what I ended with:
x = int(open("input.txt","r").read())
y = str(x)
big = 0
for i in range(0,len(y)-5):
a = int(y[i])
b = int(y[i+1])
c = int(y[i+2])
d = int(y[i+3])
e = int(y[i+4])
if a*b*c*d*e>big:
big = a*b*c*d*e
print big
thanks for the help

Python supports long integers so if the file is just one big integer you can read it like this:
bignum=int(open("input.txt","r").read())

Your indentation is wrong; if-else should be nested inside the while loop.

Related

itertools.product for the full range of columns

as a part of my code, I'm trying to get a full factorial matrix, this is not a problem since I already have a working code for it. However, I would like to generalize it in a way that it wouldn't matter the number of inputs. This would require modifying the line:
for combination in itertools.product(X[0,:],X[1,:],X[2,:],X[3,:],X[4,:],X[5,:],X[6,:]):
input_list = dfraw.columns[0:n_inputs]
output_list = dfraw.columns[n_inputs:len(dfraw.columns)]
fflvls = 4
lhspoints = 60000
X = np.zeros((n_inputs, fflvls),float)
ii=0
for entrada in input_list:
X[ii] = np.linspace(min(dfraw[entrada]), max(dfraw[entrada]), fflvls)
ii+=1
number=1
i=0
X_fact=np.zeros((int(fflvls**n_inputs),n_inputs),float)
for combination in itertools.product(X[0,:],X[1,:],X[2,:],X[3,:],X[4,:],X[5,:],X[6,:]):
X_fact[i,:] = (combination)
i +=1
number+=1
I thought of writing the input of itertools.product as a string with a loop and then evaluating but it doesn't work and I've also seen it is regarded as bad practice
prodstring = ['X[0,:]']
for ii in range(n_inputs):
prodstring.append(',X[%d,:]'%(ii))
in_products = ''.join(prodstring)
for combination in itertools.product(eval(in_products)):
X_fact[i,:] = (combination)
i +=1
number+=1
what other way is there to inputing the full range of columns in this function? (or similar ones)
who said working harder is working better? im back from lunch and I delved into *args and **kwargs as a form of procrastination cause ive sometimes seen them mentioned and i was curious. It seems like it was just the tool I needed. In case this can help other code rookies like me in the future:
args = ()
for ii in range(n_inputs):
b = (X[ii,:])
args += (b,)
for combination in itertools.product(*args):
X_fact[i,:] = (combination)
i +=1
number+=1
Seems to work properly. Solved in an hour of "not working" what i haven't solved in approx 4 hours of "working"

How to insert a variable into an "input" function

I want show two variables in a prompt line in Python as this:
a = 35
b = 11
captcha = int(input(a, '+', b '='))
It must looks like:
35 + 11 =
The terminal say there is a SyntaxError. Can someone fix my syntax please? Thanks!
You've got two problems.
You miss the third comma to separate b and =.
Then input takes only one argument. If you try and concatenate strings in a function, python will think you are trying to add multiple arguments. Try using f-strings instead.
captcha = int(input(f'{a} + {b} ='))
Try an f string:
captcha = int(input(f'{a} + {b} = '))
Here's a simpler way to do what you are trying to do:
captcha = int(input(f"{a}+{b}="))

Can I make python read a string as a parameter?

I would like to make this code somehow work, in this example i used the int() function which obviously gave me the "invalid literal for int() with base 10" error. But is there any way to make python not read the "" around the string and just read "i" in this case as a parameter.
I hope you understand what I mean.
s=0
w=""
for k in range(3):
w+="i"
for i in range(5):
s+=int(w)
I donĀ“t know whats your expected result. Your main problems seems the quotes for w = "" and w+="i" if you want to add numbers instead of textstrings.
Maybe you also mixed up your k and i variable.
Is this your expected result(?):
s = 0
w = 0
for k in range(3):
w += k
for i in range(5):
s += w
print(s)
print(w)
In your current version of code, when you say int(w) you are trying to convert 'iii' into a base 10 number which runs the error. Also, using i as a variable will only work within the for loop 'for i in range(5):'. That is where the variable i has its lifespan.

