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How to load an icon using relative path in python [duplicate]

This question already has answers here:
Using QIcon does not display the image
(2 answers)
Closed 1 year ago.
I created a package that contains an icon.png inside a resource-folder:
../mypackage/resource/icon.png
../mypackage/qtprogram.py
I am now trying to access the icon.png in qtprogram.py. As they are both in mypackage directory, I tried using:
QtGui.QIcon("resource//icon.png")
but it did not work. However, using the full path (in relation to the main script path) did. Since this should be a shareable package, I would like to avoid using the full path. How can I do this?

I think it should be \\ (or) r'relative-path-to-file' instead of // in QtGui.QIcon("resource//icon.png").
I would use the os library.
import os
# If you plan to use to without PyInstaller
icon_path = os.path.join(os.path.dirname(__file__), r'resources\icon.png')
# If you plan to use to pyinstaller
icon_path = os.path.join(os.path.abspath(os.getcwd()), r'resources\icon.png')

List the content of a folder using python [duplicate]

This question already has answers here:
How can I list the contents of a directory in Python?
(8 answers)
Closed 4 years ago.
Is it possible to output the contents of a folder in python ?
If, say you had a function and you would pass the folder path to its argument?
What would be the simplest way for a beginner to take?
By "simplest" I mean, without using any modules.
Note
Google usually leads me to stackoverflow. Plus I am not looking for generic answers. I am looking for insight based on experience and wit, which I can only find here.

You could use os.listdir() to look at the contents of a directory. It takes the path as an argument, for example:
import os
directory = os.listdir('/')
for filename in directory:
print(filename)
prints this for me:
bin
home
usr
sbin
proc
tmp
dev
media
srv
etc
lib64
mnt
boot
run
var
sys
lib
opt
root
.dockerenv
run_dir

How about listdir? Let's try like this way-
import os
def ShowDirectory:
return os.listdir("folder/path/goes/here")
ShowDirectory()

With function.
def ListFolder(folder):
import os
files = os.listdir(folder)
print(*files,sep="\n")

Please use google first next time...it seems you are looking for this:
How can I list the contents of a directory in Python?
The accepted answer there:
import os
os.listdir("path") # returns list

Python check if a directory exists, then create it if necessary and save graph to new directory? [duplicate]

This question already has answers here:
How can I safely create a directory (possibly including intermediate directories)?
(28 answers)
Closed 5 years ago.
so I want this to be independent of the computer the code is used on, so I want to be able to create a directory in the current directory and save my plots to that new file. I looked at some other questions and tried this (I have two attempts, one commented out):
import os
from os import path
#trying to make shift_graphs directory if it does not already exist:
if not os.path.exists('shift_graphs'):
os.mkdirs('shift_graphs')
plt.title('Shift by position on '+str(detector_num)+'-Detector')
#saving figure to shift_graphs directory
plt.savefig(os.path.join('shift_graphs','shift by position on '+str(detector_num)+'-detector'))
print "plot 5 done"
plt.clf
I get the error :
AttributeError: 'module' object has no attribute 'mkdirs'
I also want to know if my idea of saving it in the directory will work, which I haven't been able to test because of the errors I've been getting in the above portion.

os.mkdirs() is not a method in os module.
if you are making only one direcory then use os.mkdir() and if there are multiple directories try using os.makedirs()
Check Documentation

You are looking for either:
os.mkdir
Or os.makedirs
https://docs.python.org/2/library/os.html
os.makedirs makes all the directories, so if I type in shell (and get nothing):
$ ls
$ python
>>> import os
>>> os.listdir(os.getcwd())
[]
>>> os.makedirs('alex/is/making/a/path')
>>> os.listdir(os.getcwd())
['alex']
It has made all the directories and subdirectories. os.mkdir would throw me an error, because there is no "alex/is/making/a" directory.

How to change file extension with Python? [duplicate]

This question already has answers here:
Extracting extension from filename in Python
(33 answers)
Closed 7 years ago.
I'm trying to make a program that will take a file, say my_test_file.log and make a new file called my_test_file.mdn. I'd like to be able to use this program by typing python renameprogram.py my_test_file.log into the command line. The original file will always end in .log.

from shutil import copyfile
from glob import glob
map(lambda x:copyfile(x,x[:-3]+"mdn"),glob("*.log"))
or perhaps more simply
...
import sys
copyfile(sys.argv[1],sys.argv[1][:-3]+"mdn")

You certainly can create a Python program that will accomplish this, but there are shell level commands that already do this.
For Linux/Unix:
mv my_test_file.log my_test_file.mdn
For Windows (see this link):
rename my_test_file.log my_test_file.mdn

Copy directory contents into a directory with python [duplicate]

This question already has answers here:
How do I copy an entire directory of files into an existing directory using Python?
(15 answers)
Closed 4 years ago.
I have a directory /a/b/c that has files and subdirectories.
I need to copy the /a/b/c/* in the /x/y/z directory. What python methods can I use?
I tried shutil.copytree("a/b/c", "/x/y/z"), but python tries to create /x/y/z and raises an error "Directory exists".

I found this code working which is part of the standard library:
from distutils.dir_util import copy_tree
# copy subdirectory example
from_directory = "/a/b/c"
to_directory = "/x/y/z"
copy_tree(from_directory, to_directory)
Reference:
Python 2: https://docs.python.org/2/distutils/apiref.html#distutils.dir_util.copy_tree
Python 3: https://docs.python.org/3/distutils/apiref.html#distutils.dir_util.copy_tree

You can also use glob2 to recursively collect all paths (using ** subfolders wildcard) and then use shutil.copyfile, saving the paths
glob2 link: https://code.activestate.com/pypm/glob2/

from subprocess import call
def cp_dir(source, target):
call(['cp', '-a', source, target]) # Linux
cp_dir('/a/b/c/', '/x/y/z/')
It works for me. Basically, it executes shell command cp.

The python libs are obsolete with this function. I've done one that works correctly:
import os
import shutil
def copydirectorykut(src, dst):
os.chdir(dst)
list=os.listdir(src)
nom= src+'.txt'
fitx= open(nom, 'w')
for item in list:
fitx.write("%s\n" % item)
fitx.close()
f = open(nom,'r')
for line in f.readlines():
if "." in line:
shutil.copy(src+'/'+line[:-1],dst+'/'+line[:-1])
else:
if not os.path.exists(dst+'/'+line[:-1]):
os.makedirs(dst+'/'+line[:-1])
copydirectorykut(src+'/'+line[:-1],dst+'/'+line[:-1])
copydirectorykut(src+'/'+line[:-1],dst+'/'+line[:-1])
f.close()
os.remove(nom)
os.chdir('..')