I've looked all around Google and its archives. There are several good articles, but none seem to help me out. So I thought I'd come here for a more specific answer.
The Objective: I want to run this code on a website to get all the picture files at once. It'll save a lot of pointing and clicking.
I've got Python 2.3.5 on a Windows 7 x64 machine. It's installed in C:\Python23.
How do I get this script to "go", so to speak?
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WOW. 35k views. Seeing as how this is top result on Google, here's a useful link I found over the years:
http://learnpythonthehardway.org/book/ex1.html
For setup, see exercise 0.
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FYI: I've got zero experience with Python. Any advice would be appreciated.
As requested, here's the code I'm using:
"""
dumpimages.py
Downloads all the images on the supplied URL, and saves them to the
specified output file ("/test/" by default)
Usage:
python dumpimages.py http://example.com/ [output]
"""
from BeautifulSoup import BeautifulSoup as bs
import urlparse
from urllib2 import urlopen
from urllib import urlretrieve
import os
import sys
def main(url, out_folder="C:\asdf\"):
"""Downloads all the images at 'url' to /test/"""
soup = bs(urlopen(url))
parsed = list(urlparse.urlparse(url))
for image in soup.findAll("img"):
print "Image: %(src)s" % image
filename = image["src"].split("/")[-1]
parsed[2] = image["src"]
outpath = os.path.join(out_folder, filename)
if image["src"].lower().startswith("http"):
urlretrieve(image["src"], outpath)
else:
urlretrieve(urlparse.urlunparse(parsed), outpath)
def _usage():
print "usage: python dumpimages.py http://example.com [outpath]"
if __name__ == "__main__":
url = sys.argv[-1]
out_folder = "/test/"
if not url.lower().startswith("http"):
out_folder = sys.argv[-1]
url = sys.argv[-2]
if not url.lower().startswith("http"):
_usage()
sys.exit(-1)
main(url, out_folder)
On windows platform, you have 2 choices:
In a command line terminal, type
c:\python23\python xxxx.py
Open the python editor IDLE from the menu, and open xxxx.py, then press F5 to run it.
For your posted code, the error is at this line:
def main(url, out_folder="C:\asdf\"):
It should be:
def main(url, out_folder="C:\\asdf\\"):
Usually you can double click the .py file in Windows explorer to run it. If this doesn't work, you can create a batch file in the same directory with the following contents:
C:\python23\python YOURSCRIPTNAME.py
Then double click that batch file. Or, you can simply run that line in the command prompt while your working directory is the location of your script.
Since you seem to be on windows you can do this so python <filename.py>. Check that python's bin folder is in your PATH, or you can do c:\python23\bin\python <filename.py>. Python is an interpretive language and so you need the interpretor to run your file, much like you need java runtime to run a jar file.
use IDLE Editor {You may already have it} it has interactive shell for python and it will show you execution and result.
Your command should include the url parameter as stated in the script usage comments.
The main function has 2 parameters, url and out (which is set to a default value)
C:\python23\python "C:\PathToYourScript\SCRIPT.py" http://yoururl.com "C:\OptionalOutput\"
If you want to run .py files in Windows, Try installing Git bash
Then download python(Required Version) from python.org and install in the main c drive folder
For me, its :
"C:\Python38"
then open Git Bash and go to the respective folder where your .py file is stored :
For me, its :
File Location : "Downloads"
File Name : Train.py
So i changed my Current working Directory From "C:/User/(username)/" to "C:/User/(username)/Downloads"
then i will run the below command
" /c/Python38/python Train.py "
and it will run successfully.
But if it give the below error :
from sklearn.model_selection import train_test_split
ModuleNotFoundError: No module named 'sklearn'
Then Do not panic :
and use this command :
" /c/Python38/Scripts/pip install sklearn "
and after it has installed sklearn go back and run the previous command :
" /c/Python38/python Train.py "
and it will run successfully.
!!!!HAPPY LEARNING !!!!
Related
I'm trying to download files from a site using the wget module.
The code is really simple:
image = 'linkoftheimage'
wget.download(image)
This works fine, but it saves the file in the folder with the python script. My goal is to download it in a different folder, but I can't find a way to specify it.
I tried a different approach with os module .
os.system(f'wget -O {directory} {image}')
This metod gives me an error: sh: -c: line 0: syntax error near unexpected token `('
So I tried another method:
with open(f'{directory}/photo %s.jpg' %a,'wb') as handler:
handler.write(image)
This also didn't worked out.
Does anyone have an idea on how could I solve this?
the package you specified has not been updated since 2015, it's repository is gone and so should probably be avoided. you can download files using the built-in requests module like so:
import requests
image_url = 'https://www.fillmurray.com/200/300'
file_destination = 'desired/destination/file.jpg'
res = requests.get(image_url)
if res.status_code == 200: # http 200 means success
with open(file_destination, 'wb') as file_handle: # wb means Write Binary
file_handle.write(res.content)
import subprocess
import os
....
....
opn=open(ak,'w')
tt=txt.get(1.0,END)
opn.write(tt)
lst=[]
for i in range(0,len(ak)):
if ak[i]=='/':
lst.append(i)
else:
pass
val=lst[-1]+1
path=ak
file_name=path[val:]
sudo_path_name=path[3:val-1]
dir_name=path[:2]
path_name="cd "
for i in sudo_path_name:
if i=='/':
path_name+='\\'
else:
path_name+=i
command=dir_name+'&&'+path_name+'&&'+file_name
os.system(command)
output = subprocess.getoutput(command)
print(output)
ak is path of a file
My aim is just print the output when ak execute..
