Separating Axis Theorem and Python - python

This is what I am currently doing:
Creating 4 axis that are perpendicular to 4 edges of 2 rectangles. Since they are rectangles I do not need to generate an axis (normal) per edge.
I then loop over my 4 axes.
So for each axis:
I get the projection of every corner of a rectangle on to the axis.
There are 2 lists (arrays) containing those projections. One for each rectangle.
I then get the dot product of each projection and the axis. This returns a scalar value
that can be used to to determine the min and max.
Now the 2 lists contain scalars and not vectors. I sort the lists so I can easily select the min and max values. If the min of box B >= the max of box A OR the max of box B <= the min of box A then there is no collision on that axis and no collision between the objects.
At this point the function finishes and the loop breaks.
If those conditions are never met for all the axis then we have a collision
I hope this was the correct way of doing it.
The python code itself can be found here http://pastebin.com/vNFP3mAb
Also:
http://www.gamedev.net/page/reference/index.html/_/reference/programming/game-programming/collision-detection/2d-rotated-rectangle-collision-r2604
The problem i was having is that the code above does not work. It always detects a a collision even where there is not a collision. What i typed out is exactly what the code is doing. If I am missing any steps or just not understanding how SAT works please let me know.

In general it is necessary to carry out the steps outlined in the Question to determine if the rectangles "collide" (intersect), noting as the OP does that we can break (with a conclusion of non-intersection) as soon as a separating axis is found.
There are a couple of simple ways to "optimize" in the sense of providing chances for earlier exits. The practical value of these depends on the distribution of rectangles being checked, but both are easily incorporated in the existing framework.
(1) Bounding Circle Check
One quick way to prove non-intersection is by showing the bounding circles of the two rectangles do not intersect. The bounding circle of a rectangle shares its center, the midpoint of either diagonal, and has diameter equal to the length of either diagonal. If the distance between the two centers exceeds the sum of the two circles' radii, then the circles do not intersect. Thus the rectangles also cannot intersect. If the purpose was to find an axis of separation, we haven't accomplished that yet. However if we only want to know if the rectangles "collide", this allows an early exit.
(2) Vertex of one rectangle inside the other
The projection of a vertex of one rectangle on axes parallel to the other rectangle's edges provides enough information to detect when that vertex is inside the other rectangle. This check is especially easy when the latter rectangle has been translated and unrotated to the origin (with edges parallel to the ordinary axes). If it happens that a vertex of one rectangle is inside the other, the rectangles obviously intersect. Of course this is a sufficient condition for intersection, not a necessary one. But it allows for an early exit with a conclusion of intersection (and of course without finding an axis of separation because none will exist).

I see two things wrong. First, the projection should simply be the dot product of a vertex with the axis. What you're doing is way too complicated. Second, the way you get your axis is incorrect. You write:
Axis1 = [ -(A_TR[0] - A_TL[0]),
A_TR[1] - A_TL[1] ]
Where it should read:
Axis1 = [ -(A_TR[1] - A_TL[1]),
A_TR[0] - A_TL[0] ]
The difference is coordinates does give you a vector, but to get the perpendicular you need to exchange the x and y values and negate one of them.
Hope that helps.
EDIT Found another bug
In this code:
if not ( B_Scalars[0] <= A_Scalars[3] or B_Scalars[3] >= A_Scalars[0] ):
#no overlap so no collision
return 0
That should read:
if not ( B_Scalars[3] <= A_Scalars[0] or A_Scalars[3] <= B_Scalars[0] ):
Sort gives you a list increasing in value. So [1,2,3,4] and [10,11,12,13] do not overlap because the minimum of the later is greater than the maximum of the former. The second comparison is for when the input sets are swapped.

