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How can I convert ASCII strings to Hex strings in Python ? Is there any built in function I can use for this ?
It depends on exactly what you mean by "ASCII to hex", but you should be able to adapt this approach to get whatever you're looking for:
>>> foo = "foo"
>>> ''.join(hex(ord(c))[2:] for c in foo)
'666f6f'
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I need help with python. How can I separate combine word into two words. At the first we don't know what kind of words could be? so we must enter a string at the input (v="") and then that word must be separate. For example we have "AMnidcrheaal" and in output will be "Andrea" and "Michal".
According to the output you gave, you want to separate odd and even indices words which can be done as follows
v="AMnidcrheaal"
even=""
odd=""
for i in range(len(v)):
if i%2==0:
even+=v[i]
else:
odd+=v[i]
print(odd)
print(even)
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I have column with this kind of data:
I want to count how many times valu occur in a row. It is a string, so I want to convert this '63,63,63,63,63,63,63,63,63,63,63' to this ['63','63','63'...].
I there any way to do this quickly?
Thanks
if given string is s
l=s.split(',')
l is the required list
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Suppose I have the some code in which I used map() function.
I know I can later print it by converting it to list just like this :
get_something = map(some_function, some_list)
print(list(get_something))
But Is there any way other than list. I mean what if I want to print not as list but line by line and don't want to use for loop every now and then?
Why dont you try this:
print(*map(some_function, some_list),sep='\n')
By this print() will refer to map object and will print values with \n as a separator
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Tetravocalic: Find all words that include four consecutive vowels.
def Tetravocalic(i):
return(re.search("/\b.*[aeiou]+.*[aeiou]+.*[aeiou]+.*[aeiou]+{4}/\b",i)))
Tetravocalic("vajjekiohkkugh")
error: multiple repeat at position 42
Please let me know the meaning of the error and the correct code as well.
ex: Tetravocalic("vajjekiohkkugh apple ororaeeg")
Your regular expression is way too complex, you only need this :'[aeiou]{4}'.
Example code:
def has_four_consecutive_vowels(s):
return bool(re.search('[aeiou]{4}', s))
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I need to find a word "little" in a string but word in the string is not present as a whole.
For eg. input string="aalbeiedteetoolpue" or "lliittttllleee"
May be you can try this:
\b\w*l\w*i\w*t\w*t\w*l\w*e\w*\b
Demo