Hyperlinks in web.py - python

How do I make web.py fetch a page when I click on a link?
I have this in my template:
<a href='add.html'>Home</a>
When I click on 'Home', I get 'not found'.
In my application, I have '/add' mapped to the 'Add' class which returns 'Boom!' using the template add.html.
urls = ('/', 'Index',
'/add','Add')
class Add(object):
def GET(self):
return render.add('Boom!')
I feel when I request for /add.html, the Add class will handle the request and return 'Boom!'
Why do I keep getting 'not found'?

The origin of a page URI ending in .html lilke /add.html is that in static hosting environments those were traditionally really single text files with html-content and the file ending for such a file is .html
But your system is dynamic and creates web pages on the fly. It does not necessarily need the pages ending in .html. Although you can mimic the traditional behaviour if you desire.
But in a modern and dynamic system it is often preferred that there is no ending on the single "pages" at all.
So you could, as Ignacio also suggests, just get rid of the .html and request the /add page, which is a valid and sufficient unique identifier for that resource.
If you like to keep the .html ending. you have to add it also in the route.
urls = (
'/', 'Index',
'/add.html','Add',
)
You can also have multiple routes pointing to the same resource, so that both /add and /add.html are valid and showing the same content, but content duplication has other drawbacks:
urls = (
'/', 'Index',
'/add','Add',
'/add.html','Add',
)
I recommend getting rid of the .html. This means you stick with the code from your question and create links to the page like this:
add something

Either change the route to be "/add.html" or change the link to be "add".

Related

Is it always correct to use URLs like "./about.html" or "../about.htm" instead of Absolute URLS like /about?

I'm a computer science student. Recently we were tasked to develop a static HTTP server from scratch without using any HTTP modules, solely depending on socket programming. So this means that I had to write all the logic for HTTP message parsing, extracting headers, parsing URLs, etc.
However, I'm stuck with some confusion. As I'm somewhat experienced in web development before, I'm used to using URLs in places like anchor tags like this "/about", and "/articles/article-1".However, I've seen people sometimes people to relative paths according to their folder structure like this. "./about.html", "../contact.html".This always seemed to be a bad idea to me. However, I realized that even though in my code I'm not supporting these kinds of URLs explicitly, it seems to work anyhow.
Following is the python code I'm using to get the path from the HTTP message and then get the corresponding path in the file system.
def get_http_url(self, raw_request_headers: list[str]):
"""
Method to get HTTP url by parsing request headers
"""
if len(raw_request_headers) > 0:
method_and_path_header = raw_request_headers[0]
method_and_path_header_segments = method_and_path_header.split(" ")
if len(method_and_path_header_segments) >= 2:
"""
example: GET / HTTP/1.1 => ['GET', '/', 'HTTP/1.1] => '/'
"""
url = method_and_path_header_segments[1]
return url
return False
def get_resource_path_for_url(self, path: str | Literal[False]):
"""
Method to get the resource path based on url
"""
if not path:
return False
else:
if path.endswith('/'):
# Removing trailing '/' to make it easy to parse the url
path = path[0:-1]
# Split to see if the url also includes the file extension
parts = path.split('.')
if path == '':
# if the requested path is "/"
path_to_resource = os.path.join(
os.getcwd(), "htdocs", "index.html")
else:
# Assumes the user entered a valid url with resources file extension as well, ex: http://localhost:2728/pages/about.html
if len(parts) > 1:
path_to_resource = os.path.join(
os.getcwd(), "htdocs", path[1:]) # Get the abslute path with the existing file extension
else:
# Assumes user requested a url without an extension and as such is hoping for a html response
path_to_resource = os.path.join(
os.getcwd(), "htdocs", f"{path[1:]}.html") # Get the absolute path to the corresponding html file
return path_to_resource
So in my code, I'm not explicitly adding any logic to handle that kind of relative path. But somehow, when I use things like ../about.html in my test HTML files, it somehow works?
Is this the expected behavior? As of now (I would like to know where this behavior is implemented), I'm on Windows if that matters. And if this is expected, can I depend on this behavior and conclude that it's safe to refer to HTML files and other assets with relative paths like this on my web server?
Thanks in advance for any help, and I apologize if my question is not clear or well-formed.

