Python timer countdown - python

I want to know about timer in Python.
Suppose i have a code snippet something like:
def abc()
print 'Hi'
print 'Hello'
print 'Hai'
And i want to print it every 1 second. Max three times;ie; 1st second i need to check the printf, 2nd second I need to check as well in 3rd second.
In my actual code variables value will be updated.
I need to capture at what second all the variables are getting updated.
Can anybody tell me how to do this.

time.sleep is fine in this case but what if the abc() function takes half a second to execute? Or 5 minutes?
In this case you should use a Timer object.
from threading import Timer
def abc():
print 'Hi'
print 'Hello'
print 'Hai'
for i in xrange(3):
Timer(i, abc).start()

Use time.sleep.
import time
def abc():
print 'Hi'
print 'Hello'
print 'Hai'
for i in xrange(3):
time.sleep(1)
abc()

You should look into time.sleep(). For example:
for i in xrange(5):
abc()
time.sleep(3)
That will print your lines 5 times with a 3 second delay between.

import time
def abc()
for i in range(3):
print 'Hi'
print 'Hello'
print 'Hai'
time.sleep(1)

import time
def abc():
print 'Hi'
print 'Hello'
print 'Hai'
for i in range(3):
time.sleep(3-i)
abc()

usually for me this works...
import time
def abc():
print 'Hi'
time.sleep(1)
print 'Hello'
time.sleep(1)
print 'Hai'
time.sleep(1)
I think you can guess after that...

import sys
import time
c=':'
sec = 0
min = 0
hour = 0
#count up clock
while True:
for y in range(59): #hours
for x in range (59): #min
sec = sec+1
sec1 = ('%02.f' % sec) #format
min1 = ('%02.f' % min)
hour1= ('%02.f' % hour)
sys.stdout.write('\r'+str(hour1)+c+str(min1)+c+str(sec1)) #clear and write
time.sleep(1)
sec = 0
sys.stdout.write('\r' + str(hour1) + c + str(min1) + c + '00') #ensure proper timing and display
time.sleep(1)
min=min+1
min = 0
sys.stdout.write('\r' + str(hour1) + c + str(min1) + c + '00') #ensure proper timing and display
time.sleep(1)
hour=hour+1

Related

How could I overwrite (or update) only a single line of output string on command prompt in Python? [duplicate]

