Is there a direct equivalent to httplib.HTTPConnection() in httplib2 - python

I'm trying to get rid of an exception HTTPException('ApplicationError: 5 ',) I get when using httplib in a python27 API (running on google appengine) - further detailed in this post ApplicationError2 and ApplicationError5 when communicating with external api from AppEngine . I thought that I could perhaps instead try using httplib2. The only part of the API which makes a call to httplib that I can see is:
def _get_conn(self):
return httplib.HTTPConnection(str(self.host), str(self.port), timeout=120)
Is there a direct equivalent to httplib.HTTPConnection() in httplib2? I've had a search but cannot find anything.

It seems there is, see AppEngineHttpConnection in http2 source code.
However, AFAIK those are not part of the official httplib2 API as shown in their documentation, you'd rather do something like:
import httplib2
h = httplib2.Http()
resp, content = h.request("http://bitworking.org/")
assert resp.status == 200
assert resp['content-type'] == 'text/html'
Have you considered using Request library, it is getting a lot of good press recently.

Related

Accesing ASANA data using python requests

First of all, I'm not a Python guru as you can probably tell... So here we go.
I'm trying to use Asana's API to pull data with Python requests (Projects, tasks, etc) and doing the authentication using Oauth 2.0... I've been trying to find a simple python script to have something to begin with but I haven't had any luck and I can't find a decent and simple example!
I already created the app and got my client_secret and client_secret. But I don't really know where or how to start... Could anybody help me please?
import sys, os, requests
sys.path.append(os.path.dirname(os.path.dirname(__file__)))
import asana
import json
from six import print_
import requests_oauthlib
from requests_oauthlib import OAuth2Session
client_id=os.environ['ASANA_CLIENT_ID'],
client_secret=os.environ['ASANA_CLIENT_SECRET'],
# this special redirect URI will prompt the user to copy/paste the code.
# useful for command line scripts and other non-web apps
redirect_uri='urn:ietf:wg:oauth:2.0:oob'
if 'ASANA_CLIENT_ID' in os.environ:
#Creates a client with previously obtained Oauth credentials#
client = asana.Client.oauth(
#Asana Client ID and Secret, set as a Windows environments to avoid hardcoding variables into the script#
client_id=os.environ['ASANA_CLIENT_ID'],
client_secret=os.environ['ASANA_CLIENT_SECRET'],
# this special redirect URI will prompt the user to copy/paste the code.
# useful for command line scripts and other non-web apps
redirect_uri='urn:ietf:wg:oauth:2.0:oob'
)
print ("authorized=", client.session.authorized)
# get an authorization URL:
(url, state) = client.session.authorization_url()
try:
# in a web app you'd redirect the user to this URL when they take action to
# login with Asana or connect their account to Asana
import webbrowser
webbrowser.open(url)
except Exception as e:
print_("Open the following URL in a browser to authorize:")
print_(url)
print_("Copy and paste the returned code from the browser and press enter:")
code = sys.stdin.readline().strip()
# exchange the code for a bearer token
token = client.session.fetch_token(code=code)
#print_("token=", json.dumps(token))
print_("authorized=", client.session.authorized)
me = client.users.me()
print "Hello " + me['name'] + "\n"
params = {'client_id' : client_id, 'redirect_uri' : redirect_uri, 'response_type' : token,}
print_("*************** Request begings *******************"+"\n")
print_("r = requests.get('https://app.asana.com/api/1.0/users/me)" + "\n")
r = requests.get('https://app.asana.com/api/1.0/users/me', params)
print_(r)
print_(r.json)
print_(r.encoding)
workspace_id = me['workspaces'][0]['id']
print_("My workspace ID is" + "\n")
print_(workspace_id)
print_(client.options)
I'm not sure how to use the requests lib with Asana. Their python doc did not help me. I'm trying to pull the available projects and their code colours so I can later plot them into a web browser (For a high-level view of the different projects and their respective colours - Green, yellow or red)
When I introduce the url (https://app.asana.com/api/1.0/users/me) into a browser, it gives me back a json response with the data, but when I try to do the same with the script, it gives me back a 401 (not authorized) response.
Does anybody know what I'm missing / doing wrong?
Thank you!!!
I believe the issue is that the Requests library is a lower level library. You would need to pass all of the parameters to your requests.
Is there a reason you are not exclusively using the Asana Python client library to make requests? All of the data you are looking to fetch from Asana (projects, tasks, etc.) are accessible using the Asana Python library. You will want to look in the library to find the methods you need. For example, the methods for the tasks resource can be found here. I think this approach will be easier (and less error-prone) than switching between the Asana lib and the Requests lib. The Asana lib is actually built on top of Requests (as seen here).

