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import json
f = open('C:\Users\Hello\Desktop\usecase2.json',encoding = 'utf-8')
data = json.load(f)
print(data)
-Raw Data sheet contains the raw data to be parsed and arrange as per "Desired Output" sheet
-The number of iteration data for each Pur Lot is not same, however it is required to capture the entire raw da -you have to create a JSON file to capture entire data of Raw Data with the key as Pur Lot.
data
desired output
If you're looking to convert JSON (essentially text) to a python dict , then I would suggest you use this:
**
import json
# some JSON:
x = '{ "name":"John", "age":30, "city":"New York"}'
# parse x:
y = json.loads(x)
# the result is a Python dictionary:
print(y["age"])
**
then you can call y['keys'] = values to use data
here , y['name'] = "John"
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The Json file i want to extract "rank" information from
Basically I would like to get the top 10 ranks cryptocurrencies names.
each cryptocurrency has its rank in the given json screenshot.
is there anyway I can implement this in python?
Providing a link to the image shown
https://api.nomics.com/v1/currencies/ticker?key=demo-26240835858194712a4f8cc0dc635c7a
import requests
import json
resp = requests.get(url = "https://api.nomics.com/v1/currencies/ticker", params = {"key" :"demo-26240835858194712a4f8cc0dc635c7a"}) # Fetch response from API
resp = json.loads(resp.text)
final_names = []
for i in range(10): # JSON is ordered via Rank
final_names.append(resp[i]["name"])
print(final_names) # Print final names
Hope this answers your question!!!!
Solution if cryptocurrencies are not sorted by rank by default in your json:
import requests
from pprint import pprint
top_all = []
data = requests.get(url="https://api.nomics.com/v1/currencies/ticker",
params={"key": "demo-26240835858194712a4f8cc0dc635c7a"}).json()
for row in data:
top_all.append({"name": row["name"], "rank": row["rank"]})
top_all = sorted(top_all, key=lambda x: int(x["rank"]))
pprint(top_all[0:10])
Try this:
import json
# your saved json response from API
file_path = "full/path/to/file.json"
with open(file_path, "r") as f:
data = json.load(f)
top_10_names = [x["name"] for x in data[:10]]
# since the data is ordered by rank,
# you can take only the first 10 elements.
print(top_10_names)
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I have a file with this pattern :
[account.invoice.set_num]
job_size = 0
trans_size = 100
[commission.invoice_second.create_full]
j_size = 0
[commission.invoice_principal.finalize]
j_size = 12
in_directory = /to/the/directory
I want to transform this pattern to a text like :
ACCOUNT_INVOICE_SET_NUM_JOB_SIZE = 0
ACCOUNT_INVOICE_SET_NUM_TRANS_SIZE = 100
COMMISSION_INVOICE_SECOND_CREATE_FULL_J_SIZE=0
COMMISSION_INVOICE_PRINCIPALE_FINALIZE_J_SIZE=12
COMMISSION_INVOICE_PRINCIPALE_FINALIZE_IN_DIRECTORY=/to/the/directory
I try to do that in Bash unix or in Python.
I don't konw what is the best/easiest way to do that.
It's quite feasible with config.ConfigParser features:
from configparser import ConfigParser
config = ConfigParser()
config.read('yourfile')
config_lines = ''
for section in config.sections():
s_key = section.replace('.', '_') # transformed section key
for k, v in config.items(section):
config_lines += f'{s_key}_{k}'.upper() + f'={v}\n'
print(config_lines)
The output:
ACCOUNT_INVOICE_SET_NUM_JOB_SIZE=0
ACCOUNT_INVOICE_SET_NUM_TRANS_SIZE=100
COMMISSION_INVOICE_SECOND_CREATE_FULL_J_SIZE=0
COMMISSION_INVOICE_PRINCIPAL_FINALIZE_J_SIZE=12
COMMISSION_INVOICE_PRINCIPAL_FINALIZE_IN_DIRECTORY=/to/the/directory
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I have this JSON array with multiple roots:
[
{
"issuer_ca_id": 16418,
"issuer_name": "C=US, O=Let's Encrypt, CN=Let's Encrypt Authority X3",
"name_value": "sub.test.com",
"min_cert_id": 325717795,
"min_entry_timestamp": "2018-02-08T16:47:39.089",
"not_before": "2018-02-08T15:47:39"
},
{
"issuer_ca_id":9324,
"issuer_name":"C=US, O=Amazon, OU=Server CA 1B, CN=Amazon",
"name_value":"marketplace.test.com",
"min_cert_id":921763659,
"min_entry_timestamp":"2018-11-05T19:36:18.593",
"not_before":"2018-10-31T00:00:00",
"not_after":"2019-11-30T12:00:00"
}
]
I want to iterate over it and print issuer_name values in Python. Any solution, please?
