Input exists out of a sentence or text in s-language: Isis thasat yousour sisisteser?
Output exists out same sentence without s-language : Is that your sister?
Problems:
I have the following code but some things are not working. For example I can not append after the if statements and my if statements are too litteral. Also the print(decoded_tekst) is not working.
Method:
I iterate through the different positions of the text with two variables ("vowelgroup" to store the vowels and "decoded text" to store the consonant and if "s" to replace it by the vowelgroup).
text = input('Enter a text: ')
vowelgroup = []
decoded_text = []
sentence = []
vowel = 'aeiou'
count = 0
for i in text:
if i is not vowel and not "s":
sentence = decoded_text.append(i)
if i is vowel:
vowelgroup = vowelgroup.append(vowel)
if i is "s":
decoded_text = sentence.append(vowelgroup)
count += 1
print(decoded_text)
You look a little confused about how append works. append just adds the argument to the end of the list and it returns None. E.g:
l = [1,2]
a = l.append(3)
print a # None
print l # [1,2,3]
So you just use it like:
l = [1,2]
l.append(3)
print l # [1,2,3]
I have written a simple program that will take the first letter of a string and capitalize it.
def initials(text):
words = text.split()
a=[word[0].upper() for word in words]
b = '. '.join(a) + '.'
return b
text = "have a good day sir"
print(initials(text))
This will give me the result i want by using a list comprehension.
however i cannot make it work by using a typical FOR LOOP as below and it will give me only the last iteration:
def initials(text):
words = text.split()
for word in words:
a=word[0].upper()
b = '.'.join(a) + '.'
return b
text = "have a good day sir"
print(initials(text))
any idea why the second example doesn't work as the first one?
b is being reset every time around the loop in the second case. So you only get the last initial followed by .. The equivalent to your comprehension in a for loop, would be:
def initials(text):
words = text.split()
a = []
for word in words:
a.append(word[0].upper())
b = '.'.join(a) + '.'
return b
You're overwriting b on each loop iteration. Try:
def initials(text):
words = text.split()
for word in words:
a = word[0].upper()
b += '.'.join(a) + '.'
return b
text = "have a good day sir"
The problem is that str.join() takes a iterable of strings, but in your second function you are passing a single chararacter. The fact that you are calling it inside the loop does not convert it into a list of characters.
The easiest way for you is to get rid of the str.join() and use a simple string to accumulate the result:
def initials(text):
words = text.split()
b = ''
for word in words:
a=word[0].upper()
b += a + '.'
return b
If you insist in using str.join() you will need a list to accumulate your initials:
def initials(text):
words = text.split()
b = []
for word in words:
a=word[0].upper()
b.append(a)
return '.'.join(b) + '.'
For my comp sci class I was assigned to make an english to pirate dictionary. The user is prompted to enter a sentence which is then translated to pirate but it isn't working and I'm not sure why. Any help would be appreciated.
eng2pir = {}
eng2pir['sir'] = 'matey'
eng2pir['hotel'] = 'fleabag inn'
eng2pir['restauraunt'] = 'galley'
eng2pir['your'] = 'yer'
eng2pir['hello'] = 'avast'
eng2pir['is'] = 'be'
eng2pir['professor'] = 'foul blaggart'
a = input("Please enter a sentence to be translated into pirate: ")
for x in range(len(a)):
b = a.replace(x, eng2pir[x])
print(b)
Your loop is iterating over range(len(a)), so x will take on an integer value for each individual character in your input. This is off for a couple of reasons:
Your goal is to iterate over words, not characters.
Indexing the dictionary should be done with words, not integers (this is the cause of your error).
Finally, note that .replace() replaces the first occurrence of the searched item in the string. To revise your approach to this problem in a way that still uses that method, consider these two main changes:
Iterate over the keys of the dictionary; the words that could potentially be replaced.
Loop until no such words exist in the input, since replace only does individual changes.
You're iterating over each of the characters in the string input, as the other answer before this has said, replace only replaces the first occurence.
You'd want to do something like this (after you've made your dictionary).
a = input("Please enter a sentence to be translated into pirate: ")
for x in eng2pir:
while x in a:
a = a.replace(x,eng2pir[x])
print(a)
for x in range(len(a)):
b = a.replace(x, eng2pir[x])
because for loop x is int
but eng2pir dict no int key
so output error
#!/usr/bin/env python
# coding:utf-8
'''黄哥Python'''
eng2pir = {}
eng2pir['sir'] = 'matey'
eng2pir['hotel'] = 'fleabag inn'
eng2pir['restauraunt'] = 'galley'
eng2pir['your'] = 'yer'
eng2pir['hello'] = 'avast'
eng2pir['is'] = 'be'
eng2pir['professor'] = 'foul blaggart'
a = input("Please enter a sentence to be translated into pirate:\n ")
lst = a.split()
b = ''
for word in lst:
b += eng2pir.get(word, "")
print(b)
I'm preparing for an exam but I'm having difficulties with one past-paper question. Given a string containing a sentence, I want to find the longest word in that sentence and return that word and its length. Edit: I only needed to return the length but I appreciate your answers for the original question! It helps me learn more. Thank you.
