Background: im trying to send RSVPs(wedding to numbers from guest list in excel
Method:
im using pywhatkit to send a message with a link to RSVP page with the following code:
import pywhatkit
import openpyxl
# extracting numbers from excel
wb = openpyxl.load_workbook('wedding.xlsx')
ws = wb["Sheet1"]
num = []
for row in ws.iter_rows(min_row=1, max_col=1, values_only=True):
for value in row:
num.append('+' + str(value))
# message content
text1 = "please confirm RSVP in https://*****/?phone="
text2 = " \n _please do not reply to this number_"
# sending the links
for x in num:
pywhatkit.sendwhatmsg_instantly( x , text1 + x + text2, 10, True, 10)
for just the example lets use:
for x in range(10):
pywhatkit.sendwhatmsg_instantly( '+****' , 'test' + str(x), 10, True, 10)
i tried to change the delays to [12,3],[5,5],[5,10] and a few more
Result: sending the message fails sometimes. so if we look at the example - i get 8/10 of the messages. it seems like in those times it fails it writes the message in the text box but doesnt press send.
keep in mind that i need to send this to 400 people so i cant set long delays
is there a fix to this?
is there a way to check if the message was sent so it can retry?
any other librarys that are more stable?
Related
I want to send whatsapp using selenium python
Im getting my contact numbers from a csv file
So
With a loop
Im typing phone numbers in contact search box (WhatsApp web)
(Because that some of my phone contact are duplicate so I'm using their phone in search box instead of their name)
And entering Enter button (off course with selenium)
And with that it's entering the only result chat
So i can send the message and etc.
The problem is that when there is no result in searching number it's sending the messages to the last person that was sent to
So the last person gets duplicate message
How can i determine if the search is giving me any result
Or in this case
How can i know if the number has whatsapp or not
Thanks
from selenium import webdriver
import time
import pandas as pd
import os
import xlrd
import autoit
from selenium.webdriver.common.keys import Keys
from selenium.common.exceptions import NoSuchElementException
fileName = 'test.csv'
messages_excel = 'messages.xlsx'
driver = webdriver.Chrome('D:\python\chromedriver')
driver.get('https://web.whatsapp.com/')
input('after QR Code')
with open(fileName) as file:
data = pd.read_csv(file)
df = pd.DataFrame(data)
msgdata = pd.read_excel(messages_excel, sheet_name=r'Sheet1')
for index, row in df.iterrows():
try:
search_phone = int(row['phone'])
search_box = driver.find_element_by_class_name('_2zCfw')
search_box.send_keys(search_phone)
time.sleep(2)
search_box.send_keys(u'\ue007')
for i in msgdata.index:
try:
clipButton = driver.find_element_by_xpath('//*[#id="main"]/header/div[3]/div/div[2]/div/span')
clipButton.click()
time.sleep(1)
# To send Videos and Images.
mediaButton = driver.find_element_by_xpath(
'//*[#id="main"]/header/div[3]/div/div[2]/span/div/div/ul/li[1]/button')
mediaButton.click()
time.sleep(3)
image_path = os.getcwd() + "\\Media\\" + msgdata['photoName'][i]+'.jpg'
autoit.control_focus("Open", "Edit1")
autoit.control_set_text("Open", "Edit1", (image_path))
autoit.control_click("Open", "Button1")
time.sleep(1)
previewMsg = driver.find_element_by_class_name("_3u328").send_keys(u'\ue007')
time.sleep(3)
productName = str(msgdata['name'][i])
oldPrice = str(msgdata['oldqimat'][i])
newPrice = str(msgdata['newqimat'][i])
inventory = str(msgdata['inventory'][i])
msg_box = driver.find_element_by_xpath('//*[#id="main"]/footer/div[1]/div[2]/div/div[2]')
msg_box.send_keys("stocks")
msg_box.send_keys(Keys.SHIFT + '\ue007')
msg_box.send_keys(productName)
msg_box.send_keys(Keys.SHIFT + '\ue007')
if oldPrice != 'nan':
msg_box.send_keys("oldPrice : "+ oldPrice)
msg_box.send_keys(Keys.SHIFT + '\ue007')
if newPrice != 'nan':
msg_box.send_keys("newPrice : "+ newPrice)
msg_box.send_keys(Keys.SHIFT + '\ue007')
if inventory!= 'nan':
msg_box.send_keys("inventory : "+ inventory)
time.sleep(1)
msg_box.send_keys(Keys.ENTER)
time.sleep(3)
except NoSuchElementException:
continue
except NoSuchElementException:
continue
print("sucessfully Done")
when there is no result in searching number it's sending the messages to the last person that was sent to So the last person gets duplicate message
Im getting my contact numbers from a csv file So With a loop Im typing phone numbers in contact search box (WhatsApp web)
You could store the last # you contacted as a variable and check if the current recipient of the message, matches the stored contact #.
