I have a situation like so...
class Outer(object):
def some_method(self):
# do something
class Inner(object):
def __init__(self):
self.Outer.some_method() # <-- this is the line in question
How can I access the Outer class's method from the Inner class?
You're trying to access Outer's class instance, from inner class instance. So just use factory-method to build Inner instance and pass Outer instance to it.
class Outer(object):
def createInner(self):
return Outer.Inner(self)
class Inner(object):
def __init__(self, outer_instance):
self.outer_instance = outer_instance
self.outer_instance.somemethod()
def inner_method(self):
self.outer_instance.anothermethod()
The methods of a nested class cannot directly access the instance attributes of the outer class.
Note that it is not necessarily the case that an instance of the outer class exists even when you have created an instance of the inner class.
In fact, it is often recommended against using nested classes, since the nesting does not imply any particular relationship between the inner and outer classes.
maybe I'm mad but this seems very easy indeed - the thing is to make your inner class inside a method of the outer class...
def do_sthg(self):
...
def mess_around(self):
outer_class_self = self
class Mooble():
def do_sthg_different(self):
...
outer_class_self.do_sthg()
Plus... "self" is only used by convention, so you could do this:
def do_sthg(self):
...
def mess_around(outer_class_self):
class Mooble():
def do_sthg_different(self):
...
outer_class_self.do_sthg()
It might be objected that you can't then create this inner class from outside the outer class... but this ain't true:
class Bumblebee():
def do_sthg(self):
print "sthg"
def give_me_an_inner_class(outer_class_self):
class Mooble():
def do_sthg_different(self):
print "something diff\n"
outer_class_self.do_sthg()
return Mooble
then, somewhere miles away:
blob = Bumblebee().give_me_an_inner_class()()
blob.do_sthg_different()
even push the boat out a bit and extend this inner class (NB to get super() to work you have to change the class signature of Mooble to class Mooble(object)).
class InnerBumblebeeWithAddedBounce(Bumblebee().give_me_an_inner_class()):
def bounce(self):
print "bounce"
def do_sthg_different(self):
super(InnerBumblebeeWithAddedBounce, self).do_sthg_different()
print "and more different"
ibwab = InnerBumblebeeWithAddedBounce()
ibwab.bounce()
ibwab.do_sthg_different()
later
mrh1997 raised an interesting point about the non-common inheritance of inner classes delivered using this technique. But it seems that the solution is pretty straightforward:
class Fatty():
def do_sthg(self):
pass
class InnerFatty(object):
pass
def give_me_an_inner_fatty_class(self):
class ExtendedInnerFatty(Fatty.InnerFatty):
pass
return ExtendedInnerFatty
fatty1 = Fatty()
fatty2 = Fatty()
innerFattyClass1 = fatty1.give_me_an_inner_fatty_class()
innerFattyClass2 = fatty2.give_me_an_inner_fatty_class()
print (issubclass(innerFattyClass1, Fatty.InnerFatty))
print (issubclass(innerFattyClass2, Fatty.InnerFatty))
I found this.
Tweaked to suite your question:
class Outer(object):
def some_method(self):
# do something
class _Inner(object):
def __init__(self, outer):
outer.some_method()
def Inner(self):
return _Inner(self)
I’m sure you can somehow write a decorator for this or something
related: What is the purpose of python's inner classes?
A few years late to the party.... but to expand on #mike rodent's wonderful answer, I've provided my own example below that shows just how flexible his solution is, and why it should be (or should have been) the accepted answer.
Python 3.7
class Parent():
def __init__(self, name):
self.name = name
self.children = []
class Inner(object):
pass
def Child(self, name):
parent = self
class Child(Parent.Inner):
def __init__(self, name):
self.name = name
self.parent = parent
parent.children.append(self)
return Child(name)
parent = Parent('Bar')
child1 = parent.Child('Foo')
child2 = parent.Child('World')
print(
# Getting its first childs name
child1.name, # From itself
parent.children[0].name, # From its parent
# Also works with the second child
child2.name,
parent.children[1].name,
# Go nuts if you want
child2.parent.children[0].name,
child1.parent.children[1].name
)
print(
# Getting the parents name
parent.name, # From itself
child1.parent.name, # From its children
child2.parent.name,
# Go nuts again if you want
parent.children[0].parent.name,
parent.children[1].parent.name,
# Or insane
child2.parent.children[0].parent.children[1].parent.name,
child1.parent.children[1].parent.children[0].parent.name
)
# Second parent? No problem
parent2 = Parent('John')
child3 = parent2.Child('Doe')
child4 = parent2.Child('Appleseed')
print(
child3.name, parent2.children[0].name,
child4.name, parent2.children[1].name,
parent2.name # ....
