I'm a newbie in web development and I'm learning to use Django. Unfortunately I have been stuck for more than 24 hours trying to figure out how to set the URL of a web page. I keep getting status 404 error displayed on the browser after running python server. I have checked python documentation and other documentations online but I still don't see anywhere I'm getting it wrong.
I have the following files in the main Django follow:
urls.py
from django.contrib import admin
from django.urls import path, include
urlspatterns [
path('qbank', include ('qbank.url')),
path ('admin/', admin.site.urls),
]
settings.py
INSTALLED APPS = [
'qbank'
.....
]
In my project folder(which I named qbank) I have the following files:
urls.py
from django.urls import path
from . import views
urlspatterns = [
path ('qbank'), views.index, name = 'index'
]
view.py
from django.shortcuts import render
from django.http import HttpResponse
def index(request):
return HttpResponse ('Hello from Qbank')
The way you wrote it now, it will require two qbanks, one for the "root" urls.py, and one for the urls.py in the qbanks, hence localhost:8000/qbankqbank. If you only want to access it with qbank, then you remove the qbank for example from the urls.py of the qbanks app. So then the "root" urls.py looks like:
# project_name/urls.py
from django.contrib import admin
from django.urls import path, include
urlspatterns [
path('qbank/', include('qbank.url')),
path ('admin/', admin.site.urls),
]
and the urls.py of your app:
# qbank/urls.py
from django.urls import path
from . import views
urlspatterns = [
path ('', views.index, name='index')
]
Related
app urls.py
from django.urls import path
from . import views
urlpatterns = [
path('hello', views.index, name='index')
]
project urls.py
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('admin/', admin.site.urls),
path('hello/', include("hello.urls"))
]
views.py
from django.http import HttpResponse
from django.shortcuts import render
# Create your views here.
def index(request):
return HttpResponse("Hello, World!")
I've re-watched the tutorial several times and still can't find the error.
Since your project's urls.py includes hello using the prefix 'hello/' in
path('hello/', include("hello.urls"))
and your app's urls.py also has hello as the path in
path('hello', views.index, name='index')
you will need to access /hello/hello in your browser to get to a view that doesn't 404.
Django's technical 404 page (the one with the yellow background) should show the available paths -- if you don't get the technical 404 page, ensure you have the DEBUG setting turned on.
i have just now started learning the django basics ,but i have been keeping on facing a problem with the urls & views. i do not get the "Hello world" after i reload or even try adding myapp name in the url
wrote this code for the project url
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('', include('calc.urls')),
path('admin/', admin.site.urls),
]
wrote this for myapp urls
from django.urls import path
from . import views
urlpatterns = [
path('', views.home, name='home'),
]
wrote this for the views
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def home(request):
return HttpResponse("Hello world");
what is the mistake i am doing?
link: http://127.0.0.1:8000/calc
You are not setting the correct URL. Also have you added your in installed apps ?
if yes then visit: http://127.0.0.1:8000
or add calc in your url to use http://127.0.0.1:8000/calc
urlpatterns = [
path('calc', views.home, name='home'),
]
Is your myapp urls file inside a folder called calc? If it isn't then try doing something like this:
Change include('calc.urls') to include('\the folder name in which myapp urls is in\.urls')
Then use the http://127.0.0.1:8000 and it should work.
I uploaded my site to the live server, but still, I am seeing Django default page, I updated my urls.py file, but still, it's not working. and it's showing me this output. Please let me know where I am Mistaking.
I am trying to access this mydomain.com/dashboard
Using the URLconf defined in yoursite.urls, Django tried these URL patterns, in this order:
admin/
The current path, dashboard, didn't match any of these.
here is my urls.py file...
urlpatterns = [
path('admin/', admin.site.urls),
url(r'^dashboard/', include('dashboard.urls')),
url(r'^accounts/', include('accounts.urls')),
url('', include('frontpanel.urls')),
path('', views.index, name='index'),
]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
And here is my views.py file...
def index(request):
category = Category.objects.all().order_by('created_at')
return render(request, "base.html", {'category':category})
What version of Django are you using?
Try changing url to re_path (remember to import it first). I think url has been deprecated.
After Analyzing the question u never mentioned ur app urls.py you only mentioned project urls.py . As u have url(r'^dashboard/', include('dashboard.urls')), in ur project urls.py, there must be a file in your app also named urls.py which handles urls having prefix /dashboard/ , by default django doesnt make that file you need to manually make it add ur function names to redirect . For example this is my main urls.py file
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('display_report/', include("display_report.urls"))
]
then u have to make a file named urls.py in ur app also to handle the requests and redirect the the approaite functions , in my display_report app i made a urls.py that looks like this
from django.contrib import admin
from django.urls import path, include
from display_report import views
from django.conf.urls.static import static
from django.conf import settings
urlpatterns = [path('', views.index)]
And then it will redirect to function named index in ur views.py file inside ur app
from django.shortcuts import render, redirect, HttpResponse
# from .models import Employee, Tasks, Report, Fileupload, Fileuploadnext
from django.views.decorators.csrf import csrf_exempt
# Create your views here.
def index(request):
return render(request."index.html")
Here my ur will be mydomain.com/display_report and my index.html file will be inside the template folder
I have read many answers in this forum, but they does not solve my problem. I will be very grateful for help.