How do I use a progress bar when my script is doing some task that is likely to take time?
For example, a function which takes some time to complete and returns True when done. How can I display a progress bar during the time the function is being executed?
Note that I need this to be in real time, so I can't figure out what to do about it. Do I need a thread for this? I have no idea.
Right now I am not printing anything while the function is being executed, however a progress bar would be nice. Also I am more interested in how this can be done from a code point of view.
With tqdm (conda install tqdm or pip install tqdm) you can add a progress meter to your loops in a second:
from time import sleep
from tqdm import tqdm
for i in tqdm(range(10)):
sleep(3)
60%|██████ | 6/10 [00:18<00:12, 0.33 it/s]
Also, there is a notebook version:
from tqdm.notebook import tqdm
for i in tqdm(range(100)):
sleep(3)
You can use tqdm.auto instead of tqdm.notebook to work in both a terminal and notebooks.
tqdm.contrib contains some helper functions to do things like enumerate, map, and zip. There are concurrent maps in tqdm.contrib.concurrent.
You can even get progress sent to your phone after disconnecting from a jupyter notebook using tqdm.contrib.telegram or tqdm.contrib.discord.
There are specific libraries (like this one here) but maybe something very simple would do:
import time
import sys
toolbar_width = 40
# setup toolbar
sys.stdout.write("[%s]" % (" " * toolbar_width))
sys.stdout.flush()
sys.stdout.write("\b" * (toolbar_width+1)) # return to start of line, after '['
for i in range(toolbar_width):
time.sleep(0.1) # do real work here
# update the bar
sys.stdout.write("-")
sys.stdout.flush()
sys.stdout.write("]\n") # this ends the progress bar
Note: progressbar2 is a fork of progressbar which hasn't been maintained in years.
Use alive-progress, the coolest progress bar ever!
To use any progress bar framework in a useful manner, i.e. to get a percentage of completion and an estimated time of arrival (ETA), you need to be able to tell how many steps your processing will have.
Then you can just insert an yield to mark an item has been processed, and you're good to go!
def compute():
for i in range(1000):
... # process items as usual.
yield # insert this :)
Then just use it like:
from alive_progress import alive_bar
with alive_bar(1000) as bar:
for i in compute():
bar()
To get an awesome and alive progress bar!
|█████████████▎ | ▅▃▁ 321/1000 [32%] in 8s (40.1/s, eta: 16s)
Disclosure: I'm the author of alive-progress, but it should solve your problem nicely! Read the documentation at https://github.com/rsalmei/alive-progress to know more. Now it works also on Jupyter Notebooks! Here are some more examples of what it can do:
No external packages. A ready-made piece of code.
You can customize bar progress symbol "#", bar size, text prefix etc.
Python 3.3+
import sys
def progressbar(it, prefix="", size=60, out=sys.stdout): # Python3.3+
count = len(it)
def show(j):
x = int(size*j/count)
print("{}[{}{}] {}/{}".format(prefix, "#"*x, "."*(size-x), j, count),
end='\r', file=out, flush=True)
show(0)
for i, item in enumerate(it):
yield item
show(i+1)
print("\n", flush=True, file=out)
Usage:
import time
for i in progressbar(range(15), "Computing: ", 40):
time.sleep(0.1) # any code you need
To fill the whole character space use a unicode u"█" char replacing "#". With for i in progressbar(range(100)): ... you get :
Doesn't require a second thread. Some solutions/packages above require.
Works with any iterable it means anything that len() can be used on. A list, a dict of anything for example ['a', 'b', 'c' ... 'g']
Works with generators only have to wrap it with a list(). For example for i in progressbar(list(your_generator), "Computing: ", 40): Unless the work is done in the generator. In that case you need another solution (like tqdm).
You can also change output by changing out to sys.stderr for example.
Python 3.6+ (f-string)
def progressbar(it, prefix="", size=60, out=sys.stdout): # Python3.6+
count = len(it)
def show(j):
x = int(size*j/count)
print(f"{prefix}[{u'█'*x}{('.'*(size-x))}] {j}/{count}", end='\r', file=out, flush=True)
show(0)
for i, item in enumerate(it):
yield item
show(i+1)
print("\n", flush=True, file=out)
Python 2 (old-code)
import sys
def progressbar(it, prefix="", size=60, out=sys.stdout):
count = len(it)
def show(j):
x = int(size*j/count)
out.write("%s[%s%s] %i/%i\r" % (prefix, u"#"*x, "."*(size-x), j, count))
out.flush()
show(0)
for i, item in enumerate(it):
yield item
show(i+1)
out.write("\n")
out.flush()
The above suggestions are pretty good, but I think most people just want a ready made solution, with no dependencies on external packages, but is also reusable.
I got the best points of all the above, and made it into a function, along with a test cases.
To use it, just copy the lines under "def update_progress(progress)" but not the test script. Don't forget to import sys. Call this whenever you need to display or update the progress bar.
This works by directly sending the "\r" symbol to console to move cursor back to the start. "print" in python does not recongise the above symbol for this purpose, hence we need 'sys'
import time, sys
# update_progress() : Displays or updates a console progress bar
## Accepts a float between 0 and 1. Any int will be converted to a float.
## A value under 0 represents a 'halt'.
## A value at 1 or bigger represents 100%
def update_progress(progress):
barLength = 10 # Modify this to change the length of the progress bar
status = ""
if isinstance(progress, int):
progress = float(progress)
if not isinstance(progress, float):
progress = 0
status = "error: progress var must be float\r\n"
if progress < 0:
progress = 0
status = "Halt...\r\n"
if progress >= 1:
progress = 1
status = "Done...\r\n"
block = int(round(barLength*progress))
text = "\rPercent: [{0}] {1}% {2}".format( "#"*block + "-"*(barLength-block), progress*100, status)
sys.stdout.write(text)
sys.stdout.flush()
# update_progress test script
print "progress : 'hello'"
update_progress("hello")
time.sleep(1)
print "progress : 3"
update_progress(3)
time.sleep(1)
print "progress : [23]"
update_progress([23])
time.sleep(1)
print ""
print "progress : -10"
update_progress(-10)
time.sleep(2)
print ""
print "progress : 10"
update_progress(10)
time.sleep(2)
print ""
print "progress : 0->1"
for i in range(101):
time.sleep(0.1)
update_progress(i/100.0)
print ""
print "Test completed"
time.sleep(10)
This is what the result of the test script shows (The last progress bar animates):
progress : 'hello'
Percent: [----------] 0% error: progress var must be float
progress : 3
Percent: [##########] 100% Done...
progress : [23]
Percent: [----------] 0% error: progress var must be float
progress : -10
Percent: [----------] 0% Halt...
progress : 10
Percent: [##########] 100% Done...
progress : 0->1
Percent: [##########] 100% Done...
Test completed
Try progress from https://pypi.python.org/pypi/progress.
from progress.bar import Bar
bar = Bar('Processing', max=20)
for i in range(20):
# Do some work
bar.next()
bar.finish()
The result will be a bar like the following:
Processing |############# | 42/100
for a similar application (keeping track of the progress in a loop) I simply used the python-progressbar:
Their example goes something like this,
from progressbar import * # just a simple progress bar
widgets = ['Test: ', Percentage(), ' ', Bar(marker='0',left='[',right=']'),
' ', ETA(), ' ', FileTransferSpeed()] #see docs for other options
pbar = ProgressBar(widgets=widgets, maxval=500)
pbar.start()
for i in range(100,500+1,50):
# here do something long at each iteration
pbar.update(i) #this adds a little symbol at each iteration
pbar.finish()
print
I've just made a simple progress class for my needs after searching here for a equivalent solution. I thought I might a well post it.
from __future__ import print_function
import sys
import re
class ProgressBar(object):
DEFAULT = 'Progress: %(bar)s %(percent)3d%%'
FULL = '%(bar)s %(current)d/%(total)d (%(percent)3d%%) %(remaining)d to go'
def __init__(self, total, width=40, fmt=DEFAULT, symbol='=',
output=sys.stderr):
assert len(symbol) == 1