)
Output:
Foo Foo World World Foo World
Bar Bar Bar Bar Bar Bar Bar
Doe Doe Appleseed Appleseed John
Again, a wonderful answer, props to you mike!
You can easily access to outer class using metaclass: after creation of outer class check it's attribute dict for any classes (or apply any logic you need - mine is just trivial example) and set corresponding values:
import six
import inspect
# helper method from `peewee` project to add metaclass
_METACLASS_ = '_metaclass_helper_'
def with_metaclass(meta, base=object):
return meta(_METACLASS_, (base,), {})
class OuterMeta(type):
def __new__(mcs, name, parents, dct):
cls = super(OuterMeta, mcs).__new__(mcs, name, parents, dct)
for klass in dct.values():
if inspect.isclass(klass):
print("Setting outer of '%s' to '%s'" % (klass, cls))
klass.outer = cls
return cls
# #six.add_metaclass(OuterMeta) -- this is alternative to `with_metaclass`
class Outer(with_metaclass(OuterMeta)):
def foo(self):
return "I'm outer class!"
class Inner(object):
outer = None # <-- by default it's None
def bar(self):
return "I'm inner class"
print(Outer.Inner.outer)
>>> <class '__main__.Outer'>
assert isinstance(Outer.Inner.outer(), Outer)
print(Outer().foo())
>>> I'm outer class!
print(Outer.Inner.outer().foo())
>>> I'm outer class!
print(Outer.Inner().outer().foo())
>>> I'm outer class!
print(Outer.Inner().bar())
>>> I'm inner class!
Using this approach, you can easily bind and refer two classes between each other.
I've created some Python code to use an outer class from its inner class, based on a good idea from another answer for this question. I think it's short, simple and easy to understand.
class higher_level__unknown_irrelevant_name__class:
def __init__(self, ...args...):
...other code...
# Important lines to access sub-classes.
subclasses = self._subclass_container()
self.some_subclass = subclasses["some_subclass"]
del subclasses # Free up variable for other use.
def sub_function(self, ...args...):
...other code...
def _subclass_container(self):
_parent_class = self # Create access to parent class.
class some_subclass:
def __init__(self):
self._parent_class = _parent_class # Easy access from self.
# Optional line, clears variable space, but SHOULD NOT BE USED
# IF THERE ARE MULTIPLE SUBCLASSES as would stop their parent access.
# del _parent_class
class subclass_2:
def __init__(self):
self._parent_class = _parent_class
# Return reference(s) to the subclass(es).
return {"some_subclass": some_subclass, "subclass_2": subclass_2}
The main code, "production ready" (without comments, etc.). Remember to replace all of each value in angle brackets (e.g. <x>) with the desired value.
class <higher_level_class>:
def __init__(self):
subclasses = self._subclass_container()
self.<sub_class> = subclasses[<sub_class, type string>]
del subclasses
def _subclass_container(self):
_parent_class = self
class <sub_class>:
def __init__(self):
self._parent_class = _parent_class
return {<sub_class, type string>: <sub_class>}
Explanation of how this method works (the basic steps):
Create a function named _subclass_container to act as a wrapper to access the variable self, a reference to the higher level class (from code running inside the function).
Create a variable named _parent_class which is a reference to the variable self of this function, that the sub-classes of _subclass_container can access (avoids name conflicts with other self variables in subclasses).
Return the sub-class/sub-classes as a dictionary/list so code calling the _subclass_container function can access the sub-classes inside.
In the __init__ function inside the higher level class (or wherever else needed), receive the returned sub-classes from the function _subclass_container into the variable subclasses.
Assign sub-classes stored in the subclasses variable to attributes of the higher level class.
A few tips to make scenarios easier:
Making the code to assign the sub classes to the higher level class easier to copy and be used in classes derived from the higher level class that have their __init__ function changed:
Insert before line 12 in the main code:
def _subclass_init(self):
Then insert into this function lines 5-6 (of the main code) and replace lines 4-7 with the following code:
self._subclass_init(self)
Making subclass assigning to the higher level class possible when there are many/unknown quantities of subclasses.
