Python Sleep Function Issue [duplicate] - python

I am trying to delete text inside a text box after waiting 5 seconds, but instead the program wont run and does sleep over everything else. Also is there a way for me to just make my textbox sleep so i can run other code while the text is frozen?
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.insert(END, 'This is a test')
sleep(5)
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
empty_textbox()
root.mainloop()

You really should be using something like the Tkinter after method rather than time.sleep(...).
There's an example of using the after method at this other stackoverflow question.
Here's a modified version of your script that uses the after method:
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
textbox.insert(END, 'This is a test')
textbox.after(5000, empty_textbox)
root.mainloop()

You can emulate time.sleep in tkinter. For this we still need to use the .after method to run our code alongside the mainloop, but we could add readability to our code with a sleep function. To add the desired behavior, tkinter provides another underestimated feature, wait_variable. wait_variable stops the codeblock till the variable is set and thus can be scheduled with after.
def tksleep(t):
'emulating time.sleep(seconds)'
ms = int(t*1000)
root = tk._get_default_root('sleep')
var = tk.IntVar(root)
root.after(ms, var.set, 1)
root.wait_variable(var)
Real world examples:
update a Label to display a clock while-loop
animated writing nested for-loops
Limitation:
tkinter does not quit while tksleep is used.
Make sure there is no pending tksleep by exiting the application.
Using tksleep casually can lead to unintended behavior
UPDATE
TheLizzard worked out something superior to the code above here. Instead of tkwait command he uses the mainloop and this overcomes the bug of not quitting the process as described above, but still can lead to unintended output, depending on what you expect:
import tkinter as tk
def tksleep(self, time:float) -> None:
"""
Emulating `time.sleep(seconds)`
Created by TheLizzard, inspired by Thingamabobs
"""
self.after(int(time*1000), self.quit)
self.mainloop()
tk.Misc.tksleep = tksleep
# Example
root = tk.Tk()
root.tksleep(2)

Related

How do I keep a label changed for just a few seconds [duplicate]

I am trying to delete text inside a text box after waiting 5 seconds, but instead the program wont run and does sleep over everything else. Also is there a way for me to just make my textbox sleep so i can run other code while the text is frozen?
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.insert(END, 'This is a test')
sleep(5)
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
empty_textbox()
root.mainloop()
You really should be using something like the Tkinter after method rather than time.sleep(...).
There's an example of using the after method at this other stackoverflow question.
Here's a modified version of your script that uses the after method:
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
textbox.insert(END, 'This is a test')
textbox.after(5000, empty_textbox)
root.mainloop()
You can emulate time.sleep in tkinter. For this we still need to use the .after method to run our code alongside the mainloop, but we could add readability to our code with a sleep function. To add the desired behavior, tkinter provides another underestimated feature, wait_variable. wait_variable stops the codeblock till the variable is set and thus can be scheduled with after.
def tksleep(t):
'emulating time.sleep(seconds)'
ms = int(t*1000)
root = tk._get_default_root('sleep')
var = tk.IntVar(root)
root.after(ms, var.set, 1)
root.wait_variable(var)
Real world examples:
update a Label to display a clock while-loop
animated writing nested for-loops
Limitation:
tkinter does not quit while tksleep is used.
Make sure there is no pending tksleep by exiting the application.
Using tksleep casually can lead to unintended behavior
UPDATE
TheLizzard worked out something superior to the code above here. Instead of tkwait command he uses the mainloop and this overcomes the bug of not quitting the process as described above, but still can lead to unintended output, depending on what you expect:
import tkinter as tk
def tksleep(self, time:float) -> None:
"""
Emulating `time.sleep(seconds)`
Created by TheLizzard, inspired by Thingamabobs
"""
self.after(int(time*1000), self.quit)
self.mainloop()
tk.Misc.tksleep = tksleep
# Example
root = tk.Tk()
root.tksleep(2)

