I am trying to run a simple Python based web server given here.
And I get the following error message:
Traceback (most recent call last):
File "webserver.py", line 63, in <module>
main()
File "webserver.py", line 55, in main
server = HTTPServer(('', 80), MyHandler)
File "/usr/lib/python2.5/SocketServer.py", line 330, in __init__
self.server_bind()
File "/usr/lib/python2.5/BaseHTTPServer.py", line 101, in server_bind
SocketServer.TCPServer.server_bind(self)
File "/usr/lib/python2.5/SocketServer.py", line 341, in server_bind
self.socket.bind(self.server_address)
File "<string>", line 1, in bind
socket.error: (13, 'Permission denied')
As far as I understand my firewall blocks access to a socket? Am I right? If it is the case, how can I change the permissions? Is it dangerous to change these permissions?
If you want to bind to port numbers < 1024, you need to be root. It's not a firewall
issue; it's enforced by the operating system. Here's a reference from w3.org,
and a FAQ entry specific to Unix.
If you want to run on a port under 1024, you'll need to be root. You can open the socket and drop root's permission for the rest of your program by switching to another user.
Most times it's easier to run a real webserver (say nginx) on port 80 and proxy the requests through to your program which you can run on a high numbered port (8080 for example). This way you don't need to worry about screwing something up during the time your process is running as root, as it never runs as root.
If it's just for testing, run the server on port 8080 and connect at http://localhost:8080/
Related
so I'm pretty new to Flask and i've been following a tutorial but I have been getting a strange problem. I have the following code, a python3 script, launched in atom with the hydrogen package enabled and jupyter. I have the virtual environment running in the background in a terminal.
from flask import Flask
app = Flask(__name__)
if __name__ == '__main__':
app.run(debug=True)
So obviously the script is very basic and it's just used to see if i can connect to localhost, however when running it (through Hydrogen) I get the following error:
Serving Flask app 'main'
Debug mode: on
WARNING: This is a development server. Do not use it in a production deployment. Use a production WSGI server instead.
Running on http://127.0.0.1:5000
Press CTRL+C to quit
Restarting with stat
Traceback (most recent call last):
File "/home/uses12/.local/lib/python3.10/site-packages/ipykernel_launcher.py", line 17, in
app.launch_new_instance()
File "/home/uses12/.local/lib/python3.10/site-packages/traitlets/config/application.py", line 977, in launch_instance
app.initialize(argv)
File "/home/uses12/.local/lib/python3.10/site-packages/traitlets/config/application.py", line 110, in inner
return method(app, *args, **kwargs)
File "/home/uses12/.local/lib/python3.10/site-packages/ipykernel/kernelapp.py", line 666, in initialize
self.init_sockets()
File "/home/uses12/.local/lib/python3.10/site-packages/ipykernel/kernelapp.py", line 307, in init_sockets
self.shell_port = self._bind_socket(self.shell_socket, self.shell_port)
File "/home/uses12/.local/lib/python3.10/site-packages/ipykernel/kernelapp.py", line 244, in _bind_socket
return self._try_bind_socket(s, port)
File "/home/uses12/.local/lib/python3.10/site-packages/ipykernel/kernelapp.py", line 220, in _try_bind_socket
s.bind("tcp://%s:%i" % (self.ip, port))
File "/home/uses12/.local/lib/python3.10/site-packages/zmq/sugar/socket.py", line 232, in bind
super().bind(addr)
File "zmq/backend/cython/socket.pyx", line 568, in zmq.backend.cython.socket.Socket.bind
File "zmq/backend/cython/checkrc.pxd", line 28, in zmq.backend.cython.checkrc._check_rc
zmq.error.ZMQError: Address already in use
Upon looking online, a possible solution was to specify the port in the app. parameters, however no matter what port I specify it ALWAYS says that the address is already in use, leading me to believe that there is some deeper issue. I've done a check to see what services are using those ports and it's always just two instances of python3, I guess because Flask is set to debug. I'm completely lost. Can anyone help? Thanks so much.
My web app handles http requests using several workers. Workers use some shared state, which their actions sometimes update. So far I have used a separate script/process for initializing and managing that shared state, using multiprocessing.managers.BaseManager.