Replace line 6 with the following code:
for subclass_name in list(subclasses.keys()):
setattr(self, subclass_name, subclasses[subclass_name])
Example scenario of where this solution would be useful and where the higher level class name should be impossible to get:
A class, named "a" (class a:) is created. It has subclasses that need to access it (the parent). One subclass is called "x1". In this subclass, the code a.run_func() is run.
Then another class, named "b" is created, derived from class "a" (class b(a):). After that, some code runs b.x1() (calling the sub function "x1" of b, a derived sub-class). This function runs a.run_func(), calling the function "run_func" of class "a", not the function "run_func" of its parent, "b" (as it should), because the function which was defined in class "a" is set to refer to the function of class "a", as that was its parent.
This would cause problems (e.g. if function a.run_func has been deleted) and the only solution without rewriting the code in class a.x1 would be to redefine the sub-class x1 with updated code for all classes derived from class "a" which would obviously be difficult and not worth it.
Do you mean to use inheritance, rather than nesting classes like this? What you're doing doesn't make a heap of sense in Python.
You can access the Outer's some_method by just referencing Outer.some_method within the inner class's methods, but it's not going to work as you expect it will. For example, if you try this:
class Outer(object):
def some_method(self):
# do something
class Inner(object):
def __init__(self):
Outer.some_method()
...you'll get a TypeError when initialising an Inner object, because Outer.some_method expects to receive an Outer instance as its first argument. (In the example above, you're basically trying to call some_method as a class method of Outer.)
Another possibility:
class _Outer (object):
# Define your static methods here, e.g.
#staticmethod
def subclassRef ():
return Outer
class Outer (_Outer):
class Inner (object):
def outer (self):
return _Outer
def doSomething (self):
outer = self.outer ()
# Call your static mehthods.
cls = outer.subclassRef ()
return cls ()
What we can do is pass the self variable of Outer Class inside the Inner Class as Class Argument and Under Outer init initialise the Inner Class with Outer self passed into Inner
class Outer:
def __init__(self):
self.somevalue=91
self.Inner=self.Inner(self)
def SomeMethod(self):
print('This is Something from Outer Class')
class Inner:
def __init__(self,Outer)
self.SomeMethod=Outer.SomeMethod
self.somevalue=Outer.somevalue
def SomeAnotherMethod(self):
print(self.somevalue)
self.SomeMethod()
>>>f=Outer()
>>>f.Inner.SomeAnotherMethod()
91
This is Something from Outer Class
Now After running this function it Works
Expanding on #tsnorri's cogent thinking, that the outer method may be a static method:
class Outer(object):
#staticmethod
def some_static_method(self):
# do something
class Inner(object):
def __init__(self):
self.some_static_method() # <-- this will work later
Inner.some_static_method = some_static_method
Now the line in question should work by the time it is actually called.
The last line in the above code gives the Inner class a static method that's a clone of the Outer static method.
This takes advantage of two Python features, that functions are objects, and scope is textual.
Usually, the local scope references the local names of the (textually) current function.
...or current class in our case. So objects "local" to the definition of the Outer class (Inner and some_static_method) may be referred to directly within that definition.
You may create a class, to decorate inner classes. In this case #inner.
Since this a decorator: Outer.A = inner(Outer.A). Once your code requires Outer.A it will be executed inner.__get__ method, which returns the original class (A) with a new attribute set on it: A.owner = Outer.
A classmethod in class A, in this case def add(cls, y=3), may use new attribute owner at return cls.owner.x + y + 1.
The line setattr(owner, name, self.inner), breaks the descriptor because owner.name => Outer.A => A is no longer an instance of the class inner.
Hope this helps.
class inner:
def __init__(self, inner):
self.inner = inner
def __get__(self, instance, owner):
print('__get__ method executed, only once... ')
name = self.inner.__name__
setattr(self.inner, 'owner', owner)
setattr(owner, name, self.inner) # breaks descriptor
return self.inner #returns Inner
class Outer:
x = 1
#inner
class A:
#classmethod
def add(cls, y=3):
return cls.owner.x + y + 1
print(Outer.A.add(0)) # First time executes inner.__get__ method
print(Outer.A.add(0)) # Second time not necessary.
>> __get__ method executed, only once...
