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I have column with this kind of data:
I want to count how many times valu occur in a row. It is a string, so I want to convert this '63,63,63,63,63,63,63,63,63,63,63' to this ['63','63','63'...].
I there any way to do this quickly?
Thanks
if given string is s
l=s.split(',')
l is the required list
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So this is the list. The list contains 9 indexes and inside each indexes, there at least one position that contains more than one number. Is there a way to access each number in those posistions?
I have tried:
print(self.nums[0][1][0])
I thought that it would print out the first number of that posistion in the first index, but i recieved an error message instead.
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I need help with python. How can I separate combine word into two words. At the first we don't know what kind of words could be? so we must enter a string at the input (v="") and then that word must be separate. For example we have "AMnidcrheaal" and in output will be "Andrea" and "Michal".
According to the output you gave, you want to separate odd and even indices words which can be done as follows
v="AMnidcrheaal"
even=""
odd=""
for i in range(len(v)):
if i%2==0:
even+=v[i]
else:
odd+=v[i]
print(odd)
print(even)
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is it possible to somehow put before.rules and after.sales into two arrays, then compare the number of elements in them and subtract not their number, but the elements, so that the rest can be output later?
example
To compare the lengths of two lists, you can:
>>> print(len(after.roles)-len(before.roles))
3
In this example 3 new roles were gained
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What is the best way to replace all the null "NaN" values in a Python dataframe with the value 0?
Also, is it possible to do this with a for loop?
you can simply use
df.fillna(0)
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I need to find a word "little" in a string but word in the string is not present as a whole.
For eg. input string="aalbeiedteetoolpue" or "lliittttllleee"
May be you can try this:
\b\w*l\w*i\w*t\w*t\w*l\w*e\w*\b
Demo