Python Idle and KeyboardInterrupts - python

KeyboardInterrupts in Idle work for me 90% of the time, but I was wondering why they don't always work. In Idle, if I do
import time
time.sleep(10)
and then attempt a KeyboardInterrupt using Ctrl+C, it does not interrupt the process until after sleeping for 10 seconds.
The same code and a KeyboardInterrupt via Ctrl+C works immediately in the shell.

A quick glance at the IDLE source reveals that KeyboardInterrupts have some special case handling: http://svn.python.org/view/python/tags/r267/Lib/idlelib/PyShell.py?annotate=88851
On top of that, code is actually executed in a separate process which the main IDLE gui process communicates with via RPC. You're going to get different behavior under that model - it's best to just test with the canonical interpreter (via command line, interactive, etc.)
============
Digging deeper...
The socket on the RPC server is managed in a secondary thread which is supposed to propagate a KeyboardInterrupt using a call to thread.interrupt_main() ( http://svn.python.org/view/python/tags/r267/Lib/idlelib/run.py?annotate=88851 ). Behavior is not as expected there... This posting hints that for some reason, interrupt_main doesn't provide the level of granularity that you would expect: http://bytes.com/topic/python/answers/38386-thread-interrupt_main-doesnt-seem-work
Async API functions in cPython are a little goofy (from my experience) due to how the interpreter loop is handled, so it doesn't surprise me. interrupt_main() calls PyErr_SetInterrupt() to asynchronously notify the interpreter to handle a SIGINT in the main thread. From http://docs.python.org/c-api/exceptions.html#PyErr_SetInterrupt:
This function simulates the effect of
a SIGINT signal arriving — the next
time PyErr_CheckSignals() is called,
KeyboardInterrupt will be raised
That would require the interpreter to go though whatever number of bytecode instructions before PyErr_CheckSignals() is called again - something that probably doesn't happen during a time.sleep(). I would venture to say that's a wart of simulating a SIGINT rather than actually signaling a SIGINT.

See This article:
I quote:
If you try to stop a CPython program
using Control-C, the interpreter
throws a KeyboardInterrupt exception.
It makes some sense, because the thread is asleep for 10 seconds and so exceptions cannot be thrown until the 10 seconds pass. However, ctrl + c always work in the shell because you are trying to stop a process, not throw a python KeyboardInterrupt exception.
Also, see this previously answered question.
I hope this helps!

Related

Stop multithreaded Python script on Windows

I have troubles with a simple multithreaded Python looping program. It should loop infinitely and stop with Ctrl+C. Here is an implementation using threading:
from threading import Thread, Event
from time import sleep
stop = Event()
def loop():
while not stop.is_set():
print("looping")
sleep(2)
try:
thread = Thread(target=loop)
thread.start()
thread.join()
except KeyboardInterrupt:
print("stopping")
stop.set()
This MWE is extracted from a more complex code (obviously, I do not need multithreading to create an infinite loop).
It works as expected on Linux, but not on Windows: the Ctrl+C event is not intercepted and the loop continues infinitely. According to the Python Dev mailing list, the different behaviors are due to the way Ctrl+C is handled by the two OSs.
So, it appears that one cannot simply rely on Ctrl+C with threading on Windows. My question is: what are the other ways to stop a multithreaded Python script on this OS with Ctrl+C?
As explained by Nathaniel J. Smith in the link from your question, at least as of CPython 3.7, Ctrl-C cannot wake your main thread on Windows:
The end result is that on Windows, control-C almost never works to
wake up a blocked Python process, with a few special exceptions where
someone did the work to implement this. On Python 2 the only functions
that have this implemented are time.sleep() and
multiprocessing.Semaphore.acquire; on Python 3 there are a few more
(you can grep the source for _PyOS_SigintEvent to find them), but
Thread.join isn't one of them.
So, what can you do?
One option is to just not use Ctrl-C to kill your program, and instead use something that calls, e.g., TerminateProcess, such as the builtin taskkill tool, or a Python script using the os module. But you don't want that.
And obviously, waiting until they come up with a fix in Python 3.8 or 3.9 or never before you can Ctrl-C your program is not acceptable.
So, the only thing you can do is not block the main thread on Thread.join, or anything else non-interruptable.
The quick&dirty solution is to just poll join with a timeout:
while thread.is_alive():
thread.join(0.2)
Now, your program is briefly interruptable while it's doing the while loop and calling is_alive, before going back to an uninterruptable sleep for another 200ms. Any Ctrl-C that comes in during that 200ms will just wait for you to process it, so that isn't a problem.
Except that 200ms is already long enough to be noticeable and maybe annoying.
And it may be too short as well as too long. Sure, it's not wasting much CPU to wake up every 200ms and execute a handful of Python bytecodes, but it's not nothing, and it's still getting a timeslice in the scheduler, and that may be enough to, e.g., keep a laptop from going into one of its long-term low-power modes.
The clean solution is to find another function to block on. As Nathaniel J. Smith says:
you can grep the source for _PyOS_SigintEvent to find them
But there may not be anything that fits very well. It's hard to imagine how you'd design your program to block on multiprocessing.Semaphore.acquire in a way that wouldn't be horribly confusing to the reader…
In that case, you might want to drag in the Win32 API directly, whether via PyWin32 or ctypes. Look at how functions like time.sleep and multiprocessing.Semaphore.acquire manage to be interruptible, block on whatever they're using, and have your thread signal whatever it is you're blocking on at exit.
If you're willing to use undocumented internals of CPython, it looks like, at least in 3.7, the hidden _winapi module has a wrapper function around WaitForMultipleObjects that appends the magic _PyOSSigintEvent for you when you're doing a wait-first rather than wait-all.
One of the things you can pass to WaitForMultipleObjects is a Win32 thread handle, which has the same effect as a join, although I'm not sure if there's an easy way to get the thread handle out of a Python thread.
Alternatively, you can manually create some kind of kernel sync object (I don't know the _winapi module very well, and I don't have a Windows system, so you'll probably have to read the source yourself, or at least help it in the interactive interpreter, to see what wrappers it offers), WaitForMultipleObjects on that, and have the thread signal it.