For example: string = "Hello I like cookies". My program should then return "Cookies" and the length 7.
Now the thing is that I am not allowed to use any function from the class String for a full score, and for a full score I can only go through the string once. I am not allowed to use string.split() (otherwise there wouldn't be any problem) and the solution shouldn't have too many for and while statements. The strings contains only letters and blanks and words are separated by one single blank.
Any suggestions? I'm lost i.e. I don't have any code.
Thanks.
EDIT: I'm sorry, I misread the exam question. You only have to return the length of the longest word it seems, not the length + the word.
EDIT2: Okay, with your help I think I'm onto something...
def longestword(x):
alist = []
length = 0
for letter in x:
if letter != " ":
length += 1
else:
alist.append(length)
length = 0
return alist
But it returns [5, 1, 4] for "Hello I like cookies" so it misses "cookies". Why? EDIT: Ok, I got it. It's because there's no more " " after the last letter in the sentence and therefore it doesn't append the length. I fixed it so now it returns [5, 1, 4, 7] and then I just take the maximum value.
I suppose using lists but not .split() is okay? It just said that functions from "String" weren't allowed or are lists part of strings?
You can try to use regular expressions:
import re
string = "Hello I like cookies"
word_pattern = "\w+"
regex = re.compile(word_pattern)
words_found = regex.findall(string)
if words_found:
longest_word = max(words_found, key=lambda word: len(word))
print(longest_word)
Finding a max in one pass is easy:
current_max = 0
for v in values:
if v>current_max:
current_max = v
But in your case, you need to find the words. Remember this quote (attribute to J. Zawinski):
Some people, when confronted with a problem, think "I know, I'll use regular expressions." Now they have two problems.
Besides using regular expressions, you can simply check that the word has letters. A first approach is to go through the list and detect start or end of words:
current_word = ''
current_longest = ''
for c in mystring:
if c in string.ascii_letters:
current_word += c
else:
if len(current_word)>len(current_longest):
current_longest = current_word
current_word = ''
else:
if len(current_word)>len(current_longest):
current_longest = current_word
A final way is to split words in a generator and find the max of what it yields (here I used the max function):
def split_words(mystring):
current = []
for c in mystring:
if c in string.ascii_letters:
current.append(c)
else:
if current:
yield ''.join(current)
max(split_words(mystring), key=len)
Just search for groups of non-whitespace characters, then find the maximum by length:
longest = len(max(re.findall(r'\S+',string), key = len))
For python 3. If both the words in the sentence is of the same length, then it will return the word that appears first.
def findMaximum(word):
li=word.split()
li=list(li)
op=[]
for i in li:
op.append(len(i))
l=op.index(max(op))
print (li[l])
findMaximum(input("Enter your word:"))
It's quite simple:
def long_word(s):
n = max(s.split())
return(n)
IN [48]: long_word('a bb ccc dddd')
Out[48]: 'dddd'
found an error in a previous provided solution, he's the correction:
def longestWord(text):
current_word = ''
current_longest = ''
for c in text:
if c in string.ascii_letters:
current_word += c
else:
if len(current_word)>len(current_longest):
current_longest = current_word
current_word = ''
if len(current_word)>len(current_longest):
current_longest = current_word
return current_longest
I can see imagine some different alternatives. Regular expressions can probably do much of the splitting words you need to do. This could be a simple option if you understand regexes.
An alternative is to treat the string as a list, iterate over it keeping track of your index, and looking at each character to see if you're ending a word. Then you just need to keep the longest word (longest index difference) and you should find your answer.
Regular Expressions seems to be your best bet. First use re to split the sentence:
>>> import re
>>> string = "Hello I like cookies"
>>> string = re.findall(r'\S+',string)
\S+ looks for all the non-whitespace characters and puts them in a list:
>>> string
['Hello', 'I', 'like', 'cookies']
Now you can find the length of the list element containing the longest word and then use list comprehension to retrieve the element itself:
>>> maxlen = max(len(word) for word in string)
>>> maxlen
7
>>> [word for word in string if len(word) == maxlen]
['cookies']
This method uses only one for loop, doesn't use any methods in the String class, strictly accesses each character only once. You may have to modify it depending on what characters count as part of a word.
s = "Hello I like cookies"
word = ''
maxLen = 0
maxWord = ''
for c in s+' ':
if c == ' ':
if len(word) > maxLen:
maxWord = word
word = ''
else:
word += c
print "Longest word:", maxWord
print "Length:", len(maxWord)
Given you are not allowed to use string.split() I guess using a regexp to do the exact same thing should be ruled out as well.
