Simply put, I want to properly implement threading in a Python GTK application. This is in order to prevent UI freezing due to functions/code taking a long time to finish running. Hence, my approach was to move all code which took a long time to run into separate functions, and run them in their separate threads as needed. This however posed a problem when trying to run the functions in sequence.
For example, take a look at the following code:
class Main(Gtk.Window):
def __init__(self):
super().__init__()
self.button = Gtk.Button(label='button')
self.add(self.button)
self.button.connect('clicked', self.main_function)
def threaded_function(self):
time.sleep(20)
print('this is a threaded function')
def first_normal_function(self):
print('this is a normal function')
def second_normal_function(self):
print('this is a normal function')
def main_function(self, widget):
self.first_normal_function()
self.threaded_function()
self.second_normal_function()
Pressing the button starts main_function which then starts 3 functions in sequence. threaded_function represents a function which would take a long time to complete. Running this as is will freeze the UI. Hence it should be threaded as such:
...
...
def main_function(self, widget):
self.first_normal_function()
thread = threading.Thread(target=self.threaded_function)
thread.daemon = True
thread.start()
self.second_normal_function()
What should happen is that the following first_normal_function should run, then threaded_function in a background thread - the UI should remain responsive as the background thread is working. Finally, second_normal_function should run, but only when threaded_function is finished.
The issue with this is that the functions will not run in sequence. The behaviour I am looking for could be achieved by using thread.join() however this freezes the UI.
So I ask, what's the proper way of doing this? This is a general case, however it concerns the general issue of having code which takes a long time to complete in a graphical application, while needing code to run sequentially. Qt deals with this by using signals, and having a QThread emit a finished signal. Does GTK have an equivalent?
I'm aware that this could be partially solved using Queue , with a put() and get() in relevant functions, however I don't understand how to get this to work if the main thread is calling anything other than functions.
EDIT: Given that it's possible to have threaded_function call second_normal_function using GLib.idle_add, let's take an example where in main_function, the second_normal_function call is replaced with a print statement, such that:
def main_function(self, widget):
self.first_normal_function()
thread = threading.Thread(target=self.threaded_function)
thread.daemon = True
thread.start()
print('this comes after the thread is finished')
...
...
...
#some more code here
With GLib.idle_add, the print statement and all the code afterwards would need to be moved into a separate function. Is it possible to avoid moving the print statement into its own function while maintaining sequentiality, such that the print statement remains where it is and still gets called after threaded_function is finished?
Your suggestion on how to do this was very close to the actual solution, but it's indeed not going to work.
In essence, what you'll indeed want to do, is to run the long-running function in a different thread. That'll mean you get 2 threads: one which is running the main event loop that (amongs other things) updates your UI, and another thread which does the long-running logic.
Of course, that bears the question: how do I notify the main thread that some work is done and I want it to react to that? For example, you might want to update the UI while (or after) some complex calculation is going on. For this, you can use GLib.idle_add() from within the other thread. That function takes a single callback as an argument, which it will run as soon as it can ("on idle").
So a possibility to use here, would be something like this:
class Main(Gtk.Window):
def __init__(self):
super().__init__()
self.button = Gtk.Button(label='button')
self.add(self.button)
self.button.connect('clicked', self.main_function)
thread = threading.Thread(target=self.threaded_function)
thread.daemon = True
thread.start()
def threaded_function(self):
# Really intensive stuff going on here
sleep(20)
# We're done, schedule "on_idle" to be called in the main thread
GLib.idle_add(self.on_idle)
# Note, this function will be run in the main loop thread, *not* in this one
def on_idle(self):
second_normal_function()
return GLib.SOURCE_REMOVE # we only want to run once
# ...
For more context, you might want to read the pygobject documentation on threading and concurrency
Related
My issue follows: I've a main GUI that manages different connections with an instrument and elaborates the data coming from this latter according to the user choices. I designed a class InstrumentController that manages all the methods to speak with the instrument (connect, disconnect, set commands and read commands).
Obviously I'd like to make the instrument management to work parallel to the GUI application. I've already explored the QThread, and in particular the moveToThread option widely detailed on the Internet. However, though it works, I don't like this strategy for some reason:
I don't want my object to be a thread (subclass QThread). I'd like to maintain the modularity and generality of my class.
...even if it has to be, it doesn't solve the next point
QThread, obviously, works on a single callback base. Thus, I've an extra workload to either create a thread per each InstrumentController method or accordingly configure a single thread each time a method is called (I'm not expecting the methods of the object to work concurrently!)
As a consequence, I'm seeking a solution that allows me to have the InstrumentController entity to work like a separate program (deamon?) but that must be strongly linked to the main GUI (it has to continuously communicate back and forth), so that I need signals from GUI to be visible by this object and viceversa. I was exploring some solution, namely:
Create an extra event loop (QEventLoop) that works parallel to the main loop, but the official docs is very slim and I found little more on the Internet. Therefore I don't even know if it is practicable.
Create a separate process (another Qt application) and search for an effective protocol of communication.
