I am trying to replicate another researcher's findings by using the Python file that he added as a supplement to his paper. It is the first time I am diving into Python, so the error might be extremely simple to fix, yet after two days I haven't still. For context, in the Readme file there's the following instruction:
"To run the script, make sure Python2 is installed. Put all files into one folder designated as “cf_dir”.
In the script I get an error at the following lines:
if __name__ == '__main__':
cf_dir, cf_file, cf_phys_file = sys.argv[1:4]
os.chdir(cf_dir)
cf = pd.read_csv(cf_file)
cf_phys = pd.read_csv(cf_phys_file)
ValueError: need more than 0 values to unpack
The "cf_file" and "cf_phys_file" are two major components of all files that are in the one folder named "cf_dir". The "cf_phys_file" relates only to two survey question's (Q22 and Q23), and the "cf_file" includes all other questions 1-21. Now it seems that the code is meant to retrieve those two files from the directory? Only for the "cf_phys_file" the columns 1:4 are needed. The current working directory is already set at the right location.
The path where I located "cf_dir" is as follows:
C:\Users\Marc-Marijn Ossel\Documents\RSM\Thesis\Data\Suitable for ML\Data en Artikelen\Per task Suitability for Machine Learning score readme\cf_dir
Alternative option in readme file,
In the readme file there's this option, but also here I cannot understand how to direct the path to the right location:
"Run the following command in an open terminal (substituting for file names
below): python cfProcessor_AEAPnP.py cf_dir cf_file cf_phys_file task_file jobTaskRatingFile
jobDataFile OESfile
This should generate the data and plots as necessary."
When I run that in "Command Prompt", I get the following error, and I am not sure how to set the working directory correctly.
- python: can't open file 'cfProcessor_AEAPnP.py': [Errno 2] No such file or directory
Thanks for the reading, and I hope there's someone who could help me!
Best regards & stay safe out there during Corona!!
Marc
cf_dir, cf_file, cf_phys_file = sys.argv[1:4]
means, the python file expects few arguments when called.
In order to run
python cfProcessor_AEAPnP.py cf_dir cf_file cf_phys_file task_file jobTaskRatingFile jobDataFile OESfile
the command prompt should be in that folder.
So, open command prompt and type
cd path_to_the_folder_where_ur_python_file_is_located
Now, you would have reached the path of the python file.
Also, make sure you give full path in double quotes for the arguments.
Related
When I try to write something, such as variables, the code is renamed to the file name on the computer.
For example, if I write:
a = 20
f = 15
print(a+f)
then the code file will automatically be renamed to the first line, i.e. "a = 20"
Then, when I try to run the code, the program outputs nothing but "Python" and some incomprehensible words.
What could it be related to?
enter image description here
enter image description here
I installed the latest version of Visual Stuio Code with Python, they are new, so there should be no problems. But this time it went wrong.
After reinstalling the program, the problem remains.
First of all, if there is no special requirement, please do not use Code Runner to run the script, using the official extension Python is a better choice.
In addition, the dot on your file label means that you have not saved the file, you can add the following setting to enable automatic saving in the settings.
"files.autoSave": "afterDelay",
You may have created the file using the following method. File --> New File... --> Python File. At this time, the file has not been named, also not saved. You can see that there is no such file in the resource manager list at this time.
So the file label shows the first line of codes. This is a feature of vscode, you can refer to this link. And because the file has not been saved, there will be problems executing the script.
You can rename the script file directly (F2), or vscode will remind you to name the file when saving. Another way to create a file is to right click and choose New File..., enter filename and end with .py extension.
I'm following the tutorial here to convert MacJournal journal entries to DayOne journal entries: https://basilsalad.com/how-to/migrate-mac-journal-day-one/
And I am having issues on the very last part.
I moved my MacJournal exported text file to the same directory as MacJournalToDayOne.py so in terminal, when I run the command "ls" it lists the python file and the MacJournal file which is "dreams.txt" in the same directory.
Everything works fine up until this part here:
./MacJournalToDayOne.py "${export-file}" --journal="${journal-name}"
When I add in the file names and the journal I want to import into, I run it as:
./MacJournalToDayOne.py "${dreams.txt}" --journal="${MJImport}"
Which gives the error: -bash: ${dreams.txt}: bad substitution
What am I doing wrong here?