Tkinter unbinding key event issue

In the code below, pressing the space bar twice results in two successive beeps. I want to avoid this and instead disable the key while the first beep is happening. I thought unbinding the space key might work, but it doesn't. It's strange that only two beeps seem to stack up rather than more. I'm guessing maybe the cause of the issue is that winsound.Beep is non-blocking so the rebinding occurs almost instantly.
Any suggestion on how to get this to work please?
import winsound
from tkinter import *
def beep(e):
frame.unbind("<space>")
winsound.Beep(440, 1000)
frame.bind("<space>", beep)
root = Tk()
frame = Frame(root, width=100, height=100)
frame.bind("<space>", beep)
frame.pack()
frame.focus_set()
root.mainloop()
Here is a solution that takes the focus away from the widget, so the binding wont get triggered:
import winsound
from tkinter import *
def beep(event):
dummy.focus_set() #setting focus to dummy
winsound.Beep(440, 1000) #playing it
root.after(1000,frame.focus_set) #setting focus back after playing for 1000 ms
root = Tk()
dummy = Label() #making a dummy widget
dummy.pack()
frame = Frame(root, width=100, height=100)
frame.bind("<space>",beep)
frame.pack()
frame.focus_set()
root.mainloop()
I've commented it to understand better, but this is just a way around and its not that complicated to understand either.
Also keep in mind, in all cases of using winsound, as long as that beep has started and finished playing, the GUI will be unresponsive, that is, GUI will be unresponsive for 1 sec(in your case).
This should fix it however you have to download keyboard module with pip install keyboard :
import winsound
from tkinter import *
import keyboard
from _thread import start_new_thread
def beep():
while True:
if keyboard.is_pressed('space'):
winsound.Beep(440, 1000)
root = Tk()
frame = Frame(root, width=100, height=100)
start_new_thread(beep, ())
frame.pack()
frame.focus_set()
root.mainloop()
First start_new_thread()(syntax is important) makes beep() threaded (runs in background?) and its a while loop so it runs continuously and whenever you press space it will beep and even if you spam space it will still just run one beep. However there is a downside. It will run while script is not terminated so if you focus out it will still beep if you press spacebar
You can use the elapsed time since the last successful keypress to decide if the beep should be produced or not.
maybe like this: I do not have access to winsound, so I am using an os feature to mimic a beep. You can comment this out, and uncomment the calls to winsound
# import winsound
import os
import tkinter as tk
import time
def beep(e, time_limit=1, timer=[0]):
t0 = timer[0]
t1 = time.time()
delta_t = t1 - t0
if delta_t < time_limit:
return
# winsound.Beep(440, 1000)
os.system('say "Beep"')
timer[0] = t1
root = tk.Tk()
frame = tk.Frame(root, width=100, height=100)
frame.bind("<space>", beep)
frame.pack()
frame.focus_set()
root.mainloop()
You can bind back the event via after_idle():
def beep(e):
e.widget.unbind('<space>')
winsound.Beep(440, 1000)
e.widget.after_idle(e.widget.bind, '<space>', beep)
explanation:
The callback passed to after_idle() will be executed when tkinter mainloop is idle, i.e. no pending works/events to be handled. So if the spacebar is pressed many times, the first press triggers beep() in which tkinter unbinds the event, beep and then schedules the rebind. After beep() returns, tkinter keeps handling the pending tasks, i.e. handle the rest spacebar events (but at that moment, no bind is active) and then do the after_idle schedule task which is the rebind.

Python Tkinter Closing Windows [duplicate]

This question already has answers here:
Why is my Button's command executed immediately when I create the Button, and not when I click it? [duplicate]
(5 answers)
Closed 2 years ago.
In creating a Python Tkinter program, I wish to create a button that will close the program. I have tried the
#with master = Tk()
master.quit()
method. And it did absolutely nothing to my program - apart from stopping anything from working, although I received no Tracebacks.
The other method I have tried is:
#with master = Tk()
master.destroy()
This again did nothing to my program - it did give me a traceback error though which was:
_tkinter.TclError: can't invoke "button" command: application has been destroyed
My full code is:
from tkinter import *
master = Tk()
exitbutton = Button(master,text="Exit",(all the other personalization stuff here),command=(master.quit()))
#or I used master.destroy() in the command area.
exitbutton.grid(column=0,row=0)
None of the above methods have worked.
Many Thanks
(For the future)
You must pass the function's name rather than as a callable:
from tkinter import *
master = Tk()
exitbutton = Button(master,text="Exit",command=master.destroy)##dont include the parentheses
##or I used master.destroy() in the command area.
exitbutton.grid(column=0,row=0)
This should fix your problem.
Problem:
The only problem is that you are using parentheses() while passing the function(exit or destroy) to the Button as a command, Which causes it to be executed at the point where it is defined.
Solution:
The solution is to remove the parentheses() while passing the function(exit or destroy) to the Button as a command.
Fixed Code:
from tkinter import *
master = Tk()
exitbutton = Button(master, text="Exit", command=master.quit) # you can also use master.destroy
exitbutton.grid(column=0, row=0)
master.mainloop()
Tip:
As importing all(*) is not a good practice, you should import tkinter as tk
or as anything you want. The only change you will is to add tk. before each object belonging to tkinter.
Then your code will be as follows.
Best Practice:
import tkinter as tk
master = tk.Tk()
exitbutton = tk.Button(master, text="Exit", command=master.quit) # you can also use master.destroy
exitbutton.grid(column=0, row=0)
master.mainloop()
You want to pass a function object into the command keyword, so don't use parentheses. Also you should be using the destroy function for TKinter.
exitbutton = Button(master,text="Exit",(all the other personalization stuff here),command=master.destroy)

timer.sleep for loop inputs text into tkinter Text widget all at once instead of iterating [duplicate]

