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How to get the values of dictionary python?

I have the below python dictionary stored as dictPython
{
"paging": {"count": 10, "start": 0, "links": []},
"elements": [
{
"organizationalTarget~": {
"vanityName": "vv",
"localizedName": "ViV",
"name": {
"localized": {"en_US": "ViV"},
"preferredLocale": {"country": "US", "language": "en"},
},
"primaryOrganizationType": "NONE",
"locations": [],
"id": 109,
},
"role": "ADMINISTRATOR",
},
],
}
I need to get the values of vanityName, localizedName and also the values from name->localized and name->preferredLocale.
I tried dictPython.keys() and it returned dict_keys(['paging', 'elements']).
Also I tried dictPython.values() and it returned me what is inside of the parenthesis({}).
I need to get [vv, ViV, ViV, US, en]

I am writing this in a form of answer, so I can get to explain it better without the comments characters limit
a dict in python is an efficient key/value structure or data type
for example dict_ = {'key1': 'val1', 'key2': 'val2'} to fetch key1 we can do it in 2 different ways
dict_.get(key1) this returns the value of the key in this case val1, this method has its advantage, that if the key1 is wrong or not found it returns None so no exceptions are raised. You can do dict_.get(key1, 'returning this string if the key is not found')
dict_['key1'] doing the same .get(...) but will raise a KeyError if the key is not found
So to answer your question after this introduction,
a dict can be thought of as nested dictionaries and/or objects inside of one another
to get your values you can do the following
# Fetch base dictionary to make code more readable
base_dict = dict_["elements"][0]["organizationalTarget~"]
# fetch name_dict following the same approach as above code
name_dict = base_dict["name"]
localized_dict = name_dict["localized"]
preferred_locale_dict = name_dict ["preferredLocale"]
so now we fetch all of the wanted data in their corresponding locations from your given dictionary, now to print the results, we can do the following
results_arr = []
for key1, key2 in zip(localized_dict, preferredLocale_dict):
results_arr.append(localized_dict.get(key1))
results_arr.append(preferred_locale_dict.get(key2))
print(results_arr)

What about:
dic = {
"paging": {"count": 10, "start": 0, "links": []},
"elements": [
{
"organizationalTarget~": {
"vanityName": "vv",
"localizedName": "ViV",
"name": {
"localized": {"en_US": "ViV"},
"preferredLocale": {"country": "US", "language": "en"},
},
"primaryOrganizationType": "NONE",
"locations": [],
"id": 109,
},
"role": "ADMINISTRATOR",
},
],
}
base = dic["elements"][0]["organizationalTarget~"]
c = base["name"]["localized"]
d = base["name"]["preferredLocale"]
output = [base["vanityName"], base["localizedName"]]
output.extend([c[key] for key in c])
output.extend([d[key] for key in d])
print(output)
outputs:
['vv', 'ViV', 'ViV', 'US', 'en']

So something like this?
[[x['organizationalTarget~']['vanityName'],
x['organizationalTarget~']['localizedName'],
x['organizationalTarget~']['name']['localized']['en_US'],
x['organizationalTarget~']['name']['preferredLocale']['country'],
x['organizationalTarget~']['name']['preferredLocale']['language'],
] for x in s['elements']]

How to update/change both keys and values separately (not dedicated key-value pair) in a deeply nested JSON in python 3.x