>> 2
>> 2
It can be done by parsing the outer class object into inner class.
class Outer():
def __init__(self,userinput):
self.userinput = userinput
def outer_function(self):
self.a = self.userinput + 2
class Inner():
def inner_function(self):
self.b = self.a + 10
after defining this, it need to run the function
m = Outer(3)
m.outer_function()
print (m.a)
#this will output 5
Now it has the variable of outer class.
and then, it need to run inner class functions.
m.Inner.inner_function(m)
The object m of outer class is parsed into the function of inner class (inside the brackets)
Now, the inner class function is accessing self.a from the outer class.
print (m.b)
#this will output 15
It is too simple:
Input:
class A:
def __init__(self):
pass
def func1(self):
print('class A func1')
class B:
def __init__(self):
a1 = A()
a1.func1()
def func1(self):
print('class B func1')
b = A.B()
b.func1()
Output
class A func1
class B func1
I have a class that I need:
First instance MUST receive a parameter.
All the following instances have this parameter be optional.
If it is not passed then I will use the parameter of the previous object init.
For that, I need to share a variable between the objects (all objects belong to classes with the same parent).
For example:
class MyClass:
shared_variable = None
def __init__(self, paremeter_optional=None):
if paremeter_optional is None: # Parameter optional not given
if self.shared_variable is None:
print("Error! First intance must have the parameter")
sys.exit(-1)
else:
paremeter_optional = self.shared_variable # Use last parameter
self.shared_variable = paremeter_optional # Save it for next object
objA = MyClass(3)
objB = MyClass()
Because the shared_variable is not consistent/shared across inits, when running the above code I get the error:
Error! First intance must have the parameter
(After the second init of objB)
Of course, I could use a global variable but I want to avoid it if possible and use some best practices for this.
Update: Having misunderstood the original problem, I would still recommend being explicit, rather than having the class track information better tracked outside the class.
class MyClass:
def __init__(self, parameter):
...
objA = MyClass(3)
objB = MyClass(4)
objC = MyClass(5)
objD = MyClass(5) # Be explicit; don't "remember" what was used for objC
If objC and objD are "related" enough that objD can rely on the initialization of objC, and you want to be DRY, use something like
objC, objD = [MyClass(5) for _ in range(2)]
Original answer:
I wouldn't make this something you set from an instance at all; it's a class attribute, and so should be set at the class level only.
class MyClass:
shared_variable = None
def __init__(self):
if self.shared_variable is None:
raise RuntimeError("shared_variable must be set before instantiating")
...
MyClass.shared_variable = 3
objA = MyClass()
objB = MyClass()
Assigning a value to self.shared_variable makes self.shared_variable an instance attribute so that the value is not shared among instances.
You can instead assign the value explicitly to the class attribute by referencing the attribute of the instance's class object instead.
Change:
self.shared_variable = paremeter_optional
to:
self.__class__.shared_variable = paremeter_optional
I am rather new to using classes. I struggle with functions (i.e. methods) in classes and how to access the classes attributes via method parameter.
My aim is to have a method accessing an instance's list (and the instances contained therein, yadda yadda)
While:
class dictclasser:
def __init__(self, attribute):
self.attribute = attribute
def printattr(self):
self.printattr2()
def printattr2(self):
return self.attribute
classcollection = []
while True:
attribute = input()
classcollection.append(dictclasser(attribute))
for i in classcollection:
print(i.printattr())
Returns None
class dictclasser:
def __init__(self, attribute):
self.attribute = attribute
def printattr(self):
return self.attribute
classcollection = []
while True:
attribute = input()
classcollection.append(dictclasser(attribute))
for i in classcollection:
print(i.printattr())
Returns everything as intended. I cannot figure out why printattr can access the instances attribute and printattr2 cannot. I have checked "Similar Question" to no avail.
Thanks in advance!
Because you missed a return statement in the first printattr. In order to propagate the return value of printattr2 onwards from printattr you have to return the returned value:
def printattr(self):
return self.printattr2()
Your printattr function has no return statement. Change
self.printattr2()
to
return self.printattr2()
The following program is unable to create a function of a class
class MyClass(object):
def __init__(self, name=""):
self.name = name
def read_name(self):
return self.name
# First argument should be a ref to class
def callback(fcn, arg):
fcn.name=arg
# Create a instance of class
a = MyClass("Blue")
# Lets add new member functions
setattr(a, 'callback1', callback)
setattr(a, 'callback2', callback)
print a.read_name()
print a.callback1("purple") #! FAILS
print a.callback2("cyan") #! FAILS
What is the right way of creating a class member function automatically?
