Generating a random sentence in python - python

I have the following input which contains Aircraft and Services
AirCrafts={'Cargo Aircraft':'1','International Aircraft':'2','Domestic Aircraft':'3'}
Services={
'AirCrafts':[1,2,3],
'Cargo Aircraft':[
"Fedx","DHFL","Emirates SkyCargo","Qatar Airways Cargo","Cathay Pacific Cargo"
],
'International Aircraft':[
"Air India","Air France","BA"
],
'Domestic Aircraft':[
"TruJet","Indigo","AirAsia"
]
}
I have a generated sentence the following sentence using SenGen Function.
def SenGen(alpha,beta):
for keys,values in alpha.items():
for key,value in beta.items():
if key in keys:
if values == []:
print(f"{keys} are not found.")
if len(values) > 1:
print(f"{keys} are ", end="\n")
for i, val in enumerate(values):
if len(values) == 1:
if "Not found" in value:
print(f"{keys} are {val}. ", end="\n")
else:
print(f"{keys} is {val}. ", end = "\n")
else:
if i == len(values)-1:
print(f"•{val}. ", end="\n")
elif i == len(value)-2:
print(f"•{val} ", end="\n")
else:
print(f"•{val}, ", end="\n")
My generated output is below after running SenGen(Services,AirCrafts).
SenGen(Services,AirCrafts)
International Aircraft are
•Air India,
•Air France,
•BA.
Domestic Aircraft are
•TruJet,
•Indigo,
•AirAsia.
In the above output, I have international Aircraft are and Domestic Aircraft are.
in place of International Aircraft, I want to generate a proper sentence such that my output must look like
International Aircrafts that run from the various airport of India are
for the Domestic Aircrafts
Domestic Aircraft which run in within India are
How can I generate a proper sentence as shown above?


So basically this is the line which needed change as per your requirement
if len(values) > 1:
print(f"{keys} are ", end="\n")
You can change it to this, and you will be good to go:
if len(values) > 1:
# for international the statement is different
if keys == "International Aircraft":
print(f"{keys} that run from the various airport of India are ", end="\n")
elif keys == "Domestic Aircraft":
print(f"{keys} which run in within India are", end="\n")
else:
# your else print
Additional Information
To return the statement, do not do like this, you need to use String Concatenation. So in order to do the return, do this in place of print
if len(values) > 1:
# for international the statement is different
if keys == "International Aircraft":
return str(keys) + " that run from the various airport of India are \n"
elif keys == "Domestic Aircraft":
return str(keys) + " which run in within India are \n"
else:
# your else print


In your code, you need to plug in the additional text. Otherwise the program will not know that you want these texts added.
if len(values) > 1:
if "International" in keys:
print(f"{keys} that run from the various airports of India are ", end="\n")
elif "Domestic" in keys:
print(f"{keys} which run in within India are ", end="\n")
else:
print(f"{keys} are ", end="\n")
Here's the code that provides you a return statement.
def SenGen(alpha,beta):
temp = '' #store the results for each iteration of `AirCrafts`
for keys,values in alpha.items():
if keys == 'International Aircraft':
temp += '\n' + keys + ' that run from the various airports of India are :\n' + ',\n'.join(beta[keys])
elif keys == 'Domestic Aircraft':
temp += '\n' + keys + ' which run within India are :\n' + ',\n'.join(beta[keys])
elif keys == 'Cargo Aircraft':
temp += '\n' + keys + ' are :\n' + ',\n'.join(beta[keys])
else:
temp += '\n' + keys + ' are not found'
temp += '\n'
return temp
x = SenGen(AirCrafts,Services)
print (x)
If you don't want the results to be printed separately on each line, you can remove the \n from the string.
Output for your reference:
>>> print (x)
Cargo Aircraft are :
Fedx,
DHFL,
Emirates SkyCargo,
Qatar Airways Cargo,
Cathay Pacific Cargo
International Aircraft that run from the various airports of India are :
Air India,
Air France,
BA
Domestic Aircraft which run within India are :
TruJet,
Indigo,
AirAsia
>>> x
'\nCargo Aircraft are :\nFedx,\nDHFL,\nEmirates SkyCargo,\nQatar Airways Cargo,\nCathay Pacific Cargo\n\nInternational Aircraft that run from the various airports of India are :\nAir India,\nAir France,\nBA\n\nDomestic Aircraft which run within India are :\nTruJet,\nIndigo,\nAirAsia\n'
>>>

