Interact with python using subprocess - python

I try to interact to python interpreter using subprocess module like this :
import subprocess
def start(executable_file):
return subprocess.Popen(
executable_file,
stdin=subprocess.PIPE,
stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
def read(process):
return process.stdout.readline().decode("utf-8").strip()
def write(process, message):
process.stdin.write(f"{message.strip()}\n".encode("utf-8"))
process.stdin.flush()
def terminate(process):
process.stdin.close()
process.terminate()
process.wait(timeout=0.2)
process = start("python")
while True:
write(process, input())
print(read(process))
terminate(process)
But it seems it's locked a deadlock.
If anyone knows how to interact with python with python code and recover stdout, stderr with stream mode.

You need to use communicate() rather than read() and write() with subprocesses else it will lead to deadlock.
See red warning breakout towards middle of this page.

Related

How to run & stop python script from another python script?

I want code like this:
if True:
run('ABC.PY')
else:
if ScriptRunning('ABC.PY):
stop('ABC.PY')
run('ABC.PY'):
Basically, I want to run a file, let's say abc.py, and based on some conditions. I want to stop it, and run it again from another python script. Is it possible?
I am using Windows.
You can use python Popen objects for running processes in a child process
So run('ABC.PY') would be p = Popen("python 'ABC.PY'")
if ScriptRunning('ABC.PY) would be if p.poll() == None
stop('ABC.PY') would be p.kill()
This is a very basic example for what you are trying to achieve
Please checkout subprocess.Popen docs to fine tune your logic for running the script
import subprocess
import shlex
import time
def run(script):
scriptArgs = shlex.split(script)
commandArgs = ["python"]
commandArgs.extend(scriptArgs)
procHandle = subprocess.Popen(commandArgs, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
return procHandle
def isScriptRunning(procHandle):
return procHandle.poll() is None
def stopScript(procHandle):
procHandle.terminate()
time.sleep(5)
# Forcefully terminate the script
if isScriptRunning(procHandle):
procHandle.kill()
def getOutput(procHandle):
# stderr will be redirected to stdout due "stderr=subprocess.STDOUT" argument in Popen call
stdout, _ = procHandle.communicate()
returncode = procHandle.returncode
return returncode, stdout
def main():
procHandle = run("main.py --arg 123")
time.sleep(5)
isScriptRunning(procHandle)
stopScript(procHandle)
print getOutput(procHandle)
if __name__ == "__main__":
main()
One thing that you should be aware about is stdout=subprocess.PIPE.
If your python script has a very large output, the pipes may overflow causing your script to block until .communicate is called over the handle.
To avoid this, pass a file handle to stdout, like this
fileHandle = open("main_output.txt", "w")
subprocess.Popen(..., stdout=fileHandle)
In this way, the output of the python process will be dumped into the file.(You will have to modily the getOutput() function too for this)
import subprocess
process = None
def run_or_rerun(flag):
global process
if flag:
assert(process is None)
process = subprocess.Popen(['python', 'ABC.PY'])
process.wait() # must wait or caller will hang
else:
if process.poll() is None: # it is still running
process.terminate() # terminate process
process = subprocess.Popen(['python', 'ABC.PY']) # rerun
process.wait() # must wait or caller will hang

