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Error when adding many-to-many-field on Post

I have an app within my project called posts, where inside their in the models.py, I have two models: Post and Like.
I want to add a many-to-many-field on the post that references the Like model.
I have executed makemigrations and migrate, however I am getting this error:
NameError: name 'Like' is not defined
models.py:
class Post(models.Model):
file = models.ImageField(upload_to='images/')
summary = models.TextField(max_length=600)
pub_date = models.DateTimeField(auto_now=True)
user = models.ForeignKey(User, on_delete=models.CASCADE)
likes = models.ManyToManyField(Like)
def __str__(self):
return self.user.username
def summary_pretty(self):
return self.summary[:50]
def pub_date_pretty(self):
return self.pub_date.strftime('%b %e %Y')
class Like(models.Model):
post = models.ForeignKey(Post, on_delete=models.CASCADE)
user = models.ForeignKey(User, on_delete=models.CASCADE)
status = models.BooleanField(default=False)

it says
NameError: name 'Like' is not defined
because you must move Like model above Post model it hasn't been defined yet in your code in that line (python code is interpreted)
and it's not a good thing to design database models like that based on:
Why should I avoid loops when designing relationships for a database?
so delete the Post foreign key in Like model and you can retrieve a like's post with reverse lookup
you can find more about it in django official docs:
Lookups that span relationships
and also
Many-to-many relationships

You're referencing the class Like before initiating it in your Python file. Hence "Like" is not defined.
likes = models.ManyToManyField(Like)
You need to delete "likes" from your Post class. That will fix the error.
As for your code, I think you're misunderstanding why we use Intermediary Tables. You don't need to reference Like in your Post class. You've already established that relationship in the Like Class:
post = models.ForeignKey(Post, on_delete=models.CASCADE)
Retrieving the users who have liked a post is as simple as writing a filter on the Likes table.
#views.py
from models import Post, Like
post_id = 1
likes = Like.objects.filter(post=post_id)

manytomany field not working django-cms

I am using django-cms
many to many field is working fine when i add plugins or update but
after publish page i didn't get any data where i add many to many field.
models are look like this
#python_2_unicode_compatible
class ClientLogo(CMSPlugin):
client_logo = models.ManyToManyField(LogoPluginModel, blank=True)
class LogoPluginModel(CMSPlugin):
title = models.CharField(max_length=100)
here field 'client_logo' will be disapper when i publish djagno-cms page

The relations need to be explicitly copied through the copy_relations method (see django-cms models manual). It's also advantageous to add a related_name property to the ManyToManyField, especially when a model contains multiple sets of foreign keys or ManyToManyFields.
#python_2_unicode_compatible
class ClientLogo(CMSPlugin):
client_logo = models.ManyToManyField(
LogoPluginModel,
blank=True,
related_name='client_logos',
)
class LogoPluginModel(CMSPlugin):
title = models.CharField(max_length=100)
def copy_relations(self, oldinstance):
self.client_logos.all().delete()
for logo in oldinstance.client_logos.all():
logo.pk = None
logo.showroom = self
logo.save()

Resource nesting with tastypie

Trying to do something pretty simple with tastypie, but cannot figure out how. Lets say I have a model Author and a mode Book with a foreign key pointing to author. And I have an Author resource. So, /api/v1/author would get me a list of authors and /api/v1/author/1 would get me details on a particular author. I want /api/v1/author/1/books to get me a list of books for this particular author. How?
Example code:
from django.db import models
from tastypie.resource import ModelResource
class Author(models.Model):
name = models.CharField(max_length=200)
class Book(models.Model):
title = models.CharField(max_length=200)
author = models.ForeignKey('Author')
class AuthorResource(ModelResource):
queryset = Author.objects.all()

Looks like the recipe for this was actually in the cookbook, but for something so obvious, the implementation is rather awkward.
http://django-tastypie.readthedocs.org/en/latest/cookbook.html#nested-resources

Python Django how to retrieve specific objects

I've got this Post model at the moment:
class Post(models.Model):
title = models.CharField(max_length = 140)
body = models.TextField()
date = models.DateTimeField()
def __unicode__(self):
return self.title
If I've got different parts of a website (or a forum rather) that contain different posts, e.g. Discussion about basketball, and Discussion about football, if I wanted to return just posts concerning basketball or just posts concerning football, is the easiest way to just make a specific basketball_post model/football_post model or is there a more efficient way? Should I perhaps be storing the values differently?
Thanks

Django has a really good tutorial. It is about making a Poll app. In the first chapter the thing you want is discussed. It is about a Question that can have multiple Choices.:
class Question(models.Model):
question_text = models.CharField(max_length=200)
pub_date = models.DateTimeField('date published')
class Choice(models.Model):
question = models.ForeignKey(Question)
choice_text = models.CharField(max_length=200)
votes = models.IntegerField(default=0)
The foreignKey creates a relation between two models. The same can be done for a blog:
class Category(models.Model):
title = models.CharField(max_length=200)
class Post(models.Model):
category = models.ForeignKey(Category) # This is the important part.
title = models.CharField(max_length=200)
body = models.TextField()
date = models.DateTimeField()
def __unicode__(self):
return self.title
The ForeignKey relation lets you do really nice things:
basketball_posts = Post.objects.filter(category_title='Basketball')
But before we all tell you how it is done, I really recommend to do the tutorial. It introduces you to all important Django concepts: https://docs.djangoproject.com/en/1.7/intro/tutorial01/
Update
If you have a fixed set of categories that are not likely to change, than you can hardcode them and use field choices:
class Post(models.Model):
FOOTBALL = 'F' # Variable name and db_value
CRICKET = 'C'
INTRODUCTION = 'I'
CATEGORY_CHOICES = (
(FOOTBALL, 'Soccer'), # Variable name and display value
(CRICKET, 'Cricket'),
(INTRODUCTION, 'Hello my name is'),
)
category = models.CharField(max_length=1,
choices=CATEGORY_CHOICES,
default=INTRODUCTION)
...
https://docs.djangoproject.com/en/dev/ref/models/fields/#choices
One of the advantages of this 'choice machinery' over a CharField without pre defined choices is that you are sure what values end up in your database. This lets you query them, without worrying if your data is sane:
Post.objects.filter(category=Post.CRICKET)
Use the extra table if you need the freedom to create new categories in the future. Use field choices if you don't want (or need) that freedom.

