I'm trying to reach a nested class, originally I used xPath but it returned an empty list, so I went through the classes individually, and one of them has an issue where selenium can't find it.
Up until Price4 it works fine, but it can't seem to find Price5
So, if you want to get the text from the last element containing the price you can define
String lastPriceXpath = "(//*[#class='css-1m1f8hn'])[last()]"
String lastPrice = driver.findElement(By.xpath(lastPriceXpath)).getText()
The syntax above is in Java but I hope you will be able to convert it to python, it's quite similar
Related
I am very new to this and i have tried to look for the answer to this but unable to find any.
I am using Selenium+chromedriver, trying to monitor some items I am interested in.
Example:
a page with 20 items in a list.
Code:
#list of items on the page
search_area = driver.find_elements_by_xpath("//li[#data-testid='test']")
search_area[19].find_element_by_xpath("//p[#class='sc-hKwDye name']").text
this returns the name of item[0]
search_area[19].find_element_by_css_selector('.name').text
this returns the name of item[19]
why is xpath looking at the parent html?
I want xpath to return the name of item within the WebElement /list item. is it possible?
found the answer, add a . in front
hope this is gonna help someone new like me in the future.
from
search_area[19].find_element_by_xpath("//p[#class='sc-hKwDye name']").text
to
search_area[19].find_element_by_xpath(".//p[#class='sc-hKwDye name']").text
What you are passing in find_element_by_xpath("//p[#class='sc-hKwDye name']") is relative Xpath. You can pass the full Xpath to get the desired result.
I am using Selenium to try and get all ID elements that that start with "button-". What I have tried so far was to use regex to match the "button-" but I get an error stating that TypeError: Object of type 'SRE_Pattern' is not JSON serializable. My code so far is:
all_btns = self.driver.find_elements_by_id(re.compile('^button-?'))
But as mentioned that raises an error. What is the appropriate way of getting all elements when you don't know the full ID, class, css selector etc.?
You could use find_element_by_xpath and starts-with:
find_elements_by_xpath('//*[starts-with(#id, "button-")]')
//* will match any elements
[starts-with(#id, "button-")] will filter the elements with a property id that starts with button-
Clément's answers works just fine, but there is also a way to do this with css selectors:
*[id^='button'].
* matches all tags, just like in xpath and ^= means 'starts with'
I am using the following code using Python 3.6 and selenium:
element = driver.find_element_by_class_name("first_result_price")
print(element)
on the website it is like this
`website: span class="first_result_price">712
however if I print element I get a completely different number?
Any suggestions?
many thanks!!
"element" is a type of object called WebElement that Selenium adds. If you want to find the text inside that element, you have to say
element.text
Which should return what you're looking for, '712', albeit in string form.
I currently have a script that can find the first element with the link text "Toast" using
toast_link = driver.find_element_by_link_text('Toast')
The problem I am having is that there are multiple instances of the link text "Toast" and I would like to iterate through all of them. What is the best way to do this?
To find multiple elements, use find_elements_* instead of find_element_* (NOTE: s):
toast_links = driver.find_elements_by_link_text('Toast')
for link in toast_links:
....
In the case that I want the first use of class so I don't have to guess the find_elements_by_xpath(), what are my options for this? The goal is to write less code, assuring any changes to the source I am scraping can be fixed easily. Is it possible to essentially
find_elements_by_css_selector('source[1]')
This code does not work as is though.
I am using selenium with Python and will likely be using phantomJS as the webdriver (Firefox for testing).
In CSS Selectors, square brackets select attributes, so your sample code is trying to select the 'source' type element with an attribute named 1, eg
<source 1="your_element" />
Whereas I gather you're trying to find the first in a list that looks like this:
<source>Blah</source>
<source>Rah</source>
If you just want the first matching element, you can use the singular form:
element = find_element_by_css_selector("source")
The form you were using returns a list, so you're also able to get the n-1th element to find the nth instance on the page (Lists index from 0):
element = find_elements_by_css_selector("source")[0]
Finally, if you want your CSS selectors to be completely explicit in which element they're finding, you can use the nth-of-type selector:
element = find_element_by_css_selector("source:nth-of-type(1)")
You might find some other helpful information at this blog post from Sauce Labs to help you write flexible selectors to replace your XPath.