Python convert array to elements - python

I have a sample array ['first_name', 'last_name'] as input and would like to have the output as "first_name", "last_name" without any square brackets but need to have the double quotes around the elements. I have tried below but doesn't seem to work. appreciate any inputs on this.
The array is dynamic. Can have any number of elements. The elements need to be enclosed in double quotes each and no square brackets.
array_list = ['first_name', 'last_name']
string_list = list(array_list)
print(string_list)


array_list = ['first_name', 'last_name']
for i in array_list:
print(f' "{i}" ',end=" ".join(","))


You can add the intended quotation marks, you can do so with f-string
string_list = [f'"{item}"' for item in array_list]
print(", ".join(string_list))


array_list = ['first_name', 'last_name']
print(', '.join(f'"{e}"' for e in array_list))
Output:
"first_name", "last_name"


array_list = ['first_name', 'last_name']
pre_processed = [f'"{item}"' for item in array_list]
string_list = ", ".join(pre_processed)
print(string_list)
Output:
"first_name", "last_name"


you can do like this using list-string conversion...
Code
array_list = str(['first_name', 'last_name',5]).strip('[]')
print(array_list)
#-------OR--------
array_list = ['first_name', 'last_name'] # only string handle
print(",".join(array_list))
output
'first_name', 'last_name', 5


you can try below to achieve the same.It has for loop to iterate through the array and convert it to a string with double quotes around each element: #Pal1989
array_list = ['first_name', 'last_name']
string_list = ""
for element in array_list:
string_list += '"' + element + '", '
string_list = string_list[:-2]
print(string_list)


All you really need to do is to join by the separator and put double quotes at front and back:
array_list = ['first_name', 'last_name']
print('"' + '", "'.join(array_list) + '"')
output: "first_name", "last_name"
Remember: when you need to put double quotes in strings, surround with singles: ' " ' - I've left blanks on purpose. And " ' " to have single quotes.

Related

Remove punctation from every value in Python dictionary

I have a long dictionary which looks like this:
name = 'Barack.'
name_last = 'Obama!'
street_name = "President Streeet?"
list_of_slot_names = {'name':name, 'name_last':name_last, 'street_name':street_name}
I want to remove the punctation for every slot (name, name_last,...).
I could do it this way:
name = name.translate(str.maketrans('', '', string.punctuation))
name_last = name_last.translate(str.maketrans('', '', string.punctuation))
street_name = street_name.translate(str.maketrans('', '', string.punctuation))
Do you know a shorter (more compact) way to write this?
Result:
>>> print(name, name_last, street_name)
>>> Barack Obama President Streeet

Use a loop / dictionary comprehension
{k: v.translate(str.maketrans('', '', string.punctuation)) for k, v in list_of_slot_names.items()}
You can either assign this back to list_of_slot_names if you want to overwrite existing values or assign to a new variable
You can also then print via
print(*list_of_slot_names.values())

name = 'Barack.'
name_last = 'Obama!'
empty_slot = None
street_name = "President Streeet?"
print([str_.strip('.?!') for str_ in (name, name_last, empty_slot, street_name) if str_ is not None])
-> Barack Obama President Streeet
Unless you also want to remove them from the middle. Then do this
import re
name = 'Barack.'
name_last = 'Obama!'
empty_slot = None
street_name = "President Streeet?"
print([re.sub('[.?!]+',"",str_) for str_ in (name, name_last, empty_slot, street_name) if str_ is not None])

import re, string
s = 'hell:o? wor!d.'
clean = re.sub(rf"[{string.punctuation}]", "", s)
print(clean)
output
hello world

multiple separator in a string python

text="Brand.*/Smart Planet.#/Color.*/Yellow.#/Type.*/Sandwich Maker.#/Power Source.*/Electrical."
I have this kind of string. I am facing the problem which splits it to 2 lists. Output will be approximately like this :
name = ['Brand','Color','Type','Power Source']
value = ['Smart Plane','Yellow','Sandwich Maker','Electrical']
Is there any solution for this.

name = []
value = []
text = text.split('.#/')
for i in text:
i = i.split('.*/')
name.append(i[0])
value.append(i[1])

This is one approach using re.split and list slicing.
Ex:
import re
text="Brand.*/Smart Planet.#/Color.*/Yellow.#/Type.*/Sandwich Maker.#/Power Source.*/Electrical."
data = [i for i in re.split("[^A-Za-z\s]+", text) if i]
name = data[::2]
value = data[1::2]
print(name)
print(value)
Output:
['Brand', 'Color', 'Type', 'Power Source']
['Smart Planet', 'Yellow', 'Sandwich Maker', 'Electrical']

You can use regex to split the text, and populate the lists in a loop.
Using regex you protect your code from invalid input.
import re
name, value = [], []
for ele in re.split(r'\.#\/', text):
k, v = ele.split('.*/')
name.append(k)
value.append(v)
>>> print(name, val)
['Brand', 'Color', 'Type', 'Power Source'] ['Smart Planet', 'Yellow', 'Sandwich Maker', 'Electrical.']

text="Brand.*/Smart Planet.#/Color.*/Yellow.#/Type.*/Sandwich Maker.#/Power Source.*/Electrical."
name=[]
value=[]
word=''
for i in range(len(text)):
temp=i
if text[i]!='.' and text[i]!='/' and text[i]!='*' and text[i]!='#':
word=word+''.join(text[i])
elif temp+1<len(text) and temp+2<=len(text):
if text[i]=='.' and text[temp+1]=='*' and text[temp+2]=='/':
name.append(word)
word=''
elif text[i]=='.' and text[temp+1]=='#' and text[temp+2]=='/':
value.append(word)
word=''
else:
value.append(word)
print(name)
print(value)
this will be work...

