I am trying to visualize a tiff image in an ipython notebook using the following code, import statements are ignored for clarity purposes.
from PIL import Image
orig_img_path = os.path.join("path/to/tiff/0.tiff")
img_orig = Image.open(orig_img_path,"r")
plt.imshow(img_orig)
plt.show()
The above snippet just shows me the following black image -
I know that the image pixel values are non-zero since I can open the original images on my MacBook and they look like the following -
I also double check that the pixel values are nonzero by using the following code of casting the PIL image to an np array using the following code and printing the array out -
img_arr = np.array(img_orig)
print(img_arr)
which gives me the following output -
I think I know what the issue is as well - that the matplotlib pyplot thinks that this is a PNG image or something like that and as we can see the pixel values are very small to be perceivable by the human eyes. I mean I can simply multiply the image by 255 which gives the following image as expected, although scaling by 255 is not entirely right since the pixel values need to be normalized for the minimum to corrspond to 0 and max to 255 assuming mat plot lib thinks that it is showing a PNG image -
I would like to know if there is a better way of doing so rather than me manually doing it all the time, any native way of displaying tiff in a Jupyter/ipython notebook which preserves all the good properties of tiff images such as floating point numbers etc.
Thanks and please let me know if anything is unclear.
Edit 1: Link to the original file is here - https://drive.google.com/file/d/1O1-QM6aeU5-QZhT36vOMjDND2vkZNgqB/view?usp=sharing
-- Megh
If you share your original image in .tiff format the solution might be more precise.
You are reading the image pixels as type float: 0-1, and after that, you parse them as uint8 : 0-255 which will turn all pixels values into 0 or 1: Black or almost Black
You can try the following approach to read your image (supposedly Black and White) and parse it:
import cv2
gray = cv2.imread("path/to/tiff/0.tiff", cv2.IMREAD_UNCHANGED)
cv2.namedWindow("MyImage", cv2.WINDOW_NORMAL)
cv2.imshow("MyImage", gray)
cv2.waitKey(0)
What is the range of values that you expect in that image? Did you do any preprocessing to it?
The image you are trying to display in matplotlib contains negative values. Visualizing works well for any kind of uint8 data (Grayscale and RGB) and data in the range of 0 - 1. Your displaying issue can be addressed by adding the min value of the image and then dividing by the max value (effectively normalizing your data to the range 0-1).
[...]
img = np.array(img_orig, dtype=float)
img += abs(np.min(img))
img /= np.max(img)
plt.imshow(img)
plt.show()
Related
I want to convert a float32 image into uint8 image in Python.
I tried using the following code, but the output image only has values like 2 and 3 so the image is practically black.
gen_samples[0] * 255).round().astype(np.uint8)
When I try displaying the float32 image I get a blackish/greyish image where I can somewhat make out the required image.
Normalize the array to 0..1 first.
Assuming gen_samples is the image matrix:
arr_min = np.min(gen_samples)
arr_max = np.max(gen_samples)
gen_samples = (gen_samples - arr_min) / (arr_max - arr_min)
Since you tagged the question using scikit-image you are probably using skimage. In this case img_as_ubyte should do the trick:
from skimage.util import image_as_ubyte
img = img_as_ubyte(gen_samples[0])
Further, since you tagged the question with imageio-python I'll assume that the image data actually comes from some (binary) image format rather than being generated in the script. In this case, you can often use the backend that does the decoding and do the conversion while the image is being loaded. This is, however, specific to the format being used, so for a more specific answer you would have to provide more insight into where your images are coming from.
I try to read a TIFF file with pillow/PIL (7.2.0) in Python (3.8.3), e.g. this image.
The resulting file seems to be corrupted:
from PIL import Image
import numpy as np
myimage = Image.open('moon.tif')
myimage.mode
# 'L'
myimage.format
# 'TIFF'
myimage.size
# (358, 537)
# so far all good, but:
np.array(myimage)
# shows only zeros in the array, likewise
np.array(myimage).sum()
# 0
It doesn't seem to be a problem of the conversion to numpy array only, since if I save it to a jpg (myimage.save('moon.jpg')) the resulting jpg image has the appropriate dimensions but is all black, too.
Where did I do wrong or is it a bug?
I am not an expert in coding but i had same problem and found the TIFF file has 4 layers. R, G ,B and Alpha. When you convert it using PIL it is black.
try to view the image as plt.imshow(myimage[:, :, 0])
you could also remove the Alpha layer by saving the read image ( i used plt.imread('image')) and then saving it as image=image[:,:,3]. Now its a RGB image.
I don't know if i answered your question, but i felt this info might be of help.
I am trying to change the values from a gray scale PNG image and then create an image from those changed values.
The first step I took was using a python implementation of libpng.
With that I was able to get a list of all the pixel values of the PNG. It is a gray scale image so the values where from 0 to 100. I do a quick algorithm to change the values. And then I try to create it into a new PNG file. Its all on a single line so I use regex to format it into a 2D array.