This means that state_manager script would start BaseManager server, to which workers would connect as they go up and send their requests. This used to work fine on heroku. Now I'm migrating to another hosting (virtual), which for some reasons disallows TCP sockets and state_manager cannot start its (localhost) server. For context, I'm getting:
[Errno 1] Operation not permitted
As mentioned, this server is purely for local interprocess communication.
What are my alternatives for this shared state and worker management?
P.S.
On Heroku I used gunicorn, new hosting uses Passenger, if this somehow helps.
EDIT: Error message
Traceback (most recent call last):
File "state_manager.py", line 207, in <module>
server = manager.get_server()
File "/usr/lib/python3.6/multiprocessing/managers.py", line 482, in get_server
self._authkey, self._serializer)
File "/usr/lib/python3.6/multiprocessing/managers.py", line 139, in __init__
self.listener = Listener(address=address, backlog=16)
File "/usr/lib/python3.6/multiprocessing/connection.py", line 438, in __init__
self._listener = SocketListener(address, family, backlog)
File "/usr/lib/python3.6/multiprocessing/connection.py", line 577, in __init__
self._socket.listen(backlog)
PermissionError: [Errno 1] Operation not permitted
In Python3 I have a program to test the web framework bottle:
from bottle import route, run
#route('/')
def index():
return "olá pessoas"
if __name__ == '__main__':
run()
I am running the programs inside a virtualenv, in the command line. But there is this error:
(live-de-python) reinaldo#reinaldo-Inspiron-5567:~/Documentos/Code/live-de-python/repo$ python3 basic_bottle.py
Bottle v0.12.13 server starting up (using WSGIRefServer())...
Listening on http://127.0.0.1:8080/
Hit Ctrl-C to quit.
Traceback (most recent call last):
File "basic_bottle.py", line 11, in <module>
run()
File "/home/reinaldo/Documentos/Code/live-de-python/lib/python3.6/site-packages/bottle.py", line 3127, in run
server.run(app)
File "/home/reinaldo/Documentos/Code/live-de-python/lib/python3.6/site-packages/bottle.py", line 2781, in run
srv = make_server(self.host, self.port, app, server_cls, handler_cls)
File "/usr/lib/python3.6/wsgiref/simple_server.py", line 153, in make_server
server = server_class((host, port), handler_class)
File "/usr/lib/python3.6/socketserver.py", line 453, in __init__
self.server_bind()
File "/usr/lib/python3.6/wsgiref/simple_server.py", line 50, in server_bind
HTTPServer.server_bind(self)
File "/usr/lib/python3.6/http/server.py", line 136, in server_bind
socketserver.TCPServer.server_bind(self)
File "/usr/lib/python3.6/socketserver.py", line 467, in server_bind
self.socket.bind(self.server_address)
OSError: [Errno 98] Address already in use
I'm using Ubuntu. Does the error say that port 8080 is already in use? But I have no other program open
Please, does anyone know what it can be?
The port 8080 is already used by an other process. You probably launched the script and forgot to end it. Check with
$ ps -aux | grep basic_bottle
Or simply change the port with run(port=8090).
I have a python server script given below
# create the server, binding to localhost on port 9999
#
server = SocketServer.TCPServer((options.ip, options.port), cmdHandler)
While running a Python server script I am getting the following error:
File "C:\Devcon\OCDServer_New.py", line 225, in runTest
server = SocketServer.TCPServer((options.ip, options.port), cmdHandler)
File "C:\Python27\lib\SocketServer.py", line 419, in __init__
self.server_bind()
File "C:\Python27\lib\SocketServer.py", line 430, in server_bind
self.socket.bind(self.server_address)
File "C:\Python27\lib\socket.py", line 224, in meth
return getattr(self._sock,name)(*args)
**socket.error: [Errno 10048] Only one usage of each socket address (protocol/network address/port) is normally permitted**
How to solve this? In one link I found socket shutdown is a solution. But here the issue is coming while creating the socket itself. It might be because it was opened previously and not closed correctly. But I am unable to reset the entire thing and run the script again. Got stuck here.
