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Is there way to parse json data in python? [closed]

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import json
f = open('C:\Users\Hello\Desktop\usecase2.json',encoding = 'utf-8')
data = json.load(f)
print(data)
-Raw Data sheet contains the raw data to be parsed and arrange as per "Desired Output" sheet
-The number of iteration data for each Pur Lot is not same, however it is required to capture the entire raw da -you have to create a JSON file to capture entire data of Raw Data with the key as Pur Lot.
data
desired output

If you're looking to convert JSON (essentially text) to a python dict , then I would suggest you use this:
**
import json
# some JSON:
x = '{ "name":"John", "age":30, "city":"New York"}'
# parse x:
y = json.loads(x)
# the result is a Python dictionary:
print(y["age"])
**
then you can call y['keys'] = values to use data
here , y['name'] = "John"

Extracting information from json file and then sorting using python [closed]

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The Json file i want to extract "rank" information from
Basically I would like to get the top 10 ranks cryptocurrencies names.
each cryptocurrency has its rank in the given json screenshot.
is there anyway I can implement this in python?
Providing a link to the image shown
https://api.nomics.com/v1/currencies/ticker?key=demo-26240835858194712a4f8cc0dc635c7a

import requests
import json
resp = requests.get(url = "https://api.nomics.com/v1/currencies/ticker", params = {"key" :"demo-26240835858194712a4f8cc0dc635c7a"}) # Fetch response from API
resp = json.loads(resp.text)
final_names = []
for i in range(10): # JSON is ordered via Rank
final_names.append(resp[i]["name"])
print(final_names) # Print final names
Hope this answers your question!!!!

Solution if cryptocurrencies are not sorted by rank by default in your json:
import requests
from pprint import pprint
top_all = []
data = requests.get(url="https://api.nomics.com/v1/currencies/ticker",
params={"key": "demo-26240835858194712a4f8cc0dc635c7a"}).json()
for row in data:
top_all.append({"name": row["name"], "rank": row["rank"]})
top_all = sorted(top_all, key=lambda x: int(x["rank"]))
pprint(top_all[0:10])

Try this:
import json
# your saved json response from API
file_path = "full/path/to/file.json"
with open(file_path, "r") as f:
data = json.load(f)
top_10_names = [x["name"] for x in data[:10]]
# since the data is ordered by rank,
# you can take only the first 10 elements.
print(top_10_names)

Convert string structure in another [closed]

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I have a file with this pattern :
[account.invoice.set_num]
job_size = 0
trans_size = 100
[commission.invoice_second.create_full]
j_size = 0
[commission.invoice_principal.finalize]
j_size = 12
in_directory = /to/the/directory
I want to transform this pattern to a text like :
ACCOUNT_INVOICE_SET_NUM_JOB_SIZE = 0
ACCOUNT_INVOICE_SET_NUM_TRANS_SIZE = 100
COMMISSION_INVOICE_SECOND_CREATE_FULL_J_SIZE=0
COMMISSION_INVOICE_PRINCIPALE_FINALIZE_J_SIZE=12
COMMISSION_INVOICE_PRINCIPALE_FINALIZE_IN_DIRECTORY=/to/the/directory
I try to do that in Bash unix or in Python.
I don't konw what is the best/easiest way to do that.

It's quite feasible with config.ConfigParser features:
from configparser import ConfigParser
config = ConfigParser()
config.read('yourfile')
config_lines = ''
for section in config.sections():
s_key = section.replace('.', '_') # transformed section key
for k, v in config.items(section):
config_lines += f'{s_key}_{k}'.upper() + f'={v}\n'
print(config_lines)
The output:
ACCOUNT_INVOICE_SET_NUM_JOB_SIZE=0
ACCOUNT_INVOICE_SET_NUM_TRANS_SIZE=100
COMMISSION_INVOICE_SECOND_CREATE_FULL_J_SIZE=0
COMMISSION_INVOICE_PRINCIPAL_FINALIZE_J_SIZE=12
COMMISSION_INVOICE_PRINCIPAL_FINALIZE_IN_DIRECTORY=/to/the/directory

How to find and replace in 2 txt files with Python [closed]

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i would like to search and replace Ids in two different txt files.
So i have those .txt files.
OLDIDS.txt which seems like:
12F
130
132
106
100
...
and the other file MASTERIDS.txt where the old and new Ids where splittet in columns like: (LEFT old ids, RIGHT new ids)
100 132
12F 1FF
106 256
... ...
What I want to do is to open OLDIDS.txt like
f2 = open('OLDIDS.txt', 'w')
and search for the first id in the first line (which is 12F) find this in the second line of MASTERIDS.txt and write the new ID 1FF to the second line of newFile.txt.

I am converting the data in your MASTERIDS.txt to a dictionary. Key is the old id and value is the new ID. Then search for the dict for the new id using the value from OLDIDS.txt
Demo:
with open("PATH_TO_OLDIDS.txt", "r") as src:
data = src.readlines()
d ={}
with open("PATH_TO_MASTERIDS.txt", "r") as toReplaceSRC:
for i in toReplaceSRC.readlines():
val = i.split()
d[val[0].strip()] = val[1].strip()
for i in data:
toReplace = d.get(i.strip(), None)
if toReplace:
print(i.strip(), " = ", toReplace)
Output:
12F = 1FF
106 = 256
100 = 132

convert csv columns to dictionary in python [closed]

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I have a csv file with the following data.
Column-1 Column-2 Column-3
bob sweet 4
alice uber 4.5
bob uber 4
alice sweet 4.5
razi fav 2.5
razi uber 3.5
bob fav 4
I want to convert it to a dictionary as shown,
A={'bob':{'sweet':'4', 'uber':'4', 'fav':'4'},
'alice':{'uber':'4.5', 'sweet':'4.5'},
'razi':{'fav':'2.5', 'uber':'3.5'}}
in python
For that i am willing to do like this..convert the csv to list like this and then get my output. I am unable to do so, coz keys are repeated as shown.
A={'bob':['sweet','4'],
'alice':['uber','4.5'],
'bob':['uber','4'],
'alice':['sweet','4.5'],
'razi':['fav','2.5'],
'razi':['uber','3.5'],
'bob':['fav','4']}
Can any one suggest a way to solve problem?

Assuming you don't have any space in your datas, and all your actual data rows have exactly 3 fields:
import logging
logging.basicConfig(level=logging.INFO) # <- in a real application,
# should be set application-wide
# from a config file
logger = logging.getLogger("CSV import")
result = {}
nlines = 0
ok = 0
warnings = 0
with open("my_file.csv") as f:
f.readline() # Skip header. Assuming only one line of heading
for row in (line.split() for line in f):
nlines += 1
try:
k1,k2, val = row
result.setdefault(k1,{})[k2] = val
ok += 1
except ValueError:
logger.warning("Format mismatch: %s", row)
warnings += 1
# what to do next?
logger.info("%d lines read. %d imported. %d warnings",nlines,ok,warnings)
from pprint import pprint
pprint(result)
Given your sample data file, this produces:
INFO:CSV import:7 lines read. 7 imported. 0 warnings
{'alice': {'sweet': '4.5', 'uber': '4.5'},
'bob': {'fav': '4', 'sweet': '4', 'uber': '4'},
'razi': {'fav': '2.5', 'uber': '3.5'}}
The trick here is to use setdefault to access to outer dictionary. It will either return the value if the key was already present -- or a new dictionary if this is the first time we encounter that key. After that, this is simply a matter of adding the value to the inner dictionary as usual.