How to export int to "txt" file and then at a later date be able to import them back as int 's

Exporting the data:
num = 0
exportData = open("results_file.txt", "a")
while num < len(runs) - 1:
exportData.write(str(runs[num]) + "\n")
num = num + 1
exportData.close()
Importing the data into the new file:
runs = []
num = 1
count = len(open("results_file.txt").readlines( ))
print(count)
importData = open("results_file.txt", "r")
while num < count:
runs.append(importData.read(num))
print(importData.read(num))
num = num + 1
importData.close()
My goal is to export the array of integers to a file (can be something else than a txt file for all I care) and then to import them at a later date into a new file and use them there as integers (performing mathematical operations on them)
The error that I'm getting (on line 28 I'm trying to use the first number in the array for a mathematical calculation):
line 28, in if runs[num] < 7: TypeError: '<' not supported between instances of 'str' and 'int'
runs = []
num = 1
count = len(open("results_file.txt").readlines( ))
print(count)
importData = open("results_file.txt", "r")
while num < count:
runs.append(int(importData.read(num)))
print(importData.read(num))
num = num + 1
importData.close()
Adding int() returns this error:
ValueError: invalid literal for int() with base 10: '4\n1'
You're not being pythonic, and many of the answers here aren't either. So, let me clean up your code a bit.
from ast import literal_eval
with open("results_file.txt", "a") as exportData:
for run in runs:
exportData.write(str(run) + "\n")
runs = []
with open("results_file.txt", "r") as importData:
runs.extend([literal_eval(x) for x in importData])
I'll break this down line by line:
from ast import literal_eval is the safest way to parse things that are strings into python objects. It's better than using a plain old eval because it won't run arbitrary code. We'll use this function to read the data latter.
with open(...) as ... is the best way to open a file. It contains the file-object within a single scope and catches errors. Look this one up here: Pep 343
for ... in ... For loops that you're using are not pythonoic at all. The pythonic way is to use iterators no need to count lines and declare variables to keep track... the python objects keep track of themselves. (If you need a counter I highly recommend that you look up enumerate() Enumerate() in Python
exportData.write(str(run) + "\n") only change here is that with the pythonic for loop there's no need to index the runs list anymore.
runs = [] I think you know what this is, but I have to declare it out of the with statement because if the with statement throws an error, and you were to catch it, runs will be initialized.
I've already discussed with statements.
runs.extend([literal_eval(x) for x in importData]) Has two things going on. extend appends a list to a list... cool. The more interesting part here is the list comprehension. Here's a tutorial on list comprehensions. As soon as you get comfortable with the for loops, the list comprehension is the next pythonic step. For further pythonic enlightenment, this line could also be replaced with: runs.extend(map(literal_eval, importData))
That's it, 9 lines. Happy hacking.
The error you are experiencing is most likely due to the fact you're trying to add a string to an integer. Try doing
runs = []
num = 1
count = len(open("results_file.txt").readlines( ))
print(count)
importData = open("results_file.txt", "r")
while num < count:
runs.append(int(importData.read(num)))
print(importData.read(num))
num = num + 1
importData.close()
The main function/tool you're looking for is int(). For example:
>>> int('15')
15
>>> int('15') + 5
20
But you also can save yourself some real headaches by coding this differently. For example, you do not need to know the number of lines ahead of time. You can just call .readline() until it returns an empty string. Or even iterate over the file and when it ends, it with exit.
Another tip, and this is just good practice, is to use the context manager for opening files. So instead of
file = open('myfile.txt')
for line in file:
print(line)
you would do:
with open('myfile.txt') as file:
for line in file:
print(line)
The big advantage of the latter is that if will always make sure file is closed properly. This is especially helpful when writing to a file.