self.total = total
self.width = width
self.symbol = symbol
self.output = output
self.fmt = re.sub(r'(?P<name>%\(.+?\))d',
r'\g<name>%dd' % len(str(total)), fmt)
self.current = 0
def __call__(self):
percent = self.current / float(self.total)
size = int(self.width * percent)
remaining = self.total - self.current
bar = '[' + self.symbol * size + ' ' * (self.width - size) + ']'
args = {
'total': self.total,
'bar': bar,
'current': self.current,
'percent': percent * 100,
'remaining': remaining
}
print('\r' + self.fmt % args, file=self.output, end='')
def done(self):
self.current = self.total
self()
print('', file=self.output)
Example :
from time import sleep
progress = ProgressBar(80, fmt=ProgressBar.FULL)
for x in xrange(progress.total):
progress.current += 1
progress()
sleep(0.1)
progress.done()
Will print the following:
[======== ] 17/80 ( 21%) 63 to go
I like Brian Khuu's answer for its simplicity and not needing external packages. I changed it a bit so I'm adding my version here:
import sys
import time
def updt(total, progress):
"""
Displays or updates a console progress bar.
Original source: https://stackoverflow.com/a/15860757/1391441
"""
barLength, status = 20, ""
progress = float(progress) / float(total)
if progress >= 1.:
progress, status = 1, "\r\n"
block = int(round(barLength * progress))
text = "\r[{}] {:.0f}% {}".format(
"#" * block + "-" * (barLength - block), round(progress * 100, 0),
status)
sys.stdout.write(text)
sys.stdout.flush()
runs = 300
for run_num in range(runs):
time.sleep(.1)
updt(runs, run_num + 1)
It takes the total number of runs (total) and the number of runs processed so far (progress) assuming total >= progress. The result looks like this:
[#####---------------] 27%
You can use tqdm:
from tqdm import tqdm
with tqdm(total=100, desc="Adding Users", bar_format="{l_bar}{bar} [ time left: {remaining} ]") as pbar:
for i in range(100):
time.sleep(3)
pbar.update(1)
In this example the progress bar is running for 5 minutes
and it is shown like that:
Adding Users: 3%|█████▊ [ time left: 04:51 ]
You can change it and customize it as you like.
I really like the python-progressbar, as it is very simple to use.
For the most simple case, it is just:
import progressbar
import time
progress = progressbar.ProgressBar()
for i in progress(range(80)):
time.sleep(0.01)
The appearance can be customized and it can display the estimated remaining time. For an example use the same code as above but with:
progress = progressbar.ProgressBar(widgets=[progressbar.Bar('=', '[', ']'), ' ',
progressbar.Percentage(), ' ',
progressbar.ETA()])
Use this library: fish (GitHub).
Usage:
>>> import fish
>>> while churning:
... churn_churn()
... fish.animate()
Have fun!
If it is a big loop with a fixed amount of iterations that is taking a lot of time you can use this function I made. Each iteration of loop adds progress. Where count is the current iteration of the loop, total is the value you are looping to and size(int) is how big you want the bar in increments of 10 i.e. (size 1 =10 chars, size 2 =20 chars)
import sys
def loadingBar(count,total,size):
percent = float(count)/float(total)*100
sys.stdout.write("\r" + str(int(count)).rjust(3,'0')+"/"+str(int(total)).rjust(3,'0') + ' [' + '='*int(percent/10)*size + ' '*(10-int(percent/10))*size + ']')
example:
for i in range(0,100):
loadingBar(i,100,2)
#do some code
output:
i = 50
>> 050/100 [========== ]
pip install progressbar2
import os
import time
import progressbar
os.environ['PYCHARM_HOSTED'] = '1' # https://github.com/WoLpH/python-progressbar/issues/237
class COLOR: # https://stackoverflow.com/a/287944/11465149
YELLOW = '\033[93m'
GREEN = '\033[92m'
RED = '\033[91m'
BOLD = '\033[1m'
ENDC = '\033[0m'
widgets=[
'FILE.JSON ',
COLOR.YELLOW , progressbar.Percentage() , COLOR.ENDC,
COLOR.RED + COLOR.BOLD, progressbar.Bar(left=' ', marker='━', right=' '), COLOR.ENDC,
COLOR.YELLOW , progressbar.Timer() , COLOR.ENDC
]
for i in progressbar.progressbar(range(100), widgets=widgets):
time.sleep(0.01)
if i == 99:
widgets[4] = COLOR.GREEN
Use enumerate(...progressbar(max_value=...) + this in case you want to use it as a download progressbar
A simple oneliner:
K = 628318
for k in range(K):
# your stuff
print(end="\r|%-80s|" % ("="*int(80*k/(K-1))))
|===================================================================== |
80 is the length of the bar. Eventually you want a final print().
It can be also put into a convencience function. Along with yield, one can emulate the behaviour of tqdm:
def progbar(iterobj):
K = len(iterobj)
for k, obj in enumerate(iterobj):
print(end="\r|%-80s|" % ("="*int(80*k/(K-1))))
yield obj
print()
raise StopIteration
for k in progbar(range(628318)):
# your stuff
pass
And not to forget the digital progress indicator:
K = 628318
for k in range(K):
# your stuff
print(end="\r%6.2f %%" % (k/(K-1)*100))
94.53 %
It is not to difficult to combine both, if needed.
The keys are the "Carriage Return" \r and the suppression of the default end="\n" in print.
The code below is a quite general solution and also has a time elapsed and time remaining estimate. You can use any iterable with it. The progress bar has a fixed size of 25 characters but it can show updates in 1% steps using full, half, and quarter block characters. The output looks like this:
18% |████▌ | \ [0:00:01, 0:00:06]
Code with example:
import sys, time
from numpy import linspace
def ProgressBar(iterObj):
def SecToStr(sec):
m, s = divmod(sec, 60)
h, m = divmod(m, 60)
return u'%d:%02d:%02d'%(h, m, s)
L = len(iterObj)
steps = {int(x):y for x,y in zip(linspace(0, L, min(100,L), endpoint=False),
linspace(0, 100, min(100,L), endpoint=False))}
qSteps = ['', u'\u258E', u'\u258C', u'\u258A'] # quarter and half block chars
startT = time.time()
timeStr = ' [0:00:00, -:--:--]'
activity = [' -',' \\',' |',' /']
for nn,item in enumerate(iterObj):
if nn in steps:
done = u'\u2588'*int(steps[nn]/4.0)+qSteps[int(steps[nn]%4)]
todo = ' '*(25-len(done))
barStr = u'%4d%% |%s%s|'%(steps[nn], done, todo)
if nn>0:
endT = time.time()
timeStr = ' [%s, %s]'%(SecToStr(endT-startT),
SecToStr((endT-startT)*(L/float(nn)-1)))
sys.stdout.write('\r'+barStr+activity[nn%4]+timeStr); sys.stdout.flush()
yield item
barStr = u'%4d%% |%s|'%(100, u'\u2588'*25)
timeStr = ' [%s, 0:00:00]\n'%(SecToStr(time.time()-startT))
sys.stdout.write('\r'+barStr+timeStr); sys.stdout.flush()
# Example
s = ''
for c in ProgressBar(list('Disassemble and reassemble this string')):
time.sleep(0.2)
s += c
print(s)
Suggestions for improvements or other comments are appreciated. Cheers!
It is quite straightforward in Python3:
import time
import math
def show_progress_bar(bar_length, completed, total):
bar_length_unit_value = (total / bar_length)
completed_bar_part = math.ceil(completed / bar_length_unit_value)
progress = "*" * completed_bar_part
remaining = " " * (bar_length - completed_bar_part)
percent_done = "%.2f" % ((completed / total) * 100)
print(f'[{progress}{remaining}] {percent_done}%', end='\r')
bar_length = 30
total = 100
for i in range(0, total + 1):
show_progress_bar(bar_length, i, total)
time.sleep(0.1)
print('\n')
When running in jupyter notebooks use of normal tqdm doesn't work, as it writes output on multiple lines. Use this instead:
import time
from tqdm import tqdm_notebook as tqdm
for i in tqdm(range(100))
time.sleep(0.5)
2022 Answer for simple progress bar without external library
import time, sys
def progress(size):
for item in range(size):
if(item==0):
print("[",end="")
elif(item==size-1):
print("]",end="\n")
else:
#main work goes here
time.sleep(0.1)
print("%",end="")
sys.stdout.flush()
progress(50)
I like this page.
Starts with simple example and moves onto a multi-threaded version. Works out of the box. No 3rd party packages required.
The code will look something like this:
import time
import sys
def do_task():
time.sleep(1)
def example_1(n):
for i in range(n):
do_task()
print '\b.',
sys.stdout.flush()
print ' Done!'
print 'Starting ',
example_1(10)
Or here is example to use threads in order to run the spinning loading bar while the program is running:
import sys
import time
import threading
class progress_bar_loading(threading.Thread):
def run(self):