Hanging parent process after running a timed-out subprocess and piping results

I wrote some code to run a script (via a subprocess) and kill the child process after a certain timeout. I'm running a script called "runtime_hang_script.sh" that just contains "./runtime_hang," which runs an infinite loop. I'm also redirecting stdout to a pipe -- I plan to write it to both sys.stdout and to a file (aka I'm trying to implement tee). However, my code hangs after the subprocess times out. Note that this ONLY hangs when running "sh runtime_hang_script.sh" and not "./runtime_hang." Also, this doesn't hang when I try piping directly to a file or when I don't read from the pipe.
I've tried other implementations of creating a timed subprocess, but I keep on getting the same issue. I've even tried raising a signal at the end of the problem -- for some reason, the signal is raised earlier than anticipated, so this doesn't work either. Any help would be appreciated. Thanks in advance!
process = None
def run():
global process
timeout_secs = 5
args = ['sh', 'runtime_hang_script.sh']
sys.stdout.flush()
process = subprocess.Popen(args, stdout=subprocess.PIPE, bufsize=1)
with process.stdout:
for line in iter(process.stdout.readline, b''):
sys.stdout.write(line.decode('utf-8'))
sys.stdout.flush()
process.wait()
proc_thread = threading.Thread(target=run)
proc_thread.start()
proc_thread.join(5)
print(proc_thread.is_alive())
if proc_thread.is_alive():
process.kill()
Assuming you are using Python 3.3 or newer, you can use the timeout argument of the subprocess.communicate() method to implement your 5-second timeout:
import subprocess
import sys
timeout_secs = 5
args = ['sh', 'runtime_hang_script.sh']
process = subprocess.Popen(args, stdout=subprocess.PIPE, bufsize=1)
try:
print("Waiting for data from child process...")
(stdoutData, stderrData) = process.communicate(None, timeout_secs)
print("From child process: stdoutData=[%s] stderrData=[%s]" % (stdoutData, stderrData))
except subprocess.TimeoutExpired:
print("Oops, child process took too long! Now it has to die")
process.kill()
print("Waiting for child process to exit...")
process.wait()
print("Child process exited.")
Note that spawning a child thread isn't necessary with this approach, since the timeout can work directly from the main thread.

start a service with popen : command not stopping

I try to make a backup script in python and start, stop a service with popen...
Stopping the service is working, but unfortunatly starting the service works, but blocks the rest of the execution, the scripts stays there, why ?
Seems to be somehow linked with the httpd service... :-(
the program config element is like "service;httpd;start" or "/etc/init.d/myprog;start"
class execute(actions):
def __init__(self,config,section,logger):
self.name="execute"
actions.__init__(self,config,section,logger)
def process(self):
try:
program=self.config.get(self.section,"program").split(";")
self.logger.debug("program=%s" % program)
p = subprocess.Popen(program, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
stdout, stderr = p.communicate()
if stdout:
self.logger.info(stdout)
if stderr:
self.logger.error(stderr)
return p.returncode
except Exception:
self.logger.exception(Exception)
You have to open a stdin as a pipe as well, and then close it (if you use read() and write() instead of communicate()).
p = subprocess.Popen(..., stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
p.stdin.close()
print "Stdout:", p.stdout.read()
print "Stderr:", p.stderr.read()
If it doesn't work, and you don't really need any checks, just close all pipes after call to Popen, what will cause program execution and detachment
from pipes.
Warning: This will make program run as a daemon if it doesn't terminate on its own.
After doing this you may call wait() to see whether it'll block as well. And use exitcodes to check for eventual errors.
There are not much of them. Just service started or not. Sometimes even it returns that service is running, but service crashes.
To check whether service script is still running, but without blocking, use:
if p.poll()==None: print "Still running"
Else, poll() returns the exit code.
This works neatly for starting and stopping a service:
from subprocess import Popen, PIPE
service = "brltty"
p = Popen(["service", service, "start"], stdin=PIPE, stdout=PIPE, stderr=PIPE)
# Note: using sequence uses shell=0
stdout, stderr = p.communicate()
print "Stdout:", stdout
print "Stderr:", stderr
Don't forget to change start to stop :D :D :D
The call to p.communicate() waits for the process to terminate.
Refer to: subprocess documentation
Interact with process: Send data to stdin. Read data from stdout and
stderr, until end-of-file is reached. Wait for process to terminate.
The optional input argument should be a string to be sent to the child
process, or None, if no data should be sent to the child.
You can try to use p.poll() instead. This method doesn't wait for a process to terminate.