I attempted to use this that I found here
from PIL import Image
import numpy as np
pixels = [[100,0,0],[0,100,0],[0,0,100]]
# Convert the pixels into an array using numpy
array = np.array(pixels)
print(array)
# Use PIL to create an image from the new array of pixels
new_image = Image.fromarray(array, 'L')
new_image.save('testing.png')
But I guess the formatting that PIL uses is different from what the libpng is so instead of making an image that looks like 3 white pixels diagonally, I only get 1 white pixel on the top left. So either I change the values I am getting from libpng so that numpy works, or I find something in libpng that will allow me to change the values directly and create the new file.
The error in your code is that you are not setting the right data type for the array. If you call array = np.array(pixels, dtype='uint8') then your code will work.
I've tried overlaying two images in openCV both in openCV and in PIL, but to no avail. I'm using a 1000x1000x3 array of np.zeros for the background (aka, a black background) and this random image of my monitor, but I really can't get it to work for some reason unbeknownst to me.
Trying with OpenCV only: (result(if you pay attention, you can see a couple of weird lines and dots in the middle))
base_temp = np.zeros((1000,1000,3))
foreground_temp = cv2.imread('exampleImageThatILinkedAbove.png')
base_temp[offset_y:offset_y+foreground_temp.shape[0], offset_x:offset_x+foreground_temp.shape[1]] = foreground_temp
Trying with PIL: (The result is literally the same as the OpenCV version)
base_temp = cv2.convertScaleAbs(self.base) #Convert to uint8 for cvtColor
base_temp = cv2.cvtColor(base_temp, cv2.COLOR_BGR2RGB) #PIL uses RGB and OpenCV uses BGR
base_temp = Image.fromarray(base_temp) #Convert to PIL Image
foreground_temp = cv2.cvtColor(cv2.convertScaleAbs(self.last_img), cv2.COLOR_BGR2RGB)
foreground_temp = Image.fromarray(foreground_temp)
base_temp.paste(foreground_temp, offset)
I'm using python3.5 and and OpenCV3.4 on Windows 10, if that's any help.
I'd like to avoid any solutions that require saving the cv2 images and then reloading them in another module to convert them but if it's unavoidable that's okay too. Any help would be appreciated!
If you check the type of base_temp, you will see it is float64 and that is going to cause you problems when you try to save it as a JPEG which expects unsigned 8-bit values.
So the solution is to create your base_temp image with the correct type:
base_temp = np.zeros((1000,1000,3), dtype=np.uint8)
The complete code and result look like this:
import cv2
import numpy as np
from PIL import Image
# Make black background - not square, so it shows up problems with swapped dimensions
base_temp=np.zeros((768,1024,3),dtype=np.uint8)
foreground_temp=cv2.imread('monitor.png')
# Paste with different x and y offsets so it is clear when indices are swapped
offset_y=80
offset_x=40
base_temp[offset_y:offset_y+foreground_temp.shape[0], offset_x:offset_x+foreground_temp.shape[1]] = foreground_temp
Image.fromarray(base_temp).save('result.png')
After searching for a few hours, I ended up on this link. A little background information follows.
I'm capturing live frames of a running embedded device via a hardware debugger. The captured frames are stored as raw binary files, without headers or format. After looking at the above link and understanding, albeit perfunctorily, the NumPY and Matplotlib, I was able to convert the raw binary data to an image successfully. This is important because I'm not sure if the link to the raw binary file will help any one.
I use this code:
import matplotlib.pyplot as plt # study documentation
import numpy as np # " "
iFile = "FramebufferL0_0.bin" # Layer-A
shape = (430, 430) # length and width of the image
dtype = np.dtype('<u2') # unsigned 16 bit little-endian.
oFile = "FramebufferL0_0.png"
fid = open(iFile, 'rb')
data = np.fromfile(fid, dtype)
image = data.reshape(shape)
plt.imshow(image, cmap = "gray")
plt.savefig(oFile)
plt.show()
Now, the image I'm showing is black and white because the color map is gray-scale (right?). The actual captured frame is NOT black and white. That is, the image I see on my embedded device is "colorful".
My question is, how can I calculate actual color of each pixel from the raw binary file? Is there a way I can get the actual color map of the image from the raw binary? I looked into this example and I'm sure that, if I'm able to calculate the R, G and B channels (and Alpha too), I'll be able to recreate the exact image. An example code would be of much help.
An RGBA image has 4 channels, one for each color and one for the alpha value. The binary file seems to have a single channel, as you don't report an error when performing the data.reshape(shape) operation (the shape for the corresponding RGBA image would be (430, 430, 4)).
I see two potential reasons:
The image actual does have colour information but when you are grabbing the data you are only grabbing one of the four channels.
The image is actually a gray-scale image, but the embedded device shows a pseudocolor image, creating the illusion of colour information. Without knowing what the colourmap is being used, it is hard to help you, other than point you towards matplotlib.pyplot.colormaps(), which lists all already available colour maps in matplotlib.
Could you
a) explain the exact source / type of imaging modality, and
b) show a photo of the output of the embedded device?
PS: Also, at least in my hands, the pasted binary file seems to have a size of 122629, which is incongruent with an image shape of (430,430).