I am trying to delete text inside a text box after waiting 5 seconds, but instead the program wont run and does sleep over everything else. Also is there a way for me to just make my textbox sleep so i can run other code while the text is frozen?
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.insert(END, 'This is a test')
sleep(5)
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
empty_textbox()
root.mainloop()
You really should be using something like the Tkinter after method rather than time.sleep(...).
There's an example of using the after method at this other stackoverflow question.
Here's a modified version of your script that uses the after method:
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
textbox.insert(END, 'This is a test')
textbox.after(5000, empty_textbox)
root.mainloop()
You can emulate time.sleep in tkinter. For this we still need to use the .after method to run our code alongside the mainloop, but we could add readability to our code with a sleep function. To add the desired behavior, tkinter provides another underestimated feature, wait_variable. wait_variable stops the codeblock till the variable is set and thus can be scheduled with after.
def tksleep(t):
'emulating time.sleep(seconds)'
ms = int(t*1000)
root = tk._get_default_root('sleep')
var = tk.IntVar(root)
root.after(ms, var.set, 1)
root.wait_variable(var)
Real world examples:
update a Label to display a clock while-loop
animated writing nested for-loops
Limitation:
tkinter does not quit while tksleep is used.
Make sure there is no pending tksleep by exiting the application.
Using tksleep casually can lead to unintended behavior
UPDATE
TheLizzard worked out something superior to the code above here. Instead of tkwait command he uses the mainloop and this overcomes the bug of not quitting the process as described above, but still can lead to unintended output, depending on what you expect:
import tkinter as tk
def tksleep(self, time:float) -> None:
"""
Emulating `time.sleep(seconds)`
Created by TheLizzard, inspired by Thingamabobs
"""
self.after(int(time*1000), self.quit)
self.mainloop()
tk.Misc.tksleep = tksleep
# Example
root = tk.Tk()
root.tksleep(2)

tkinter and time.sleep

I am trying to delete text inside a text box after waiting 5 seconds, but instead the program wont run and does sleep over everything else. Also is there a way for me to just make my textbox sleep so i can run other code while the text is frozen?
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.insert(END, 'This is a test')
sleep(5)
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
empty_textbox()
root.mainloop()
You really should be using something like the Tkinter after method rather than time.sleep(...).
There's an example of using the after method at this other stackoverflow question.
Here's a modified version of your script that uses the after method:
from time import time, sleep
from Tkinter import *
def empty_textbox():
textbox.delete("1.0", END)
root = Tk()
frame = Frame(root, width=300, height=100)
textbox = Text(frame)
frame.pack_propagate(0)
frame.pack()
textbox.pack()
textbox.insert(END, 'This is a test')
textbox.after(5000, empty_textbox)
root.mainloop()
You can emulate time.sleep in tkinter. For this we still need to use the .after method to run our code alongside the mainloop, but we could add readability to our code with a sleep function. To add the desired behavior, tkinter provides another underestimated feature, wait_variable. wait_variable stops the codeblock till the variable is set and thus can be scheduled with after.
def tksleep(t):
'emulating time.sleep(seconds)'
ms = int(t*1000)
root = tk._get_default_root('sleep')
var = tk.IntVar(root)
root.after(ms, var.set, 1)
root.wait_variable(var)
Real world examples:
update a Label to display a clock while-loop
animated writing nested for-loops
Limitation:
tkinter does not quit while tksleep is used.
Make sure there is no pending tksleep by exiting the application.
Using tksleep casually can lead to unintended behavior
UPDATE
TheLizzard worked out something superior to the code above here. Instead of tkwait command he uses the mainloop and this overcomes the bug of not quitting the process as described above, but still can lead to unintended output, depending on what you expect:
import tkinter as tk
def tksleep(self, time:float) -> None:
"""
Emulating `time.sleep(seconds)`
Created by TheLizzard, inspired by Thingamabobs
"""
self.after(int(time*1000), self.quit)
self.mainloop()
tk.Misc.tksleep = tksleep
# Example
root = tk.Tk()
root.tksleep(2)

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