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Web scrape second number between tags

I am new to Python, and never done HTML. So any help would be appreciated.
I need to extract two numbers: '1062' and '348', from a website's inspect element.
This is my code:
page = requests.get("https://www.traderscockpit.com/?pageView=live-nse-advance-decline-ratio-chart")
soup = BeautifulSoup(page.content, 'html.parser')
Adv = soup.select_one ('.col-sm-6 .advDec:nth-child(1)').text[10:]
Dec = soup.select_two ('.col-sm-6 .advDec:nth-child(2)').text[10:]
The website element looks like below:
<div class="nifty-header-shade1 col-xs-12 col-sm-6 col-md-3">
<div class="row">
<div class="col-sm-12">
<h4>Stocks</h4>
</div>
<div class="col-sm-6">
<p class="advDec">Advanced: 1062</p>
</div>
<div class="col-sm-6">
<p class="advDec">Declined: 348</p>
</div>
</div>
</div>
Using my code, am able to extract first number (1062). But unable to extract the second number (348). Can you please help.

Assuming the Pattern is always the same, you can select your elements by text and get its next_sibling:
adv = soup.select_one('a:-soup-contains("Advanced:")').next_sibling.strip()
dec = soup.select_one('a:-soup-contains("Declined:")').next_sibling.strip()
Example
import requests
from bs4 import BeautifulSoup
page = requests.get("https://www.traderscockpit.com/?pageView=live-nse-advance-decline-ratio-chart")
soup = BeautifulSoup(page.content)
adv = soup.select_one('a:-soup-contains("Advanced:")').next_sibling.strip()
dec = soup.select_one('a:-soup-contains("Declined:")').next_sibling.strip()
print(adv, dec)

If there are always 2 elements, then the simplest way would probably be to destructure the array of selected elements.
import requests
from bs4 import BeautifulSoup
page = requests.get("https://www.traderscockpit.com/?pageView=live-nse-advance-decline-ratio-chart")
soup = BeautifulSoup(page.content, "html.parser")
adv, dec = [elm.next_sibling.strip() for elm in soup.select(".advDec a") ]
print("Advanced:", adv)
print("Declined", dec)

How to parse the drop down list and get the all the links for the pdf using Beautiful Soup in Python?

I'm trying to scrape the pdf links from the drop down this website. I want to scrape just the Guideline Values (CVC) drop down. Following is the code that i used but did not succeed
import requests
from bs4 import BeautifulSoup
req_ses = requests.Session()
igr_get_base_response = req_ses.get("https://igr.karnataka.gov.in/english#")
soup = BeautifulSoup(igr_get_base_response.text)
def matches_block(tag):
return matches_dropdown(tag) and tag.find(matches_text) != None
def matches_dropdown(tag):
return tag.name == 'li' and tag.has_attr('class') and 'dropdown-toggle' in tag['class']
def matches_text(tag):
return tag.name == 'a' and tag.get_text()
for li in soup.find_all(matches_block):
for ul in li.find_all('ul', class_='dropdown-toggle'):
for a in ul.find_all('a'):
if a.has_attr('href'):
print (a['href'])
any suggestion would be great help !
Edit: Adding part of HTML below:
<div class="collapse navbar-collapse">
<ul class="nav navbar-nav">
<li class="">
<i class="fa fa-home"> </i>
</li>
<li>
<a class="dropdown-toggle" data-toggle="dropdown" title="RTI Act">RTI Act <b class="caret"></b></a>
<ul class="dropdown-menu multi-level">
<!-- <li> -->
<li class="">
<a href=" https://igr.karnataka.gov.in/page/RTI+Act/Yadagiri+./en " title="Yadagiri .">Yadagiri .
</a>
</li>
<!-- </li> -->
<!-- <li>

I have tried to get the links of all the PDF files that you need.
I have selected the <a> tags whose href matches with the pattern - see patt in code. This pattern is common to all the PDF files that you need.
Now you have all the links to the PDF files in links list.
from bs4 import BeautifulSoup
import requests
url = 'https://igr.karnataka.gov.in/english#'
resp = requests.get(url)
soup = BeautifulSoup(resp.text, 'html.parser')
a = soup.find('a', attrs= {'title': 'Guidelines Value (CVC)'})
lst = a.parent()
links = []
patt = 'https://igr.karnataka.gov.in/storage/pdf-files/Guidelines Value/'
for i in lst:
temp = i.find('a')
if temp:
if patt in temp['href']:
links.append(temp['href'].strip())