Try using a different port to see if you get the same message or a different one. Something else could be using the same port therefore your code not being able to use it.
i have a rabbit mq running on machine
both client and rabbitMQ are running on the same network
rabbitMQ has many clients
i can ping client from rabbitMQ and back
longest latency measured between the machine is 12.1 ms
network details : Standard Switch network (network of virtual machines running on single physical machine - using vmware VC)
im getting random timeouts when initializing RPC connection
/usr/lib/python2.6/site-packages/pika-0.9.5-py2.6.egg/pika/adapters/blocking_connection.py
problem is that the timeout isn't consistent and happens from time to time.
when manually testing this issue and running the blocking_connection.py 1000 times from the same machine that it fails no timeout accrue.
this is the error i get when failing :
2013-04-23 08:24:23,396 runtest-trigger.24397 24397 DEBUG producer_rabbit initiate_rpc_connection Connecting to RabbitMQ RPC queue rpcqueue_java on host: auto-db1
2013-04-23 08:24:25,350 runtest-trigger.24397 24397 ERROR testrunner go Run 1354: cought exception: timed out
Traceback (most recent call last):
File "/testrunner.py", line 193, in go
self.set_runparams(jobid)
File "/testrunner.py", line 483, in set_runparams
self.runparams.producers_testrun = self.initialize_producers_testrun(self.runparams)
File "/basehandler.py", line 114, in initialize_producers_testrun
producer.set_testcase_checkout()
File "/baseproducer.py", line 73, in set_testcase_checkout
self.checkout_handler = pm_checkout.get_producer(self.testcasecheckout)
File "/producer_manager.py", line 101, in get_producer
producer = self.load_producer(plugin_dir, producer_name)
File "/producer_manager.py", line 20, in load_producer
producer = getattr(producer_module, 'Producer')(producer_name, self.runparams)
File "/producer_rabbit.py", line 13, in __init__
self.initiate_rpc_connection()
File "/producer_rabbit.py", line 67, in initiate_rpc_connection
self.connection = pika.BlockingConnection(pika.ConnectionParameters( host=self.conf.rpc_proxy))
File "/usr/lib/python2.6/site-packages/pika-0.9.5-py2.6.egg/pika/adapters/blocking_connection.py", line 32, in __init__
BaseConnection.__init__(self, parameters, None, reconnection_strategy)
File "/usr/lib/python2.6/site-packages/pika-0.9.5-py2.6.egg/pika/adapters/base_connection.py", line 50, in __init__
reconnection_strategy)
File "/usr/lib/python2.6/site-packages/pika-0.9.5-py2.6.egg/pika/connection.py", line 170, in __init__
self._connect()
File "/usr/lib/python2.6/site-packages/pika-0.9.5-py2.6.egg/pika/connection.py", line 228, in _connect
self.parameters.port or spec.PORT)
File "/usr/lib/python2.6/site-packages/pika-0.9.5-py2.6.egg/pika/adapters/blocking_connection.py", line 44, in _adapter_connect
self._handle_read()
File "/usr/lib/python2.6/site-packages/pika-0.9.5-py2.6.egg/pika/adapters/base_connection.py", line 151, in _handle_read
data = self.socket.recv(self._suggested_buffer_size)
timeout: timed out
please assist
I had a similar issue. If everything looks fine, then you most likely have some sort of miss configuration, e.g. bad binding. If miss configured, then you'll get a timeout because the script can't reach where it thinks it needs to go, so the error can be miss leading in this case.
For my problem, I specifically had issues with both my rabbitmq.config file and my bindings and had to use my python solution shown in: RabbitMQ creating queues and bindings from a command line over the command line example I showed. Once updated and configured properly, everything worked fine. Hopefully this gets you in the right direction.
Pika provides some time out issue when connecting different hosts.Solution is to pass a socket_timeout argument in connection parameter.Pika should upgrade to >=0.9.14
credentials = pika.PlainCredentials(RABBITMQ_USER, RABBITMQ_PASS)
connection = pika.BlockingConnection(pika.ConnectionParameters(
credentials=credentials,
host=RABBITMQ_HOST,
socket_timeout=300))
channel = connection.channel()