Related

Trying to find averages from a .txt but I keep getting ValueError: could not convert string to float: ''

I'm using the txt file: https://drive.google.com/file/d/1-VrWf7aqiqvnshVQ964zYsqaqRkcUoL1/view?usp=sharin
I'm running the script:
data = f.read()
ny_sum=0
ny_count=0
sf_sum=0
sf_count=0
for line in data.split('\n'):
print(line)
parts = line.split('\t')
city = parts[2]
amount = float(parts[4])
if city == 'San Francisco':
sf_sum = sf_sum + amount
elif city == 'New York':
ny_sum = ny_sum + amount
ny_count = ny_count + 1
ny_avg = ny_sum / ny_count
sf_avg = sf_sum / sf_count
#print(ny_avg, sf_avg)
f = open('result_file.txt', 'w')
f.write('The average transaction amount based on {} transactions in New York is {}\n'.format(ny_count, ny_avg))
f.write('The average transaction amount based on {} transactions in San Francisco is {}\n'.format(sf_count, sf_avg))
if ny_avg>sf_avg:
f.write('New York has higher average transaction amount than San Francisco\n')
else:
f.write('San Francisco has higher average transaction amount than New York\n')
f.close()
And I ALWAYS get the error:
ValueError: could not convert string to float: ''
I'm pretty new-ish to Python and I'm really not sure what I'm doing wrong here. I'm trying to get averages for New York and San Francisco, then export the results AND the comparison to a txt results file

This should give you what you're looking for:
from collections import defaultdict as DD
with open('New Purchases.txt') as pfile:
sums = DD(lambda: [0.0, 0])
for line in [line.split('\t') for line in pfile]:
try:
k = line[2]
sums[k][0] += float(line[4])
sums[k][1] += 1
except Exception:
pass
for k in ['San Francisco', 'New York']:
v = sums.get(k, [0.0, 1])
print(f'Average for {k} = ${v[0]/v[1]:.2f}')

I have re-arranged the code. I agree with BrutusFocus that the splits are making it difficult to read exactly the location on each row. I have set it so if it sees the location at any point in the row, it counts it.
with open("data.txt", "r") as f:
data = f.read()
ny_sum=0
ny_count=0
sf_sum=0
sf_count=0
for line in data.split('\n'):
parts = line.split('\t')
city = parts[2]
amount = float(parts[4])
print(city, amount)
if "New York" in line:
ny_sum = ny_sum + amount
ny_count = ny_count + 1
elif "San Francisco" in line:
sf_sum = sf_sum + amount
sf_count = sf_count + 1
ny_avg = ny_sum / ny_count
sf_avg = sf_sum / sf_count
#print(ny_avg, sf_avg)
f = open('result_file.txt', 'w')
f.write('The average transaction amount based on {} transactions in New York is
{}\n'.format(ny_count, ny_avg))
f.write('The average transaction amount based on {} transactions in San
Francisco is {}\n'.format(sf_count, sf_avg))
if ny_avg>sf_avg:
f.write('New York has higher average transaction amount than San Francisco\n')
else:
f.write('San Francisco has higher average transaction amount than New York\n')
f.close()