Django child url does not show its template

I have two different urls:
1) /campaigns/, which lists available campaigns and 2)campaigns/add/ where there is a form to fill the details of a campaign to be created.
My django urls.py file looks like:
url(r'^campaigns/', views.campaigns, name='agency-campaigns'),
url(r'^campaigns/add/$', views.add_campaign, name='agency-add-campaign')
The problem is that whenever I browse the /campaigns/ url, it shows the correct template. But when I browse the /campaigns/add/ url, it still shows the /campaigns/ url template.
What can be wrong with this subdirectory?
Any ideas?
Thanks in advance!
That's because you don't have the end of string match ($) at the end of the regular expression:
url(r'^campaigns/$', views.campaigns, name='agency-campaigns'),
# HERE^
Or, you can also put the "agency-add-campaign" pattern before the "agency-campaigns":
url(r'^campaigns/add/$', views.add_campaign, name='agency-add-campaign'),
url(r'^campaigns/', views.campaigns, name='agency-campaigns')

How to handle url path in web.py?

I'm new to web.py, and use a lot of hardcoded url in my code for href in tag a,like
/loginor/?type=example.
The problem is,
when I set my application running under a certain path, not the root of a URL, like
http://example.com/appname/
The link will direct me to some place like
http://example.com/login
While the expected/wanted one is
http://example.com/appname/login
How do I handle this?
Make web.ctx.homepath available in your template globals, and output it before your paths.
From http://webpy.org/cookbook/ctx
homepath – The part of the path requested by the user which was
trimmed off the current app. That is homepath + path = the path
actually requested in HTTP by the user. E.g. /admin This seems to be
derived during startup from the environment variable REAL_SCRIPT_NAME.
It affects what web.url() will prepend to supplied urls. This in turn
affects where web.seeother() will go, which might interact badly with
your url rewriting scheme (e.g. mod_rewrite)
template_globals = {
'app_path': lambda p: web.ctx.homepath + p,
}
render = template.render(my_template_dir, globals=template_globals, base="mylayout")
Then you should be able to output app_path in your templates
Login

Unable to view item in browser based on its key in Python GAE

I'm using python GAE with webapp.
I have a form for a user to create a object in the database, something like:
class SpamRecord(db.Model):
author = db.ReferenceProperty(Author, required=True)
text = db.StringProperty()
After it's created, the user is redirected to a page whose URL contains that object's key... using code such as:
spam = SpamRecord(author=author, text=text)
spam.put()
new_spam_key = spam.key()
self.redirect("/view_spam/%s" % new_spam_key)
And this mostly works, with me being able to view items at:
sitename.com/view_spam/ag1waWNreXByZXNlbnRzchQLEgxBbm5vdW5jZW1lbnQYy8oJDA
sitename.com/view_spam/ag1waWNreXByZXNlbnRzchQLEgxBbm5vdW5jZW1lbnQY_boJDA
However, there's an occasional key that won't work. Here are 2 recent examples of pages that won't load and return HTTP 404 not found errors:
sitename.com/view_spam/ag1waWNreXByZXNlbnRzchQLEgxBbm5vdW5jZW1lbnQY-5MJDA
sitename.com/view_spam/ag1waWNreXByZXNlbnRzchQLEgxBbm5vdW5jZW1lbnQY-boJDA
My html-mappings.py contains the following mapping:
(r"/view_spam/(\w+)", ViewSpamPage)
And the ViewSpamPage looks something like:
class ViewSpamPage(webapp.RequestHandler):
def get(self, spam_id):
self.response.out.write("Got here")
Can anyone offer any insight as to why this is occurring and how it may be prevented?
Thanks very much!
In regular expressions, \w doesn't match hyphens. (It will match underscores.) For that second pair of keys, this'll result in only passing part of the key to your handler.
In your URL pattern, try r"/view_spam/(.*)" instead.

Pylons: How to write a custom 404 page?

So this question has been asked before, but not answered in great detail.
I want to override the default Pylons error page to make a nicer, custom one. I've got as far as overwriting the controller in error.py, as follows:
def document(self):
"""Render the error document"""
resp = request.environ.get('pylons.original_response')
content = literal(resp.body) or cgi.escape(request.GET.get('message', ''))
custom_error_template = literal("""\
# some brief HTML here
""")
page = custom_error_template % \
dict(prefix=request.environ.get('SCRIPT_NAME', ''),
code=cgi.escape(request.GET.get('code', str(resp.status_int))),
message=content)
return page
This works OK. What I'd like to do now is use a template in the templates directory, so that the 404 page can inherit my usual layout template, CSS etc.
(I know this is a bad idea for 500 errors - I'll check in error.py that the code is 404 before I use the template rather than a literal.)
So, here's the question. How do I define custom_error_template to point at my template, rather than at a literal?
You should be able to use render method (import it from yourapp.lib.base, and use return render('/path/to/error/template').
Just create your view and use add_notfound_view configuration method to configure it.
See: http://docs.pylonsproject.org/docs/pyramid/en/latest/api/config.html?highlight=document%20error#pyramid.config.Configurator.add_notfound_view

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