How to kill a Python thread without communication

I have read most of the similar questions in stackoverflow, but none see to solve my problem. I use ctypes to call a function from dll file. Therefore, I can't edit the source codes of the dll file to add any "end looping" conditions. Also, this function may last long (like some printing command). I need to design a "halt" command in case that something of emergency happens while printing is processed. The only way I can do is to kill the thread.
It is never good to forcibly kill a thread. Your program should be designed to cleanly exit from threads.
You can mark it as "daemon" before starting it. If you exit the main thread it will not wait on daemonized threads.
Terminating a thread can still be done in two ways. You can asynchronously raise a Python exception in a thread, via https://docs.python.org/2/c-api/init.html#c.PyThreadState_SetAsyncExc (as stated, this requires building a C module or using ctypes to make it work). The other approach on Windows is to call the Windows API TerminateThread():
TerminateThread is used to cause a thread to exit. When this occurs,
the target thread has no chance to execute any user-mode code. DLLs
attached to the thread are not notified that the thread is
terminating. The system frees the thread's initial stack.
[...]
TerminateThread is a dangerous function that should only be used in
the most extreme cases. You should call TerminateThread only if you
know exactly what the target thread is doing, and you control all of
the code that the target thread could possibly be running at the time
of the termination. For example, TerminateThread can result in the
following problems: ...
I think this should also be doable using ctypes.
You cannot safely terminate a thread without its cooperation. Threads are not isolated within a process, so unsafely terminating a thread contaminates the process. Please, don't go down this road.
If you need this kind of isolation, you need a process. You can safely terminate a process without its cooperation, though it may leave system objects (such as files) that the process was working on in an intermediate state. In your case, that may mean a print job half-done and a page halfway in the printer. Or it may mean temporary files that don't get removed.

Listening for subprocess failure in python

Using subprocess.Popen(), I'm launching a process that is supposed to take a long time. However, there is a chance that the process will fail shortly after it launches (producing a return code of 1). If that happens, I want to intercept the failure and present an explanatory message to the user. Is there a way to "listen" to the process and respond if it fails? I can't just use Popen.wait() because my python program has to keep running.
The hack I have in place right now is to time.sleep() my python program for .5 seconds (which should be enough time for the subprocess to to fail if it's going to do so). After the python program resumes, it polls the subprocess to determine if it has failed or not.
I imagine that a better solution might use threading and Popen.wait(), but I'm a relative beginner to python.
Edit:
The subprocess is a Java daemon that I'm launching. If another instance of the daemon is already running on the system, the Java subprocess will exit with a return code of 1, and I want to intercept the messy Java exception stack trace and present an understandable error message to the user.
Two approaches:
Call Popen.wait() on a thread as you suggested yourself, then call an error handler function if the exit code is non-zero. Make sure that the error handler is thread safe, preferably by dispatching the error message to the main thread if your application has an event loop.
Rewrite your application to use an event loop that already supports monitoring child processes, such as pyev. If you just want to monitor one subprocess, this is probably overkill.