Related

Algorithm to check if cylinders are overlapping in 3D

I am creating a script to generate cylinders in a 3D space, however, I would like for them to not occupy the same region in space (avoid overlapping).
The cylinders are defined by a start and end point, and all have a fixed radius.
I am storing the existing cylinder in an array called listOfCylinders which is an nDim array of shape (nCylinders, 2Points [start, end], {x,y,z} coordinates of each point)
I was able to cook up:
def detect_overlap(new_start, new_end, listOfCylinders):
starts = listOfCylinders[:, 0]
ends = listOfCylinders[:, 1]
radius = 0.1
# Calculate the distance between the new cylinder and all the existing cylinders
dists = np.linalg.norm(np.cross(new_end - new_start, starts - new_start), axis=1) / np.linalg.norm(new_end - new_start)
# Check if any of the distances are less than the sum of the radii
if np.any(dists < (2*radius)):
return True
# If no overlap or intersection is found, return False
return False
But this is not accountting for situations where there is lateral overlaping.
Does anyone have a good algorithm for this?
Best Regards
WLOG one of the cylinders is vertical (otherwise rotate space). If you look at the projections of the apparent outline onto XY, you see a circle and a rectangle ended with ellipses. (For simplicity of the equations, you can also make the second cylindre parallel to XZ.)
If these 2D shapes do not overlap, your are done. Anyway, the intersection of a circle and an ellipse leads to a quartic equation.
You can repeat this process, exchanging the roles of the two cylinders. This gives a sufficient condition of non-overlap. Unfortunately, I am not sure it is necessary, though there is a direct connection to the plane separation theorem.
For a numerical approach, you can proceed as follows:
move the cylindre in the canonical position;
generate rectangles on the oblique cylindre, by rotation around the axis and using an angular parameter;
for all sides of the rectangles, detect interference with the cylindre (this involves a system of a quadratic inequation and two linear ones, which is quite tractable);
sample the angular parameter densely enough to check for no valid intersection.
I guess that a complete analytical solution is possible, but complex, and might anyway lead to equations that need to be solved numerically.

Coordinates Python

I am facing with the sorting airfoil coordinates. In particular given a set of coordinates, which are not sorted, I have to sorted them starting from the trailing edge upper surface. Here I report the code that I have developed but as you can see, the starting point do not match with what I suppose, moreover exist several oscillations as you can see in the reported figure (and a detail, in blue the starting point after the sort).
Can someone suggest me what I miss? How can I do?
Thanks you in advance.
def sort_airfoil(points):
x0 = np.mean(-points[:,1])
y0 = np.mean(points[:,2])
r = np.sqrt((-points[:,1]-x0)**2 + (points[:,2]-y0)**2)
tempx=-points[:,1]
xmax=np.max(tempx)
ind_max=np.where(tempx==xmax)
ymax=np.max(points[ind_max,2])
ind_max_t=np.where((tempx>0.95*xmax) & (tempx<xmax))
ymax_t=points[ind_max_t,2]
ymin=np.min(ymax_t)
indx_temp=np.where(points[:,2]==ymin)
xmin=np.max(tempx[indx_temp])
xmed=(xmin+xmax)/2
ymed=(ymin+ymax)/2
print(x0,y0)
print(xmin,ymin)
print((xmin+xmax)/2, (ymin+ymax)/2)
angle0=np.arctan2((ymed-y0),(xmed-x0))
print("angle", angle0)
angles = np.where((points[:,2]-y0) > 0, np.arccos((-points[:,1]-x0)/r), 2*np.pi-np.arccos((-points[:,1]-x0)/r))
angles=angles-angle0
for i in range(len(angles)):
if angles[i]<0:
angles[i]=angles[i]+2*np.pi
elif angles[i]>2*np.pi:
angles[i]=angles[i]-2*np.pi
mask = np.argsort(angles)
x_sorted = points[mask,1]
y_sorted = points[mask,2]
points_new=np.zeros([len(points), 3])
points_new[:,0]=points[:,0]
points_new[:,1]=x_sorted
points_new[:,2]=y_sorted
return points_new
The issue comes from the algorithm itself: it only work when the points form a convex polygon. However, the shape is concave.
More specifically, the first sorted points (and the last ones) form a zigzag-shaped lines because there is two sets of points (green arrows) interleaving with growing angles (red arrow) from the median point (red line).
Note the points are horizontally flipped on the gathered point from the question. Thus the points are sorted clockwise.
One simple solution is to split horizontally the shape in many set of point (eg. 10 set) so that each set form a convex shape. Then, the parts can be merged to form the final shape. The merge consists in finding the points at the "edge" of each locally-sorted set of points (parts) and reorder the partially sorted array of points consequently.
More specifically, the points of each part are split in 2 sub-sets: the upper ones and the lower ones. You can find them easily by selecting the 2 left-most points of a right part with the right-most points of a left part. The 2 top-most points needs to be connected each other and the same for the 2 bottom-most points. Thus, the sequence of the two upper sets of points needs to be reordered so they are contiguous and the same for the lower part.
Here is an example:
Note that if you are unsure about how to split the points in many parts so that each one form a convex-shaped sets of points, then you can: split the shape in n parts, check if the set of points form a convex shape by computing a convex hull (eg. using a Graham scan) and split evenly the parts that are concave (recursively). This is quite expensive, but more robust.