A simple If/Else should do the trick.
Code
last_contacted = None
for index, row in df.iterrows():
try:
if row['phone'] == last_contacted:
print("number already contacted")
next
else:
search_phone = int(row['phone'])
last_contacted = search_phone
print(search_phone)
After you fill the search contact box string and send the Enter key, the “best match” contact name will be displayed at top of the right message panel.
Inspect that element and make sure it matches your search before continuing.
I would like some help. I'm trying to send a variable to T0. I've tried but I cannot send a variable value. Please help.
CODE
import serial
import time
import struct
from requests import get
ip = get('https://api.ipify.org').text
ser = serial.Serial("/dev/ttyAMA0")
time.sleep(1)
k=struct.pack('B', 0xff )
while True:
ser.write(b't0.txt=ip')
ser.write(k)
ser.write(k)
ser.write(k)
You have to wrap your string in quotation marks (") for Nextion to read the string.
Not a Python expert, but this should give you a clue:
Change ser.write(b't0.txt=ip') to something like ser.write(b't0.txt="' + ip + '"').
This works for me.
port=serial.Serial(port='/dev/ttyAMA0',baudrate=9600, timeout=1.0)
eof = "\xff\xff\xff"
tn = str(datetime.now().time())
alt = 'page0.T0.txt="'+tn+'"'+eof
dimCmd = "dim=0"
undimCmd = "dim=100"
cmd1 = "https://api.thingspeak.com/apps/thinghttp/send_request?api_key=YOUR_API_KEY" #IF USING THINGSPEAK
#get temp Sub - USING THINGSPEAK GET LOCAL WEATHER
def GetTemp():
global temp
response = urllib.urlopen(cmd1)
temp = response.read()
temp = temp[:-2] #gets all characters in temp except the last 2
while True:
port.write(alt) #writes time to T0 textbox on screen
port.write(undimCmd + eof) #set screen brightness to 100%
port.write("page 1")#set screen to page 1 for multiple page setups
I'm trying to write a message to a hardware mailbox using a memory mapped dev/mem/ but everything I send, gets sent twice. So in the code below, after sending a single 1 to MBOX, the mailbox depth indicates a depth of two.
When I read from the mailbox it has 2 ones. Any idea why this is happening?
with open("/dev/mem", "r+b") as mem_fd:
addr_p = mmap.mmap(mem_fd.fileno(), mem_size[UPROC_PIF_AREA], offset = mem_offsets[PROC_PIF_AREA])
#Sending the message header to register mbox_xt first
print "Sending message header"
packed_mbox_status = addr_p[MBOX_STATUS:MBOX_STATUS + 4]
mbox_to_microp_depth = struct.unpack("BBBB", packed_mbox_status)
print "mbox_to_microp_depth : " + str(mbox_to_microp_depth)
addr_p[MBOX_XT:MBOX_XT+4] = struct.pack("<L", 1)
packed_mbox_status = addr_p[MBOX_STATUS:MBOX_STATUS + 4]
mbox_to_microp_depth = struct.unpack("BBBB", packed_mbox_status)
print "mbox_to_microp_depth : " + str(mbox_to_microp_depth)
I'm writing a simple little script to send me a text message when the Ultra Music Festival early bird tickets go on sale so I can snatch them up. When I came to writing this I figured python would be a quick way to achieve my goal. What I do is collect the links and then count them and determine if there is a change and send a google voice text message to a couple numbers. Here is my code ran against stackoverflow.
from googlevoice import Voice
from googlevoice.util import input
from bs4 import BeautifulSoup, SoupStrainer
from time import sleep
import urllib2
from array import *
#define login details
email = 'example#gmail.com'
password = 'password'
url = 'http://stackoverflow.com/questions'
def send_message(var_text):
voice = Voice()
voice.login(email, password)
phoneNumber = array('L',[9998675309, 9998675309])
for i in phoneNumber:
voice.send_sms(i, var_text)
#init
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
link_count = len(soup)
#start the loop
var = 1
while var == 1 : # This constructs an infinite loop
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
if link_count != len(soup):
string = str('Link Count Changed\n\nSite:\n' + url + '\nPrev:\n' + str(link_count) + '\nNew:\n' + str(len(soup)))
send_message(string)
print (string)
link_count = len(soup)
sleep(10)
pass
else:
print('Number of links ('+ str(link_count) + ') has not changed, going to sleep now.')
sleep(10)
pass
print "Good bye!"