global stop
global kill
print 'Loading.... ',
sys.stdout.flush()
i = 0
while stop != True:
if (i%4) == 0:
sys.stdout.write('\b/')
elif (i%4) == 1:
sys.stdout.write('\b-')
elif (i%4) == 2:
sys.stdout.write('\b\\')
elif (i%4) == 3:
sys.stdout.write('\b|')
sys.stdout.flush()
time.sleep(0.2)
i+=1
if kill == True:
print '\b\b\b\b ABORT!',
else:
print '\b\b done!',
kill = False
stop = False
p = progress_bar_loading()
p.start()
try:
#anything you want to run.
time.sleep(1)
stop = True
except KeyboardInterrupt or EOFError:
kill = True
stop = True
I used format() method to make a load bar. Here is my solution:
import time
loadbarwidth = 23
for i in range(1, loadbarwidth + 1):
time.sleep(0.1)
strbarwidth = '[{}{}] - {}\r'.format(
(i * '#'),
((loadbarwidth - i) * '-'),
(('{:0.2f}'.format(((i) * (100/loadbarwidth))) + '%'))
)
print(strbarwidth ,end = '')
print()
Output:
[#######################] - 100.00%
Here's a short solution that builds the loading bar programmatically (you must decide how long you want it).
import time
n = 33 # or however many loading slots you want to have
load = 0.01 # artificial loading time!
loading = '.' * n # for strings, * is the repeat operator
for i in range(n+1):
# this loop replaces each dot with a hash!
print('\r%s Loading at %3d percent!' % (loading, i*100/n), end='')
loading = loading[:i] + '#' + loading[i+1:]
time.sleep(load)
if i==n: print()
If your work can't be broken down into measurable chunks, you could call your function in a new thread and time how long it takes:
import thread
import time
import sys
def work():
time.sleep( 5 )
def locked_call( func, lock ):
lock.acquire()
func()
lock.release()
lock = thread.allocate_lock()
thread.start_new_thread( locked_call, ( work, lock, ) )
# This part is icky...
while( not lock.locked() ):
time.sleep( 0.1 )
while( lock.locked() ):
sys.stdout.write( "*" )
sys.stdout.flush()
time.sleep( 1 )
print "\nWork Done"
You can obviously increase the timing precision as required.
I like Gabriel answer, but i changed it to be flexible. You can send bar-length to the function and get your progress bar with any length that you want. And you can't have a progress bar with zero or negative length. Also, you can use this function like Gabriel answer (Look at the Example #2).
import sys
import time
def ProgressBar(Total, Progress, BarLength=20, ProgressIcon="#", BarIcon="-"):
try:
# You can't have a progress bar with zero or negative length.
if BarLength <1:
BarLength = 20
# Use status variable for going to the next line after progress completion.
Status = ""
# Calcuting progress between 0 and 1 for percentage.
Progress = float(Progress) / float(Total)
# Doing this conditions at final progressing.
if Progress >= 1.:
Progress = 1
Status = "\r\n" # Going to the next line
# Calculating how many places should be filled
Block = int(round(BarLength * Progress))
# Show this
Bar = "[{}] {:.0f}% {}".format(ProgressIcon * Block + BarIcon * (BarLength - Block), round(Progress * 100, 0), Status)
return Bar
except:
return "ERROR"
def ShowBar(Bar):
sys.stdout.write(Bar)
sys.stdout.flush()
if __name__ == '__main__':
print("This is a simple progress bar.\n")
# Example #1:
print('Example #1')
Runs = 10
for i in range(Runs + 1):
progressBar = "\rProgress: " + ProgressBar(10, i, Runs)
ShowBar(progressBar)
time.sleep(1)
# Example #2:
print('\nExample #2')
Runs = 10
for i in range(Runs + 1):
progressBar = "\rProgress: " + ProgressBar(10, i, 20, '|', '.')
ShowBar(progressBar)
time.sleep(1)
print('\nDone.')
# Example #2:
Runs = 10
for i in range(Runs + 1):
ProgressBar(10, i)
time.sleep(1)
Result:
This is a simple progress bar.
Example #1
Progress: [###-------] 30%
Example #2
Progress: [||||||||||||........] 60%
Done.
Guess i'm a little late but this should work for people working with the current versions of python 3, since this uses "f-strings", as introduced in Python 3.6 PEP 498:
Code
from numpy import interp
class Progress:
def __init__(self, value, end, title='Downloading',buffer=20):
self.title = title
#when calling in a for loop it doesn't include the last number
self.end = end -1
self.buffer = buffer
self.value = value
self.progress()
def progress(self):
maped = int(interp(self.value, [0, self.end], [0, self.buffer]))
print(f'{self.title}: [{"#"*maped}{"-"*(self.buffer - maped)}]{self.value}/{self.end} {((self.value/self.end)*100):.2f}%', end='\r')
Example
#some loop that does perfroms a task
for x in range(21) #set to 21 to include until 20
Progress(x, 21)
Output
Downloading: [########------------] 8/20 40.00%
Use the progress library!
pip install progress
Here is a custom subclass I wrote to format the ETA/Elapsed times into a better readable format:
import datetime
from progress.bar import IncrementalBar
class ProgressBar(IncrementalBar):
'''
My custom progress bar that:
- Show %, count, elapsed, eta
- Time is shown in H:M:S format
'''
message = 'Progress'
suffix = '%(percent).1f%% (%(index)d/%(max)d) -- %(elapsed_min)s (eta: %(eta_min)s)'
def formatTime(self, seconds):
return str(datetime.timedelta(seconds=seconds))
#property
def elapsed_min(self):
return self.formatTime(self.elapsed)
#property
def eta_min(self):
return self.formatTime(self.eta)
if __name__=='__main__':
counter = 120
bar = ProgressBar('Processing', max=counter)
for i in range(counter):
bar.next()
time.sleep(1)
bar.finish()
This is my simple solution:
import time
def progress(_cur, _max):
p = round(100*_cur/_max)
b = f"Progress: {p}% - ["+"."*int(p/5)+" "*(20-int(p/5))+"]"
print(b, end="\r")
# USAGE:
for i in range(0,101):
time.sleep(0.1)
progress(i,100)
print("..."*5, end="\r")
print("Done")
A very simple approach:
def progbar(count: int) -> None:
for i in range(count):
print(f"[{i*'#'}{(count-1-i)*' '}] - {i+1}/{count}", end="\r")
yield i
print('\n')
And the usage:
from time import sleep
for i in progbar(10):
sleep(0.2) #whatever task you need to do
There are a lot of amazing answers already still I would like to share my solution to the progress bar.
from time import sleep
def progress_bar(progress: float, total: float, width: int = 25):
percent = width * ((progress + 1) / total)
bar = chr(9608) * int(percent) + "-" * (width - int(percent))
print(f"\r|{bar}| {(100/width)*percent:.2f}%", end="\r")
numbers = range(0, 1000)
numbersLen = len(numbers)
for i in numbers:
sleep(0.01) # Do something usefull here
progress_bar(i, numbersLen)
EDIT:
If you are looking for a bar that adjusts it's with based on the terminal's width and a possibility for messages at the end then this works too. Note that the message will disappear if the Terminal gets too narrow as the bar will break if it's too wide for 1 line.
def progressBar(progress: float, total: float, message: str = ""):
terminalWidth = get_terminal_size().columns
width = int(terminalWidth / 4)
percent = width * ((progress + 1) / total)
bar = chr(9608) * int(percent) + "-" * (width - int(percent))
if terminalWidth <= 40:
message = ""
else:
message = message + (" " * (int(terminalWidth / 2) - len(message)))
print(f"\r|{bar}| {(100/width)*percent:.2f}% " + message, end="\r")
Try PyProg. PyProg is an open-source library for Python to create super customizable progress indicators & bars.
It is currently at version 1.0.2; it is hosted on Github and available on PyPI (Links down below). It is compatible with Python 3 & 2 and it can also be used with Qt Console.
It is really easy to use. The following code:
import pyprog
from time import sleep
# Create Object
prog = pyprog.ProgressBar(" ", "", 34)
# Update Progress Bar
prog.update()
for i in range(34):
# Do something
sleep(0.1)
# Set current status
prog.set_stat(i + 1)
# Update Progress Bar again
prog.update()
# Make the Progress Bar final
prog.end()
will produce:
Initial State:
Progress: 0% --------------------------------------------------
When half done:
Progress: 50% #########################-------------------------
Final State:
Progress: 100% ##################################################
I actually made PyProg because I needed a simple but super customizable progress bar library. You can easily install it with: pip install pyprog.
PyProg Github: https://github.com/Bill13579/pyprog
PyPI: https://pypi.python.org/pypi/pyprog/