Popen communicate is not working

I have a script that has been working properly for the past 3 months. The Server went down last Monday and since then my script stopped working. The script hangs at coords = p.communicate()[0].split().
Here's a part of the script:
class SelectByLatLon(GridSelector):
def __init__(self, from_lat, to_lat, from_lon, to_lon):
self.from_lat = from_lat
self.to_lat = to_lat
self.from_lon = from_lon
self.to_lon = to_lon
def get_selection(self, file):
p = subprocess.Popen(
[
os.path.join(module_root, 'bin/points_from_latlon.tcl'),
file,
str(self.from_lat), str(self.to_lat), str(self.from_lon), str(self.to_lon)
],
stdout = subprocess.PIPE
)
coords = p.communicate()[0].split()
return ZGridSelection(int(coords[0]), int(coords[1]), int(coords[2]), int(coords[3]))
When I run the script on another server everything works just fine.
Can I use something else instead of p.communicate()[0].split() ?
You might have previously run your server without daemonization i.e., you had functional stdin, stdout, stderr streams. To fix, you could redirect the streams to DEVNULL for the subprocess:
import os
from subprocess import Popen, PIPE
DEVNULL = os.open(os.devnull, os.O_RDWR)
p = Popen(tcl_cmd, stdin=DEVNULL, stdout=PIPE, stderr=DEVNULL, close_fds=True)
os.close(DEVNULL)
.communicate() may wait for EOF on stdout even if tcl_cmd already exited: the tcl script might have spawned a child process that inherited the standard streams and outlived its parent.
If you know that you don't need any stdout after the tcl_cmd exits then you could kill the whole process tree when you detect that tcl_cmd is done.
You might need start_new_session=True analog to be able to kill the whole process tree:
import os
import signal
from threading import Timer
def kill_tree_on_exit(p):
p.wait() # wait for tcl_cmd to exit
os.killpg(p.pid, signal.SIGTERM)
t = Timer(0, kill_tree_on_exit, [p])
t.start()
coords = p.communicate()[0].split()
t.cancel()
See How to terminate a python subprocess launched with shell=True