Translate unicode characters in a string to ISO 8859-1 Characters

I have the following string:
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I want to transform this string into the following JSON-object:
{"h":[{"id":"242611","minute":"2","result":"MissedShots","X":"0.9359999847412109","Y":"0.534000015258789","xG":"0.1072189137339592","player":"Ari","h_a":"h","player_id":"2930","situation":"OpenPlay","season":"2018","shotType":"Head","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":"Wanderson","lastAction":"Chipped"},{"id":"242612","minute":"4","result":"SavedShot","X":"0.8059999847412109","Y":"0.7069999694824218","xG":"0.021672379225492477","player":"Cristian Ramirez","h_a":"h","player_id":"5477","situation":"OpenPlay","season":"2018","shotType":"LeftFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":null,"lastAction":"None"},{"id":"242613","minute":"4","result":"SavedShot","X":"0.7780000305175782","Y":"0.505","xG":"0.023817993700504303","player":"Mauricio Pereyra","h_a":"h","player_id":"2922","situation":"OpenPlay","season":"2018","shotType":"RightFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":"Viktor Claesson","lastAction":"Pass"},{"id":"242614","minute":"17","result":"MissedShots","X":"0.9330000305175781","Y":"0.41","xG":"0.01863950863480568","player":"Ari","h_a":"h","player_id":"2930","situation":"FromCorner","season":"2018","shotType":"Head","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":"Mauricio Pereyra","lastAction":"Aerial"},{"id":"242617","minute":"21","result":"SavedShot","X":"0.710999984741211","Y":"0.534000015258789","xG":"0.015956614166498184","player":"Ivan Ignatyev","h_a":"h","player_id":"6025","situation":"OpenPlay","season":"2018","shotType":"RightFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":"Ari","lastAction":"Pass"},{"id":"242621","minute":"31","result":"MissedShots","X":"0.7959999847412109","Y":"0.4640000152587891","xG":"0.03898102045059204","player":"Viktor Claesson","h_a":"h","player_id":"5478","situation":"OpenPlay","season":"2018","shotType":"RightFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":null,"lastAction":"None"},{"id":"242622","minute":"36","result":"MissedShots","X":"0.759000015258789","Y":"0.3509999847412109","xG":"0.05237437039613724","player":"Mauricio Pereyra","h_a":"h","player_id":"2922","situation":"DirectFreekick","season":"2018","shotType":"LeftFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":null,"lastAction":"Standard"},{"id":"242624","minute":"42","result":"BlockedShot","X":"0.919000015258789","Y":"0.37","xG":"0.10843519121408463","player":"Sergei Petrov","h_a":"h","player_id":"2920","situation":"OpenPlay","season":"2018","shotType":"RightFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":"Viktor Claesson","lastAction":"Pass"},{"id":"242625","minute":"48","result":"MissedShots","X":"0.7719999694824219","Y":"0.385","xG":"0.023656079545617104","player":"Aleksandr Martynovich","h_a":"h","player_id":"2790","situation":"OpenPlay","season":"2018","shotType":"RightFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural","h_goals":"2","a_goals":"0","date":"2018-12-02 11:00:00","player_assisted":"Yuri Gazinskiy","lastAction":"Pass"},{"id":"242626","minute":"49","result":"MissedShots","X":"0.715999984741211","Y":"0.4879999923706055","xG":"0.013118931092321873","player":"Yuri Gazinskiy","h_a":"h","player_id":"2929","situation":"OpenPlay","season":"2018","shotType":"RightFoot","match_id":"9071","h_team":"FC Krasnodar","a_team":"Ural"}]}
With the help of a table I what each of the following unicode-characters represents:
\x7B = {
\x22 = "
\x3A = :
\x5B = [
\x7D = }
\x5D = ]
As a result, I have written the following script:
string = '\x7B\x22h\x22\x3A\....\\x22\x22\x7D\x5D\x7D'
cleaned_string = string.replace("\x7B","{")
cleaned_string = cleaned_string.replace('\x22', '"')
cleaned_string = cleaned_string.replace("\x3A", ":")
cleaned_string = cleaned_string.replace("\x5B", "[")
cleaned_string = cleaned_string.replace("\x7D", "}")
cleaned_string = cleaned_string.replace("\x5D", "]")
s = json.loads(cleaned_string)
However, The problem arises in the player- and player-assisted -field. Especially, for French or Spanish names there are multiple special characters possible. Currently, my script is only transforming the "standard" characters. In theory, there are of course a lot of different other characters that need to be transformed. How can I do this easily?
Thanks in advance,

separate text with semicolons in python

I have a text file in this format:
subscriber=admin lname="adamec22a" password="kofola1224" first-name="Anton net na M.lehote,zapajal si to sam!!" last-name="Adamec 1.3.2012 skoncil zmluvu" phone="00421917499086" location="NB, Sturova 18, 2pos." rate-limit=" 1M/3M" last-seen=never
What I need to do in Python is that each record in the line should be separated by a semicolon and if there is no record (like first-name, or some other), the script should leave there a blank space between two semicolons.