Python if condition true for x amount of time

I would like to create a condition that only gets executed if a is True for more than 3 seconds. I would like it to work like this.
if a == True for more than 3 seconds:
dosomething
If you want to check if the value hasn't change for 3 seconds.
import time
id_a_old = id(a)
time.sleep(3)
id_a_new = id(a)
if id_a_old == id_a_new: # assumes that a is initially true
dosomething
Since bool type is immutable the object id changes if it gets changed.
If you want to check if is has changed after 3 seconds do the following. If any thread changes a within 3 seconds it will capture that.
import time
time.sleep(3)
if a:
dosomething
Simple solution (motivated from Marlon Abeykoon's solution):
import time
startTime = time.time()
while a == True:
endTime = time.time()
#do other stuff
if (endTime - startTime > 3):
print("Longer than 3 seconds")
break
import time
a = True
x = int(time.time())
xa = a
while 1:
if a == True and xa == a and int(time.time()) == x + 3:
# dosomething
print "A is True for 3 seconds"
break
if(xa != a):
# dosomething
print "Value of alfa changed from %s to %s in less than 3 seconds" %(xa, a)
break

printing out letter every min Python

so i am trying to figure this out for school. Im trying to print x out every minute and every ten min it will print on a new line. so far i cant get the "printing x" every min down. can someone please help.
this is my code
import time;
inTime = float(input("type in how many second"))
oldTime = time.time()-inTime
print (time.time())
def tenMin(oldTime):
newTime = time.time()
if ((newTime - oldTime)>= 25):
return True
else:
False
while (True):
if (tenMin==True):
print ("x")
newTime = time.time()
oldtime = time.time()
else:
oldTime = time.time()
continue
Your first problem is in the line
if (tenMin==True):
You compare a function reference to a boolean, clearly the answer would be False. You have to pass a parameter
if (tenMIn(oldTime)):
...
First you have some issues with you code:
else:
False - This is not true syntax in python.
If you want timer, why are you asking the user for input?
You have a logic problem:
inTime = float(input("type in how many second"))
oldTime = time.time()-inTime
time.time is float yes, but can a user really know what to print in UnixTime?
I'll suggest a simple solution it's not the very best but it works.
It will print "x" every 1 Min and after 10 Min it will print "\n" (new line)
import time
def main():
#both timers are at the same start point
startTimerTen = time.time()
startTimerMin = startTimerTen
while True:
getCurrentTime = time.time()
if getCurrentTime - startTimerTen >= 600:
# restart both parameters
startTimerTen = getCurrentTime
startTimerMin = getCurrentTime
print "This in 10 min!\n"
if getCurrentTime - startTimerMin >= 60:
# restart only min parameter
startTimerMin = getCurrentTime
print "x"
#end of main
if __name__ == "__main__":
main()

clock countdown calculation in python

I want to write a function called boom(h,m,s) that after input from main starts printing in HH:MM:SS format the countdown clock, and then prints "boom".
I'm not allowed to use existing modules except the time.sleep(), so I have to base on While\For loops.
import time
def boom(h,m,s):
while h>0:
while m>0:
while s>0:
print ("%d:%d:%d"%(h,m,s))
time.sleep(1)
s-=1
print ("%d:%d:%d"%(h,m,s))
time.sleep(1)
s=59
m-=1
print ("%d:%d:%d"%(h,m,s))
time.sleep(1)
s=59
m=59
h-=1
while h==0:
while m==0:
while s>0:
print ("%d:%d:%d"%(h,m,s))
time.sleep(1)
s-=1
print ("BooM!!")
I figured how to calculate the seconds part, but when I input zeros on H and M parameters, it's messing with the clock.
The problem is here:
while h==0:
while m==0:
while s>0:
If m == 0, and s == 0 the while loop doesn't break, so there is an infinite loop.
Just add an else clause to the (last and) inner-most while, like so:
while s>0:
...
else: # executed once the above condition is False.
print ('BooM!!')
return # no need to break out of all the whiles!!
just convert it all to seconds and convert it back when you print ...
def hmsToSecs(h,m,s):
return h*3600 + m*60 + s
def secsToHms(secs):
hours = secs//3600
secs -= hours*3600
mins = secs//60
secs -= mins*60
return hours,mins,secs
def countdown(h,m,s):
seconds = hmsToSecs(h,m,s)
while seconds > 0:
print "%02d:%02d:%02d"%secsToHms(seconds)
seconds -= 1
sleep(1)
print "Done!"