My file views.py returns this error:
from . import views
ImportError: cannot import name 'views' from '__main__' (C:/Users/tymot/Desktop/weather app/env/Environemnt/the_weather/weather/views.py)
views.py (Environemnt\the_weather\weather)
from django.shortcuts import render
from django.contrib import admin
def index(request):
return render(request, 'weather/index.html') #returns the index.html
urls.py (Environemnt\the_weather\weather)
from django.urls import path
from . import views
urlpatterns = [
path('', views.index), #the path for our index view
]
urls.py (Environemnt\the_weather\the_weather)
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('weather.urls')),
templates(the_weather\weather\templates\weather)
only file index.html
Directory
-the_weather
--the_weather
---__init__
---setting
---urls
---wsgi
--weather
---migrations
----__init__
---templates
----weather
-----index
---__init__
---admin
---apps
---models
---tests
---urls
---views
--db
--manage.py
I try use to resolved my problem from __future__ import absolute_import, or homepage import views. I else try copy views.py to directory templates (and modify its code) but unfortunately it not work
You need to separate your views and urls create a new module (file) urls.py in your app, in your case it is weather folder, and add these code there, and remove it from views.py, you can read here about it to understand it better.
Path : the_weather/weather/urls.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.index), #the path for our index view
]
Path : the_weather/weather/views.py
from django.shortcuts import render
from django.contrib import admin
def index(request):
return render(request, 'weather/index.html') #returns the index.html template
You would need to put your views.py file in your weather folder. Make sure it is in the right weather folder, I am guessing you have two weather folders. Also make sure these codes are right;
#Path : the_weather/weather/urls.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.index), #the path for our index view
]
#Path : the_weather/weather/views.py
from django.shortcuts import render
from django.contrib import admin
def index(request):
return render(request, 'weather/index.html') #returns the index.html template
Why don't you try like this
from .views import index
There may be separate folder of urls and views.py
what you have to do is you have to write
from appname import views
suppose your app name is myapp
you have have to write
from myapp import views
use should create new url.py in weather and write code in views.py
url.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.index, name='index')
]
write code in urls.py of your project
from django.urls import path, include
from . import views
urlpatterns = [
path('wheather/',include('wheather'))
]
I had Similar problem, it didn't solved, till I added an empty views.py in root in example, in your case add to Environemnt\the_weather\the_weather
I had the same problem.
In formsdemo\formsdemo\__init__.py, I changed the import code to from forms app import views.
from django.contrib import admin
from django.urls import path
import main.views
urlpatterns = [
path('admin/', admin.site.urls),
path('', main.views.home_page, name="home_page"),
]
Well, i was also facing the same issue. I was continuously getting server errors but then I figured out it was a simple error.
go to the urls.py file
from django.urls import path
from . import views
urlpatterns = [
path('', views.index, name = index), #the path for our index view
]
I just had to remove name = index and the server worked with 0 errors.
enter image description here
I have the following urls.py file in a Django project, and I am getting an error which I assume is relating to the latest syntax relating to urls and paths.
The code I have in the urls file which is url.py in the mysite (outermost directory) is:
from django.urls import path
from django.conf.urls import url, include
urlpatterns = [
path(r'^$', include('aboutme.urls')),
]
The error message is:
Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order:
^$
The empty path didn't match any of these.
In the actual app (website folder) which is called 'aboutme', the urls.py file looks like this:
from django.urls import path
from django.conf.urls import url, include
from .import views #this is the main thing we are going to be doing ....returning views!
urlpatterns = [
path(r'^$', views.index,name='index'),
]
Can anyone shed any light on the correct syntax or what I am doing wrong?
UPDATE:
I also went back and tried to update the main mysite's url.py file to include the admin commands (which were in the previously working version). The code and resultant error are also shown below:
Tried this code:
from django.contrib import admin
from django.urls import path
from django.conf.urls import url, include
urlpatterns = [
path('admin/', admin.site.urls),
path(r' ', include('aboutme.urls')),
]
Error
Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order:
admin/
The empty path didn't match any of these.
Remove the ^ and $ in the urls.py files.
from django.urls import path
from django.conf.urls import url, include
urlpatterns = [
path(r'', include('aboutme.urls')),
]
And in your app urls.py:
from django.urls import path
from django.conf.urls import url, include
from .import views #this is the main thing we are going to be doing
app_name="myappname"
urlpatterns = [
path(r'', views.index,name='index'),
]
In django 2.0 they are not needed anymore if you are using path().
Related link: https://code.djangoproject.com/ticket/28691