I would suggest to just add a field which makes the post relevant to that certain topic:
class Post(models.Model):
title = models.CharField(max_length = 140)
body = models.TextField()
date = models.DateTimeField()
type = models.CharField(max_length=20) #<--- new field: e.g 'basketball','hockey'..
def __unicode__(self):
return self.title
example query:
#basketball posts
qs = Post.objects.filter(type__icontains="basketball")
then you dont need to have multiple models which also would be redundant.

Assuming all of the posts are in the same format, you could add another field to your model like "type". Different discussion forums could send a different values for that field when the post is added.
type = models.CharField(max_length=140, choices=['Football', 'Basketball', 'Baseball'])
Storing this would make it easy to filter which posts are which.
Post.objects.filter(type = 'Football')

Assuming that one post can be about only one sport, the better approach would be to have a foreign key relation between a model that stores data about a post with another model that stores the data about sports.
Something like this
class Sport(models.Model):
name = models.CharField(max_length = 200)
description = models.TextField()
def __unicode__(self):
return self.name
class Post(models.Model):
title = models.CharField(max_length = 140)
body = models.TextField()
date = models.DateTimeField()
sport = models.ForeignKey(Sport)
def __unicode__(self):
return self.title
This gives you the advantage of isolating the 'Sport' and the 'Post' models.You can add as many sports as you want, without any posts referring to it.
One more advantage is that you can add relevant information to the relevant models.
Eg:Suppose you want to add the information about "how many players are there in a team for sport x?". You can easily achieve this by adding a field "number_of_players" in the 'Sport' model without affecting the 'Post' model.
If you had to do this in one model, 'Post', then it would create lot of issues in terms of data consistency and other undesirable things.
Also, the query will look something like this:
posts = Post.objects.filter(sport__name = "Basketball")
PS:If your requirement is that a post can be tagged to multiple sports, then you can use ManyToMany field instead of a simple foreign key.
https://docs.djangoproject.com/en/dev/topics/db/examples/many_to_many/

You could assign your posts tags or category, and filter on those.
If you use the model approach what happens when you add more sports? You'll need manually add the sports in your code, using a tags or category approach allows you to handle it in the db, and would then allow you to filter on the tags/categories in your system

Django multiple tag field

I'm trying to find a good tutorial for django how to create multiple tags in a model.
For example:
class Tag(models.Model):
name = models.CharField()
class Sample(models.Model):
name = models.CharField()
urlA = models.CharField()
urlB = models.CharField()
tagA = models.ManyToManyField(Tag)
tagB = models.ManyToManyField(Tag)
I would like to display the tags as an input field and separate by ',' and split in the save method. So I'd like to see 2 different input for the 2 tag field.
If you have an easy way to do or know a good tutorial, please tell me! :)
Thank you guys!

Edit: you do not have to have the actual table sets over laid. You can generate any queryset you want to inn your views. Your url conf can be set up to display the detail view from multiple url. If i am still not understanding then please refine your question.
For having multiple anything tags categories your either going m21 or m2m. So when you create your tags you can add them one by one. Are you familiar with what the Django ORM has to offer with some of its admin functionality? Please give the documentation a good look through. Your approach to this problem is anything but reasonable. Not trying to rub you the wrong way I'm no genius. You would do something like so.
class Tag(models.Model):
title = models.CharField(max_length=250, blank=True)
slug = models.SlugField(blank=True
class Meta:
verbose_name = "tag"
verbose_name_plural = "tags"
ordering = ['title']
#models.permalink
def get_absolute_url(self):
return "/tags/%s/" % self.slug
class Entry(models.Model):
title = models.CharField(max_length=250, blank=True)
body = models.TextField()
tags = models.ManyToMany('Tag')
slug = models.SlugField()
#models.permalink
def get_absolute_url(self):
return "/blog/%s/" % self.slug
There's a little more code to be done for the EntryAdmin and the TagAdmin models, Many other things that can be done as well. I am not sure what you are trying to achieve with that if you could be more clear? Thank you, the above is a rough illustration of how I would approach it.

I found a solution from here:
https://dev.to/thepylot/how-to-add-tags-to-your-models-in-django-django-packages-series-1-3704
django-taggit is very useful for tagging.
It is
a reusable application that primarily offers you a Tag model, and a manager for easily adding tags to any model.
pip install django-taggit
After that, open settings.py and edit the installed apps section:
INSTALLED_APPS = [
...
'taggit'
]
After that, edit your model and add tags like this:
tags = TaggableManager()
The TaggableManager will show up automatically as a field in a ModelForm or in the admin.
Documentation: https://django-taggit.readthedocs.io/en/latest/index.html