Python Progress Bar

How do I use a progress bar when my script is doing some task that is likely to take time?
For example, a function which takes some time to complete and returns True when done. How can I display a progress bar during the time the function is being executed?
Note that I need this to be in real time, so I can't figure out what to do about it. Do I need a thread for this? I have no idea.
Right now I am not printing anything while the function is being executed, however a progress bar would be nice. Also I am more interested in how this can be done from a code point of view.
With tqdm (conda install tqdm or pip install tqdm) you can add a progress meter to your loops in a second:
from time import sleep
from tqdm import tqdm
for i in tqdm(range(10)):
sleep(3)
60%|██████ | 6/10 [00:18<00:12, 0.33 it/s]
Also, there is a notebook version:
from tqdm.notebook import tqdm
for i in tqdm(range(100)):
sleep(3)
You can use tqdm.auto instead of tqdm.notebook to work in both a terminal and notebooks.
tqdm.contrib contains some helper functions to do things like enumerate, map, and zip. There are concurrent maps in tqdm.contrib.concurrent.
You can even get progress sent to your phone after disconnecting from a jupyter notebook using tqdm.contrib.telegram or tqdm.contrib.discord.
There are specific libraries (like this one here) but maybe something very simple would do:
import time
import sys
toolbar_width = 40
# setup toolbar
sys.stdout.write("[%s]" % (" " * toolbar_width))
sys.stdout.flush()
sys.stdout.write("\b" * (toolbar_width+1)) # return to start of line, after '['
for i in range(toolbar_width):
time.sleep(0.1) # do real work here
# update the bar
sys.stdout.write("-")
sys.stdout.flush()
sys.stdout.write("]\n") # this ends the progress bar
Note: progressbar2 is a fork of progressbar which hasn't been maintained in years.
Use alive-progress, the coolest progress bar ever!
To use any progress bar framework in a useful manner, i.e. to get a percentage of completion and an estimated time of arrival (ETA), you need to be able to tell how many steps your processing will have.
Then you can just insert an yield to mark an item has been processed, and you're good to go!
def compute():
for i in range(1000):
... # process items as usual.
yield # insert this :)
Then just use it like:
from alive_progress import alive_bar
with alive_bar(1000) as bar:
for i in compute():
bar()
To get an awesome and alive progress bar!
|█████████████▎ | ▅▃▁ 321/1000 [32%] in 8s (40.1/s, eta: 16s)
Disclosure: I'm the author of alive-progress, but it should solve your problem nicely! Read the documentation at https://github.com/rsalmei/alive-progress to know more. Now it works also on Jupyter Notebooks! Here are some more examples of what it can do:
No external packages. A ready-made piece of code.
You can customize bar progress symbol "#", bar size, text prefix etc.
Python 3.3+
import sys
def progressbar(it, prefix="", size=60, out=sys.stdout): # Python3.3+
count = len(it)
def show(j):
x = int(size*j/count)
print("{}[{}{}] {}/{}".format(prefix, "#"*x, "."*(size-x), j, count),
end='\r', file=out, flush=True)
show(0)
for i, item in enumerate(it):
yield item
show(i+1)
print("\n", flush=True, file=out)
Usage:
import time
for i in progressbar(range(15), "Computing: ", 40):
time.sleep(0.1) # any code you need
To fill the whole character space use a unicode u"█" char replacing "#". With for i in progressbar(range(100)): ... you get :
Doesn't require a second thread. Some solutions/packages above require.
Works with any iterable it means anything that len() can be used on. A list, a dict of anything for example ['a', 'b', 'c' ... 'g']
Works with generators only have to wrap it with a list(). For example for i in progressbar(list(your_generator), "Computing: ", 40): Unless the work is done in the generator. In that case you need another solution (like tqdm).
You can also change output by changing out to sys.stderr for example.
Python 3.6+ (f-string)
def progressbar(it, prefix="", size=60, out=sys.stdout): # Python3.6+
count = len(it)
def show(j):
x = int(size*j/count)
print(f"{prefix}[{u'█'*x}{('.'*(size-x))}] {j}/{count}", end='\r', file=out, flush=True)
show(0)
for i, item in enumerate(it):
yield item
show(i+1)
print("\n", flush=True, file=out)
Python 2 (old-code)
import sys
def progressbar(it, prefix="", size=60, out=sys.stdout):
count = len(it)
def show(j):
x = int(size*j/count)
out.write("%s[%s%s] %i/%i\r" % (prefix, u"#"*x, "."*(size-x), j, count))
out.flush()
show(0)
for i, item in enumerate(it):
yield item
show(i+1)
out.write("\n")
out.flush()
The above suggestions are pretty good, but I think most people just want a ready made solution, with no dependencies on external packages, but is also reusable.
I got the best points of all the above, and made it into a function, along with a test cases.
To use it, just copy the lines under "def update_progress(progress)" but not the test script. Don't forget to import sys. Call this whenever you need to display or update the progress bar.
This works by directly sending the "\r" symbol to console to move cursor back to the start. "print" in python does not recongise the above symbol for this purpose, hence we need 'sys'
import time, sys
# update_progress() : Displays or updates a console progress bar
## Accepts a float between 0 and 1. Any int will be converted to a float.
## A value under 0 represents a 'halt'.
## A value at 1 or bigger represents 100%
def update_progress(progress):
barLength = 10 # Modify this to change the length of the progress bar
status = ""
if isinstance(progress, int):
progress = float(progress)
if not isinstance(progress, float):
progress = 0
status = "error: progress var must be float\r\n"
if progress < 0:
progress = 0
status = "Halt...\r\n"
if progress >= 1:
progress = 1
status = "Done...\r\n"
block = int(round(barLength*progress))
text = "\rPercent: [{0}] {1}% {2}".format( "#"*block + "-"*(barLength-block), progress*100, status)
sys.stdout.write(text)
sys.stdout.flush()
# update_progress test script
print "progress : 'hello'"
update_progress("hello")
time.sleep(1)
print "progress : 3"
update_progress(3)
time.sleep(1)
print "progress : [23]"
update_progress([23])
time.sleep(1)
print ""
print "progress : -10"
update_progress(-10)
time.sleep(2)
print ""
print "progress : 10"
update_progress(10)
time.sleep(2)
print ""
print "progress : 0->1"
for i in range(101):
time.sleep(0.1)
update_progress(i/100.0)
print ""
print "Test completed"
time.sleep(10)
This is what the result of the test script shows (The last progress bar animates):
progress : 'hello'
Percent: [----------] 0% error: progress var must be float
progress : 3
Percent: [##########] 100% Done...
progress : [23]
Percent: [----------] 0% error: progress var must be float
progress : -10
Percent: [----------] 0% Halt...
progress : 10
Percent: [##########] 100% Done...
progress : 0->1
Percent: [##########] 100% Done...
Test completed
Try progress from https://pypi.python.org/pypi/progress.
from progress.bar import Bar
bar = Bar('Processing', max=20)
for i in range(20):
# Do some work
bar.next()
bar.finish()
The result will be a bar like the following:
Processing |############# | 42/100
for a similar application (keeping track of the progress in a loop) I simply used the python-progressbar:
Their example goes something like this,
from progressbar import * # just a simple progress bar
widgets = ['Test: ', Percentage(), ' ', Bar(marker='0',left='[',right=']'),
' ', ETA(), ' ', FileTransferSpeed()] #see docs for other options
pbar = ProgressBar(widgets=widgets, maxval=500)
pbar.start()
for i in range(100,500+1,50):
# here do something long at each iteration
pbar.update(i) #this adds a little symbol at each iteration
pbar.finish()
print
I've just made a simple progress class for my needs after searching here for a equivalent solution. I thought I might a well post it.
from __future__ import print_function
import sys
import re
class ProgressBar(object):
DEFAULT = 'Progress: %(bar)s %(percent)3d%%'
FULL = '%(bar)s %(current)d/%(total)d (%(percent)3d%%) %(remaining)d to go'
def __init__(self, total, width=40, fmt=DEFAULT, symbol='=',
output=sys.stderr):
assert len(symbol) == 1
