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parsing XML in python by using xml.etree.ElementTree

I get an XML file using the request module, then I want to use the xml.etree.ElementTree module to get the output of the element
core-usg-01
but I'm already confused how to do it, im stuck. I tried writing this simple code to get the sysname element, but I get an empty output.
Python code:
import xml.etree.ElementTree as ET
tree = ET.parse('usg.xml')
root = tree.getroot()
print(root.findall('sysname'))
XML file:
<rpc-reply xmlns="urn:ietf:params:xml:ns:netconf:base:1.0" message-id="1">
<data>
<system-state xmlns="urn:ietf:params:xml:ns:yang:ietf-system">
<sysname xmlns="urn:huawei:params:xml:ns:yang:huawei-system">
core-usg-01
</sysname>
</system-state>
</data>
</rpc-reply>

You need to iter() over the root to reach to the child.
for child in root.iter():
print (child.tag, child.attrib)
Which will give you the present children tags and their attributes.
{urn:ietf:params:xml:ns:netconf:base:1.0}rpc-reply {'message-id': '1'}
{urn:ietf:params:xml:ns:netconf:base:1.0}data {}
{urn:ietf:params:xml:ns:yang:ietf-system}system-state {}
{urn:huawei:params:xml:ns:yang:huawei-system}sysname {}
Now you need to loop to your desired tag using following code:
for child in root.findall('.//{urn:ietf:params:xml:ns:yang:ietf-system}system-state'):
temp = child.find('.//{urn:huawei:params:xml:ns:yang:huawei-system}sysname')
print(temp.text)
The output will look like this:
core-usg-01

Try the below one liner
import xml.etree.ElementTree as ET
xml = '''<rpc-reply xmlns="urn:ietf:params:xml:ns:netconf:base:1.0" message-id="1">
<data>
<system-state xmlns="urn:ietf:params:xml:ns:yang:ietf-system">
<sysname xmlns="urn:huawei:params:xml:ns:yang:huawei-system">
core-usg-01
</sysname>
</system-state>
</data>
</rpc-reply>'''
root = ET.fromstring(xml)
print(root.find('.//{urn:huawei:params:xml:ns:yang:huawei-system}sysname').text)
output
core-usg-01

parsing xml with Python minidom

I'm trying to parse elements from .xml file with Python minidom library, but it doesn't seem to work. It's returning "IndexError list out of range". Perhaps I'm using incorrect method/library for the job. Please suggest how to do this. Thanks
from xml.dom import minidom
doc = minidom.parse('/path/to/file/runParameters.xml')
docs = doc.getElementsByTagName('RunParameters')
for el in docs:
cloud = el.getElementsByTagName("EnableCloud")
print(cloud[0].firstChild.nodeValue)
Here is what the structure of the file looks like
<?xml version="1.0"?>
<RunParameters xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<EnableCloud>false</EnableCloud>
<RunParametersVersion>MiSeq</RunParametersVersion>
<CopyManifests>true</CopyManifests>
<FlowcellRFIDTag>
<SerialNumber>000000000-AG01C</SerialNumber>
<PartNumber>17772</PartNumber>
<ExpirationDate>2016-04-10T00:00:00</ExpirationDate>
</FlowcellRFIDTag>
</RunParameters>

Using ElementTree
import xml.etree.ElementTree as ET
xml = '''<?xml version="1.0"?>
<RunParameters xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<EnableCloud>false</EnableCloud>
<RunParametersVersion>MiSeq</RunParametersVersion>
<CopyManifests>true</CopyManifests>
<FlowcellRFIDTag>
<SerialNumber>000000000-AG01C</SerialNumber>
<PartNumber>17772</PartNumber>
<ExpirationDate>2016-04-10T00:00:00</ExpirationDate>
</FlowcellRFIDTag>
</RunParameters>'''
root = ET.fromstring(xml)
print(root.find('.//EnableCloud').text)
output
false

This code works for me. Please try it on your system:
xx = '''
<?xml version="1.0"?>
<RunParameters xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<EnableCloud>false</EnableCloud>
<RunParametersVersion>MiSeq</RunParametersVersion>
<CopyManifests>true</CopyManifests>
<FlowcellRFIDTag>
<SerialNumber>000000000-AG01C</SerialNumber>
<PartNumber>17772</PartNumber>
<ExpirationDate>2016-04-10T00:00:00</ExpirationDate>
</FlowcellRFIDTag>
</RunParameters>
'''.strip()
with open('test2.xml','w') as f:
f.write(xx)
from xml.dom import minidom
doc = minidom.parse('test2.xml')
docs = doc.getElementsByTagName('RunParameters')
for el in docs:
cloud = el.getElementsByTagName("EnableCloud")
print(cloud[0].firstChild.nodeValue)
Output
false