How to check if server is apache in python?

I need some idea to test the server from a link. I do not know where to start
Would be:
site = 'example.com'
if(site === Apache)
print '[ok] Apache - Version:'
else
print '[No] Is not apache'
I prefer using requests since it's simple and well documented. And it doesn't return an error like urllib
import requests
request = requests.get("http://stackoverflow.com/")
if "Apache" in request.headers['server']:
print "Apache Server found"
else:
print "This is no Apache Server"
Also see : http://www.python-requests.org/en/latest/ for more information
In python 3:
import urllib.request
response = urllib.request.urlopen('http://www.google.com')
print(response.headers['Server'])
would be the simplest way to get the server header in some cases.
Some sites (like stackoverflow), however, will return 403 error code.

Programmatically getting an access token for using the Facebook Graph API

I am trying to put together a bash or python script to play with the facebook graph API. Using the API looks simple, but I'm having trouble setting up curl in my bash script to call authorize and access_token. Does anyone have a working example?
Update 2018-08-23
Since this still gets some views and upvotes I just want to mention that by now there seems to exist a maintained 3rd party SDK: https://github.com/mobolic/facebook-sdk
Better late than never, maybe others searching for that will find it. I got it working with Python 2.6 on a MacBook.
This requires you to have
the Python facebook module installed: https://github.com/pythonforfacebook/facebook-sdk,
an actual Facebook app set up
and the profile you want to post to must have granted proper permissions to allow all the different stuff like reading and writing.
You can read about the authentication stuff in the Facebook developer documentation. See https://developers.facebook.com/docs/authentication/ for details.
This blog post might also help with this: http://blog.theunical.com/facebook-integration/5-steps-to-publish-on-a-facebook-wall-using-php/
Here goes:
#!/usr/bin/python
# coding: utf-8
import facebook
import urllib
import urlparse
import subprocess
import warnings
# Hide deprecation warnings. The facebook module isn't that up-to-date (facebook.GraphAPIError).
warnings.filterwarnings('ignore', category=DeprecationWarning)
# Parameters of your app and the id of the profile you want to mess with.
FACEBOOK_APP_ID = 'XXXXXXXXXXXXXXX'
FACEBOOK_APP_SECRET = 'XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX'
FACEBOOK_PROFILE_ID = 'XXXXXX'
# Trying to get an access token. Very awkward.
oauth_args = dict(client_id = FACEBOOK_APP_ID,
client_secret = FACEBOOK_APP_SECRET,
grant_type = 'client_credentials')
oauth_curl_cmd = ['curl',
'https://graph.facebook.com/oauth/access_token?' + urllib.urlencode(oauth_args)]
oauth_response = subprocess.Popen(oauth_curl_cmd,
stdout = subprocess.PIPE,
stderr = subprocess.PIPE).communicate()[0]
try:
oauth_access_token = urlparse.parse_qs(str(oauth_response))['access_token'][0]
except KeyError:
print('Unable to grab an access token!')
exit()
facebook_graph = facebook.GraphAPI(oauth_access_token)
# Try to post something on the wall.
try:
fb_response = facebook_graph.put_wall_post('Hello from Python', \
profile_id = FACEBOOK_PROFILE_ID)
print fb_response
except facebook.GraphAPIError as e:
print 'Something went wrong:', e.type, e.message
Error checking on getting the token might be better but you get the idea of what to do.
Here you go, as simple as it can get. Doesn’t require any 3rd-party SDK etc.
Make sure Python 'requests' module is installed
import requests
def get_fb_token(app_id, app_secret):
url = 'https://graph.facebook.com/oauth/access_token'
payload = {
'grant_type': 'client_credentials',
'client_id': app_id,
'client_secret': app_secret
}
response = requests.post(url, params=payload)
return response.json()['access_token']
Easy! Just use facebook-sdk.
import facebook
app_id = 'YOUR_APP_ID'
app_secret = 'YOUR_APP_SECRET'
graph = facebook.GraphAPI()
# exactly what you're after ;-)
access_token = graph.get_app_access_token(app_id, app_secret)
You first need to set up an application. The following will then spit out an access token given your application ID and secret:
> curl -F type=client_cred -F client_id=[...] -F client_secret=[...] https://graph.facebook.com/oauth/access_token
Since a web browser needs to be involved for the actual authorization, there is no such thing as a "standalone script" that does it all. If you're just playing with the API, or are writing a script to automate something yourself, and want a access_token for yourself that does not expire, you can grab one here: http://fbrell.com/auth/offline-access-token
There IS a way to do it, I've found it, but it's a lot of work and will require you to spoof a browser 100% (and you'll likely be breaking their terms of service)
Sorry I can't provide all the details, but the gist of it:
assuming you have a username/password for a facebook account, go curl for the oauth/authenticate... page. Extract any cookies returned in the "Set-Cookie" header and then follow any "Location" headers (compiling cookies along the way).
scrape the login form, preserving all fields, and submit it (setting the referer and content-type headers, and inserting your email/pass) same cookie collection from (1) required
same as (2) but now you're going to need to POST the approval form acquired after (2) was submitted, set the Referer header with thr URL where the form was acquired.
follow the redirects until it sends you back to your site, and get the "code" parameter out of that URL
Exchange the code for an access_token at the oauth endpoint
The main gotchas are cookie management and redirects. Basically, you MUST mimic a browser 100%. I think it's hackery but there is a way, it's just really hard!
s29 has the correct answer but leaves some steps to solve. The following script demonstrates a working script for acquiring an access token using the Facebook SDK:
__requires__ = ['facebook-sdk']
import os
import facebook
def get_app_access_token():
client = facebook.GraphAPI()
return client.get_app_access_token(
os.environ['FACEBOOK_APP_ID'],
os.environ['FACEBOOK_APP_SECRET'],
)
__name__ == '__main__' and print(get_app_access_token())
This script expects the FACEBOOK_APP_ID and FACEBOOK_APP_SECRET environment variables are set to the values for your app. Feel free to adapt that technique to load those values from a different source.
You must first install the Facebook SDK (pip install facebook-sdk; python get-token.py) or use another tool like rwt to invoke the script (rwt -- get-token.py).
Here is the Python Code. Try running some of these examples on command line, they work fine for me. See also — http://www.pythonforfacebook.com/