Use the json package and load the json. Assuming it is a string in memory (as opposed to a .json file):
jsonstring = """
[
{
"issuer_ca_id": 16418,
"issuer_name": "C=US, O=Let's Encrypt, CN=Let's Encrypt Authority X3",
"name_value": "sub.test.com",
"min_cert_id": 325717795,
"min_entry_timestamp": "2018-02-08T16:47:39.089",
"not_before": "2018-02-08T15:47:39"
},
{
"issuer_ca_id":9324,
"issuer_name":"C=US, O=Amazon, OU=Server CA 1B, CN=Amazon",
"name_value":"marketplace.test.com",
"min_cert_id":921763659,
"min_entry_timestamp":"2018-11-05T19:36:18.593",
"not_before":"2018-10-31T00:00:00",
"not_after":"2019-11-30T12:00:00"
}
]"""
import json
j = json.loads(jsonstring)
[item["issuer_name"] for item in j]
Gives:
["C=US, O=Let's Encrypt, CN=Let's Encrypt Authority X3",
'C=US, O=Amazon, OU=Server CA 1B, CN=Amazon']
Now, these don't look like names to me, but that's what is assigned to the issuer_name field, so I think that's something you have to take up with the owner of the data.
If it's a file, you do the loading in this basic pattern:
# something like this
with open("jsonfile.json", "rb") as fp:
j = json.load(fp)
See the docs here: https://docs.python.org/3.7/library/json.html
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This is a snippet of the output:
{...,"resultMap":
{..."SEARCH_RESULTS":
[{..."resultList":[
{"userClientId":"1"","preferenceValues":["48","51","94"],"MyDate":"7/26/2017 8:30:00 AM"},
{"userClientId":"2","preferenceValues":["42","11","84"],"MyDate":"7/26/2017 9:40:00 AM"},
{"userClientId":"3","preferenceValues":["4","16","24"],"MyDate":"7/26/2017 4:20:00 PM"},
{"userClientId":"4","preferenceValues":["7","2","94"],"MyDate":"7/27/2017 8:00:00 AM"},
{"userClientId":"1","preferenceValues":["48","22","94"],"MyDate":"7/27/2017 1:50:00 PM"},
{"userClientId":"2","preferenceValues":["42","11"],"MyDate":"7/27/2017 2:00:00 PM"},
{"userClientId":"3","preferenceValues":["4","24"],"MyDate":"7/27/2017 6:15:00 PM"},
{"userClientId":"4","preferenceValues":"7","MyDate":"7/27/2017 9:30:00 PM"}]
}]
}
}
I am looking to get a variable pageIdCount that is in dictionary format, where the key is page_id and the values are a counts of occurrences of page_id, by user_id. So for userId 1 it should look like:
{"userClientId":"1","preferenceValues":{48:2, 51:1, 94:2, 22:1}}
Note that when there is only 1 variable inside preferenceValues- there are no brackets. There is also a field "preferenceValue" where there are no brackets no matter what and it is identical to "preferenceValues" otherwise.
Is that possible?
In Python 2.7, I specify user, password and url and then I have the following:
req = requests.post(url = url, auth=(user, password))
ans = req.json()
print ["resultMap"]["SEARCH_RESULTS"][0]["resultList"]
Any help is greatly appreciated.
your_data # this is your data
final_data = {}
for line in yourdata:
uid = line["userId"]
pids = line["PageId"]
if uid not in final_data :
final_data[uid] = {}
for pid in pids :
pid = int(pid)
if pid not in final_data[uid]:
final_data[uid][pid]=0
final_data[uid][pid] += 1
res = [{"userId":uid,"PageIDCount":pids} for uid,pids in final_data.items()]
I suppose you are beginning, if so, the most tricky part of this code will probably be the last line, it uses list comprehension. here is a good lesson about it.
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Tell me how to replace python data
a.txt
abcd.com 0.0
* 6.6999306E7
asdf.com 1.50744025E8
asfd.df.com 1.93139033E8
fdsa.com 9.07938122E8
bank.com 2.638989462E9
fire.com 4.151822166E9
ms.com 7.026079907E9
How can I read the a.txt file and make it in the following format?
Output result :
['abcd.com', 0],
['*', 66999306],
['asdf.com', 150744025],
['asfd.df.com', 193139033],
['fdsa.com', 907938122],
['bank.com', 2638989462],
['fire.com', 4151822166],
['ms.com', 7026079907]
file = open('a.txt', 'r')
l = []
for line in file:
l.append( line.split())
Then if you want the second part to be integer, you can use list comprehension:
l = [ [i[0], int(float(i[1]))] for i in l]
output
[['abcd.com', 0],
['*', 66999306],
['asdf.com', 150744025],
['asfd.df.com', 193139033],
['fdsa.com', 907938122],
['bank.com', 2638989462],
['fire.com', 4151822166],
['ms.com', 7026079907] ]