But whenever I tried to execute it give output as
The system cannot find the path specified.
The system cannot find the path specified.
When i get command and run with commmand prompt it executes successfully with no error..
Thank You
This depends on the editor. It happened to me too I used VS-code but when I changed cwd it worked! So it may be that problem.
Also try putting the full path or try this code:-
from pathlib import Path
import os
os.chdir(Path(__file__).parent)
I have a URL which is a download link to a software .exe file.
The intended operation is to use Python 3 to download the said file and then do a silent installation.
import ssl
from urllib.parse import urlparse
import requests
#convert to string
url = str(url)
#convert ftp download path to http and remove chars to make it downloadable
httpurl = re.sub("ftp://","https://",url)
print("url is: " + url)
#function to break file name from the full path
def split(downloadurl):
p,downloadexename = os.path.split(downloadurl)
return [downloadexename]
#Remove all the unnecessary stuff you don't need
downloadurl = httpurl.replace("'","").replace(',','').replace(":2100/FTP Folders/Software","").replace(" ","%20").strip("(").strip(")")
print("Download URL is: "+downloadurl)
down_name = os.path.basename(downloadurl)
down_dir = r"C:\Desktop"
#Create folder if it doesn't exist for download as required
if not os.path.exists(down_dir):
os.makedirs(down_dir)
full_path = os.path.join(down_dir, down_name)
# Silent Install
subprocess.call([full_path, '/Silent'], shell=True)
It depends on what kind of installer the .exe is, but there is a high chance it already has the ability to install silently. For example, InnoSetup installers (a very common type) use the parameter /SILENT. If you don't know the installer type, you may try running the .exe with different variants of /s, /S, /SILENT etc. -- or some variants of /?, --help to show command line usage.
I have a problem with converting docx to pdf files in my script.
At first I tried to use a pure php-based solution, described here:
https://stackoverflow.com/a/20035739/12812601
Unfortunatelly this does not work (it creates an empty com object, then throws a fatal error).
So I've tried to use a python script to do this.
I use a great script from here:
https://stackoverflow.com/a/20035739/12812601
So here is a problem.
The Python script standalone (run via a command line) works just fine, and saves the converted pdf. Unfortunatelly when I try to call it via PHP it can't save a converted file.
PHP scripts can create and write files oin the same directory without any problem
This supposed to be a local configuration, so I do not care about any portability
Scripts:
*******PHP*******
<?php
//Script only for testing Python calls, tried different methods
error_reporting(E_ALL);
echo '<h1>Begin</h1>';
echo '<h2>Before call</h2>';
exec ('python dp.py');
echo '<h2>After exec call</h2>';
system('python dp.py');
echo '<h2>After Sys Call</h2>';
passthru('python dp.py');
echo '<h2>After Pass Call</h2>';
$w = get_current_user();
var_dump($w);
?>
*****Python*****
import sys
import os
import comtypes.client
import win32com.client
wdFormatPDF = 17
#static file names for testing
in_file = 'C:\\Users\\fake_user\\OneDrive\\Stuff\\f1.docx'
out_file = 'C:\\Users\\fake_user\\OneDrive\\Stuff\\f3.pdf'
print('BEGIN<br>\n')
word = win32com.client.Dispatch('Word.Application')
word.Visible = False
doc = word.Documents.Open(in_file)
print('\nOpened Docx\n<br>')
print(in_file);
doc.SaveAs(out_file, FileFormat=wdFormatPDF)
print('\nSaved\n<br>')
doc.Close()
word.Quit()
print('DONE\n')
*****Output from the browser*****
Begin
Before call
After exec call
BEGIN
Opened Docx
C:\Users\fake_user\OneDrive\Stuff\f1.docx
After Sys Call
BEGIN
Opened Docx
C:\Users\fake_user\OneDrive\Stuff\f1.docx
After Pass Call
string(5) "fake_user"
System configuration
Windows 7 Professional Edition Service Pack 1
Apache/2.4.26 (Win32)
OpenSSL/1.0.2l
PHP/7.1.7
Python 3.8.1
I tried to run Apache both as a system service and as a user who owns the OneDrive (name changed to "fake_user" here), so it shouldn't be a permissions issue (I think)
Any help appreciated
I have a web server with CGI script calling python scripts.
When i try to execute in a main file (test1.py) another script called via
os.system('/var/www/cgi-bin/readIRtemp.py '+arg1+' '+arg2+' '+arg3)
I get his error message in /var/log/apache2/error.log :
import: not found
from: can't read /var/mail/jinja2
this is understandable for me since when called directly from the python console my script works !
its content is:
import sys, os
from jinja2 import Environment, FileSystemLoader, select_autoescape
last20values=sys.argv[1]
currTempInDegreesCelcius=sys.argv[2]
print('test '+last20values+' '+currTempInDegreesCelcius)
env = Environment(
loader=FileSystemLoader('/var/www/html/templates'),
autoescape=select_autoescape(['html', 'xml'])
)
template = env.get_template('IR.html')
updatedTemplate=template.render( arrayOfTemp = last20values, currTemp=currTempInDegreesCelcius)
Html_file=open("/var/www/html/IR.html","w")
Html_file.write(updatedTemplate)
Html_file.close()
I read somewhere something like maybe when calling os.system() the script is running with a different user account or some crazy things like that ... please help!
of course i chmod 777 * everything but that doesnt help ...