Python subprocess readlines() hangs

The task I try to accomplish is to stream a ruby file and print out the output. (NOTE: I don't want to print out everything at once)
main.py
from subprocess import Popen, PIPE, STDOUT
import pty
import os
file_path = '/Users/luciano/Desktop/ruby_sleep.rb'
command = ' '.join(["ruby", file_path])
master, slave = pty.openpty()
proc = Popen(command, bufsize=0, shell=True, stdout=slave, stderr=slave, close_fds=True)
stdout = os.fdopen(master, 'r', 0)
while proc.poll() is None:
data = stdout.readline()
if data != "":
print(data)
else:
break
print("This is never reached!")
ruby_sleep.rb
puts "hello"
sleep 2
puts "goodbye!"
Problem
Streaming the file works fine. The hello/goodbye output is printed with the 2 seconds delay. Exactly as the script should work. The problem is that readline() hangs in the end and never quits. I never reach the last print.
I know there is a lot of questions like this here a stackoverflow but non of them made me solve the problem. I'm not that into the whole subprocess thing so please give me a more hands-on/concrete answer.
Regards
edit
Fix unintended code. (nothing to do with the actual error)
I assume you use pty due to reasons outlined in Q: Why not just use a pipe (popen())? (all other answers so far ignore your "NOTE: I don't want to print out everything at once").
pty is Linux only as said in the docs:
Because pseudo-terminal handling is highly platform dependent, there
is code to do it only for Linux. (The Linux code is supposed to work
on other platforms, but hasn’t been tested yet.)
It is unclear how well it works on other OSes.
You could try pexpect:
import sys
import pexpect
pexpect.run("ruby ruby_sleep.rb", logfile=sys.stdout)
Or stdbuf to enable line-buffering in non-interactive mode:
from subprocess import Popen, PIPE, STDOUT
proc = Popen(['stdbuf', '-oL', 'ruby', 'ruby_sleep.rb'],
bufsize=1, stdout=PIPE, stderr=STDOUT, close_fds=True)
for line in iter(proc.stdout.readline, b''):
print line,
proc.stdout.close()
proc.wait()
Or using pty from stdlib based on #Antti Haapala's answer:
#!/usr/bin/env python
import errno
import os
import pty
from subprocess import Popen, STDOUT
master_fd, slave_fd = pty.openpty() # provide tty to enable
# line-buffering on ruby's side
proc = Popen(['ruby', 'ruby_sleep.rb'],
stdin=slave_fd, stdout=slave_fd, stderr=STDOUT, close_fds=True)
os.close(slave_fd)
try:
while 1:
try:
data = os.read(master_fd, 512)
except OSError as e:
if e.errno != errno.EIO:
raise
break # EIO means EOF on some systems
else:
if not data: # EOF
break
print('got ' + repr(data))
finally:
os.close(master_fd)
if proc.poll() is None:
proc.kill()
proc.wait()
print("This is reached!")
All three code examples print 'hello' immediately (as soon as the first EOL is seen).
leave the old more complicated code example here because it may be referenced and discussed in other posts on SO
Or using pty based on #Antti Haapala's answer:
import os
import pty
import select
from subprocess import Popen, STDOUT
master_fd, slave_fd = pty.openpty() # provide tty to enable
# line-buffering on ruby's side
proc = Popen(['ruby', 'ruby_sleep.rb'],
stdout=slave_fd, stderr=STDOUT, close_fds=True)
timeout = .04 # seconds
while 1:
ready, _, _ = select.select([master_fd], [], [], timeout)
if ready:
data = os.read(master_fd, 512)
if not data:
break
print("got " + repr(data))
elif proc.poll() is not None: # select timeout
assert not select.select([master_fd], [], [], 0)[0] # detect race condition
break # proc exited
os.close(slave_fd) # can't do it sooner: it leads to errno.EIO error
os.close(master_fd)
proc.wait()
print("This is reached!")
Not sure what is wrong with your code, but the following seems to work for me:
#!/usr/bin/python
from subprocess import Popen, PIPE
import threading
p = Popen('ls', stdout=PIPE)
class ReaderThread(threading.Thread):
def __init__(self, stream):
threading.Thread.__init__(self)
self.stream = stream
def run(self):
while True:
line = self.stream.readline()
if len(line) == 0:
break
print line,
reader = ReaderThread(p.stdout)
reader.start()
# Wait until subprocess is done
p.wait()
# Wait until we've processed all output
reader.join()
print "Done!"
Note that I don't have Ruby installed and hence cannot check with your actual problem. Works fine with ls, though.
Basically what you are looking at here is a race condition between your proc.poll() and your readline(). Since the input on the master filehandle is never closed, if the process attempts to do a readline() on it after the ruby process has finished outputting, there will never be anything to read, but the pipe will never close. The code will only work if the shell process closes before your code tries another readline().
Here is the timeline:
readline()
print-output
poll()
readline()
print-output (last line of real output)
poll() (returns false since process is not done)
readline() (waits for more output)
(process is done, but output pipe still open and no poll ever happens for it).
Easy fix is to just use the subprocess module as it suggests in the docs, not in conjunction with openpty:
http://docs.python.org/library/subprocess.html
Here is a very similar problem for further study:
Using subprocess with select and pty hangs when capturing output
Try this:
proc = Popen(command, bufsize=0, shell=True, stdout=PIPE, close_fds=True)
for line in proc.stdout:
print line
print("This is most certainly reached!")
As others have noted, readline() will block when reading data. It will even do so when your child process has died. I am not sure why this does not happen when executing ls as in the other answer, but maybe the ruby interpreter detects that it is writing to a PIPE and therefore it will not close automatically.

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