Search in List; Display names based on search input

I have sought different articles here about searching data from a list, but nothing seems to be working right or is appropriate in what I am supposed to implement.
I have this pre-created module with over 500 list (they are strings, yes, but is considered as list when called into function; see code below) of names, city, email, etc. The following are just a chunk of it.
empRecords="""Jovita,Oles,8 S Haven St,Daytona Beach,Volusia,FL,6/14/1965,32114,386-248-4118,386-208-6976,joles#gmail.com,http://www.paganophilipgesq.com,;
Alesia,Hixenbaugh,9 Front St,Washington,District of Columbia,DC,3/3/2000,20001,202-646-7516,202-276-6826,alesia_hixenbaugh#hixenbaugh.org,http://www.kwikprint.com,;
Lai,Harabedian,1933 Packer Ave #2,Novato,Marin,CA,1/5/2000,94945,415-423-3294,415-926-6089,lai#gmail.com,http://www.buergimaddenscale.com,;
Brittni,Gillaspie,67 Rv Cent,Boise,Ada,ID,11/28/1974,83709,208-709-1235,208-206-9848,bgillaspie#gillaspie.com,http://www.innerlabel.com,;
Raylene,Kampa,2 Sw Nyberg Rd,Elkhart,Elkhart,IN,12/19/2001,46514,574-499-1454,574-330-1884,rkampa#kampa.org,http://www.hermarinc.com,;
Flo,Bookamer,89992 E 15th St,Alliance,Box Butte,NE,12/19/1957,69301,308-726-2182,308-250-6987,flo.bookamer#cox.net,http://www.simontonhoweschneiderpc.com,;
Jani,Biddy,61556 W 20th Ave,Seattle,King,WA,8/7/1966,98104,206-711-6498,206-395-6284,jbiddy#yahoo.com,http://www.warehouseofficepaperprod.com,;
Chauncey,Motley,63 E Aurora Dr,Orlando,Orange,FL,3/1/2000,32804,407-413-4842,407-557-8857,chauncey_motley#aol.com,http://www.affiliatedwithtravelodge.com
"""
a = empRecords.strip().split(";")
And I have the following code for searching:
import empData as x
def seecity():
empCitylist = list()
for ct in x.a:
empCt = ct.strip().split(",")
empCitylist.append(empCt)
t = sorted(empCitylist, key=lambda x: x[3])
for c in t:
city = (c[3])
print(city)
live_city = input("Enter city: ")
for cy in city:
if live_city in cy:
print(c[1])
# print("Name: "+ c[1] + ",", c[0], "| Current City: " + c[3])
Forgive my idiotic approach as I am new to Python. However, what I am trying to do is user will input the city, then the results should display the employee's last name, first name who are living in that city (I dunno if I made sense lol)
By the way, the code I used above doesn't return any answers. It just loops to the input.
Thank you for helping. Lovelots. <3
PS: the format of the empData is: first name, last name, address, city, country, birthday, zip, phone, and email

You can use the csv module to read easily a file with comma separated values
import csv
with open('test.csv', newline='') as csvfile:
records = list(csv.reader(csvfile))
def search(data, elem, index):
out = list()
for row in data:
if row[index] == elem:
out.append(row)
return out
#test
print(search(records, 'Orlando', 3))

Based on your original code, you can do it like this:
# Make list of list records, sorted by city
t = sorted((ct.strip().split(",") for ct in x.a), key=lambda x: x[3])
# List cities
print("Cities in DB:")
for c in t:
city = (c[3])
print("-", city)
# Define search function
def seecity():
live_city = input("Enter city: ")
for c in t:
if live_city == c[3]:
print("Name: "+ c[1] + ",", c[0], "| Current City: " + c[3])
seecity()
Then, after you understand what's going on, do as #Hoxha Alban suggested, and use the csv module.

The beauty of python lies in list comprehension.
empRecords="""Jovita,Oles,8 S Haven St,Daytona Beach,Volusia,FL,6/14/1965,32114,386-248-4118,386-208-6976,joles#gmail.com,http://www.paganophilipgesq.com,;
Alesia,Hixenbaugh,9 Front St,Washington,District of Columbia,DC,3/3/2000,20001,202-646-7516,202-276-6826,alesia_hixenbaugh#hixenbaugh.org,http://www.kwikprint.com,;
Lai,Harabedian,1933 Packer Ave #2,Novato,Marin,CA,1/5/2000,94945,415-423-3294,415-926-6089,lai#gmail.com,http://www.buergimaddenscale.com,;
Brittni,Gillaspie,67 Rv Cent,Boise,Ada,ID,11/28/1974,83709,208-709-1235,208-206-9848,bgillaspie#gillaspie.com,http://www.innerlabel.com,;
Raylene,Kampa,2 Sw Nyberg Rd,Elkhart,Elkhart,IN,12/19/2001,46514,574-499-1454,574-330-1884,rkampa#kampa.org,http://www.hermarinc.com,;
Flo,Bookamer,89992 E 15th St,Alliance,Box Butte,NE,12/19/1957,69301,308-726-2182,308-250-6987,flo.bookamer#cox.net,http://www.simontonhoweschneiderpc.com,;
Jani,Biddy,61556 W 20th Ave,Seattle,King,WA,8/7/1966,98104,206-711-6498,206-395-6284,jbiddy#yahoo.com,http://www.warehouseofficepaperprod.com,;
Chauncey,Motley,63 E Aurora Dr,Orlando,Orange,FL,3/1/2000,32804,407-413-4842,407-557-8857,chauncey_motley#aol.com,http://www.affiliatedwithtravelodge.com
"""
rows = empRecords.strip().split(";")
data = [ r.strip().split(",") for r in rows ]
then you can use any condition to filter the list, like
print ( [ "Name: " + emp[1] + "," + emp[0] + "| Current City: " + emp[3] for emp in data if emp[3] == "Washington" ] )
['Name: Hixenbaugh,Alesia| Current City: Washington']