Aware that venturing into one of these solution might be time-consuming and possibly -waisting, I'd like to ask for any effective, efficient and practicable suggestion that might help with my problem.
The first thing to consider is that a QThread is only a wrapper to a OS thread.
moveToThread() does not move an object to the QThread object, but to the thread that it refers to; in fact, a QThread might have its own thread() property (as Qt documentation reports, it's "the thread in which the object lives").
With that in mind, moveToThread() is not the same as creating a QThread, and, most importantly, a QThread does not work "on a single callback base". What's important is what it's executed in the thread that QThread refers to.
When a QThread is started, whatever is executed in the threaded function (aka, run()) is actually executed in that thread.
Connecting a function to the started signal results in executing that function in the OS thread the QThreads refers to.
Calling a function from any of that functions (including the basic run()) results in running that function in the other thread.
If you want to execute functions for that thread, those functions must be called from there, so a possible solution is to use a Queue to pass that function reference to ensure that a command is actually executed in the other thread. So, you can run a function on the other thread, as long as it's called (not just referenced to) from that thread.
Here's a basic example:
import sys
from queue import Queue
from random import randrange
from PyQt5 import QtCore, QtWidgets
class Worker(QtCore.QThread):
log = QtCore.pyqtSignal(object)
def __init__(self):
super().__init__()
self.queue = Queue()
def run(self):
count = 0
self.keepRunning = True
while self.keepRunning:
wait = self.queue.get()
if wait is None:
self.keepRunning = False
continue
count += 1
self.log.emit('Process {} started ({} seconds)'.format(count, wait))
self.sleep(wait)
self.log.emit('Process {} finished after {} seconds'.format(count, wait))
self.log.emit('Thread finished after {} processes ({} left unprocessed)'.format(
count, self.queue.qsize()))
def _queueCommand(self, wait=0):
self.queue.put(wait)
def shortCommand(self):
self._queueCommand(randrange(1, 5))
def longCommand(self):
self._queueCommand(randrange(5, 10))
def stop(self):
if self.keepRunning:
self.queue.put(None)
self.keepRunning = False
class Test(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.startShort = QtWidgets.QPushButton('Start short command')
self.startLong = QtWidgets.QPushButton('Start long command')
self.stop = QtWidgets.QPushButton('Stop thread')
self.log = QtWidgets.QTextEdit(readOnly=True)
layout = QtWidgets.QVBoxLayout(self)
layout.addWidget(self.startShort)
layout.addWidget(self.startLong)
layout.addWidget(self.stop)
layout.addWidget(self.log)
self.worker = Worker()
self.worker.log.connect(self.log.append)
self.startShort.clicked.connect(self.worker.shortCommand)
self.startLong.clicked.connect(self.worker.longCommand)
self.stop.clicked.connect(self.worker.stop)
self.worker.finished.connect(lambda: [
w.setEnabled(False) for w in (self.startShort, self.startLong, self.stop)
])
self.worker.start()
app = QtWidgets.QApplication(sys.argv)
test = Test()
test.show()
app.exec()
I was attempting to create a thread class that could be terminated by an exception (since I am trying to have the thread wait on an event) when I created the following:
import sys
class testThread(threading.Thread):
def __init__(self):
super(testThread,self).__init__()
self.daemon = True
def run(self):
try:
print('Running')
while 1:
pass
except:
print('Being forced to exit')
test1 = testThread()
test2 = testThread()
print(test1.daemon)
test1.run()
test2.run()
sys.exit()
However, running the program will only print out one Running message, until the other is terminated. Why is that?
The problem is that you're calling the run method.
This is just a plain old method that you implement, which does whatever you put in its body. In this case, the body is an infinite loop, so calling run just loops forever.
The way to start a thread is the start method. This method is part of the Thread class, and what it does is:
Start the thread’s activity.
It must be called at most once per thread object. It arranges for the object’s run() method to be invoked in a separate thread of control.
So, if you call this, it will start a new thread, make that new thread run your run() method, and return immediately, so the main thread can keep doing other stuff.1 That's what you want here.
1. As pointed out by Jean-François Fabre, you're still not going to get any real parallelism here. Busy loops are never a great idea in multithreaded code, and if you're running this in CPython or PyPy, almost all of that busy looping is executing Python bytecode while holding the GIL, and only one thread can hold the GIL at a time. So, from a coarse view, things look concurrent—three threads are running, and all making progress. But if you zoom in, there's almost no overlap where two threads progress at once, usually not even enough to make up for the small scheduler overhead.
My goal for a task is to allow one button press to start two processes, both running simultaneously on different QThreads.