Does urllib2 in Python 2.6.1 support proxy via https

Does urllib2 in Python 2.6.1 support proxy via https?
I've found the following at http://www.voidspace.org.uk/python/articles/urllib2.shtml:
NOTE
Currently urllib2 does not support
fetching of https locations through a
proxy. This can be a problem.
I'm trying automate login in to web site and downloading document, I have valid username/password.
proxy_info = {
'host':"axxx", # commented out the real data
'port':"1234" # commented out the real data
}
proxy_handler = urllib2.ProxyHandler(
{"http" : "http://%(host)s:%(port)s" % proxy_info})
opener = urllib2.build_opener(proxy_handler,
urllib2.HTTPHandler(debuglevel=1),urllib2.HTTPCookieProcessor())
urllib2.install_opener(opener)
fullurl = 'https://correct.url.to.login.page.com/user=a&pswd=b' # example
req1 = urllib2.Request(url=fullurl, headers=headers)
response = urllib2.urlopen(req1)
I've had it working for similar pages but not using HTTPS and I suspect it does not get through proxy - it just gets stuck in the same way as when I did not specify proxy. I need to go out through proxy.
I need to authenticate but not using basic authentication, will urllib2 figure out authentication when going via https site (I supply username/password to site via url)?
EDIT:
Nope, I tested with
proxies = {
"http" : "http://%(host)s:%(port)s" % proxy_info,
"https" : "https://%(host)s:%(port)s" % proxy_info
}
proxy_handler = urllib2.ProxyHandler(proxies)
And I get error:
urllib2.URLError: urlopen error
[Errno 8] _ssl.c:480: EOF occurred in
violation of protocol
Fixed in Python 2.6.3 and several other branches:
_bugs.python.org/issue1424152 (replace _ with http...)
http://www.python.org/download/releases/2.6.3/NEWS.txt
Issue #1424152: Fix for httplib, urllib2 to support SSL while working through
proxy. Original patch by Christopher Li, changes made by Senthil Kumaran.
I'm not sure Michael Foord's article, that you quote, is updated to Python 2.6.1 -- why not give it a try? Instead of telling ProxyHandler that the proxy is only good for http, as you're doing now, register it for https, too (of course you should format it into a variable just once before you call ProxyHandler and just repeatedly use that variable in the dict): that may or may not work, but, you're not even trying, and that's sure not to work!-)
Incase anyone else have this issue in the future I'd like to point out that it does support https proxying now, make sure the proxy supports it too or you risk running into a bug that puts the python library into an infinite loop (this happened to me).
See the unittest in the python source that is testing https proxying support for further information:
http://svn.python.org/view/python/branches/release26-maint/Lib/test/test_urllib2.py?r1=74203&r2=74202&pathrev=74203

