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Closed 7 years ago.
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I am performing one python program and the part of the code is as follows
while 1:
data = conn.recv(BUFFER_SIZE)
if not data: break
print "received data:", data
com = "echo " + data
print com
conn.send(data)
conn.close()
but when i am trying to execute the code i am getting the following error.
File "server.py", line 17
com = "echo " + data
^
IndentationError: unexpected indent
I am not getting whats wrong with the code above.
check that you either consistently have tabs or spaces not a mix of both.
Related
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I was working on a problem and came across a syntax error for a print statement. I started commenting out lines and have an EOF error for a comment line. Any clue how to fix this EOF error for comments?
I've tried commenting out the lines, deleting the lines and typing them again in case I had a typo, and looking up similar solutions
Here is what I am currently trying to run:
# np_baseball is available
# Import numpy
import numpy as n
# Create np_height_in from np_baseball
np_height_in = np_baseball[0]
print(n.median(np_height_in))
# Print out the mean of np_height_in
print(n.mean(np_height_in)
#print(n.median(np_height_in))
# Print out the median of np_height_in
Here's the current error:
File "", line 12
# Print out the median of np_height_in
^
SyntaxError: unexpected EOF while parsing
print(n.mean(np_height_in)
is missing a closing ) . It should be:
print(n.mean(np_height_in))
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I am trying to use machine learning to predict students' future grade, but am stuck at the beginning.
Seems like pandas.read_csv cannot read psv file, I got:
df = pd.read_csv(‘training.psv’)
^
SyntaxError: invalid character in identifier
How can I read psv file through python?
The problem is in the quotes symbol. You should either use ' or ".
Try:
df = pd.read_csv('training.psv')
pd.read_csv("training.psv", sep = "|", header = FALSE, stringsAsFactors = FALSE)
That should work
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My terminal is producing the error "unexpected indent" at the start of my for loop, when it is not indented at all in my editor. How can I fix this? See code below:
wb = openpyxl.load_workbook(filename = 'BE110FinalProject.xlsx')
type(wb)
sheet = wb.get_sheet_by_name('Sheet1')
for row in sheet.iter_rows('K{}:K{}'.format(258,sheet.max_row)):
for cell in row:
if (cell.value):
numerator = float(cell.value.split(':')[1])
denominator = float(cell.value.split(':')[0])
japanOutput.write(numerator + '/' + denominator + '\n')
else:
japanOutput.write('\n')
You most likely have spaces instead of tabs.
Python tends to be picky when it comes to tabs and spaces.
One thing to try would be removing your indentations and making sure you use tabs.
I hope this helped!
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Closed 8 years ago.
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Every time I try to run these first 2 lines in python, it says:
SyntaxError: invalid syntax
And highlights the name of the variable I'm trying to define (Yname).
These are the lines I'm trying to run:
print("Hello what's your name?")\
Yname = input("your name:")
It is because of the \ at the end of the first line.
in Python \ is the line continuation character. Python is trying to parse this as
print("Hello what's your name?")Yname = input("your name:")
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Closed 9 years ago.
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python3-invalid syntax error
File "6_1.py", line 8
SyntaxError: invalid syntax
But there is no line 8. So what is the problem.
import zipfile,re
with ZipFile('../../下载/channel.zip') as myzip:
nothing = '90052'
rex = re.compile(r'\d+')
while True:
print(myzip.getinfo(nothing+'txt'))
nothing = re.findall(rex, myzip.open(nothing+'txt')[0]
No, but Python thinks there should be because line 7 is not complete:
nothing = re.findall(rex, myzip.open(nothing+'txt')[0]
# open 1 -------- open 2 ----- close 2 - ^ where is close 1?
There is a closing ) missing at the end.