How to get the content of child->child->child->child in XML file using Python

<?xml version="1.0" encoding="UTF-8"?>
<Document xmlns="urn:iso:std:iso:20022:tech:xsd:camt.056.001.01" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<FIToFIPmtCxlReq>
<Assgnmt>
<Id>TEST-ISO-81</Id>
<Assgnr>
<Agt>
<FinInstnId>
<BIC>CCCCGB2L</BIC>
</FinInstnId>
</Agt>
</Assgnr>
<Assgne>
<Agt>
<FinInstnId>
<BIC>MMMMGB2L</BIC>
</FinInstnId>
</Agt>
</Assgne>
<CreDtTm>2009-03-24T11:22:59</CreDtTm>
</Assgnmt>
<TxInf>
<CxlId>103012345</CxlId>
<Case>
<Id>ISO_TEST_CASE</Id>
<Cretr>
<Agt>
<FinInstnId>
<BIC>MMMMGB2L</BIC>
</FinInstnId>
</Agt>
</Cretr>
</Case>
</TxInf>
</Undrlyg>
</FIToFIPmtCxlReq>
</Document>
Here I want to get the content of "TxInf" like all its child and child of child and the data.
What I have tried is :
import xml.etree.ElementTree as ET
from xml.etree import ElementTree
tree = ET.parse('R3-CAMT.056.001.07-ISO-V.XML')
root = tree.getroot()
for element in root.iter():
if element.tag == "{urn:iso:std:iso:20022:tech:xsd:camt.056.001.01}TxInf":
tree._setroot(element.tag)
print(root.tag)
print(root.attrib)
Please suggest if I can change the root with _setroot or any other possible method

Try something along these lines on your code to see if it works:
for r in root.findall(".//*"):
if 'TxInf' in r.tag:
print(ET.tostring(r))
By the way, it may be easier to do it with lxml, if you can use it.

How to get node's value of an XML in Python?

suppose i have an xml file:
<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<quarkSettings>
<UpdatePath></UpdatePath>
<Version>Development</Version>
<Project>ABC</Project>
</quarkSettings>
</configuration>
now i want get Project's value. I have written following code:
import xml.etree.ElementTree as ET
doc1 = ET.parse("Configuration.xml")
for e in doc1.find("Project"):
project =e.text
but it doesn't give the value.

i got the answer:
import xml.etree.ElementTree as ET
doc1 = ET.parse(get_path_for_config_Quark_Release)
root = doc1.getroot()
for element in root.findall("quarkSettings"):
project = element.find("Project").text

Emitting namespace specifications with ElementTree in Python

I am trying to emit an XML file with element-tree that contains an XML declaration and namespaces. Here is my sample code:
from xml.etree import ElementTree as ET
ET.register_namespace('com',"http://www.company.com") #some name
# build a tree structure
root = ET.Element("STUFF")
body = ET.SubElement(root, "MORE_STUFF")
body.text = "STUFF EVERYWHERE!"
# wrap it in an ElementTree instance, and save as XML
tree = ET.ElementTree(root)
tree.write("page.xml",
xml_declaration=True,
method="xml" )
However, neither the <?xml tag comes out nor any namespace/prefix information. I'm more than a little confused here.

Although the docs say otherwise, I only was able to get an <?xml> declaration by specifying both the xml_declaration and the encoding.
You have to declare nodes in the namespace you've registered to get the namespace on the nodes in the file. Here's a fixed version of your code:
from xml.etree import ElementTree as ET
ET.register_namespace('com',"http://www.company.com") #some name
# build a tree structure
root = ET.Element("{http://www.company.com}STUFF")
body = ET.SubElement(root, "{http://www.company.com}MORE_STUFF")
body.text = "STUFF EVERYWHERE!"
# wrap it in an ElementTree instance, and save as XML
tree = ET.ElementTree(root)
tree.write("page.xml",
xml_declaration=True,encoding='utf-8',
method="xml")
Output (page.xml)
<?xml version='1.0' encoding='utf-8'?><com:STUFF xmlns:com="http://www.company.com"><com:MORE_STUFF>STUFF EVERYWHERE!</com:MORE_STUFF></com:STUFF>
ElementTree doesn't pretty-print either. Here's pretty-printed output:
<?xml version='1.0' encoding='utf-8'?>
<com:STUFF xmlns:com="http://www.company.com">
<com:MORE_STUFF>STUFF EVERYWHERE!</com:MORE_STUFF>
</com:STUFF>
You can also declare a default namespace and don't need to register one:
from xml.etree import ElementTree as ET
# build a tree structure
root = ET.Element("{http://www.company.com}STUFF")
body = ET.SubElement(root, "{http://www.company.com}MORE_STUFF")
body.text = "STUFF EVERYWHERE!"
# wrap it in an ElementTree instance, and save as XML
tree = ET.ElementTree(root)
tree.write("page.xml",
xml_declaration=True,encoding='utf-8',
method="xml",default_namespace='http://www.company.com')
Output (pretty-print spacing is mine)
<?xml version='1.0' encoding='utf-8'?>
<STUFF xmlns="http://www.company.com">
<MORE_STUFF>STUFF EVERYWHERE!</MORE_STUFF>
</STUFF>

I've never been able to get the <?xml tag out of the element tree libraries programatically so I'd suggest you try something like this.
from xml.etree import ElementTree as ET
root = ET.Element("STUFF")
root.set('com','http://www.company.com')
body = ET.SubElement(root, "MORE_STUFF")
body.text = "STUFF EVERYWHERE!"
f = open('page.xml', 'w')
f.write('<?xml version="1.0" encoding="UTF-8"?>' + ET.tostring(root))
f.close()
Non std lib python ElementTree implementations may have different ways to specify namespaces, so if you decide to move to lxml, the way you declare those will be different.