WCF and Python

Is there any example code of a cpython (not IronPython) client which can call Windows Communication Foundation (WCF) service?
I used suds.
from suds.client import Client
print "Connecting to Service..."
wsdl = "http://serviceurl.com/service.svc?WSDL"
client = Client(wsdl)
result = client.service.Method(variable1, variable2)
print result
That should get you started. I'm able to connect to exposed services from WCF and a RESTful layer. There needs to be some data massaging to help do what you need, especially if you need to bind to several namespaces.
TL;DR: For wsHttpBinding (SOAP 1.2) use zeep
In case someone is having trouble using suds (or suds-jurko for that matter) with WCF and wsHttpBinding (which is SOAP 1.2):
suds is pretty much dead (can't even pip install it on python 3)
suds-jurko seems kind-of dead. The 0.6 release has a very annoying infinite recursion bug (at least on the WSDL exposed by our service) which is fixed in the tip but that's not released and it's been 1.5years (at time of this writing in Feb'17) since the last commit.
It works on python 3 but doesn't support SOAP 1.2. Sovetnikov's answer is an attempt to get it working with 1.2 but I haven't managed to make it work for me.
zeep seems to be the current way to go and worked out of the box (I'm not affiliated with zeep, it just works for me and I spent several hours banging my head against a brick wall trying to make suds work). For zeep to work, the WCF service host configuration must include <security mode="None"/> under the wsHttpBinding node Actually zeep seems to support username and signature (x509) based WS-SE but I haven't tried that so can't speak to any problems around it.
WCF needs to expose functionality through a communication protocol. I think the most commonly used protocol is probably SOAP over HTTP. Let's assume that's
what you're using then.
Take a look at this chapter in Dive Into Python. It will show you how to
make SOAP calls.
I know of no unified way of calling a WCF service in Python, regardless of communication
protocol.
Just to help someone to access WCF SOAP 1.2 service with WS-Addressing using suds.
Main problem is to inject action name in every message.
This example for python 3 and suds port https://bitbucket.org/jurko/suds.
Example uses custom authentification based on HTTP headers, i leave it as is.
TODO: Automatically get api_direct_url from WSDL (at now it is hard coded).
from suds.plugin import MessagePlugin
from suds.sax.text import Text
from suds.wsse import Security, UsernameToken
from suds.sax.element import Element
from suds.sax.attribute import Attribute
from suds.xsd.sxbasic import Import
api_username = 'some'
api_password = 'none'
class api(object):
api_direct_url = 'some/mex'
api_url = 'some.svc?singleWsdl|Wsdl'
NS_WSA = ('wsa', 'http://www.w3.org/2005/08/addressing')
_client_instance = None
#property
def client(self):
if self._client_instance:
return self._client_instance
from suds.bindings import binding
binding.envns = ('SOAP-ENV', 'http://www.w3.org/2003/05/soap-envelope')
api_inst = self
class _WSAPlugin(MessagePlugin):
def marshalled(self, context):
api_inst._marshalled_message(context)
self._client_instance = Client(self.api_url,
plugins=[_WSAPlugin()],
headers={'Content-Type': 'application/soap+xml',
'login':api_username,
'password': api_password}
)
headers = []
headers.append(Element('To', ns=self.NS_WSA).setText(self.api_direct_url))
headers.append(Element('Action', ns=self.NS_WSA).setText('Blank'))
self._client_instance.set_options(soapheaders=headers)
cache = self._client_instance.options.cache
cache.setduration(days=10)
return self._client_instance
def _marshalled_message(self, context):
def _children(r):
if hasattr(r, 'children'):
for c in r.children:
yield from _children(c)
yield c
for el in _children(context.envelope):
if el.name == 'Action':
el.text = Text(self._current_action)
return
_current_action = None
def _invoke(self, method, *args):
try:
self._current_action = method.method.soap.action.strip('"')
return method(*args)
finally:
self._current_action = None
def GetRequestTypes(self):
return self._invoke(self.client.service.GetRequestTypes)[0]
def GetTemplateByRequestType(self, request_type_id):
js = self._invoke(self.client.service.GetTemplateByRequestType, request_type_id)
return json.loads(js)
def GetRequestStatus(self, request_guid):
return self._invoke(self.client.service.GetRequestStatus, request_guid)
def SendRequest(self, request_type_id, request_json):
r = json.dumps(request_json, ensure_ascii=False)
return self._invoke(self.client.service.SendRequest, request_type_id, r)
I do not know of any direct examples, but if the WCF service is REST enabled you could access it through POX (Plain Old XML) via the REST methods/etc (if the service has any). If you are in control of the service you could expose endpoints via REST as well.
if you need binary serialized communication over tcp then consider implementing solution like Thrift.
Even if there is not a specific example of calling WCF from Python, you should be able to make a fully SOAP compliant service with WCF. Then all you have to do is find some examples of how to call a normal SOAP service from Python.
The simplest thing will be to use the BasicHttpBinding in WCF and then you can support your own sessions by passing a session token with each request and response.

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