self.total = total
self.width = width
self.symbol = symbol
self.output = output
self.fmt = re.sub(r'(?P<name>%\(.+?\))d',
r'\g<name>%dd' % len(str(total)), fmt)
self.current = 0
def __call__(self):
percent = self.current / float(self.total)
size = int(self.width * percent)
remaining = self.total - self.current
bar = '[' + self.symbol * size + ' ' * (self.width - size) + ']'
args = {
'total': self.total,
'bar': bar,
'current': self.current,
'percent': percent * 100,
'remaining': remaining
}
print('\r' + self.fmt % args, file=self.output, end='')
def done(self):
self.current = self.total
self()
print('', file=self.output)
Example :
from time import sleep
progress = ProgressBar(80, fmt=ProgressBar.FULL)
for x in xrange(progress.total):
progress.current += 1
progress()
sleep(0.1)
progress.done()
Will print the following:
[======== ] 17/80 ( 21%) 63 to go
I like Brian Khuu's answer for its simplicity and not needing external packages. I changed it a bit so I'm adding my version here:
import sys
import time
def updt(total, progress):
"""
Displays or updates a console progress bar.
Original source: https://stackoverflow.com/a/15860757/1391441
"""
barLength, status = 20, ""
progress = float(progress) / float(total)
if progress >= 1.:
progress, status = 1, "\r\n"
block = int(round(barLength * progress))
text = "\r[{}] {:.0f}% {}".format(
"#" * block + "-" * (barLength - block), round(progress * 100, 0),
status)
sys.stdout.write(text)
sys.stdout.flush()
runs = 300
for run_num in range(runs):
time.sleep(.1)
updt(runs, run_num + 1)
It takes the total number of runs (total) and the number of runs processed so far (progress) assuming total >= progress. The result looks like this:
[#####---------------] 27%
You can use tqdm:
from tqdm import tqdm
with tqdm(total=100, desc="Adding Users", bar_format="{l_bar}{bar} [ time left: {remaining} ]") as pbar:
for i in range(100):
time.sleep(3)
pbar.update(1)
In this example the progress bar is running for 5 minutes
and it is shown like that:
Adding Users: 3%|█████▊ [ time left: 04:51 ]
You can change it and customize it as you like.
I really like the python-progressbar, as it is very simple to use.
For the most simple case, it is just:
import progressbar
import time
progress = progressbar.ProgressBar()
for i in progress(range(80)):
time.sleep(0.01)
The appearance can be customized and it can display the estimated remaining time. For an example use the same code as above but with:
progress = progressbar.ProgressBar(widgets=[progressbar.Bar('=', '[', ']'), ' ',
progressbar.Percentage(), ' ',
progressbar.ETA()])
Use this library: fish (GitHub).
Usage:
>>> import fish
>>> while churning:
... churn_churn()
... fish.animate()
Have fun!
If it is a big loop with a fixed amount of iterations that is taking a lot of time you can use this function I made. Each iteration of loop adds progress. Where count is the current iteration of the loop, total is the value you are looping to and size(int) is how big you want the bar in increments of 10 i.e. (size 1 =10 chars, size 2 =20 chars)
import sys
def loadingBar(count,total,size):
percent = float(count)/float(total)*100
sys.stdout.write("\r" + str(int(count)).rjust(3,'0')+"/"+str(int(total)).rjust(3,'0') + ' [' + '='*int(percent/10)*size + ' '*(10-int(percent/10))*size + ']')
example:
for i in range(0,100):
loadingBar(i,100,2)
#do some code
output:
i = 50
>> 050/100 [========== ]
pip install progressbar2
import os
import time
import progressbar
os.environ['PYCHARM_HOSTED'] = '1' # https://github.com/WoLpH/python-progressbar/issues/237
class COLOR: # https://stackoverflow.com/a/287944/11465149
YELLOW = '\033[93m'
GREEN = '\033[92m'
RED = '\033[91m'
BOLD = '\033[1m'
ENDC = '\033[0m'
widgets=[
'FILE.JSON ',
COLOR.YELLOW , progressbar.Percentage() , COLOR.ENDC,
COLOR.RED + COLOR.BOLD, progressbar.Bar(left=' ', marker='━', right=' '), COLOR.ENDC,
COLOR.YELLOW , progressbar.Timer() , COLOR.ENDC
]
for i in progressbar.progressbar(range(100), widgets=widgets):
time.sleep(0.01)
if i == 99:
widgets[4] = COLOR.GREEN
Use enumerate(...progressbar(max_value=...) + this in case you want to use it as a download progressbar
A simple oneliner:
K = 628318
for k in range(K):
# your stuff
print(end="\r|%-80s|" % ("="*int(80*k/(K-1))))
|===================================================================== |
80 is the length of the bar. Eventually you want a final print().
It can be also put into a convencience function. Along with yield, one can emulate the behaviour of tqdm:
def progbar(iterobj):
K = len(iterobj)
for k, obj in enumerate(iterobj):
print(end="\r|%-80s|" % ("="*int(80*k/(K-1))))
yield obj
print()
raise StopIteration
for k in progbar(range(628318)):
# your stuff
pass
And not to forget the digital progress indicator:
K = 628318
for k in range(K):
# your stuff
print(end="\r%6.2f %%" % (k/(K-1)*100))
94.53 %
It is not to difficult to combine both, if needed.
The keys are the "Carriage Return" \r and the suppression of the default end="\n" in print.
The code below is a quite general solution and also has a time elapsed and time remaining estimate. You can use any iterable with it. The progress bar has a fixed size of 25 characters but it can show updates in 1% steps using full, half, and quarter block characters. The output looks like this:
18% |████▌ | \ [0:00:01, 0:00:06]
Code with example:
import sys, time
from numpy import linspace
def ProgressBar(iterObj):
def SecToStr(sec):
m, s = divmod(sec, 60)
h, m = divmod(m, 60)
return u'%d:%02d:%02d'%(h, m, s)
L = len(iterObj)
steps = {int(x):y for x,y in zip(linspace(0, L, min(100,L), endpoint=False),
linspace(0, 100, min(100,L), endpoint=False))}
qSteps = ['', u'\u258E', u'\u258C', u'\u258A'] # quarter and half block chars
startT = time.time()
timeStr = ' [0:00:00, -:--:--]'
activity = [' -',' \\',' |',' /']
for nn,item in enumerate(iterObj):
if nn in steps:
done = u'\u2588'*int(steps[nn]/4.0)+qSteps[int(steps[nn]%4)]
todo = ' '*(25-len(done))
barStr = u'%4d%% |%s%s|'%(steps[nn], done, todo)
if nn>0:
endT = time.time()
timeStr = ' [%s, %s]'%(SecToStr(endT-startT),
SecToStr((endT-startT)*(L/float(nn)-1)))
sys.stdout.write('\r'+barStr+activity[nn%4]+timeStr); sys.stdout.flush()
yield item
barStr = u'%4d%% |%s|'%(100, u'\u2588'*25)
timeStr = ' [%s, 0:00:00]\n'%(SecToStr(time.time()-startT))
sys.stdout.write('\r'+barStr+timeStr); sys.stdout.flush()
# Example
s = ''
for c in ProgressBar(list('Disassemble and reassemble this string')):
time.sleep(0.2)
s += c
print(s)
Suggestions for improvements or other comments are appreciated. Cheers!
It is quite straightforward in Python3:
import time
import math
def show_progress_bar(bar_length, completed, total):
bar_length_unit_value = (total / bar_length)
completed_bar_part = math.ceil(completed / bar_length_unit_value)
progress = "*" * completed_bar_part
remaining = " " * (bar_length - completed_bar_part)
percent_done = "%.2f" % ((completed / total) * 100)
print(f'[{progress}{remaining}] {percent_done}%', end='\r')
bar_length = 30
total = 100
for i in range(0, total + 1):
show_progress_bar(bar_length, i, total)
time.sleep(0.1)
print('\n')
When running in jupyter notebooks use of normal tqdm doesn't work, as it writes output on multiple lines. Use this instead:
import time
from tqdm import tqdm_notebook as tqdm
for i in tqdm(range(100))
time.sleep(0.5)
2022 Answer for simple progress bar without external library
import time, sys
def progress(size):
for item in range(size):
if(item==0):
print("[",end="")
elif(item==size-1):
print("]",end="\n")
else:
#main work goes here
time.sleep(0.1)
print("%",end="")
sys.stdout.flush()
progress(50)
I like this page.
Starts with simple example and moves onto a multi-threaded version. Works out of the box. No 3rd party packages required.
The code will look something like this:
import time
import sys
def do_task():
time.sleep(1)
def example_1(n):
for i in range(n):
do_task()
print '\b.',
sys.stdout.flush()
print ' Done!'
print 'Starting ',
example_1(10)
Or here is example to use threads in order to run the spinning loading bar while the program is running:
import sys
import time
import threading
class progress_bar_loading(threading.Thread):
def run(self):
global stop
global kill