Cannot set an array element with a sequence

I'm using the NumPy python library to run large-scale edits on a .csv file. I'm using this python code:
import numpy as np
def main():
try:
e,a,ad,c,s,z,ca,fn,ln,p,p2,g,ssn,cn,com,dob,doh,em = np.loadtxt('c:\wamp\www\_quac\carryover_data\SI\Employees.csv',delimiter=',',unpack=True,dtype='str')
x=0
dob = dob.split('/')
for digit in dob:
if len(digit) == 1:
digit = str('0'+digit)
dob = str(dob[2]+'-'+dob[0]+'-'+dob[1])
doh = doh.split('/')
for digit in doh:
if len(digit) == 1:
digit = str('0'+digit)
doh = str(doh[2]+'-'+doh[0]+'-'+doh[1])
for eID in e:
saveLine=eID+','+a[x]+','+ad[x]+','+c[x]+','+s[x]+','+z[x]+','+ca[x]+','+fn[x]+','+ln[x]+','+p[x]+','+p2[x]+','+g[x]+','+ssn[x]+','+cn[x]+','+com[x]+','+dob[x]+','+doh[x]+','+em[x]+'\n'
saveFile = open('fixedEmployees.csv','a')
saveFile.write(saveLine)
saveFile.close()
x+=1
except Exception, e:
print str(e)
main()
dob and doh contain a string, e.g. 4/26/2012 and I'm trying to convert these to mysql friendly DATE forms, e.g. 2012-04-26. The error that is printed when I run this script is
cannot set an array element with a sequence
It does not specify a line and so I don't know what this really means. I'm pretty new to python; I've checked other questions with this same error but I can't make sense of their code. Any help is very appreciated.
Try using zfill to reformat the date string so you can have a '0' before your '4'. (zfill pads a string on the left with zeros to fill the width.)
doh = '4/26/2012'
doh = doh.split('/')
for i, s in enumerate(doh):
doh[i] = s.zfill(2)
doh = doh[2]+'-'+doh[0]+'-'+doh[1]
# result: '2012-04-26'
As for the cannot set an array element with a sequence it would be helpful to know
where that is occurring. I'm guessing there is something wrong with structure of the array.
Ok, to solve it I had to do a couple things. After removing the try-except commands, I found out that the error was on line 5, the line with e,a,ad,c,s etc. I couldn't eliminate the problem until I simply copied the 2 columns I wanted to focus on only and made a new program for dealing with those.
Then I had to create a .txt instead of a .csv because Excel auto-formats the dates and literally changes the values before I can even touch them. There is no way around that, I've learned. You can't turn the date-auto-format off. A serious problem with excel. So here's my solution for this NumPy script (it changes the first column and keeps the second the same):
import numpy as np
def main():
dob,doh=np.loadtxt('temp.csv',
delimiter=',',
unpack=True,
dtype='str')
x=0
for eachDate in dob:
if any(c.isalpha() for c in eachDate):
newDate=eachDate
elif (eachDate == ''):
newDate=''
else:
sp = eachDate.split('/')
y=0
ndArray = ['','','']
for eachDig in sp:
if len(eachDig) == 1:
eachDig = str('0'+eachDig)
if y == 0:
ndArray[0] = eachDig
elif y == 1:
ndArray[1] = eachDig
elif y == 2:
ndArray[2] = eachDig
newDate=str(ndArray[2]+'-'+ndArray[0]+'-'+ndArray[1])
y=0
y+=1
print eachDate+'--->'+newDate
"""creates a .txt file with the edited dates"""
saveLine=str(newDate+','+doh[x]+'\n')
saveFile=open('__newTemp.txt','a')
saveFile.write(saveLine)
saveFile.close()
x+=1
main()
I then used Data->Import from text with "TEXT" format option in Excel to get the column into my .csv. I realize this is probably bulky and noobish but it got the job done :3

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