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how to I make the code to print the numbers given and and show what it equals

I tried to make just add print(a+b) and I only got what it equals I don't know what to do I can't find it or look for it online.

You are mixing up printing a string vs. printing an expression.
Printing a string like print('hello world') will print the literal message because you've indicated it's a string with quotes.
However, if you provide an expression like print(a+b), it will evaluate that expression (calculate the math) and then print the string representation of that evaluation.
Now, what you want is actually a mix of both, you want to print a string that has certain parts replaced with an expression. This can be done by "adding" strings and expressions together like so:
print(a + '+' + b + '=' + (a+b))
Notice the difference between + without quotes and '+' with quotes. The first is the addition operator, the second is the literal plus character. Let's break down how the print statement parses this. Let's say we have a = 5 and b = 3. First, we evaluate all the expressions:
print(5 + '+' + 3 + '=' + 8)
Now, we have to add a combination of numbers with strings. The + operator acts differently depending on context, but here it will simply convert everything into a string and then "add" them together like letters or words. Now it becomes something like:
print('5' + '+' + '3' + '=' + '8')
Notice how each number is now a string by the surrounding quotes. This parses to:
print('5+3=8')
which prints the literal 5+3=8

You mean like that:
a = int(input("Give me a number man: "))
b = int(input("Give me another number: "))
print(f'print({a} + {b}) = {a + b}')
print(f'print({a} - {b}) = {a - b}')
print(f'print({a} * {b}) = {a * b}')
print(f'print({a} // {b}) = {a // b}')
print("Look at all those maths!")
Output
Give me a number man: 3
Give me another number: 2
print(3 + 2) = 5
print(3 - 2) = 1
print(3 * 2) = 6
print(3 // 2) = 1
Look at all those maths!

How can I add a if statement that goes back in string if there is a number, and to stop if there is something other than a number?

So let's say I have a string, like this:
string = '12345+67890'
I want to go back to search for that plus, and add a letter 'H', so the end result would be like this:
string = '12345+h67890
Also, what if I want to get the latest +, so if there is two +'s, I want to get the last +?
Any help would be appreciated!

You could use reverse split to split on the last instance of +, then join with +H:
>>> '+H'.join('123+456+789'.rsplit('+',1))
'123+456+H789'

Convert into list, iterate through list, when you find the plus add an 'h' into the next index.
string = '12345+67890'
stringList = list(string)
i = 0
newString = ''
for i in range(len(stringList)):
if stringList[i] == '+':
stringList.insert(i+1,'h')
for letter in stringList:
newString += letter
print(newString)

Since you asked how to do it with if statements:
i = -1
for i in range(len(my_str)):
if my_str[i] == '+':
plus = i+1 # <- will update every time you see a + symbol
if i != -1:
my_str = my_str[:i] + 'h' + my_str[i:]
Alternatively, you can search backwards:
i = -1
for i in reversed(range(len(my_str))):
if my_str[i] == '+':
plus = i+1 # <- will update every time you see a + symbol
break
if i != -1:
my_str = my_str[:i] + 'h' + my_str[i:]
As others have mentioned you can use built-in functions like find and rfind. My personal choice is to refer to regular expressions for this type of thing:
import re
my_str = re.sub('(.*\+)(.*)',r"\1h\2", my_str))

Adding blank spaces to a list of strings at a specific position

I am trying to process a list of strings in order to get all my strings with 8 characters. If a string has less than 8 characters I fill as many blank spaces as needed to get an 8 character long string before the last 4 characters. I wrote the following function and tried to apply it to a list of strings, but got a list with None values.
def lengthstring(string):
if len(string) == 5:
new_string = string[0] + " " + string[1:5]
elif len(string) == 6:
new_string = string[0:2] + " " + string[2:6]
elif len(string) == 7:
new_string = string[0:3] + " " + string[3:7]
else:
new_string = string
lp = ['7C246', '7B8451', 'NDKW0745', '5B06833']
labels_with_eight_characters = [lengthstring(string) for string in lp]
Thank you!

Just in case you need a more concise version of the code:
def lengthstring(string):
return (
string if len(string) >= 8
else string[:-4] + ' ' * (8 - len(string)) + string[-4:])
labels_with_eight_characters = list(map(lengthstring, lp))
print(labels_with_eight_characters)
This prints:
['7 C246', '7B 8451', 'NDKW0745', '5B0 6833']

This is because you did not return values in your lengthstring function. After new_string = string, add return new_string and your code should run fine.

a little easier would be to use rjust...
for loc in lp:
print(loc.rjust(8, ' '))

How can I remove the hyphen at the end?

Heres my code
#!/usr/bin/env python
s = raw_input()
n = input()
x = (s + " ") * n
def remove(x):
return x.replace(" ","-")
print remove(x)
Basically its like this
s = abc
n = 2
I want to print abc-abc
but I end up getting abc-abc-
don't know how to do this.

n = input()
x = (s + " ") * n
Assuming you enter 'abc' and '2', the string becomes 'abc abc ' (Note the space at the end). When you replace with -, it replaces the trailing space with a -. A very quick solution would be to use
x.replace(" ", "-", n-1)
The third parameter is the count, so it will replace all but the trailing space.

This code will do the job
'-'.join([s]*n)
for your data it will be abc-abc

How about this solution:
#!/usr/bin/env python
s = raw_input()
n = input()
x = (s + " ") * (n-1)
x += s
def remove(x):
return x.replace(" ","-")
print remove(x)
So the last 's' would not add any space to x and therefor there is no space at the end to turn into a hyphen.

Python: count word lenth in site name

Got stuck with a part of the python script. For example I got 2 domain names like:
domain.com
new.domain1.us
is it possible to count word lenght of every word, splited with dot and put the lenght in brackets before every word like:
(6)domain(3)com
(3)new(7)domain1(2)us

string = 'domain.com'
answer = ''
for x in string.split('.'):
answer += '(' + str(len(x)) + ')' + x
print(answer)

The method split() will split the string at the given char into an array of strings.
len() will return you the length of the given string/array/...
With these two functions you can solve your problem:
domain = "www.google.de"
split_domain = domain.split('.')
domain_with_len = ""
for part in split_domain:
domain_with_len += "(" + str(len(part)) + ")" + part
if you print the domain_with_len you get the following result:
(3)www(6)google(2)de