I have first find ul_tag in which all the data is available now from that find_all method on a where it contains .pdf href with attrs having target:_blank so from it we can extract only .pdf links
from bs4 import BeautifulSoup
import requests
res=requests.get("https://igr.karnataka.gov.in/english#")
soup=BeautifulSoup(res.text,"lxml")
ul_tag=soup.find("ul",class_="nav navbar-nav")
a_tag=ul_tag.find_all("a",attrs={"target":"_blank"})
for i in a_tag:
print(i.get_text(strip=True))
print(i.get("href").strip())
Output:
SRO Chikkaballapur
https://igr.karnataka.gov.in/storage/pdf-files/Guidelines Value/chikkaballapur sro.pdf
SRO Gudibande
https://igr.karnataka.gov.in/storage/pdf-files/Guidelines Value/gudibande sro.pdf
SRO Shidlaghatta
https://igr.karnataka.gov.in/storage/pdf-files/Guidelines Value/shidlagatta sro.pdf
SRO Bagepalli
....

So, i used the following approach to complete the above mentioned part:
def make_sqlite_dict_from_parsed_row(district_value, sro_value, pdf_file_link):
sqlite_dict = {
"district_value": district_value,
"sro_value": sro_value,
"pdf_file_link": pdf_file_link.strip().replace(' ', '%20'),
"status": "PENDING"
}
sqlite_dict['hsh'] = get_hash(sqlite_dict, IGR_SQLITE_HSH_TUP)
return sqlite_dict
li_element_list = home_response_soup.find_all('li', {'class': 'dropdown-submenu'})
parsed_row_list=[]
for ele in li_element_list:
district_value = ele.find('a', {'class': 'dropdown-toggle'}).get_text().strip()
sro_pdf_a_tags = ele.find_all('a', attrs={'target': '_blank'})
if len(sro_pdf_a_tags) >=1:
for sro_a_tag in sro_pdf_a_tags:
sqlite_dict = make_sqlite_dict_from_parsed_row(
district_value,
sro_a_tag.get_text(strip=True),
sro_a_tag.get('href')
)
parsed_row_list.append(sqlite_dict)
else:
print("District: ", district_value, "'s pdf is corrupted")
this will give a proper_pdf_link, sro_name and disctrict_name

Parsing IMDB with BeautifulSoup

I've stripped the following code from IMDB's mobile site using BeautifulSoup, with Python 2.7.
I want to create a separate object for the episode number '1', title 'Winter is Coming', and IMDB score '8.9'. Can't seem to figure out how to split apart the episode number and the title.
<a class="btn-full" href="/title/tt1480055?ref_=m_ttep_ep_ep1">
<span class="text-large">
1.
<strong>
Winter Is Coming
</strong>
</span>
<br/>
<span class="mobile-sprite tiny-star">
</span>
<strong>
8.9
</strong>
17 Apr. 2011
</a>

You can use find to locate the span with the class text-large to the specific element you need.
Once you have your desired span, you can use next to grab the next line, containing the episode number and find to locate the strong containing the title
html = """
<a class="btn-full" href="/title/tt1480055?ref_=m_ttep_ep_ep1">
<span class="text-large">
1.
<strong>
Winter Is Coming
</strong>
</span>
<br/>
<span class="mobile-sprite tiny-star">
</span>
<strong>
8.9
</strong>
17 Apr. 2011
</a>
"""
from bs4 import BeautifulSoup
soup = BeautifulSoup(html)
span = soup.find('span', attrs={'text-large'})
ep = str(span.next).strip()
title = str(span.find('strong').text).strip()
print ep
print title
> 1.
> Winter Is Coming

Once you have each a class="btn-full", you can use the span classes to get the tags you want, the strong tag is a child of the span with the text-large class so you just need to call .strong.text on the Tag, for the span with the css class mobile-sprite tiny-star, you need to find the next strong tag as it is a sibling of the span not a child:
h = """<a class="btn-full" href="/title/tt1480055?ref_=m_ttep_ep_ep1">
<span class="text-large">
1.
<strong>
Winter Is Coming
</strong>
</span>
<br/>
<span class="mobile-sprite tiny-star">
</span>
<strong>
8.9
</strong>
17 Apr. 2011
</a>
"""
from bs4 import BeautifulSoup
soup = BeautifulSoup(h)
title = soup.select_one("span.text-large").strong.text.strip()
score = soup.select_one("span.mobile-sprite.tiny-star").find_next("strong").text.strip()
print(title, score)
Which gives you:
(u'Winter Is Coming', u'8.9')
If you really want to get the episode the simplest way is to split the text once:
soup = BeautifulSoup(h)
ep, title = soup.select_one("span.text-large").text.split(None, 1)
score = soup.select_one("span.mobile-sprite.tiny-star").find_next("strong").text.strip()
print(ep, title.strip(), score)
Which will give you:
(u'1.', u'Winter Is Coming', u'8.9')