print 'Loading.... ',
sys.stdout.flush()
i = 0
while stop != True:
if (i%4) == 0:
sys.stdout.write('\b/')
elif (i%4) == 1:
sys.stdout.write('\b-')
elif (i%4) == 2:
sys.stdout.write('\b\\')
elif (i%4) == 3:
sys.stdout.write('\b|')
sys.stdout.flush()
time.sleep(0.2)
i+=1
if kill == True:
print '\b\b\b\b ABORT!',
else:
print '\b\b done!',
kill = False
stop = False
p = progress_bar_loading()
p.start()
try:
#anything you want to run.
time.sleep(1)
stop = True
except KeyboardInterrupt or EOFError:
kill = True
stop = True
I used format() method to make a load bar. Here is my solution:
import time
loadbarwidth = 23
for i in range(1, loadbarwidth + 1):
time.sleep(0.1)
strbarwidth = '[{}{}] - {}\r'.format(
(i * '#'),
((loadbarwidth - i) * '-'),
(('{:0.2f}'.format(((i) * (100/loadbarwidth))) + '%'))
)
print(strbarwidth ,end = '')
print()
Output:
[#######################] - 100.00%
Here's a short solution that builds the loading bar programmatically (you must decide how long you want it).
import time
n = 33 # or however many loading slots you want to have
load = 0.01 # artificial loading time!
loading = '.' * n # for strings, * is the repeat operator
for i in range(n+1):
# this loop replaces each dot with a hash!
print('\r%s Loading at %3d percent!' % (loading, i*100/n), end='')
loading = loading[:i] + '#' + loading[i+1:]
time.sleep(load)
if i==n: print()
If your work can't be broken down into measurable chunks, you could call your function in a new thread and time how long it takes:
import thread
import time
import sys
def work():
time.sleep( 5 )
def locked_call( func, lock ):
lock.acquire()
func()
lock.release()
lock = thread.allocate_lock()
thread.start_new_thread( locked_call, ( work, lock, ) )
# This part is icky...
while( not lock.locked() ):
time.sleep( 0.1 )
while( lock.locked() ):
sys.stdout.write( "*" )
sys.stdout.flush()
time.sleep( 1 )
print "\nWork Done"
You can obviously increase the timing precision as required.
I like Gabriel answer, but i changed it to be flexible. You can send bar-length to the function and get your progress bar with any length that you want. And you can't have a progress bar with zero or negative length. Also, you can use this function like Gabriel answer (Look at the Example #2).
import sys
import time
def ProgressBar(Total, Progress, BarLength=20, ProgressIcon="#", BarIcon="-"):
try:
# You can't have a progress bar with zero or negative length.
if BarLength <1:
BarLength = 20
# Use status variable for going to the next line after progress completion.
Status = ""
# Calcuting progress between 0 and 1 for percentage.
Progress = float(Progress) / float(Total)
# Doing this conditions at final progressing.
if Progress >= 1.:
Progress = 1
Status = "\r\n" # Going to the next line
# Calculating how many places should be filled
Block = int(round(BarLength * Progress))
# Show this
Bar = "[{}] {:.0f}% {}".format(ProgressIcon * Block + BarIcon * (BarLength - Block), round(Progress * 100, 0), Status)
return Bar
except:
return "ERROR"
def ShowBar(Bar):
sys.stdout.write(Bar)
sys.stdout.flush()
if __name__ == '__main__':
print("This is a simple progress bar.\n")
# Example #1:
print('Example #1')
Runs = 10
for i in range(Runs + 1):
progressBar = "\rProgress: " + ProgressBar(10, i, Runs)
ShowBar(progressBar)
time.sleep(1)
# Example #2:
print('\nExample #2')
Runs = 10
for i in range(Runs + 1):
progressBar = "\rProgress: " + ProgressBar(10, i, 20, '|', '.')
ShowBar(progressBar)
time.sleep(1)
print('\nDone.')
# Example #2:
Runs = 10
for i in range(Runs + 1):
ProgressBar(10, i)
time.sleep(1)
Result:
This is a simple progress bar.
Example #1
Progress: [###-------] 30%
Example #2
Progress: [||||||||||||........] 60%
Done.
Guess i'm a little late but this should work for people working with the current versions of python 3, since this uses "f-strings", as introduced in Python 3.6 PEP 498:
Code
from numpy import interp
class Progress:
def __init__(self, value, end, title='Downloading',buffer=20):
self.title = title
#when calling in a for loop it doesn't include the last number
self.end = end -1
self.buffer = buffer
self.value = value
self.progress()
def progress(self):
maped = int(interp(self.value, [0, self.end], [0, self.buffer]))
print(f'{self.title}: [{"#"*maped}{"-"*(self.buffer - maped)}]{self.value}/{self.end} {((self.value/self.end)*100):.2f}%', end='\r')
Example
#some loop that does perfroms a task
for x in range(21) #set to 21 to include until 20
Progress(x, 21)
Output
Downloading: [########------------] 8/20 40.00%
Use the progress library!
pip install progress
Here is a custom subclass I wrote to format the ETA/Elapsed times into a better readable format:
import datetime
from progress.bar import IncrementalBar
class ProgressBar(IncrementalBar):
'''
My custom progress bar that:
- Show %, count, elapsed, eta
- Time is shown in H:M:S format
'''
message = 'Progress'
suffix = '%(percent).1f%% (%(index)d/%(max)d) -- %(elapsed_min)s (eta: %(eta_min)s)'
def formatTime(self, seconds):
return str(datetime.timedelta(seconds=seconds))
#property
def elapsed_min(self):
return self.formatTime(self.elapsed)
#property
def eta_min(self):
return self.formatTime(self.eta)
if __name__=='__main__':
counter = 120
bar = ProgressBar('Processing', max=counter)
for i in range(counter):
bar.next()
time.sleep(1)
bar.finish()
This is my simple solution:
import time
def progress(_cur, _max):
p = round(100*_cur/_max)
b = f"Progress: {p}% - ["+"."*int(p/5)+" "*(20-int(p/5))+"]"
print(b, end="\r")
# USAGE:
for i in range(0,101):
time.sleep(0.1)
progress(i,100)
print("..."*5, end="\r")
print("Done")
A very simple approach:
def progbar(count: int) -> None:
for i in range(count):
print(f"[{i*'#'}{(count-1-i)*' '}] - {i+1}/{count}", end="\r")
yield i
print('\n')
And the usage:
from time import sleep
for i in progbar(10):
sleep(0.2) #whatever task you need to do
There are a lot of amazing answers already still I would like to share my solution to the progress bar.
from time import sleep
def progress_bar(progress: float, total: float, width: int = 25):
percent = width * ((progress + 1) / total)
bar = chr(9608) * int(percent) + "-" * (width - int(percent))
print(f"\r|{bar}| {(100/width)*percent:.2f}%", end="\r")
numbers = range(0, 1000)
numbersLen = len(numbers)
for i in numbers:
sleep(0.01) # Do something usefull here
progress_bar(i, numbersLen)
EDIT:
If you are looking for a bar that adjusts it's with based on the terminal's width and a possibility for messages at the end then this works too. Note that the message will disappear if the Terminal gets too narrow as the bar will break if it's too wide for 1 line.
def progressBar(progress: float, total: float, message: str = ""):
terminalWidth = get_terminal_size().columns
width = int(terminalWidth / 4)
percent = width * ((progress + 1) / total)
bar = chr(9608) * int(percent) + "-" * (width - int(percent))
if terminalWidth <= 40:
message = ""
else:
message = message + (" " * (int(terminalWidth / 2) - len(message)))
print(f"\r|{bar}| {(100/width)*percent:.2f}% " + message, end="\r")
Try PyProg. PyProg is an open-source library for Python to create super customizable progress indicators & bars.
It is currently at version 1.0.2; it is hosted on Github and available on PyPI (Links down below). It is compatible with Python 3 & 2 and it can also be used with Qt Console.
It is really easy to use. The following code:
import pyprog
from time import sleep
# Create Object
prog = pyprog.ProgressBar(" ", "", 34)
# Update Progress Bar
prog.update()
for i in range(34):
# Do something
sleep(0.1)
# Set current status
prog.set_stat(i + 1)
# Update Progress Bar again
prog.update()
# Make the Progress Bar final
prog.end()
will produce:
Initial State:
Progress: 0% --------------------------------------------------
When half done:
Progress: 50% #########################-------------------------
Final State:
Progress: 100% ##################################################
I actually made PyProg because I needed a simple but super customizable progress bar library. You can easily install it with: pip install pyprog.
PyProg Github: https://github.com/Bill13579/pyprog
PyPI: https://pypi.python.org/pypi/pyprog/

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