How do I use stereoscopy in IDLE/Python? - python

I have downloaded and installed the stereoscopy library. I know how to execute the program via command line as it shows clearly here: https://pypi.org/project/stereoscopy/#description
However, i looked at its code and I wanted to do it myself. I want to insert the code from: https://github.com/2sh/StereoscoPy/blob/master/stereoscopy/init.py and see if it works there.
I copied the code and when I run it, nothing happens. No errors or anything, but no picture shows up and no picture is saved.
So I would like to learn how to use this library to make my own anaglyph pictures by coding it myself and not use the command line executable.
Thank you for your help :)

Running StereoscoPy from a command line executes stereoscopy.__main__, which mainly consists of
from . import _main
_main()
_main is imported from _init.py. The latter defines some constants, classes, and functions, including _main, but does not call any of them. You need to do what __main__.py does, call _main, after stuffing arguments into sys.argv. One way to do the latter is to use sys.argv = shlex.split(cli_string, posix=True) where cli_string is the string that would be typed at a command line.

Related

Load and execute a full python script from a raw link?

I'm facing some problems trying to load a full python script from my pastebin/github pages.
I followed this link, trying to convert the raw into a temp file and use it like a module: How to load a python script from a raw link (such as Pastebin)?
And this is my test (Using a really simple python script as raw, my main program is not so simple unfortunately): https://trinket.io/python/0e95ba50c8
When I run the script (that now is creating a temp file in the current directory of the .py file) I get this error:
PermissionError: [Errno 13] Permission denied: 'C:\\Users\\BOT\\Images\\tempxm4xpwpz.py'
Otherwise I also treid the exec() function... No better results unfortunately.
With this code:
import requests as rq
import urllib.request
def main():
code = "https://pastebin.com/raw/MJmYEKqh"
response = urllib.request.urlopen(code)
data = response.read()
exec(data)
I get this error:
File "<string>", line 10, in <module>
File "<string>", line 5, in hola
NameError: name 'printest' is not defined
Since my program is more complex compared to this simple test, I don't know how to proceed...
Basically What I want to achieve is to write the full script of my program on GitHub and connect it to a .exe so if I upgrade the raw also my program is updated. Avoiding to generate and share (only with my friends) a new .exe everytime...
Do you think is possible? If so.. what am I doing wrong?
PS: I'm also open to other possibilities to let my friends update the program without downloading everytime the .exe, as soon as they don't have to install anything (that's why I'm using .exe).
Disclaimer: it is really not a good idea to run an unverified (let alone untrusted) code. That being said if you really want to do it...
Probably the easiest and "least-dirty" way would be to run whole new process. This can be done directly in python. Something like this should work (inspiration from the answer you linked in your question):
import urllib.request
import tempfile
import subprocess
code = "https://pastebin.com/raw/MJmYEKqh"
response = urllib.request.urlopen(code)
data = response.read()
with tempfile.NamedTemporaryFile(suffix='.py') as source_code_file:
source_code_file.write(data)
source_code_file.flush()
subprocess.run(['python3', source_code_file.name])
You can also make your code with exec run correctly:
What may work:
exec(data, {}) -- All you need to do, is to supply {} as second argument (that is use exec(data, {})). Function exec may receive two additional optional arguments -- globals and locals. If you supply just one, it will use the same directory for locals. That is the code within the exec would behave like sort-of "clean" environment, at the top-level. Which is something you aim for.
exec(data, globals()) -- Second option is to supply the globals from your current scope. This will also work, though you probably has no need to give the execucted code access to your globals, given that that code will set-up everything inside anyway
What does not work:
exec(data, {}, {}) -- In this case the executed code will have two different dictionaries (albeit both empty) for locals and globals. As such it will behavie "as-in" (I'm not really sure about this part, but as I tested it, it seams as such) the function. Meaning that it will add the printest and hola functions to the local scope instead of global scope. Regardless, I expected it to work -- I expected it will just query the printest in the hola function from the local scope instead of global. However, for some reason the hola function in this case gets compiled in such a way it expects printest to be in global scope and not local, which is not there. I really did not figured out why. So this will result in the NameError
exec(data, globals(), locals()) -- This will provide access to the state from the caller function. Nevertheless, it will crash for the very same reason as in the previous case
exec(data) -- This is just a shorthand for exec(data, globals(), locals()

Using subprocess in Python, I get different results when in Python cmd and Python IDLE

I hope the title makes sense. To give specifics:
I am using csvtotable (https://github.com/vividvilla/csvtotable) to generate HTML tables from CSVs. I have installed via pip and am able to run a command line command:
csvtotable test1743.csv test1743.html
to generate a HTML page. All good so far.
I wanted to do this from within a Python script I had already written so I heard that subprocess was the way to do this. I looked up how to do it and understood that it can be done using the following:
subprocess.run('csvtotable test1743.csv test1743.html',shell=True)
So I tested this via the command line first by doing
python
from the command line and then running
import subprocess
subprocess.run('csvtotable test1743.csv test1743.html',shell=True)
Success! It worked. Fantastic.
However, when I try to do this from IDLE, it just returns a 1. I have checked the directory thinking that maybe the csv was missing from there, but it still doesn't work.
Am I misunderstanding how subprocess works?
Solved by finding a way to call the function without subprocess. I think the issue may have related to default arguments not being set when it is executed through python and hence why below I have had to specify so many arguments.
Code:
from csvtotable import convert
content = convert.convert("C:\\Users\\admin\\Google Drive\\test1743.csv",delimiter=",",quotechar='"',display_length=-1,overwrite=False,serve=False,pagination=True,virtual_scroll=1000, no_header=False, export=True, export_options=["copy","csv","json","print"])
convert.save("C:\\Users\\admin\\Google Drive\\test1743.html",content)
Note that the argument names had to be changed where they had a - in the name. I just changed any instance e.g. display-length to display_length in convert.py