Implementing collisions using the Separating axis theorem and Pygame [duplicate]

This is what I am currently doing:
Creating 4 axis that are perpendicular to 4 edges of 2 rectangles. Since they are rectangles I do not need to generate an axis (normal) per edge.
I then loop over my 4 axes.
So for each axis:
I get the projection of every corner of a rectangle on to the axis.
There are 2 lists (arrays) containing those projections. One for each rectangle.
I then get the dot product of each projection and the axis. This returns a scalar value
that can be used to to determine the min and max.
Now the 2 lists contain scalars and not vectors. I sort the lists so I can easily select the min and max values. If the min of box B >= the max of box A OR the max of box B <= the min of box A then there is no collision on that axis and no collision between the objects.
At this point the function finishes and the loop breaks.
If those conditions are never met for all the axis then we have a collision
I hope this was the correct way of doing it.
The python code itself can be found here http://pastebin.com/vNFP3mAb
Also:
http://www.gamedev.net/page/reference/index.html/_/reference/programming/game-programming/collision-detection/2d-rotated-rectangle-collision-r2604
The problem i was having is that the code above does not work. It always detects a a collision even where there is not a collision. What i typed out is exactly what the code is doing. If I am missing any steps or just not understanding how SAT works please let me know.
In general it is necessary to carry out the steps outlined in the Question to determine if the rectangles "collide" (intersect), noting as the OP does that we can break (with a conclusion of non-intersection) as soon as a separating axis is found.
There are a couple of simple ways to "optimize" in the sense of providing chances for earlier exits. The practical value of these depends on the distribution of rectangles being checked, but both are easily incorporated in the existing framework.
(1) Bounding Circle Check
One quick way to prove non-intersection is by showing the bounding circles of the two rectangles do not intersect. The bounding circle of a rectangle shares its center, the midpoint of either diagonal, and has diameter equal to the length of either diagonal. If the distance between the two centers exceeds the sum of the two circles' radii, then the circles do not intersect. Thus the rectangles also cannot intersect. If the purpose was to find an axis of separation, we haven't accomplished that yet. However if we only want to know if the rectangles "collide", this allows an early exit.
(2) Vertex of one rectangle inside the other
The projection of a vertex of one rectangle on axes parallel to the other rectangle's edges provides enough information to detect when that vertex is inside the other rectangle. This check is especially easy when the latter rectangle has been translated and unrotated to the origin (with edges parallel to the ordinary axes). If it happens that a vertex of one rectangle is inside the other, the rectangles obviously intersect. Of course this is a sufficient condition for intersection, not a necessary one. But it allows for an early exit with a conclusion of intersection (and of course without finding an axis of separation because none will exist).
I see two things wrong. First, the projection should simply be the dot product of a vertex with the axis. What you're doing is way too complicated. Second, the way you get your axis is incorrect. You write:
Axis1 = [ -(A_TR[0] - A_TL[0]),
A_TR[1] - A_TL[1] ]
Where it should read:
Axis1 = [ -(A_TR[1] - A_TL[1]),
A_TR[0] - A_TL[0] ]
The difference is coordinates does give you a vector, but to get the perpendicular you need to exchange the x and y values and negate one of them.
Hope that helps.
EDIT Found another bug
In this code:
if not ( B_Scalars[0] <= A_Scalars[3] or B_Scalars[3] >= A_Scalars[0] ):
#no overlap so no collision
return 0
That should read:
if not ( B_Scalars[3] <= A_Scalars[0] or A_Scalars[3] <= B_Scalars[0] ):
Sort gives you a list increasing in value. So [1,2,3,4] and [10,11,12,13] do not overlap because the minimum of the later is greater than the maximum of the former. The second comparison is for when the input sets are swapped.