Using url html scraping with reguest and regular expression search.
import os, sys, requests
frame = ('http://www.imdb.com/title/tt1480055?ref_=m_ttep_ep_ep1')
f = requests.get(frame)
helpme = f.text
import re
result = re.findall('itemprop="name" class="">(.*?) ', helpme)
result2 = re.findall('"ratingCount">(.*?)</span>', helpme)
result3 = re.findall('"ratingValue">(.*?)</span>', helpme)
print result[0].encode('utf-8')
print result2[0]
print result3[0]
output:
Winter Is Coming
24,474
9.0

How to extracts contents of a div tag containing a particular text using BeautifulSoup

I am new to BeautifulSoup and am looking to extract texts from a list inside a div tag. this is the code
<div class="contentBlurb">Description Synonyms
<ul class="definitionList">
<li>Awaiting bone marrow transplant</li>
</ul>
</div>
I would like to extract the text "Awaiting bone marrow transplant". This is the code which I use now which gives me an empty list:
for link in soup.findAll('div', text = re.compile('Description Synonyms ')):
print link
Sorry for not adding this. I do have other divs by the same class name. I am interested in only the description synonyms.The other div is listed below
<div class="contentBlurb">Applicable To
<ul class="definitionList">
<li>Patient waiting for organ availability</li>
</ul>
</div>

Dsoup.find(text='...') doesn't work if there's other text or tags inside that tag.
Try:
[i.find('ul', {'class': "definitionList"}).find('li').text
for i in soup.find_all('div', {'class': "contentBlurb"})
if 'Description Synonyms' in str(i.text)][0]

You can do this:
# coding: utf-8
from bs4 import BeautifulSoup
html = """
<div class="contentBlurb">Description Synonyms
<ul class="definitionList">
<li>Awaiting bone marrow transplant</li>
</ul>
</div>
<div class="contentBlurb">Applicable To
<ul class="definitionList">
<li>Patient waiting for organ availability</li>
</ul>
</div>
"""
souped = BeautifulSoup(html)
matching_divs = [div for div in souped.find_all(
'div', {'class': 'contentBlurb'}) if 'Description Synonyms' in div.getText()]
li_elements = []
matching_uls = []
for mdiv in matching_divs:
matching_uls.extend(mdiv.findAll('ul', {'class': 'definitionList'}))
for muls in matching_uls:
li_elements.extend(muls.findAll('li'))
for li in li_elements:
print(li.getText())
EDIT: Updated for matching particular div.

Try this, Change it to the required string in the if clause. The below snippet will print if the tag's text has Applicable To, you can change it to your requirement
val = soup.find('div', {'class': 'contentBlurb'}).text
if "Description Synonyms" in val:
print soup.find('div', {'class': 'contentBlurb'}).find('ul', {'class': 'definitionList'}).find('li').text

How to print the text inside of a child tag and the href of a grandchild element with a single BeautifulSoup Object?

I have a document which contains several div.inventory siblings.
<div class="inventory">
<span class="item-number">123</span>
<span class="cost">
$1.23
</span>
</div>
I would like to iterate over them to print the item number and link of the item.
123 http://linktoitem
456 http://linktoitem2
789 http://linktoitem3
How do I parse these two values after selecting the div.inventory element?
import requests
from bs4 import BeautifulSoup
htmlSource = requests.get(url).text
soup = BeautifulSoup(htmlSource)
matches = soup.select('div.inventory')
for match in matches:
#prints 123
#prints http://linktoitem
Also - what is the difference between the select function and find* functions?

You can find both items using find() relying on the class attributes:
soup = BeautifulSoup(data)
for inventory in soup.select('div.inventory'):
number = inventory.find('span', class_='item-number').text
link = inventory.find('span', class_='cost').a.get('href')
print number, link
Example:
from bs4 import BeautifulSoup
data = """
<body>
<div class="inventory">
<span class="item-number">123</span>
<span class="cost">
$1.23
</span>
</div>
<div class="inventory">
<span class="item-number">456</span>
<span class="cost">
$1.23
</span>
</div>
<div class="inventory">
<span class="item-number">789</span>
<span class="cost">
$1.23
</span>
</div>
</body>
"""
soup = BeautifulSoup(data)
for inventory in soup.select('div.inventory'):
number = inventory.find('span', class_='item-number').text
link = inventory.find('span', class_='cost').a.get('href')
print number, link
Prints:
123 http://linktoitem
456 http://linktoitem2
789 http://linktoitem3
Note the use of select() - this method allows to use CSS Selectors for searching over the page. Also note the use of class_ argument - underscore is important since class is a reversed keyword in Python.