I have a JSON file where I need to replace the UUID and update it with another one. I'm having trouble replacing the deeply nested keys and values.
Below is my JSON file that I need to read in python, replace the keys and values and update the file.
JSON file - myfile.json
{
"name": "Shipping box"
"company":"Detla shipping"
"description":"---"
"details" : {
"boxes":[
{
"box_name":"alpha",
"id":"a3954710-5075-4f52-8eb4-1137be51bf14"
},
{
"box_name":"beta",
"id":"31be3763-3d63-4e70-a9b6-d197b5cb6929"
} ​
​ ]
​}
"container": [
"a3954710-5075-4f52-8eb4-1137be51bf14":[],
"31be3763-3d63-4e70-a9b6-d197b5cb6929":[] ​
​]
​"data":[
{
"data_series":[],
"other":50
},
{
"data_series":[],
"other":40
},
{
"data_series":
{
"a3954710-5075-4f52-8eb4-1137be51bf14":
{
{
"dimentions":[2,10,12]
}
},
"31be3763-3d63-4e70-a9b6-d197b5cb6929":
{
{
"dimentions":[3,9,12]
}
}
},
"other":50
}
]
}
I want achieve something like the following-
"details" : {
"boxes":[
{
"box_name":"alpha"
"id":"replace_uuid"
},
}
.
.
.
​ "data":[ {
"data_series":
{
"replace_uuid":
{
{
"dimentions":[2,10,12]
}
}
]
In such a type of deeply nested dictionary, how can we replace all the occurrence of keys and values with another string, here replace_uuid?
I tried with pop() and dotty_dict but I wasn't able to replace the nested list.

I was able to achieve it in the following way-
def uuid_change(): #generate a random uuid
new_uuid = uuid.uuid4()
return str(new_uuid)
dict = json.load(f)
for uid in dict[details][boxes]:
old_id = uid['id']
replace_id = uuid_change()
uid['id'] = replace_id
for i in range(n):
for uid1 in dict['container'][i].keys()
if uid1 == old_id:
dict['container'][i][replace_id]
= dict['container'][i].pop(uid1) #replace the key
for uid2 in dict['data'][2]['data_series'].keys()
if uid2 == old_id:
dict['data'][2]['data_series'][replace_id]
= dict['data'][2]['data_series'].pop(uid2) #replace the key

Elegant way of iterating list of dict python

I have a list of dictionary as below. I need to iterate the list of dictionary and remove the content of the parameters and set as an empty dictionary in sections dictionary.
input = [
{
"category":"Configuration",
"sections":[
{
"section_name":"Global",
"parameters":{
"name":"first",
"age":"second"
}
},
{
"section_name":"Operator",
"parameters":{
"adrress":"first",
"city":"first"
}
}
]
},
{
"category":"Module",
"sections":[
{
"section_name":"Global",
"parameters":{
"name":"first",
"age":"second"
}
}
]
}
]
Expected Output:
[
{
"category":"Configuration",
"sections":[
{
"section_name":"Global",
"parameters":{}
},
{
"section_name":"Operator",
"parameters":{}
}
]
},
{
"category":"Module",
"sections":[
{
"section_name":"Global",
"parameters":{}
}
]
}
]
My current code looks like below:
category_list = []
for categories in input:
sections_list = []
category_name_dict = {"category": categories["category"]}
for sections_dict in categories["sections"]:
section = {}
section["section_name"] = sections_dict['section_name']
section["parameters"] = {}
sections_list.append(section)
category_name_dict["sections"] = sections_list
category_list.append(category_name_dict)
Is there any elegant and more performant way to do compute this logic. Keys such as category, sections, section_name, and parameters are constants.

The easier way is not to rebuild the dictionary without the parameters, just clear it in every section:
for value in values:
for section in value['sections']:
section['parameters'] = {}
Code demo

Elegance is in the eye of the beholder, but rather than creating empty lists and dictionaries then filling them why not do it in one go with a list comprehension:
category_list = [
{
**category,
"sections": [
{
**section,
"parameters": {},
}
for section in category["sections"]
],
}
for category in input
]
This is more efficient and (in my opinion) makes it clearer that the intention is to change a single key.

