Is there anyway I can parse a website by just viewing the content as displayed to the user in his browser? That is, instead of downloading "page.htm"l and starting to parse the whole page with all the HTML/javascript tags, I will be able to retrieve the version as displayed to users in their browsers. I would like to "crawl" websites and rank them according to keywords popularity (viewing the HTML source version is problematic for that purpose).
Thanks!
Joel
A browser also downloads the page.html and then renders it. You should work the same way. Use a html parser like lxml.html or BeautifulSoup, using those you can ask for only the text enclosed within tags (and arguments you do like, like title and alt attributes).
You could get the source and strip the tags out, leaving only non-tag text, which works for almost all pages, except those where JavaScript-generated content is essential.
The pyparsing wiki Examples page includes this html tag stripper.
Related
A newbie to Python here. I want to extract info from multiple websites (e.g. 100+) from a google search page. I just want to extract the key info, e.g. those with <h1>, <h2> or <b> or <li> HTML tags etc. But I don't want to extract the entire paragraph <p>.
I know how to gather a list of website URLs from that google search; and I know how to web scrape individual website after looking at the page's HTML. I use the Request and BeautifulSoup for these tasks.
However, I want to know how can I extract key info from all these (100+ !) websites without having to look at their html one by one. Is there a way to automatically find out the HTML tags the website used to emphasize key messages? e.g. some websites may use <h1>, while some may use <b> , or something else...
All I can think of is to come up with a list of possible "emphasis-typed" HTML tags and then just use BeautifulSoup.find_all() to do a wide-scale extraction. But surely there must be an easier way?
It would seem that you must first learn how to do loops and function first. Every website is completely different and scraping a website alone to extract useful information is daunting. I'm a newb myself, but if I have to extract info from headers like you, this is what I would do: (this is just concept code, but hope you'll find it useful)
def getLinks(articleUrl):
html = urlopen('http://en.web.com{}'.format(articleUrl))
bs = BeautifulSoup(html, 'html.parser')
return bs.find('h1', {'class':'header'}).find_all('h1',
header=re.compile('^(/web/)((?!:).)*$'))
I'm making a twitterbot for an honors project and have it almost completed. However, when I scrape the website for a specific URL, the href refers to a link that looks like this:
?1dmy&urile=wcm%3apath%3a%2Fohio%2Bcontent%2Benglish%2Fcovid-19%2Fresources%2Fnews-releases-news-you-can-use%2Fnew-restartohio-opening-dates
When inspecting the html and hovering over the href contents above, it shows that the above is actually the tail-end of the link. Is there any way to take this data and make it into a usable link? Other links within the same carousal provide full links on the same website, so I'm not sure why this is different than the others.
I tried searching for answers to this question but came up short: sorry if this is a repeat.
BeautifulSoup is showing you what the HTML of the page has. If the link is relative, you need the base URL for the page. That should come back in your request result, not in the HTML itself.
We use NLTK to extract text from HTML pages, but we want only most trivial text analysis, e.g. word count.
Is there a faster way to extract visible text from HTML using Python?
Understanding HTML (and ideally CSS) at some minimal level, like visible / invisible nodes, images' alt texts, etc, would be additionally great.
Ran into the same problem at my previous workplace. You'll want to check out beautifulsoup.
from bs4 import BeautifulSoup
soup = BeautifulSoup(html)
print soup.text
You'll find its documentation here: https://www.crummy.com/software/BeautifulSoup/bs4/doc/
You can ignore elements based on attributes. As to understanding external stylesheets im not too sure. However what you could do there and something that would not be too slow (depending on the page) is to look into rendering the page with something like phantomjs and then selecting the rendered text :)
I have a folder full of HTML documents that are saved copies of webpages, but i need to know what site they came from, what function can i use to extract the website name from the documents? I did not find anything in the BeautifulSoup module. Is there a specific that i should be looking for in the document? I do not need to know the full url i just need to know the name of the website.
You can only do that if the url is mentioned somewhere in the source...
First find out where the url is if it is mentioned. If it's there it'll probably be in the base tag. Sometimes websites have nice headers with a link to their landing page which could be used if all you want is the domain. Or it could be in a comment somewhwere depending on how you saved it.
If the way the url is mentioned is similar in all the pages then your job is easy: Either use re or BeautifulSoup or lxml and xpath to grab the info you need. There are other tools available but either of those will do.
How would I look for all URLs on a web page and then save them to individual variables with urllib2 In Python?
Parse the html with an html parser and find all (e.g. using Beutiful Soup's findAll() method) <a> tags and check their href attributes.
If, however, you want to find all URLs in the page even if they aren't hyperlinks, then you can use a regular expression which could be anything from simple to ridiculously insane.
You don't do it with urllib2 alone. What are you looking for is parsing urls in a web page.
You get your first page using urllib2, read its contents and then pass it through parser like Beautifulsoup or as the other poster explained, you can regex to search the contents of the page too.
You could simply download the raw html with urllib2, then simply search through it. There might be easier ways but you could do this:
1:Download the source code.
2:Use strings library to split it into a list.
3:Search the first 7 characters of each section-->
4:If the first 7 characters are http://, write that to a variable.
Why do you need separate variables though? Wouldn't it be easier to save them all to a list, using list.append(URL_YOU_JUST_FOUND), every time you find another url?