while 1:
wat=water()
if wat==10:
print("water condition")
mixer.music.load("water.mp3")
mixer.music.play()
first=input("Drank?Y/N")
if first.lower()=="y":
with open("HealthLog.txt","a") as water1:
Content=f"Drank water at [{getdate()}] \n"
water1.write(Content)
else:
pass
Is there any way to wait for a couple of minutes and if no input is provided, then take the value "n" as input for the first variable?
Guess by default it will wait indefinitely. I tried using a timer function, but it cannot record any input.
What I am trying to do is to track my activities, so if I drink water I say y--> this records my activity and writes it to a file.
All help will be greatly appreciated
Here is how you can use a combination of pyautogui.typewrite, threading.Thread and time.sleep:
from pyautogui import typewrite
from threading import Thread
from time import sleep
a = ''
def t():
sleep(5)
if not a: # If by 5 seconds a still equals to '', as in, the user haven't overwritten the original yet
typewrite('n')
typewrite(['enter'])
T = Thread(target=t)
T.start()
a = input()
b = input() # Test it on b, nothing will happen
Here is the code implemented into your code:
from pyautogui import typewrite
from threading import Thread
from time import sleep
while 1:
wat = water()
if wat == 10:
print("water condition")
mixer.music.load("water.mp3")
mixer.music.play()
first = 'waiting...'
def t():
sleep(5)
if first == 'waiting...':
typewrite('n')
typewrite(['enter'])
T = Thread(target=t)
T.start()
first = input("Drank?Y/N")
if first.lower() == "y":
with open("HealthLog.txt","a") as water1:
Content=f"Drank water at [{getdate()}] \n"
water1.write(Content)
else:
pass
Description: now, I have done input and countdown, both of which are carried out at the same time, but I want to achieve like this:
When I don't input anything during the countdown, it will execute another function after the countdown
When I input something before the end of the countdown, the countdown will pause, and then another function will be executed
My code is as follows：
import time
from threading import Thread
def waitinput():
wait_input_str = input("Please enter your account：\n")
print(wait_input_str)
thd = Thread(target=waitinput)
thd.daemon = True
thd.start()
for i in reversed(range(1, 11)):
print("\rcountdown:{}second".format(i), end="")
time.sleep(1)
# ###########################################
You can use isAlive() method to check if your thread has terminated.
In your case:
import time
from threading import Thread
def waitinput():
wait_input_str = input("Please enter your account：\n")
print(wait_input_str)
thd = Thread(target=waitinput)
thd.daemon = True
thd.start()
for i in reversed(range(1, 11)):
if not thd.isAlive():
# Execute 2
print("\nCountdown has stopped")
break
print("\rcountdown:{}second".format(i), end="")
time.sleep(1)
if thd.isAlive():
# Execute 1
print("\nCountdown has ended")
I want to run a loop in my script while the user has not input anything. But when they have input something I want the loop to break.
The issue I am currently having is that when using the input() function, the script will stop and wait for an input, but I want to run another part of the script while waiting for the user input.
I have tried using try: with a raw_input():
while True:
try:
print('SCAN BARCODE')
userInput= raw_input()
#doing something with input
except:
#run this while there is no input
With this, I find that whatever is in the except: will always run, but it will not run try: even when there is a user input. If I change raw_input() to input() the script just waits at input() and doesn't run anything in the except:.
How do I achieve what I am after?
you can use python threads:
from threading import Thread
import time
thread_running = True
def my_forever_while():
global thread_running
start_time = time.time()
# run this while there is no input
while thread_running:
time.sleep(0.1)
if time.time() - start_time >= 5:
start_time = time.time()
print('Another 5 seconds has passed')
def take_input():
user_input = input('Type user input: ')
# doing something with the input
print('The user input is: ', user_input)
if __name__ == '__main__':
t1 = Thread(target=my_forever_while)
t2 = Thread(target=take_input)
t1.start()
t2.start()
t2.join() # interpreter will wait until your process get completed or terminated
thread_running = False
print('The end')
In my example you have 2 threads, the first thread is up and executes code until you have some input from the user, thread 2 is waiting for some input from the user. After you got the user input thread 1 and 2 will stop.
It simple bro u use flag boolean values
Flag = True
while Flag:
try:
Print('scan bar code')
User_inp = input()
if User_inp != '':
Flag = False
Except:
Print('except part')
I suggest you to look for select
it allow you to check if a file descriptor is ready for read/write/expect operation
I want to execute a function repeatedly every 5 seconds and at the same time take input from the user and based on the input stop the execution?
Ex:
def printit():
t=threading.Timer(3.0,printit)
t.start()
n=str(input())
if(n=='rajesh'):
t.cancel()
else:
#I want to continue the execution here
This Should Help
import time
#use a While loop
While True:
#request said user input
x= input("Please Press 1 to continue Or 2 to Exit")
#then an if statement
if x==1:
#call your function
printit()
time.sleep(5)
else:break
This should Do the trick
If you really want to use threading, then this should work:
import threading
import time
def worker():
while True:
user_input = input("Enter text:")
if user_input == 'rajesh':
break
else:
time.sleep(5)
thread = threading.Thread(target=worker, daemon=True)
thread.start()
thread.join()
This Should Help
#request said user input
x= input("Please Press 1 to continue Or 2 to Exit")
#use a While loop
While True:
#then an if statement
if x==1:
#call your function
printit()
else:break
This should Do the trick
in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?
The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.
I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.
The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')
from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!
A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)
under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0
This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")