Assuming that the input lines are consistently formatted, and that I understand what you're asking, you can recover the data in the way indicated here. Then you can output it in any way that suits you.
>>> pieces = '''subscriber=admin lname="adamec22a" password="kofola1224" first-name="Anton net na M.lehote,zapajal si to sam!!" last-name="Adamec 1.3.2012 skoncil zmluvu" phone="00421917499086" location="NB, Sturova 18, 2pos." rate-limit=" 1M/3M" last-seen=never'''.split('=')
>>> fieldNames = [ pieces[0] ]
>>> for i in range(1, -1+len(pieces)):
... fieldNames.append(pieces[i][1+pieces[i].rfind(' '):])
...
>>> fieldNames
['subscriber', 'lname', 'password', 'first-name', 'last-name', 'phone', 'location', 'rate-limit', 'last-seen']
>>> fieldValues = [ pieces[-1]]
>>> for i in range(-2+len(pieces),0,-1):
... fieldValues.append(pieces[i][:pieces[i].rfind(' ')])
...
>>> fieldValues.reverse()
>>> fieldValues
['admin', '"adamec22a"', '"kofola1224"', '"Anton net na M.lehote,zapajal si to sam!!"', '"Adamec 1.3.2012 skoncil zmluvu"', '"00421917499086"', '"NB, Sturova 18, 2pos."', '" 1M/3M"', 'never']
>>> for fieldName, fieldValue in zip(fieldNames, fieldValues):
... fieldName, fieldValue
...
('subscriber', 'admin')
('lname', '"adamec22a"')
('password', '"kofola1224"')
('first-name', '"Anton net na M.lehote,zapajal si to sam!!"')
('last-name', '"Adamec 1.3.2012 skoncil zmluvu"')
('phone', '"00421917499086"')
('location', '"NB, Sturova 18, 2pos."')
('rate-limit', '" 1M/3M"')
('last-seen', 'never')

Multiple split of input?

I know that you can use split() to split a user input into two, but how would you split input that consists of multiple variables ? For example:
User input:
Shawn=14:soccer#2991842
What I would like to do:
name = Shawn
age = 14
course = soccer
idnumber = 2991842
What's the best way to do such thing ?

str = 'Shawn=14:soccer#2991842'
keys = ['name', 'age', 'course', 'idnumber']
values = re.split('[=:#]', str)
print dict(zip(keys, values))
Out[114]: {'age': '14', 'course': 'soccer', 'idnumber': '2991842', 'name': 'Shawn'}

I think Regex will work best here:
>>> from re import split
>>> mystr = "Shawn=14:soccer#2991842"
>>> split("\W", mystr)
['Shawn', '14', 'soccer', '2991842']
>>> lst = split("\W", mystr)
>>> name = lst[0]
>>> name
'Shawn'
>>> age = lst[1]
>>> age
'14'
>>> course = lst[2]
>>> course
'soccer'
>>> idnumber = lst[3]
>>> idnumber
'2991842'
>>>
Also, the above is a step-by-step demonstration. You can actually just do:
name, age, course, idnumber = split("\W", mystr)

Here's how I would do it.
def splitStr(str):
temp = str.split(':')
temp_nameAge = temp[0].split('=')
temp_courseId = temp[1].split('#')
name = temp_nameAge[0]
age = int(temp_nameAge[1])
course = temp_courseId[0]
idnumber = int(temp_courseId[1])
print 'Name = %s, age = %i, course = %s, id_number = %i' % (name, age, course, idnumber)

Another thing you can do is use split like: string.split(":").
Then you can change the format to "name:age:course:number"

You could just keep splitting the splits...
text2split = "Shawn=14:soccer#2991842"
name = text2split.split('=')[0]
age = text2split.split('=')[1].split(':')[0]
course = text2split.split('=')[1].split(':')[1].split('#')[0]
idnumber = text2split.split('=')[1].split(':')[1].split('#')[1]
This isn't the most elegant way to do it, but it'll work so long as text2split always has the same delimeters.

If you are ok with storing them under dictionary keys, you could use named group references
import re
x='shawn=14:soccer#2991842'
re.match(r'(?P<name>.*?)=(?P<age>.*):(?P<course>.*?)#(?P<idnumber>.*)', x).groupdict()
{'idnumber': '2991842', 'course': 'soccer', 'age': '14', 'name': 'shawn

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