breakpoint on all files from a certain directory

I like to use ipdb to debug my code. I know we could stop the code on a file on a specific line with b(reak) file:lineno. That command will set a breakpoint in file at line 'no'.
Actually, I have inserted import ipdb; ipdb.set_trace() on a specific file. Each time I use the command s(tep), it executes and step into functions. My problem is it is too slow before seeing what I want to see. The stacktrace showed me lines I do not necessarily want to see. Then I was thinking to put a breakpoint on all files from a certain directory, i.e., b mydirectory/**. Therefore, eachtime I will execute c, it will show me all lines I want to see. However, I can't execute such command (i.e., b mydirectory/**). Could anyone have a solution to this problem?
Thanks!
P.S. The following picture show ton of those irrelevant files I don't want to see. In fact, it is normal to see those files, because I am working on a django project.
Please tell me if the question is unclear
import pdb; pdb.Pdb(skip=['mydirectory.*']).set_trace()
mydirectory have to be a python module, here is more info from the documentaion
The skip argument, if given, must be an iterable of glob-style module
name patterns. The debugger will not step into frames that originate
in a module that matches one of these patterns. [1]
source: https://docs.python.org/2/library/pdb.html#pdb.Pdb

How to access the calling source line from interactive shell

I want to make a function that can determine the source code of how it was called. I'm aware of how to do this generally with the inspect module. For example, this question, works well and provides my desired output in the lines variable as shown below:
def hello(x):
frame,filename,line_number,function_name,lines,index=\
inspect.getouterframes(inspect.currentframe())[1]
print(frame,filename,line_number,function_name,lines,index)
The problem is that this solution doesn't work in an interactive command line session. For example, from a command line, the result looks like:
>>> y = hello(7)
(<frame object at 0x01ECA9E8>, '<stdin>', 1, '<module>', None, None)
The problem is that the source file is '<stdin>', so the lines variable is None. How can I access the calling line to find the result containing the string y = hello(7) during an interactive session?
It may not be possible, as #abarnert says. There are at least partial workarounds, however.
Getting source code lines isn't the biggest problem; modules like readline keep track of them. Interactive Python and iPython expose their lines slightly differently (sigh), but that too can be equalized. (My show package, for example, does this; its linecacher module puts a veneer on to equalize source access for normal Python and the different interactive flavors.)
The bigger problem is that, even once you have the source code, inspect doesn't provide legitimate line numbers (e.g. inspect.currentframe().f_back.f_lineno works great in normal code, but gives values like 1 or the point of the call in <stdin> when called interactively.)
But I'm not quite ready to call it impossible. Based on tracebacks generated by interactive Python and iPython, it appears that there may be sufficient information available to reconstruct "where did this call come from?" How much effort that would take, and how robust the answers would be...those are open questions.

How do I execute all the code inside a python file?

How do I execute all the code inside a python file so I can use def's in my current code? I have about 100 scripts that were all written like the script below.
For a simple example, I have a python file called:
D:/bt_test.py
His code looks like this:
def bt_test():
test = 2;
test += addFive(test)
return(test)
def addFive(test):
return(test+5)
Now, I want to from a completely new file, run bt_test()
I've tried doing this:
def openPyFile(script):
execfile(script)
openPyFile('D:/bt_test.py')
bt_test()
But this doesn't work.
I've tried doing this as well:
sys.path.append('D:/')
def openPyFile(script):
name = script.split('/')[-1].split('.')[0]
command = 'from ' + name + ' import *'
exec command
openPyFile('D:/bt_test.py')
bt_test()
Does anyone know why this isn't working?
Here's a link to a quicktime video that will help explain what's happening.
https://dl.dropbox.com/u/1612489/pythonHelp.mp4
You should put those files somewhere on your Python path, and then import them. That's what the import statement is for. BTW: the same directory as your main program is on the Python path, that could be a good place to put them.
# Find and execute bt_test.py, and make a module object of it.
import bt_test
# Use the bt_test function in the bt_test module.
bt_test.bt_test()
The reason that execfile doesn't work is because the functions inside bt_test are limited by the scope of the openPyFile function. One simple test would be to try to run bt_test() from inside openPyFile. Since openPyFile doesn't really do anything other than execfile you could get rid of it altogether, or you could alias execfile
openPyFile=execfile
Note putting the file in your python path and importing it is definitely your best bet -- I only post this answer here to hopefully point out why you're not seeing what you want to see.
In addition to Ned's answer, __import__() might be useful if you don't want the file names hardcoded.
http://docs.python.org/library/functions.html#__import__
Update based on the video.
I don't have access to Maya, but i can try and speculate.
cmds.button(l='print', c='bt_press()') is where the issue seems to lurk. bt_press() is passed as a string object, and whatever way the interpreter uses to resolve that identifier doesn't look in the right namespace.
1) Try passing bt_press() with the module prepended: cmds.button(l='print', c='bt_test.bt_press()')
2) See if you can bind c directly to the function object: cmds.button(l='print', c=bt_press)
Good luck.
>>> from bt_test import bt_test
>>> bt_test()

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