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is it possible to somehow put before.rules and after.sales into two arrays, then compare the number of elements in them and subtract not their number, but the elements, so that the rest can be output later?
example
To compare the lengths of two lists, you can:
>>> print(len(after.roles)-len(before.roles))
3
In this example 3 new roles were gained
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So this is the list. The list contains 9 indexes and inside each indexes, there at least one position that contains more than one number. Is there a way to access each number in those posistions?
I have tried:
print(self.nums[0][1][0])
I thought that it would print out the first number of that posistion in the first index, but i recieved an error message instead.
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I would like to know how to find the values of a list that result in the sum of a specific value example that I have a list of payments but a payment is found that comes from different values of the list that added together result in the total value of the payment
I just want to know how to find the values of a sum in a way to be program it
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I have column with this kind of data:
I want to count how many times valu occur in a row. It is a string, so I want to convert this '63,63,63,63,63,63,63,63,63,63,63' to this ['63','63','63'...].
I there any way to do this quickly?
Thanks
if given string is s
l=s.split(',')
l is the required list
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df['Total']= df.iloc[3:5].sum(axis=1)
returns NaN for some most values, why is this? They are all intergers.
Also is there a better way of doing this?
Check with add with columns slice
df['Total'] = df.iloc[:, 3:5].sum(axis=1)
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Say I have these two lists:
list1=["Green","2","Blue","4"]
list2=["1","Orange","3","red"]
If I wanted to swap the '3' with 'blue' how would I do if it if I don't already know the positions of the elements in the list?
I'm using Python 2.7
list1=["Green","2","Blue","4"]
list2=["1","Orange","3","red"]
l1 = list1.index("Blue")
l2 = list2.index("3")
list1[l1], list2[l2] = list2[l2], list1[l1]