My code is structured like this (simplified)
class Main_Window():
# My UI stuff goes here
class worker1(QtCore.QObject):
def __init__(self):
...
def run1():
...
class worker2(QtCore.QObject):
def __init__(self):
...
def run2():
...
app = QtGui.QApplication(sys.argv)
myapp = Main_Window()
thr1 = QtCore.QThread()
thr2 = QtCore.QThread()
work1 = worker1()
work2 = worker2()
work1.moveToThread(thr1)
work2.moveToThread(thr2)
# I have a signal coming in from main thread
app.connect(myapp, QtCore.SIGNAL('start1'), work1.run1())
app.connect(myapp, QtCore.SIGNAL('start1'), work2.run2())
thr1.start()
thr2.start()
Is this kind of QThread coding incorrect if I want to setup two Qthreads?
I am getting a "Segmentation fault" when I try to start the program, but as soon as I take the second app.connect away, it runs fine.
I was wondering if anyone can tell me where I've gone wrong.
Thanks!
When you connect your signals with:
app.connect(myapp, QtCore.SIGNAL('start1'), work1.run1())
You are actually executing the run function, not just connecting it. You want to leave out the "()" or else python executes the function and tries to connect whatever it returns.
EDIT:
Two more suggestions in response to your comment saying you took out the "()".
First, I've never seen someone rename the run function when using the QtThread class and you may want to try the same code where both run1 and run2 are actually just named "run". Check out this thread for some good example:
How to use QThread correctly in pyqt with moveToThread()?
Second, can you post the actual error? Does it like anything like the one in this thread:
Is this PyQt 4 python bug or wrongly behaving code?
I'm trying to wrap the blocking calls in pyaudio with a thread to give me non-blocking access through queues. However, the problem I have is not with pyaudio, or queues, but with the issue of trying to test a thread. In keeping with "strip the example down to the minimum possible", all the pyaudio stuff has vanished, to leave only the thread class, and its instantiation in a main.
What I was hoping for was an object that I could create, and leave to get on with its stuff in the background, while I do control things with the console or tk. I figure the following max-stripped down example should have the thread doing stuff, while main runs and asks me if it is working. The raw_input prompt never appears. I would not be surprised at this if I was running it from IDLE, which is not thread safe, but I get the same behaviour if I run the script directly from the OS. I was prepared to see the raw input prompt disappear up the screen pushed by 'running' prints, but not even that happens. The prompt never appears. What's going on? It does respond to ctrl-C and to closing the window, but I'd still like to be able to see main running.
import threading
import time
class TestThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.running=True
self.run()
def run(self):
while self.running:
time.sleep(0.5)
print 'running'
def stop(self):
self.running=False
if __name__=='__main__':
tt=TestThread()
a=raw_input('simple stuff working ? -- ')
tt.stop()
You should start the thread with self.start() instead of self.run(). In this case you are just running the thread function like any other normal function.
Normally you do not inherit from Thread. Instead, you use Thread(target=func2run).start()
For example:
class DemoFrame(wx.Frame):
def __init__(self):
Initializing
...
self.TextA = wx.StaticText(MainPanel, id = -1, label = "TextAOrWhatever")
self.TextB = wx.StaticText(MainPanel, id = -1, label = "TextBOrWhatever")
...
def StaticTextUpdating(self, ObjectName, Message):
ObjectName.SetLabel(Message)
def WorkerA(self):
while True:
Work on something
UpdatingThread = threading.Thread(target = self.StaticTextUpdating, args = (self.TextA, "Something for TextA", ))
UpdatingThread.start()
time.sleep(randomSecs)
def WorkerB(self):
while True:
Work on something
UpdatingThread = threading.Thread(target = self.StaticTextUpdating, args = (self.TextB, "Something for TextB", ))
UpdatingThread.start()
time.sleep(randomSecs)
...
def StartWorking(self):
Spawn WorkerA thread
Spawn WorkerB thread
...
As you can see, I always update StaticText in new threads, and I'm 100% sure at a whatever certain time point there's only one thread updating a specific object, but the problem is, every now and then after running for a while, some objects just disappear. Why is this happening? Does it mean GUI updating is not thread safe? Maybe only one object can be updated at a certain time point?
Added:
OK, wx.CallAfter should be a good solution for above codes. But I got another question, what if a button event and SetLabel happens at the same time? Wouldn't things like this cause troubles although I don't see any?
Most wx methods are not thread-safe. Use wx.CallAfter if you want to invoke a wx method from another thread; replace
ObjectName.SetLabel(Message)
with:
wx.CallAfter(ObjectName.SetLabel, Message)
Edit: Some Background Information
In wx (And in most other UI platforms) all the UI updates get executed in a single thread called main thread (Or UI Thread). This is to make the UI work faster by avoiding the performance hit of thread synchronization.
But the down side of this is that If we write code to update the UI from a different thread the results are undefined. Sometimes it may work, sometimes it may crash, sometimes some other thing may happen. So we should always go to UI thread to do the UI updates. So we use CallAfter function to make UI update function execute in the UI thread.
UI thread in java
UI thread in C#
The main thing to remember is that you shouldn't update anything in wxPython without using a threadsafe method, such as wx.CallAfter, wx.CallLater or wx.PostEvent. See http://wiki.wxpython.org/LongRunningTasks or http://www.blog.pythonlibrary.org/2010/05/22/wxpython-and-threads/ for more information.