profiling fuse-python

I am currently writing a fuse using fuse-python. It's already doing what it should. However, after it's mounted for a few weeks, it's becoming noticeably slow. So I wanted to profile it. I know about a few point where it could be optimized. But these should not be the culprits.
However, fuse-python hangs in an infinite loop (see line 733 and 757 of the fuse source). If I run fuse in debug mode (using the -d switch), it will run in foreground. However, I cannot stop it with SIGINT nor with CTRL+C (which is anyway the same).
I tried to use the signal module to trap the signal in the main thread. But this does not work either. Interestingly, once I shoot the process down with SIGKILL, I see the KeyboardInterrupt on stdout. Also, after a SIGKILL, the signal handler is executed as expected.
This has repercussions on profiling. As the process never terminates normally, cProfile never gets the chance to save the stats file.
Any ideas?
Python installs a handler that raises KeyboardInterrupt on SIGINT. If a non-default signal handler is detected when fuse's main is called, it will not replace the handler with its own, which normally calls fuse_session_exit and cleans up. After you've called fuse's main, the KeyboardInterrupt is swallowed by CFUNCTYPE wrappers and you never see them.
Your options are to:
Send SIGQUIT by pressing Ctrl+\, or any other terminating signal other than SIGINT. However fuse will not exit cleanly.
Install the default signal handler to SIGINT before calling fuse's main, and restore the original when you're done.
old_handler =signal(SIGINT, SIG_DFL)
# call main
signal(SIGINT, old_handler)
I'd highly recommend you switch to an alternative binding also, fuse-python is terribly messy and difficult to work with. I've had a lot of luck with fusepy, and have submitted a few patches there.
When you're able to terminate your FUSE instance without using uncaught signals, the Python profiler will be able to save the stats as per normal.

Signal handling in Python

In my program I have a bunch of threads running and I'm trying
to interrupt the main thread to get it to do something asynchronously.
So I set up a handler and send the main process a SIGUSR1 - see the code
below:
def SigUSR1Handler(signum, frame):
self._logger.debug('Received SIGUSR1')
return
signal.signal(signal.SIGUSR1, SigUSR1Handler)
[signal.signal(signal.SIGUSR1, signal.SIG_IGN)]
In the above case, all the threads and the main process stops - from a 'c'
point of view this was unexpected - I want the threads to continue as they
were before the signal. If I put the SIG_IGN in instead, everything continues
fine.
Can somebody tell me how to do this? Maybe I have to do something with the 'frame'
manually to get back to where it was..just a guess though
thanks in advance,
Thanks for your help on this.
To explain a bit more, I have thread instances writing string information to
a socket which is also output to a file. These threads run their own timers so they
independently write their outputs to the socket. When the program runs I also see
their output on stdout but it all stops as soon as I see the debug line from the signal.
I need the threads to constantly send this info but I need the main program to
take a command so it also starts doing something else (in parallel) for a while.
I thought I'd just be able to send a signal from the command line to trigger this.
Mixing signals and threads is always a little precarious. What you describe should not happen, however. Python only handles signals in the main thread. If the OS delivered the signal to another thread, that thread may be briefly interrupted (when it's performing, say, a systemcall) but it won't execute the signal handler. The main thread will be asked to execute the signalhandler at the next opportunity.
What are your threads (including the main thread) actually doing when you send the signal? How do you notice that they all 'stop'? Is it a brief pause (easily explained by the fact that the main thread will need to acquire the GIL before handling the signal) or does the process break down entirely?
I'll sort-of answer my own question:
In my first attempt at this I was using time.sleep(run_time) in the main
thread to control how long the threads ran until they were stopped. By adding
debug I could see that the sleep loop seemed to be exiting as soon as the
signal handler returned so everything was shutting down normally but early!
I've replaced the sleep with a while loop and that doesn't jump out after
the signal handler returns so my threads keep running. So it solves the
problem but I'm still a bit puzzled about sleep()'s behaviour.
You should probably use a threading.Condition variable instead of sending signals. Have your main thread check it every loop and perform its special operation if it's been set.
If you insist on using signals, you'll want to move to using subprocess instead of threads, as your problem is likely due to the GIL.
Watch this presentation by David Beazley.
http://blip.tv/file/2232410
It also explains some quirky behavior related to threads and signals (Python specific, not the general quirkiness of the subject :-) ).
http://pyprocessing.berlios.de/ Pyprocessing is a neat library that makes it easier to work with separate processes in Python.

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