I want to create 'N' callback functions, they all will modify some common/uncommon class data (A shared dict)
EDIT 1
I wish to collect information from 'N' separate/parallel threads by passing callback functions. I do not know beforehand how many callback functions I need thus I want to create them on fly.
EDIT 2
I have a dictionary(d) where I am storing the information of different processes. The dictionary(d) is accessed within the callback. But because the same callback function is called at different threads, the dictionary data gets garbled. As a quickfix, I thought of creating separate callbacks.
If you know what you're doing, you'd want to try
import types
setattr(a, 'callback1', types.MethodType(callback, a, MyClass))
In short: when grafting a method, assign it to the class, not to the instance.
Here's an elucidating example.
class A(object):
"""As trivial as a class can get."""
def foo(self):
return self.bar(1) + self.baz()
# Rework everything!
def new_bar(self, x):
return 'I got %r' % x
def new_baz(self):
return ' and I\'m okay!'
A.bar = new_bar
A.baz = new_baz
print A().foo()
Now grafting method to an instance.
a = A()
# An instance attribute is a bound method;
# when we replace it with a function, we lose access to self.
a.bar = lambda x: x * 100
A.baz = lambda self: 42
assert a.foo() == 142
# We can do better, though.
from types import MethodType
a2 = A()
a2.foo = MethodType(lambda self: 'I know myself, my class is %s' % self.__class__.__name__, a2)
print a2.foo()
Note how you don't need setattr to set an attribute, even an unknown attribute. You may remember that you don't use setattr in __init__ either.
You can't add a class method to an instance; you have to add it to the class:
setattr(MyClass, 'callback1', callback)
But it's still a terrible idea. Why would you want this functionality?
Edit: keep your callbacks in a container instead:
class MyClass(object):
def __init__(self, name=""):
self.name = name
self.callbacks = []
def callback(self, idx, arg):
self.callbacks[idx](self, arg)
# First argument should be a ref to class
def callback(fcn, arg):
fcn.name=arg
# Create a instance of class
a = MyClass("Blue")
# Lets add new member functions
a.callbacks.append(callback)
a.callbacks.append(callback)
print a.name
a.callback(0, "purple")
print a.name
a.callback(1, "cyan")
print a.name
I am trying to create a new MyClass instance in MyClass's definition.
Why does this code fail and how can achieve it?
class MyClass:
def __init__(self):
self.child=MyClass()
mc=MyClass()
Well, it fails because it has infinite recursion. Think about it, if every MyClass has a child which is a MyClass, it will go on for infinity!
You can resolve this a couple of ways. First, you can have a parameter to the constructor:
class MyClass:
def __init__(self, create = True):
if create:
self.child = MyClass(False)
mc = MyClass()
Or, you can have another, external method:
class MyClass:
def set_child(self,child = None):
# I prefer to make child optional for ease of use.
child = MyClass() if child is None else child
self.child=child
mc=MyClass()
mc.set_child()
I personally prefer the first solution as it means that outside objects don't need to know anything about the class. Of course, you could combine the two:
class MyClass:
def __init__(self, create):
if create:
self.set_child(create=False)
def set_child(self,child = None, create = True):
child = MyClass(create) if child is None else child
self.child=child
mc=MyClass()
This way mc has a child by default and you have the option of setting the child whenever you like.
Then there is also the "let's create a certain number" approach:
class MyClass:
def __init__(self, count = 10):
count -= 1
if count:
# the first child gets the value 9.
# the second gets 8.
# when the count gets to 0, stop!
self.child = MyClass(count)
Aside: If you want to get an object's class, you can use the value obj.__class__. That will output MyClass in all of the examples above.
You're making an infinitely recursing call — MyClass is creating another MyClass during initialization, and thus it recurses infinitely.
You may want to do something like:
class MyClass:
def create_child(self):
self.child=MyClass()
mc=MyClass()
mc.create_child()
If you're feeling particularly naughty, you could try:
class MyClass(object):
#property
def child(self):
if self._child is None: self._child = MyClass()
return self._child
def __init__(self):
self._child=None
mc=MyClass()
What you did there is actualy recursive, the new isntance of MyClass will create a new instance that will in turn create a new one, etc ...
Soo I supose that is why your code fails, I can't tell for sure since you didn't post the error message.
I suggest to define two classes:
class MyClass(object):
def __init__(self):
self.child = MyChildClass()
...many other methods...
class MyChildClass(MyClass):
def __init__(self):
pass
I think that if two classes must behave in two different ways, they must be different (although one can subclass the other)