How to get values of keys for changing Json

I am using python2.7
I have a json i pull that is always changing when i request it.
I need to pull out Animal_Target_DisplayName under Term7 Under Relation6 in my dict.
The problem is sometimes the object Relation6 is in another part of the Json, it could be leveled deeper or in another order.
I am trying to create code that can just export the values of the key Animal_Target_DisplayName but nothing is working. It wont even loop down the nested dict.
Now this can work if i just pull it out using something like ['view']['Term0'][0]['Relation6'] but remember the JSON is never returned in the same structure.
Code i am using to get the values of the key Animal_Target_DisplayName but it doesnt seem to loop through my dict and find all the values with that key.
array = []
for d in dict.values():
row = d['Animal_Target_DisplayName']
array.append(row)
JSON Below:
dict = {
"view":{
"Term0":[
{
"Id":"b0987b91-af12-4fe3-a56f-152ac7a4d84d",
"DisplayName":"Dog",
"FullName":"Dog",
"AssetType1":[
{
"AssetType_Id":"00000000-0000-0000-0000-000000031131",
}
]
},
{
"Id":"ee74a59d-fb74-4052-97ba-9752154f015d",
"DisplayName":"Dog2",
"FullName":"Dog",
"AssetType1":[
{
"AssetType_Id":"00000000-0000-0000-0000-000000031131",
}
]
},
{
"Id":"eb548eae-da6f-41e8-80ea-7e9984f56af6",
"DisplayName":"Dog3",
"FullName":"Dog3",
"AssetType1":[
{
"AssetType_Id":"00000000-0000-0000-0000-000000031131",
}
]
},
{
"Id":"cfac6dd4-0efa-4417-a2bf-0333204f8a42",
"DisplayName":"Animal Set",
"FullName":"Animal Set",
"AssetType1":[
{
"AssetType_Id":"00000000-0000-0000-0001-000400000001",
}
],
"StringAttribute2":[
{
"StringAttribute_00000000-0000-0000-0000-000000003114_Id":"00a701a8-be4c-4b76-a6e5-3b0a4085bcc8",
"StringAttribute_00000000-0000-0000-0000-000000003114_Value":"Desc"
}
],
"StringAttribute3":[
{
"StringAttribute_00000000-0000-0000-0000-000000000262_Id":"a81adfb4-7528-4673-8c95-953888f3b43a",
"StringAttribute_00000000-0000-0000-0000-000000000262_Value":"meow"
}
],
"BooleanAttribute4":[
{
"BooleanAttribute_00000000-0000-0000-0001-000500000001_Id":"932c5f97-c03f-4a1a-a0c5-a518f5edef5e",
"BooleanAttribute_00000000-0000-0000-0001-000500000001_Value":"true"
}
],
"SingleValueListAttribute5":[
{
"SingleValueListAttribute_00000000-0000-0000-0001-000500000031_Id":"ef51dedd-6f25-4408-99a6-5a6cfa13e198",
"SingleValueListAttribute_00000000-0000-0000-0001-000500000031_Value":"Blah"
}
],
"Relation6":[
{
"Animal_Id":"2715ca09-3ced-4b74-a418-cef4a95dddf1",
"Term7":[
{
"Animal_Target_Id":"88fd0090-4ea8-4ae6-b7f0-1b13e5cf3d74",
"Animal_Target_DisplayName":"Animaltheater",
"Animal_Target_FullName":"Animaltheater"
}
]
},
{
"Animal_Id":"6068fe78-fc8e-4542-9aee-7b4b68760dcd",
"Term7":[
{
"Animal_Target_Id":"4e87a614-2a8b-46c0-90f3-8a0cf9bda66c",
"Animal_Target_DisplayName":"Animaltitle",
"Animal_Target_FullName":"Animaltitle"
}
]
},
{
"Animal_Id":"754ec0e6-19b6-4b6b-8ba1-573393268257",
"Term7":[
{
"Animal_Target_Id":"a8986ed5-3ec8-44f3-954c-71cacb280ace",
"Animal_Target_DisplayName":"Animalcustomer",
"Animal_Target_FullName":"Animalcustomer"
}
]
},
{
"Animal_Id":"86b3ffd1-4d54-4a98-b25b-369060651bd6",
"Term7":[
{
"Animal_Target_Id":"89d02067-ebe8-4b87-9a1f-a6a0bdd40ec4",
"Animal_Target_DisplayName":"Animalfact_transaction",
"Animal_Target_FullName":"Animalfact_transaction"
}
]
},
{
"Animal_Id":"ea2e1b76-f8bc-46d9-8ebc-44ffdd60f213",
"Term7":[
{
"Animal_Target_Id":"e398cd32-1e73-46bd-8b8f-d039986d6de0",
"Animal_Target_DisplayName":"Animalfact_transaction",
"Animal_Target_FullName":"Animalfact_transaction"
}
]
}
],
"Relation10":[
{
"TargetRelation_b8b178ff-e957-47db-a4e7-6e5b789d6f03_Id":"aff80bd0-a282-4cf5-bdcc-2bad35ddec1d",
"Term11":[
{
"AnimalId":"3ac22167-eb91-469a-9d94-315aa301f55a",
"AnimalDisplayName":"Animal",
"AnimalFullName":"Animal"
}
]
}
],
"Tag12":[
{
"Tag_Id":"75968ea6-4c9f-43c9-80f7-dfc41b24ec8f",
"Tag_Name":"AnimalAnimaltitle"
},
{
"Tag_Id":"b1adbc00-aeef-415b-82b6-a3159145c60d",
"Tag_Name":"Animal2"
},
{
"Tag_Id":"5f78e4dc-2b37-41e0-a0d3-cec773af2397",
"Tag_Name":"AnimalDisplayName"
}
]
}
]
}
}
The output i am trying to get is a list of all the values from key Animal_Target_DisplayName like this ['Animaltheater','Animaltitle', 'Animalcustomer', 'Animalfact_transaction', 'Animalfact_transaction'] but we need to remember the nested structure of this json always changes but the keys for it are always the same.