Python: Search for string from dictionaryCSV file and display matching rows

I have this program right now where it allows users to choose from a category(pulling from the file). Then it will print the University data using dictionary.
What I want to do next on my code is for users to search for a specific string from that file and it will display all of the keys. It can be the whole word or part of the string from that file.
I need help on searching for a given string or part of a string and display matching categories (NameID, StudentName, University, Phone, State).
Example:
search: on
output: (Note: that this is in dictionary format)
{'NameID': 'JSNOW', ' StudentName': ' Jon Snow', ' University': ' UofWinterfell', ' Phone': ' 324234423', ' State': 'Westeros'}
{'NameID': 'JJONS', ' StudentName': ' Joe Jonson', ' University': ' NYU', ' Phone': ' 123432333', ' State': 'New York'}
My text file looks like this:
NameID, StudentName, University, Phone, State
JJONS, Joe Jonson, NYU, 123432333, New York
SROGE, Steve Rogers, UofI, 324324423, New York
JSNOW, Jon Snow, UofWinterfell, 324234423, Westeros
DTARG, Daenerys Targaryen, Dragonstone, 345345, NULL
This is what I have so far:
import csv
def load_data(file_name):
university_data=[]
with open("file.csv", mode='r') as csv_file:
csv_reader = csv.DictReader(csv_file, skipinitialspace=True)
for col in csv_reader:
university_data.append(dict(col))
print(university_data)
return university_data
# def search_file():
# for l in data:
# no idea what to do here
def main():
filename='file.csv'
university_data = load_data(filename)
print('[1] University\n[2] Student Name\n[3] Exit\n[4] Search')
while True:
choice=input('Enter choice 1/2/3? ')
if choice=='1':
for university in university_data:
print(university['University'])
elif choice=='2':
for university in university_data:
print(university['StudentName'])
elif choice =='3':
print('Thank You')
break
elif choice =='4':
search_file()
else:
print('Invalid selection')
main()
I need choice 4 to work. I would ignore the choice 1 and 2 because they just display the names and is not in dictionary format.

You have to figure out which field you are searching by and then iterate over the list of dicts.
def search_file(field, query):
for l in data:
if l.get(field, None) == query:
return l

How to print list of lists without extra brackets and quotes?

I'm working on assignment for my Python 3 programming class. It's a database to look up movies and the year they came out. However, I'm having a hard time printing the output without extra brackets and quotes:
# Build a dictionary containing the specified movie collection
list_2005 = [["Munich", "Steven Spielberg"]]
list_2006 = [["The Departed", "Martin Scorsese"], ["The Prestige", "Christopher Nolan"]]
list_2007 = [["Into the Wild", "Sean Penn"]]
movies = {
'2005': list_2005,
'2006': list_2006,
'2007': list_2007
}
# Prompt the user for a year
# Displaying the title(s) and directors(s) from that year
user_year = str(input("Enter a year between 2005 and 2007:\n"))
if user_year in movies:
for name in movies[user_year]:
print("%s" % ', '.join(name))
print()
elif user_year not in movies:
print("N/A")
# Display menu
user_choice = ''
while user_choice != 'q':
print("MENU\nSort by:\ny - Year\nd - Director\nt - Movie title\nq - Quit")
print()
user_choice = str(input("Choose an option:\n"))
if user_choice == 'y':
for key, value in sorted(movies.items()):
print("%s:" % key)
print(" %s" % ''.join(str(movies[key])))
# Carry out the desired option: Display movies by year,
# display movies by director, display movies by movie title, or quit
I would like this output to be:
2005:
Munich, Steven Spielberg
2006:
The Prestige, Christopher Nolan
The Departed, Martin Scorsese
etc.
The output I am getting:
2005:
['Munich', 'Steven Spielberg']
2006:
[['The Prestige', 'Christopher Nolan'], ['The Departed', 'Martin Scorsese']]
etc.

Replace
print(" %s" % ''.join(str(movies[key])))
with
print("\t" + '\n\t'.join("{}, {}".format(m[0], m[1]) for m in movies[key]))

How to read a particular line of interest from a text file?