I do not want to solve your exercise for you, but here are a few pointers:
Suppose you have a list of numbers and you want to return the highest value. How would you do that? What information do you need to track?
Now, given your string, how would you build a list of all word lengths? What do you need to keep track of?
Now, you only have to intertwine both logics so computed word lengths are compared as you go through the string.
My proposal ...
import re
def longer_word(sentence):
word_list = re.findall("\w+", sentence)
word_list.sort(cmp=lambda a,b: cmp(len(b),len(a)))
longer_word = word_list[0]
print "The longer word is '"+longer_word+"' with a size of", len(longer_word), "characters."
longer_word("Hello I like cookies")
import re
def longest_word(sen):
res = re.findall(r"\w+",sen)
n = max(res,key = lambda x : len(x))
return n
print(longest_word("Hey!! there, How is it going????"))
Output : there
Here I have used regex for the problem. Variable "res" finds all the words in the string and itself stores them in the list after splitting them.
It uses split() to store all the characters in a list and then regex does the work.
findall keyword is used to find all the desired instances in a string. Here \w+ is defined which tells the compiler to look for all the words without any spaces.
Variable "n" finds the longest word from the given string which is now free of any undesired characters.
Variable "n" uses lambda expressions to define the key len() here.
Variable "n" finds the longest word from "res" which has removed all the non-string charcters like %,&,! etc.
>>>#import regular expressions for the problem.**
>>>import re
>>>#initialize a sentence
>>>sen = "fun&!! time zone"
>>>res = re.findall(r"\w+",sen)
>>>#res variable finds all the words and then stores them in a list.
>>>res
Out: ['fun','time','zone']
>>>n = max(res)
Out: zone
>>>#Here we get "zone" instead of "time" because here the compiler
>>>#sees "zone" with the higher value than "time".
>>>#The max() function returns the item with the highest value, or the item with the highest value in an iterable.
>>>n = max(res,key = lambda x:len(x))
>>>n
Out: time
Here we get "time" because lambda expression discards "zone" as it sees the key is for len() in a max() function.
list1 = ['Happy', 'Independence', 'Day', 'Zeal']
listLen = []
for i in list1:
listLen.append(len(i))
print list1[listLen.index(max(listLen))]
Output - Independence
I Am writing a function that should take a string input and return the string with every first letter of every word as a capital letter, I have achieved this to a certain degree.
My Code:
string = input("Please Enter A string:")
def capitalize_words(string):
split = string.split()
letter1 = ''
letter2 = ''
letter3 = ''
str1 = split[0]
str2 = split[1]
str3 = split[2]
for i in str1:
if i in str1[0]:
first = i.upper()
else:
letter1 = letter1 + i
string1 = (first+letter1)
for i in str2:
if i in str2[0]:
first = i.upper()
else:
letter2 = letter2 + i
string2 = (first+letter2)
for i in str3:
if i in str3[0]:
first = i.upper()
else:
letter3 = letter3 + i
string3 = (first+letter3)
result = string1+' '+string2+' '+string3
return result
func = capitalize_words(string)
print(func)
Input:
Please Enter A string:herp derp sherp
Output:
Herp Derp Sherp
However this is very inflexible because i can only enter 3 words with spaces no more no less , this makes for a rather primal program. I would like to be able to enter anything and get the desired result of the first letter of every word being a capital letter no matter how many words i enter.
I fear with my skills this is as far as I am able to get, can you please improve my program if possible.
>>> print(raw_input('Please Enter A string: ').title())
Please Enter A string: herp derp sherp
Herp Derp Sherp
Use str.title() to achieve what you want in one go.
But to process words in a sentence, use a loop instead of a series of local variables; here is a version that does the same what you are doing for an arbitrary number of words:
for i, word in enumerate(split):
split[i] = word[0].upper() + word[1:]
result = ' '.join(split)
I used string slicing as well to select just the first character, and all but the first character of a word. Note the use of enumerate() to give us a counter which wich we can replace words in the split list directly.
An alternative method is to use re.sub such as:
re.sub(r'\b.', lambda c: c.group().upper(), 'herp derp sherp and co.')
# 'Herp Derp Sherp And Co.'
You could write this in a one-line generator expression:
def upper_case(text):
return ' '.join(w[0].upper() + w[1:] for w in text.split())
Notice, that this function fails on single letter words and replaces any whitespace by a single space character.
Use this as
In [1]: upper_case(input('Please Enter A string: '))
Please Enter A string: hello world
Out[1]: 'Hello World'