Triangulation patterns in .ifc file format using coordinates and indexes

I've posted this in another forum as well due to the mathematical nature of the issue:
forum post
I have an .ifc file in which the raw data exported describes a wall in the xy plane by a set of coordinates and their corresponding indexes according to the link explanation:
Explanation
I have a txt where the data is divided into the coordinates in xyz space, then indexes and some other data.
I was hoping that someone can help me understand how to link the indexes to their corresponding coordinates. There are 164 coordinate pairs and 324 index pairs so it doesn't make sense to me that each index relates to only 1 coordinate pair.
The goal is to establish a relationship between indexes and coordinates such that this type of data can output the wall thickness, which is in this case '10'. I was thinking that (according to the link above) by taking the first triangle described, it should describe the edge of the wall in 3D and therefore give us one of its sides as the shortest segment in the wall which is the thickness.
I received an answer in the mentioned forum post, that I should
"...expanding out each coordinate in terms of X's, Y's, and Z's [instead of (X,Y,Z) triples) and then use every index triple to get the actual coordinate for the individual coordinate instead of one triple.
So for example you have X[], Y[] and Z[] and you have an index (a,b,c) then you find X[a], Y[b], and Z[c] not Point(a,b,c)... "
I didn't quite understand this explanation, and would appreciate any help or further explanation in order to achieve my goal.
Thank you
Let's start with the cordinates (IfcCartesianPointList3D): each one is a triplet, resulting in a Point with (x,y,z) coordinates.
Then the IfcTriangulatedFaceSet uses indices to construct triangles. It has 2 indexing modes: direct and indirect via PnIndex. The indexing mode is determined by the existence of an array for PnIndex (attribute number 5). Take note that I call these variants direct and indirect - they aren't mentioned that way in the IFC documentation.
Direct indexing
PnIndex is not set. Lets look at an (simple and constructed) example:
#100=IFCCARTESIANPOINTLIST(((0,0,0),(1,0,0),(1,1,0),(0,1,0)));
#101=IFCTRIANGULATEDFACESET(
/*reference to the points*/ #100,
/*no normals*/ $,
/*no indication if closed or open*/ $,
/*coordinate indices*/ ((1,2,3),(1,3,4)),
/*no PnIndex*/ ());
This describes a square lying in the x-y-plane. Each entry in attribute CoordIndex is a triplet giving a one-based index into a point in the IfcCartesianPointList. This means there are two triangles constructed from the following points:
(0,0,0) (1,0,0) (1,1,0)
(0,0,0) (1,1,0) (0,1,0)
Indirect indexing
Lets build further on the previous example:
#100=IFCCARTESIANPOINTLIST(((0,0,0),(1,0,0),(1,1,0),(0,1,0)));
#101=IFCTRIANGULATEDFACESET(
/*reference to the points*/ #100,
/*no normals*/ $,
/*no indication if closed or open*/ $,
/*coordinate indices*/ ((1,2,3),(1,3,4)),
/*PnIndex*/ (2,3,4,1));
This time there is PnIndex set. It adds a level of indirection to access the points. Triplets from CoordIndex point into PnIndex (1-based). The value found in PnIndex is then used to access the IfcCartesianPointList.
So for the first triangle we have: (1,2,3) in CoordIndex. These point to 2, 3 and 4 in PnIndex. These result in the following points from the point list: (1,0,0) (1,1,0) (0,1,0)
Repeating the procudure for the second triangle (1,3,4) we get values 2, 4, 1 from PnIndex and the following points: (1,0,0) (0,1,0) (0,0,0)
It is again a square, but this time with a different triangulation.
Now if you want to know your wall thickness you will need to calculate the extents from the resulting geometry. If your wall is aligned with the coordinate system axes this is easy (get the difference between the smallest and largest X, Y and Z). If it is not, you might need to transform the points or look further into 3D-extent calculations (my knowledge ends there).
In a triangulation it's roughly num of triangles = 2 * num of vertices.
A wall (e.g. a rectangle) may be described by two triangles that share an edge and the two vertices of this edge.
Instead of describing the whole model triangle by triangle, each with its three vertices, or edge by edge, it's cheaper, avoids repeating vertex data, to set an index for each vertex and set a triangle by the three indices of its vertices. This is usually called "indexed rendering".