Here I have a text file. I want to read Adress, Beneficiary, Beneficiary Bank, Acc Nbr, Total US$, Date which is at the top, RUT, BOX. I tried writing some code by myself but I am not able to correctly get the required information and moreover if the length of character changes I will not get correct output. How should I do this such that I will get every required information in a particular string.
The main problem will arise when my slicings will go wrong. For eg: I am using line[31:] for Acc Nbr. But if the address change then my slicing will also go wrong
My Text.txt
2014-11-09 BOX 1531 20140908123456 RUT 21 654321 0123
Girry S.A. CONTADO
G 5 Y Serie A
NO 098765
11 al Rayo 321 - Oqwerty 108 Monteaudio - Gruguay
Pharm Cosco, Inc - Britania PO Box 43215
Dirección Hot Springs AR 71903 - Estados Unidos
Oescripción Importe
US$
DO 7640183 - 50% of the Production Degree 246,123
Beneficiary Bank: Bankue Heritage (Gruguay) S.A Account Nbr: 1234563 Swift: MANIUYMM
Adress: Tencon 108 Monteaudio, Gruguay.
Beneficiary: Girry SA Acc Nbr: 1234567
Servicios prestados en el exterior, exentos de IVA o IRAE
Subtotal US$ 102,500
Iva US$ ---------------
Total US$ 102,500
I.V.A AL DIA Fecha de Vencimiento
IMPRENTA IRIS LTDA. - RUT 210161234015 - 0/40987 17/11/2015
CONSTANCIA N9 1234559842 -04/2013
CONTADO A 000.001/ A 000.050 x 2 VIAS
QWERTYAS ZXCVBIZADA
R. U.T. Bamprador Asdfumldor Final
Fecha 12/12/2014
1º ORIGINAL CLLLTE (Blanco) 2º CASIA AQWERVO (Rosasd)
My Code:
txt = 'Text.txt'
lines = [line.rstrip('\n') for line in open(txt)]
for line in lines:
if 'BOX' in line:
Date = line.split("BOX")[0]
BOX = line.split('BOX ', 1)[-1].split("RUT")[0]
RUT = line.split('RUT ',1)[-1]
print 'Date : ' + Date
print 'BOX : ' + BOX
print 'RUT : ' + RUT
if 'Adress' in line:
Adress = line[8:]
print 'Adress : ' + Adress
if 'NO ' in line:
Invoice_No = line.split('NO ',1)[-1]
print 'Invoice_No : ' + Invoice_No
if 'Swift:' in line:
Swift = line.split('Swift: ',1)[-1]
print 'Swift : ' + Swift
if 'Fecha' in line and '/' in line:
Invoice_Date = line.split('Fecha ',1)[-1]
print 'Invoice_Date : ' + Invoice_Date
if 'Beneficiary Bank' in line:
Beneficiary_Bank = line[18:]
Ben_Acc_Nbr = line.split('Nbr: ', 1)[-1]
print 'Beneficiary_Bank : ' + Beneficiary_Bank.split("Acc")[0]
print 'Ben_Acc_Nbr : ' + Ben_Acc_Nbr.split("Swift")[0]
if 'Beneficiary' in line and 'Beneficiary Bank' not in line:
Beneficiary = line[13:]
print 'Beneficiary : ' + Beneficiary.split("Acc")[0]
if 'Acc Nbr' in line:
Acc_Nbr = line.split('Nbr: ', 1)[-1]
print 'Acc_Nbr : ' + Acc_Nbr
if 'Total US$' in line:
Total_US = line.split('US$ ', 1)[-1]
print 'Total_US : ' + Total_US
Output:
Date : 2014-11-09
BOX : 1531 20140908123456
RUT : 21 654321 0123
Invoice_No : 098765
Swift : MANIUYMM
Beneficiary_Bank : Bankue Heritage (Gruguay) S.A
Ben_Acc_Nbr : 1234563
Adress : Tencon 108 Monteaudio, Gruguay.
Beneficiary : Girry SA
Acc_Nbr : 1234567
Total_US : 102,500
Invoice_Date : 12/12/2014
Some Code Changes
I have made some changes but still I am not convinced as I need to provide spaces also in split.

I would recommend you to use regular expressions to extract information you need. It helps to avoid the calculation of the numbers of offset characters.
import re
with open('C:\Quad.txt') as f:
for line in f:
match = re.search(r"Acc Nbr: (.*?)", line)
if match is not None:
Acc_Nbr = match.group(1)
print Acc_Nbr
# etc...

you can search to obtain index of it. for example:
if 'Acc Nbr' in line:
Acc_Nbr = line[line.find("Acc Nbr") + 10:]
print Acc_Nbr
note that find gives you index of first char of item you searched.

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