I am new at python and learning the language. The following code should create a file in the running program directory and write to it but it doesn't do this at all in a .py file. If I put the same code in the IDLE shell it returns 17. No errors just doesn't create the file. What am I doing wrong?
with open("st.txt", "w") as f:
f.write("Hi from Python!")
Thanks for the help
Mike
This code is flawless, no problem!
I guess that in your REPL shell, the $PWD environment variable is set for somewhere, so your destination file is in some corner.
No exception thrown indicates that no problem with access authority.
Maybe you can set some absolute path string, such as ~/st.txt
By the way, the successful invoke should return 15 instead of 17, totally count 15 chars.
your code works well, st.txt will be touched at executing path.
other ways, your system account can't write in your execute path.
try in your $HOME path to execute your code, I think, It will work well
I'm following along with the examples in a translated version of Wes McKinney's "Python for Data Analysis" and I was blocked in first example of Chapter 2
I think my problem arose because I saved a data file in a wrong path. is that right?
I stored a file, usagov_bitly_data2012-03-16-1331923249.txt, in C:\Users\HRR
and also stored folder, pydata-book-mater, that can be downloaded from http://github.com/pydata-book in C:\Users\HRR\Anaconda2\Library\bin.
Depends.
You might change the location you save your File or eddit the path you give to your code in Line 10. Since you're yousing relativ Paths i guess your script runs in C:\Users\HRR\Anaconda2\Library\bin, which means you have to go back to C:\Users\HRR or use an absolute Path ... or move the File, but hell you don't want to move a file every time you want to open it, like moving word files into msoffice file to open it, so try to change the Path.
And allways try harder ;)
In python open() will open from the current directory down unless given a full path (in linux that starts with / and windows <C>://). In your case the command is open the folder ch02 in the directory the script is running from and then open usagov_bitly_data2012-03-16-1331923249.txt in that folder.
Since you are storing the text file in C:\Users\HRR\usagov_bitly_data2012-03-16-1331923249.txt and you did not specify the directory of the script. I recommend the following command instead open(C:\\Users\\HRR\\usagov_bitly_data2012-03-16-1331923249.txt)
Note: the double \ is to escape the characters and avoid tabs and newlines showing up in the path.
I am attempting to run this .PY file from Command Prompt:
# Merge two .BSG files
# Starting block and world position are taken from the first file
# Example: "bsgmerge input.bsg output.bsg merged.bsg"
import io, sys
one = open(sys.argv[1]).readlines()
two = open(sys.argv[2]).readlines()
for n in [1,3,5,7,9,11,17,19,21,23]:
one[n] = one[n][:-1]+"|"+two[n].partition("|")[2]
open(sys.argv[3],"w").write("".join(one))
It is a program that takes a creation from the game Beseige and merges it with another saved creation so that opening the merged file results in both creations being present. If you want more details, you can read up on that here.
I am having trouble figuring out how to call this program from the command line. At first I thought the problem was me having Python 2 (it requires Python 3), so I uninstalled 2 and installed 3. This did not help.
What I am doing is entering the "python" command to pull up the Python environment within CMD, then entering the command to call the program based on the third comment in the file ("bsgmerge input.bsg output.bsg merged.bsg").
I tried using full file paths or simply changing to the correct directory before typing the "python" command and using only the file names, but so far I've had no luck.
When I am in the correct directory, then enter the Python environment, typing the command "bsgmerge 1.bsg 2.bsg M.bsg" (my existing files to be merged are 1.bsg and 2.bsg), this error occurs:
File "<stdin>", line 1
bsgmerge 1.bsg 2.bsg M.bsg
^
SyntaxError: invalid syntax
I took a Python course (which is why I used to have Python 2 on my machine) last fall, so I noticed that there is no "def" defining a function in the above code, which is something I've never encountered, so I'm thinking that is the root of my problems.
Thanks in advance for the help.
I was probably same problem with python launcher.
If you use Linux, first line shoud be:
#! /path/to/your/python/3
In Windows it some more complicated:
In registry by regedit change
HKEY_CLASSES_ROOT\Python.File\shell\open\command from "C:\Python27\python.exe" "%1" %* to "C:\Windows\py.exe" "%1" %*.
And first line of script shoud be:
#! python3
Now it shoud work properly.