Here is the error I keep getting (only seems to happen when sending to more then one number)
doesn't work array('L',[9998675309, 9998675309])
works array('L',[9998675309])
ERROR:
bash-3.2# python gvsendalert.py
Number of links (195) has not changed, going to sleep now.
Traceback (most recent call last):
File "gvsendalert.py", line 32, in <module>
send_message(string)
File "gvsendalert.py", line 19, in send_message
voice.send_sms(i, var_text)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/voice.py", line 151, in send_sms
self.__validate_special_page('sms', {'phoneNumber': phoneNumber, 'text': text})
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/voice.py", line 225, in __validate_special_page
load_and_validate(self.__do_special_page(page, data))
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/util.py", line 65, in load_and_validate
validate_response(loads(response.read()))
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/util.py", line 59, in validate_response
raise ValidationError('There was a problem with GV: %s' % response)
googlevoice.util.ValidationError: There was a problem with GV: {u'data': {u'code': 58}, u'ok': False}
Ok I've taken into consideration what some of you have posted and come out with this. For the number array sending my google voice number twice it will send 2 messages. If I put my friends number as the second it breaks it. Could this be because my friends number is not a google voice number? I have been able to send messages to this number using Google Voice and some other 3rd party iPhone applications so I would think the python module would work the same way.
Here is my 2nd Revision Code:
def send_message(var_text):
voice = Voice()
voice.login(email, password)
phoneNumber = ['myrealgooglenumber', 'myfriendsactualphonenumber']
for i in phoneNumber:
print( str('sending to: ') + str(i))
voice.send_sms(str(i), str(var_text))
sleep(5)
#init
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
link_count = len(soup)
#start the loop
var = 1
while var == 1 : # This constructs an infinite loop
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
if link_count != len(soup):
string = ('Link Count Changed\n\nSite:\n{0}\nPrev:\n{1}\nNew:\n{2}').format(url, link_count, len(soup))
send_message(string)
link_count = len(soup)
print (string)
sleep(10)
pass
else:
string = ('Number of links ({0}) has not changed, going to sleep now.').format(str(link_count))
print(string)
sleep(10)
pass
print "Good bye!"
Have tested with 2 google voice numbers and it works. Still doesn't work with non google voice numbers.
It looks like you're using ints for the phone numbers.
Phone numbers are not true numbers.
Try strings instead:
phoneNumber = ['9998675309', '9998675309']
Also, on a style note, have a look at string formatting:
string = 'Link Count Changed\n\nSite:\n{0}\nPrev:\n{1}\nNew:\n{2}').format(url, link_count, len(soup))
Google may have a timer to prevent you sending too many SMS messages back to back.
Perhaps you could try changing your loop to something like:
for i in phoneNumber:
voice.send_sms(i, var_text)
sleep(5)
One other thought, does it work better if you use 2 different phone numbers?
I found this python script at metafilter and modified the addresses and pass as needed, but I get a script error at the very last line. In the error the little carat symbol is underneath the quote after print "\n
Not being a coder at all, I have no idea where to turn next. Any help would be greatly appreciated.
What I actually want to do is pull out the "From" addresses and not to and CC, but I figured I would get this working properly first.
Script was run in Windows using Python 3.2 and redirected output to a text file.
import email
import getpass
import imaplib
HOST = "mail.-----.com"
USER = "sales#-----.com"
FOLDER = "Folder"
connection = imaplib.IMAP4_SSL(HOST)
res, data = connection.login(USER, getpass.getpass())
assert res == "OK"
res, count = connection.select(FOLDER)
assert res == "OK"
res, (msg_nums,) = connection.search(None, "ALL")
assert res == "OK"
for msg_num in msg_nums.split():
res, message_text = connection.fetch(msg_num, "(RFC822)")
assert res == "OK"
message = email.message_from_string(message_text[0][1])
tos = message.get_all("From") or []
ccs = message.get_all("Cc") or []
all_recipients = email.Utils.getaddresses(tos + ccs)
print "\n".join(addr.lower() for realname, addr in all_recipients)
print is a function in Python 3, so it needs to be:
print("\n".join(addr.lower() for realname, addr in all_recipients))
The script was probably originally written for use with Python 2.x.