3D rotations to connect balls and cylinders

I've been tasked with writing a python based plugin for a graph drawing program that generates an STL model of a graph. A graph being an object made up of vertices and edges, where a vertex is represented by a 3D ball (a tessellated icosahedron), and an edge is represented with a cylinder that connects with two balls at either end. The end result of the 3D model is that it will get dumped out to an STL file for 3D printing. I'm able to generate the 3D models for the balls and cylinders without any issues, but I'm having some issues generating the overall model, and getting the balls and cylinders to connect properly.
My original idea was to create tessellated icosahedrons at the origin, then translate them out to the positions of the vertices. This works fine. I then, for each edge, I would create a cylinder at the origin, rotate it to the correct angle so that it points in the correct direction, then translate it to the midpoint between the two vertices so that the ends of the cylinders are embedded in the icosahedrons. This is where things are going wrong. I'm having some difficulties getting the rotations correct. To calculate the rotations, I'm doing the following:
First, I find the angle between the two points as follows (where source and target are both vertices in the graph, belonging to the edge that I'm currently processing):
deltaX = source.x - target.x
deltaY = source.y - target.y
deltaZ = source.z - target.z
xyAngle = math.atan2(deltaX, deltaY)
xzAngle = math.atan2(deltaX, deltaZ)
yzAngle = math.atan2(deltaY, deltaZ)
The angles being calculated seem reasonable, and as far as I can tell, do actually represent the angle between the vertices. For example, if I have a vertex at (1, 1, 0) and another vertex at (3, 3, 0), the angle edge connecting them does show up as a 45 degree angle between the two vertices. (That, or -135 degrees, depending which vertex is the source and which is the target).
Once I have the angles calculated, I create a cylinder and rotate it by the angles that have been calculated, like so, using some other classes that I've created:
c = cylinder()
c.createCylinder(edgeThickness, edgeLength)
c.rotateX(-yzAngle)
c.rotateY(xzAngle)
c.rotateZ(-xyAngle)
c.translate(edgePosition.x, edgePosition.y, edgePosition.z)
(Where edgePosition is the midpoint between the two vertices in the graph, edgeThickness is the radius of the cylinder being created, and edgeLength is the distance between the two vertices).
As mentioned, its the rotating of the cylinders that doesn't work as expected. It seems to do the correct rotation on the x/y plane, but as soon as an edge has vertices that differ in all three components (x, y, and z), the rotation fails. Here's an example of a graph that differs in the x, and y components, but not in the z component:
And here's the resulting STL file, as seen in Makerware (which is used to send the 3D models to the 3D printer):
(The extra cylinder looking bit in the bottom left is something I've currently left in for testing purposes - a cylinder that points in the direction of the z axis, located at the origin).
If I take that same graph and move the middle vertex out in the z axis, so now all the edges involve angles in all three axis, I get a result something like the following:
As show in the app:
The resulting STL file, as show in Makerware:
...and that same model as viewed from the side:
As you can see, the cylinders definitely aren't meeting up with the balls like I thought they would. My question is this: Is my approach to doing this flawed, or is it some small but critical mistake that I'm making somewhere in my rotations? I'm pretty sure it isn't a problem with the rotation functions themselves, as I've been able to independently verify that they work as expected. I also tried creating a rotate function that takes in a yaw, pitch, and roll and does all three at once, and it seemed to generate the same result, like so:
c.rotateYawPitchRoll(xzAngle, -yzAngle, -xyAngle)
So... anyone have any ideas on what I might be doing wrong?
UPDATE: As joojaa pointed out, it was a combination of calculating the correct angles as well as the order that they were applied. In order to get things working, I first calculate the rotation on the x axis, as follows:
zyAngle = math.atan2(deltaVector.z, deltaVector.y)
where deltaVector is the difference between the target and source vectors. This rotation is not yet applied though! The next step is to calculate the rotation on the y axis, as follows:
angle = vector.angleBetweenVectors(vector(target.x - source.x, target.y - source.y, target.z - source.z), vector(target.x - source.x, target.y - source.y, 0.0))
Once both rotations are calculated, they are then applied... in the reverse order! First, the x, then the y:
c.rotateY(angle)
c.rotateX(-zyAngle) #... where c is a cylinder object
There still seems to be a few bugs, but this seems to at least work for a simple test case.
Rotation happens in successive order, so the angles affect each other. It is not possible to use a Euler model to rotate them at once. This is why you can not just calculate the rotations based on the first static situation. Just imagine turning a cube so that it is standing on its corner upright. Yes the first rotation is 45 but the second is not since the cube is already turned by that time (draw a each step of the sequence and see what happens). Space rotations aren't trivial.
So you need to rotate one angle then re calculate the second angle and so forth. This is also why your first rotation works right. You only need 2 rotations unless your interested in making sure the rotation around the shaft has a certain direction.
I would suggest you use axis angles or matrices instead to do this. Mainly because in axis angles this is trivial the angle is the dot between the along tube start and end vectors and the axis is the cross between those 2. You can then convert those to Euler angles if you need. But probably you can just use the matrix directly. For ideas on how conversions and how the rotation could directly be calculated see: transformations.py by Christoph Gohlke. Also see the accompanying c source.
I think i need to expand this answer a bit
There is a really easy way out for this question that sidesteps all your and many other persons problems. The answer is do not use Euler angle rotation. Ive used a lot of brainpower to try to explain Euler rotations to problems that are ultimately solved more easily without Euler rotations. To justify i will leave just one reason for this if you want more think up of some more answers.
The reason most to use Euler rotation sequences is that you probably don't understand Euler angles. There are in fact only a handful of situations where they are good. No self respecting programmer uses Euler rotations to solve this issue. What you do is you use vector math instead.
So you have the direction vector from the source to target which is usually calculated:
along = normalize(target-source)
this is simply one of your matrix rows (or column notation is up to model maker), the one that corresponds to your cylinders original direction (the rows are just x y z w), then you need another vector perpendicular to this one. Choose a arbitrary vector like up (or left if your along is pointing close to up). cross product this up vector by your along for the second row direction. and finally put your source as the last row with 1 in the last column. Done fully formed affine matrix describing the cylinders prition. Much easier to understand since you can draw the vectors.
There are shorter ways but this one is easy to understand.

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