In python, how do I end the countdown when I have input - python

Description: now, I have done input and countdown, both of which are carried out at the same time, but I want to achieve like this:
When I don't input anything during the countdown, it will execute another function after the countdown
When I input something before the end of the countdown, the countdown will pause, and then another function will be executed
My code is as follows:
import time
from threading import Thread
def waitinput():
wait_input_str = input("Please enter your account:\n")
print(wait_input_str)
thd = Thread(target=waitinput)
thd.daemon = True
thd.start()
for i in reversed(range(1, 11)):
print("\rcountdown:{}second".format(i), end="")
time.sleep(1)
# ###########################################

You can use isAlive() method to check if your thread has terminated.
In your case:
import time
from threading import Thread
def waitinput():
wait_input_str = input("Please enter your account:\n")
print(wait_input_str)
thd = Thread(target=waitinput)
thd.daemon = True
thd.start()
for i in reversed(range(1, 11)):
if not thd.isAlive():
# Execute 2
print("\nCountdown has stopped")
break
print("\rcountdown:{}second".format(i), end="")
time.sleep(1)
if thd.isAlive():
# Execute 1
print("\nCountdown has ended")

Related

Terminate Python program if input isn't specified in due timeframe

I'm trying to terminate python program if an input isn't provided by user within specific time frame, say - 5 seconds.
The code has been taken and edited from mediocrity's answer
import sys
import time
from threading import Thread
x = None
def check():
global x
time.sleep(5)
if x:
print("Input has been given!")
return
sys.exit()
Thread(target=check).start()
x = input("Input something: ")
But it keeps waiting for the input and doesn't terminate, unless the input is given.
How could I change the code so that it executes as inteded?
you should try this code its working on vscode
import sys
import time
from threading import Thread
x = None
def check():
global x
time.sleep(5)
if x:
print("Input has been given!")
return
else:
print("input has not been given for last 5 sec")
sys.exit()
if __name__=='__main__':
t1=Thread(target=check)
t1.start()
x = input("Input something: ")
t1.join()

Is there anyway to wait for a couple of minutes and if no input is provided then take the value "n" as input for first variable?

while 1:
wat=water()
if wat==10:
print("water condition")
mixer.music.load("water.mp3")
mixer.music.play()
first=input("Drank?Y/N")
if first.lower()=="y":
with open("HealthLog.txt","a") as water1:
Content=f"Drank water at [{getdate()}] \n"
water1.write(Content)
else:
pass
Is there any way to wait for a couple of minutes and if no input is provided, then take the value "n" as input for the first variable?
Guess by default it will wait indefinitely. I tried using a timer function, but it cannot record any input.
What I am trying to do is to track my activities, so if I drink water I say y--> this records my activity and writes it to a file.
All help will be greatly appreciated
Here is how you can use a combination of pyautogui.typewrite, threading.Thread and time.sleep:
from pyautogui import typewrite
from threading import Thread
from time import sleep
a = ''
def t():
sleep(5)
if not a: # If by 5 seconds a still equals to '', as in, the user haven't overwritten the original yet
typewrite('n')
typewrite(['enter'])
T = Thread(target=t)
T.start()
a = input()
b = input() # Test it on b, nothing will happen
Here is the code implemented into your code:
from pyautogui import typewrite
from threading import Thread
from time import sleep
while 1:
wat = water()
if wat == 10:
print("water condition")
mixer.music.load("water.mp3")
mixer.music.play()
first = 'waiting...'
def t():
sleep(5)
if first == 'waiting...':
typewrite('n')
typewrite(['enter'])
T = Thread(target=t)
T.start()
first = input("Drank?Y/N")
if first.lower() == "y":
with open("HealthLog.txt","a") as water1:
Content=f"Drank water at [{getdate()}] \n"
water1.write(Content)
else:
pass

Run a loop while waiting for a user input

I want to run a loop in my script while the user has not input anything. But when they have input something I want the loop to break.
The issue I am currently having is that when using the input() function, the script will stop and wait for an input, but I want to run another part of the script while waiting for the user input.
I have tried using try: with a raw_input():
while True:
try:
print('SCAN BARCODE')
userInput= raw_input()
#doing something with input
except:
#run this while there is no input
With this, I find that whatever is in the except: will always run, but it will not run try: even when there is a user input. If I change raw_input() to input() the script just waits at input() and doesn't run anything in the except:.
How do I achieve what I am after?
you can use python threads:
from threading import Thread
import time
thread_running = True
def my_forever_while():
global thread_running
start_time = time.time()
# run this while there is no input
while thread_running:
time.sleep(0.1)
if time.time() - start_time >= 5:
start_time = time.time()
print('Another 5 seconds has passed')
def take_input():
user_input = input('Type user input: ')
# doing something with the input
print('The user input is: ', user_input)
if __name__ == '__main__':
t1 = Thread(target=my_forever_while)
t2 = Thread(target=take_input)
t1.start()
t2.start()
t2.join() # interpreter will wait until your process get completed or terminated
thread_running = False
print('The end')
In my example you have 2 threads, the first thread is up and executes code until you have some input from the user, thread 2 is waiting for some input from the user. After you got the user input thread 1 and 2 will stop.
It simple bro u use flag boolean values
Flag = True
while Flag:
try:
Print('scan bar code')
User_inp = input()
if User_inp != '':
Flag = False
Except:
Print('except part')
I suggest you to look for select
it allow you to check if a file descriptor is ready for read/write/expect operation

Python pause loop on user input

Hey I am trying to have a loop be pausable from user input like having a input box in the terminal that if you type pause it will pause the loop and then if you type start it will start again.
while True:
#Do something
pause = input('Pause or play:')
if pause == 'Pause':
#Paused
Something like this but having the #Do something continually happening without waiting for the input to be sent.
Ok I get it now, here is a solution with Threads:
from threading import Thread
import time
paused = "play"
def loop():
global paused
while not (paused == "pause"):
print("do some")
time.sleep(3)
def interrupt():
global paused
paused = input('pause or play:')
if __name__ == "__main__":
thread2 = Thread(target = interrupt, args = [])
thread = Thread(target = loop, args = [])
thread.start()
thread2.start()
You can't directly, as input blocks everything until it returns.
The _thread module, though, can help you with that:
import _thread
def input_thread(checker):
while True:
text = input()
if text == 'Pause':
checker.append(True)
break
else:
print('Unknown input: "{}"'.format(text))
def do_stuff():
checker = []
_thread.start_new_thread(input_thread, (checker,))
counter = 0
while not checker:
counter += 1
return counter
print(do_stuff())

What is best way to repeatedly execute a function in python and stop it based on some condition?

I want to execute a function repeatedly every 5 seconds and at the same time take input from the user and based on the input stop the execution?
Ex:
def printit():
t=threading.Timer(3.0,printit)
t.start()
n=str(input())
if(n=='rajesh'):
t.cancel()
else:
#I want to continue the execution here
This Should Help
import time
#use a While loop
While True:
#request said user input
x= input("Please Press 1 to continue Or 2 to Exit")
#then an if statement
if x==1:
#call your function
printit()
time.sleep(5)
else:break
This should Do the trick
If you really want to use threading, then this should work:
import threading
import time
def worker():
while True:
user_input = input("Enter text:")
if user_input == 'rajesh':
break
else:
time.sleep(5)
thread = threading.Thread(target=worker, daemon=True)
thread.start()
thread.join()
This Should Help
#request said user input
x= input("Please Press 1 to continue Or 2 to Exit")
#use a While loop
While True:
#then an if statement
if x==1:
#call your function
printit()
else:break
This should Do the trick

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