I guess your only option is running through the entire dict and get the values of Animal_Target_DisplayName key, I propose the following recursive solution:
def run_json(dict_):
animal_target_sons = []
if type(dict_) is list:
for element in dict_:
animal_target_sons.append(run_json(element))
elif type(dict_) is dict:
for key in dict_:
if key=="Animal_Target_DisplayName":
animal_target_sons.append([dict_[key]])
else:
animal_target_sons.append(run_json(dict_[key]))
return [x for sublist in animal_target_sons for x in sublist]
run_json(dict_)
Then calling run_json returns a list with what you want. By the way, I recommend you to rename your json from dict to, for example dict_, since dict is a reserved word of Python for the dictionary type.

Since you're getting JSON, why not make use of the json module? That will do the parsing for you and allow you to use dictionary functions+features to get the information you need.
#!/usr/bin/python2.7
from __future__ import print_function
import json
# _somehow_ get your JSON in as a string. I'm calling it "jstr" for this
# example.
# Use the module to parse it
jdict = json.loads(jstr)
# our dict has keys...
# view -> Term0 -> keys-we're-interested-in
templist = jdict["view"]["Term0"]
results = {}
for _el in range(len(templist)):
if templist[_el]["FullName"] == "Animal Set":
# this is the one we're interested in - and it's another list
moretemp = templist[_el]["Relation6"]
for _k in range(len(moretemp)):
term7 = moretemp[_k]["Term7"][0]
displayName = term7["Animal_Target_DisplayName"]
fullName = term7["Animal_Target_FullName"]
results[fullName] = displayName
print("{0}".format(results))
Then you can dump the results dict plain, or with pretty-printing:
>>> print(json.dumps(results, indent=4))
{
"Animaltitle2": "Animaltitle2",
"Animalcustomer3": "Animalcustomer3",
"Animalfact_transaction4": "Animalfact_transaction4",
"Animaltheater1": "Animaltheater1"
}

How to create a custom dictionary in python?

There is what i have in source:
"VirtualizationType": "hvm",
"Tags": [
{
"Value": "Test",
"Key": "Name"
}
]
and here is a bit of my code:
for item in result:
temp = {"Tags": item["Value"], "VirtualizationType": item["VirtualizationType"]}
output.append(temp)
I can easily export VirtualizationType but couldn`t do it with Tags

An example of how to create a dictionary in Python, from docs:
tel = {'jack': 4098, 'sape': 4139}
In this example jack, snape are the keys and 4098, 4139 are the values.
Values can also be strings and a list of dictionary like in your case,
your code can modified into this:
dictionary = {"Virtualization Type" : "hvm", "Tags" : [{"Value" : "Test", "Key" : "Name"}] } #Runs in the python interpreter with no errors